I said:
On the other hand, maybe these should be DateTime::Set methods:
my $mean = $set-mean( $sunrise, $sunset );
my $median = $set-median( $sunrise, $sunset );
On Thu, 10 Jun 2004 18:04:36 -0700, Bruce Van Allen wrote
Huh? I'm confused by your usage of 'mean' and 'median'. In the case
Quoting Dave Rolsky [EMAIL PROTECTED]:
With DateTime::Span:
$mid_point =
$span-start-add_duration(
seconds = $span-duration-seconds / 2
);
With DateTime:
$mid_point =
$start-add_duration(
seconds = $end-subtract_datetime_absolute(
On Fri, 11 Jun 2004, Matt Sisk wrote:
Quoting Dave Rolsky [EMAIL PROTECTED]:
With DateTime::Span:
$mid_point =
$span-start-add_duration(
seconds = $span-duration-seconds / 2
);
With DateTime:
$mid_point =
$start-add_duration(
On Thu, 10 Jun 2004, Matt Sisk wrote:
What I'd like to do is simply find the midpoint, more or less, between
two arbitrary datetimes. Off the cuff, knowing nothing about the
internals (which I do, but I'm pretending not to) I'd think this:
$mid = $dt1 + ($dt2 - $dt1)/2
to dwim.
On Thu, 10 Jun 2004, Matt Sisk wrote:
What I'd like to do is simply find the midpoint, more or less, between
two arbitrary datetimes. Off the cuff, knowing nothing about the
internals (which I do, but I'm pretending not to) I'd think this:
Also, I'd like to point out that this really doesn't
Dave Rolsky wrote:
Well, if you just want the _date_, it's pretty easy.
my $dur = $dt1-delta_days($dt2);
# or use Math::Round if you want
my $mid = $dt1-add( days = int( $dur-delta_days / 2 ) );
If you want to account for the time then it gets funkier.
Hmm, indeed.
I need to approximate solar noon
Dave Rolsky wrote:
Also, I'd like to point out that this really doesn't have as much to do
with the internals as it does with the nature of date time math.
You cannot expect to understand date math without understanding that it's
not possible to convert between various units of date/time, in
Matt Sisk wrote:
what is the midpoint of a span?
With DateTime::Span:
$mid_point =
$span-start-add_duration(
seconds = $span-duration-seconds / 2
);
With DateTime:
$mid_point =
$start-add_duration(
seconds = $end-subtract_datetime_absolute(
On Thu, 10 Jun 2004 [EMAIL PROTECTED] wrote:
Matt Sisk wrote:
what is the midpoint of a span?
With DateTime::Span:
$mid_point =
$span-start-add_duration(
seconds = $span-duration-seconds / 2
);
With DateTime:
$mid_point =
$start-add_duration(
seconds
On Thu, 10 Jun 2004 [EMAIL PROTECTED] wrote:
How about a DateTime::Span-midpoint method?
On 11 Jun 2004, at 6:55 AM, Dave Rolsky replied:
Let's wait and see if others ask for it. For now, let's just add those
recipes to the faq.
I'm not sure of the best namespace, but I can see a Util namespace
On 6/11/04 Rick Measham wrote:
On Thu, 10 Jun 2004 [EMAIL PROTECTED] wrote:
How about a DateTime::Span-midpoint method?
On 11 Jun 2004, at 6:55 AM, Dave Rolsky replied:
Let's wait and see if others ask for it. For now, let's just
add those recipes to the faq.
I'm not sure of the best
I understand that division can be expressed as multiplication, but is
there any particular reason why division (/) is not overloaded but
multiplication is for durations? Then you could say:
$midpoint = ($dt2 - $dt1)/2;
rather than
$midpoint = ($dt2 - $dt1) * 0.5;
Small thing. Just curious.
On Wed, 9 Jun 2004, Matt Sisk wrote:
I understand that division can be expressed as multiplication, but is
there any particular reason why division (/) is not overloaded but
multiplication is for durations? Then you could say:
$midpoint = ($dt2 - $dt1)/2;
rather than
$midpoint =
On 10 Jun 2004, at 9:25 AM, Dave Rolsky wrote:
What is half a minute? How long is half a month?
$dtd = DateTime::Duration-new(
months = 1,
minutes = 1,
);
$half_dtd = $dtd / 2;
print $half_dtd-months . \n;
# 0.5
print $half_dtd-seconds . \n;
# 0.5
print strfduration(
normalise =
On Thu, 10 Jun 2004, Rick Measham wrote:
On 10 Jun 2004, at 9:25 AM, Dave Rolsky wrote:
What is half a minute? How long is half a month?
$dtd = DateTime::Duration-new(
months = 1,
minutes = 1,
);
$half_dtd = $dtd / 2;
print $half_dtd-months . \n;
# 0.5
print
On Wed, 9 Jun 2004, Matt Sisk wrote:
I understand that division can be expressed as multiplication, but is
there any particular reason why division (/) is not overloaded but
multiplication is for durations? Then you could say:
$midpoint = ($dt2 - $dt1)/2;
rather than
$midpoint =
Dave Rolsky wrote:
Thinking about this more, I'm considering maybe just requiring that
multiplication be passed an integer, because if you do this:
What I'd like to do is simply find the midpoint, more or less, between
two arbitrary datetimes. Off the cuff, knowing nothing about the
internals
17 matches
Mail list logo
