void F1(...)
{
}
void F2(...)
{
//HOW TO pass F1(..) the args we were called with ?
}
Gabi:
//HOW TO pass F1(..) the args we were called with ?
import std.stdio;
void f1(Args...)(Args args) {
foreach (arg; args)
arg.writeln;
}
void f2(Args...)(Args args) {
f1(args);
}
void main() {
f2(10, "hello", 1.5);
}
Bye,
bearophile
On 08/03/2013 07:58 AM, bearophile wrote:
> Gabi:
>
>> //HOW TO pass F1(..) the args we were called with ?
>
>
> import std.stdio;
>
> void f1(Args...)(Args args) {
> foreach (arg; args)
> arg.writeln;
Would you expect the following two lines behave the same?
writeln(args);
On Saturday, 3 August 2013 at 15:10:20 UTC, Ali Çehreli wrote:
On 08/03/2013 07:58 AM, bearophile wrote:
> Gabi:
>
>> //HOW TO pass F1(..) the args we were called with ?
>
>
> import std.stdio;
>
> void f1(Args...)(Args args) {
> foreach (arg; args)
> arg.writeln;
Would you expe
monarch_dodra:
writefln("%s", 10, "hello", 1.5);
=> 10
According to a recent discussion with Andrei, that's (thankfully)
going to become a run-time exception:
http://d.puremagic.com/issues/show_bug.cgi?id=4927
Bye,
bearophile
On Saturday, 3 August 2013 at 14:58:49 UTC, bearophile wrote:
Gabi:
//HOW TO pass F1(..) the args we were called with ?
import std.stdio;
void f1(Args...)(Args args) {
foreach (arg; args)
arg.writeln;
}
void f2(Args...)(Args args) {
f1(args);
}
void main() {
f2(10, "h
On Saturday, 3 August 2013 at 16:57:41 UTC, Gabi wrote:
On Saturday, 3 August 2013 at 14:58:49 UTC, bearophile wrote:
Gabi:
//HOW TO pass F1(..) the args we were called with ?
import std.stdio;
void f1(Args...)(Args args) {
foreach (arg; args)
arg.writeln;
}
void f2(Args...)(Arg
On Saturday, 3 August 2013 at 18:48:17 UTC, monarch_dodra wrote:
On Saturday, 3 August 2013 at 16:57:41 UTC, Gabi wrote:
On Saturday, 3 August 2013 at 14:58:49 UTC, bearophile wrote:
Gabi:
//HOW TO pass F1(..) the args we were called with ?
import std.stdio;
void f1(Args...)(Args args) {
monarch_dodra:
My guess though, is that it's the same syntax as in C? Use a
straight up elispis:
void foo(...).
Note that you *can't* extract the types from the vararg unless
you *guess* them from an alternative source (for example, "fmt"
in the printf function)
Also, importing "core.vara
On Saturday, 3 August 2013 at 19:12:40 UTC, bearophile wrote:
monarch_dodra:
My guess though, is that it's the same syntax as in C? Use a
straight up elispis:
void foo(...).
Note that you *can't* extract the types from the vararg unless
you *guess* them from an alternative source (for examp
On 08/03/2013 09:05 AM, monarch_dodra wrote:
> On Saturday, 3 August 2013 at 15:10:20 UTC, Ali Çehreli wrote:
>> On 08/03/2013 07:58 AM, bearophile wrote:
>>
>> > Gabi:
>> >
>> >> //HOW TO pass F1(..) the args we were called with ?
>> >
>> >
>> > import std.stdio;
>> >
>> > void f1(Args...)(Arg
On Sunday, 4 August 2013 at 15:29:48 UTC, Ali Çehreli wrote:
On 08/03/2013 09:05 AM, monarch_dodra wrote:
> On Saturday, 3 August 2013 at 15:10:20 UTC, Ali Çehreli wrote:
>> On 08/03/2013 07:58 AM, bearophile wrote:
>>
>> > Gabi:
>> >
>> >> //HOW TO pass F1(..) the args we were called with ?
>
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