Sorry for the fake links, i don't know why it happend.
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Hi,
I ran in this today. Say i have these two models in my app called atest
class Person(models.Model):
name = models.CharField(max_length=255)
age = models.IntegerField(null=True)
class Car(models.Model):
owner = models.ForeignKey('Person', related_name='cars')
brand =
Sorry for all the fake links i don't know why it happend
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Hi,
I ran in this today. Say i have these two models in my app called atest
class Person(models.Model):
name = models.CharField(max_length=255)
age = models.IntegerField(null=True)
class Car(models.Model):
owner = models.ForeignKey('Person', related_name='cars')
brand =
this is expected behavior.
SMTP server should blocks attempt to send email from nonauth client. In
other case it is open relay.
Many thanks,
Serge
+380 636150445
skype: skhohlov
On Thu, Apr 11, 2013 at 9:37 PM, Venkatraman S wrote:
>
> Am sure many in this mailing
I will read those links as soon as I get a chance.
As for the particulars:
Errors:
"NetworkError: 404 NOT FOUND - http://localhost:8001/static/admin/css/base.css;
"NetworkError: 404 NOT FOUND -
http://localhost:8001/static/admin/css/dashboard.css;
OS: Windows 7
Web server: IIS 7 with FastCGI
On 12/04/2013 12:56pm, Mark Lybrand wrote:
I have managed to get a Django app installed on IIS7. It is not finding
the static files for the admin section. Can someone give me some
pointers on the steps I need to take to get static files to work in
general,
On 12 April 2013 10:47, Matt Schinckel wrote:
>
> But a partner relationship is not at all related to a parent-child
> relationship.
Ah! But if you look at my original spec, I had the desire to track
partners - I know it's not part of the parent-child relationship, but
I did
I have managed to get a Django app installed on IIS7. It is not finding
the static files for the admin section. Can someone give me some pointers
on the steps I need to take to get static files to work in general, as well
as specifically how to make my Django app pull the appropriate static
Hi,
I'm fairly new to web development and Django, and I'm trying to make sure
my application is protected against CSRF attacks. I've read through
https://docs.djangoproject.com/en/dev/ref/contrib/csrf/, but I'm not
confident I'm understanding it fully. I'd be very grateful for some
Conceptually all there is in families is people objects and relationship
objects. Therefore, you really only need two tables being person and
relationship.
This could be satisfied with relationship being the 'through' table for
person having m2m('self').
You would probably need a clean()
On Friday, April 12, 2013 9:52:10 AM UTC+9:30, Lachlan Musicman wrote:
>
> On 12 April 2013 08:43, Dennis Lee Bieber
> wrote:
> > On Thu, 11 Apr 2013 16:41:37 +1000, Lachlan Musicman
> >
>
> > declaimed the following in gmane.comp.python.django.user:
Since you're a "reverse" newbie, I'll also mention that you can pass url
variables when you call it. Given this url:
url(r'^books/(?P\d+)/details/', 'detail_view',
name='books_detail_view')
You would call reverse like this (assume that you already have the desired
book in a variable called
Derp, my fault, thanks. I don't know how I missed that.
Odd that that was the page that showed up first in the search results too.
Regards,
-scott
On Apr 11, 2013, at 8:24 PM, James Bennett wrote:
> Notice that your URL marks the version of Django as 'dev' -- that means it's
> the
Notice that your URL marks the version of Django as 'dev' -- that means
it's the documentation for the next, and as-yet-unreleased, version of
Django, which will be 1.6.
For the documentation for 1.5, change 'dev' in the URL to '1.5' (which is
also what will happen when you click the
On 12 April 2013 08:43, Dennis Lee Bieber wrote:
> On Thu, 11 Apr 2013 16:41:37 +1000, Lachlan Musicman
> declaimed the following in gmane.comp.python.django.user:
>
>> # Relations
>> parents = models.ManyToManyField("self", related_name='p',
>>
Hello all,
The public current version cache docs reference make_template_cache_key:
https://docs.djangoproject.com/en/dev/topics/cache/
django.core.cache.utils.make_template_fragment_key(fragment_name, vary_on=None)
If you want to obtain the cache key used for a cached fragment, you can use
Did you try entity.photo.url ? Assuming that entity is a model and photo is
a fileobject like field.
On Friday, April 5, 2013 8:20:11 PM UTC+2, knowledge_seeker wrote:
>
> I am trying to learn to use easy-thumbnails, which is necessary for
> Userena. Now, in the easy-thumbnails 'ReadMe' file it
Joe,
Thanks for looking into it. The app isn't actually doing anything yet.
Eventually I'll have the submit do some work and redirect to a more useful
page.
Thanks again for your help.
On Thursday, April 11, 2013 4:44:18 PM UTC-7, JoeLinux wrote:
> Keep in mind that your "p" variable won't
Keep in mind that your "p" variable won't be available to your index view
on a redirect, so I'm just working on the assumption that you just posted a
small code snippet and you're actually doing something with it beforehand.
--
Joey Espinosa
Python Developer
http://about.me/joelinux
On Apr 11,
I got it, thanks Joe!
url(r'^$', 'index', name='gis_wo_index'),
return HttpResponseRedirect(reverse('gis_wo_index'))
On Thursday, April 11, 2013 4:31:26 PM UTC-7, Nick D wrote:
> I'm trying to use the reverse() function to get back to my index, but I'm
> not sure if my view are
Here's my urlconf for the index: url(r'^$', 'index'),
So how should I call it in the reverse function?
If I try the reverse function without the args I get the following error:
Reverse for 'gis_wo_app.views.index' with arguments '()' and keyword
arguments '{}' not found.
On Thursday, April 11,
Hi Nick,
The request object is always sent to a view, so from the perspective of
"reverse", index has no args. Try removing the args= part of the reverse
call and see if it works.
_Nik
On 4/11/2013 4:31 PM, Nick D wrote:
> I'm trying to use the reverse() function to get back to my index, but
>
If you have your index page as a named url in your urls.py:
url(r'^$', 'index', name='app_index')
Then you can call HttpResponseRedirect as follows:
return HttpResponseRedirect(reverse('app_index'))
No need to directly specify the request object... it will definitely be
available to your index
I'm trying to use the reverse() function to get back to my index, but I'm
not sure if my view are compatible. My index funtion takes a request ( def
index(request)). I can't seem to call the reverse function with the request
object in the args, but if I call the reverse function without any
Fixed now.
See
https://groups.google.com/forum/?fromgroups=#!topic/django-users/FxTD5M0x-G8
for the resolution, if anyone runs into the same thing.
On Wednesday, April 10, 2013 5:04:58 PM UTC-7, Lewis Sobotkiewicz wrote:
>
> Seems to be caused by Django not sending the "request_finished"
So figured it out.
Apparently Ubuntu 12.04 packages uwsgi 1.0.3 in their apt repository, which
doesn't support calling close() on the WSGI application object returned by
Django. I had installed that uWsgi version, then installed a more
up-to-date version with pip. ie.
pip install uwsgi==1.4.4
On Thu, Apr 11, 2013 at 9:36 PM, Mark Lybrand wrote:
> I understand that there is only experimental support for Python 3.x in
> Django 1.5. Is there any feeling for how far out a stable version of
> Django using Python 3.x might be? I understand that any answer is likely
>
Another direction might be to run a separate WSGI HTTP server (like
gunicorn) and proxy to it from Apache. Saves the hassle of messing
around with mod_wsgi.
_Nik
On 4/11/2013 3:20 PM, Joey Espinosa wrote:
>
> I had basically the same issue as you.
>
> With only one Django app deployed, it's easy
I had basically the same issue as you.
With only one Django app deployed, it's easy to just stick your
WSGIPythonPath directive in /etc/apache2/apache.conf.
But with multiple different virtualenvs, you need to do something like this:
Tommy, an store procedure its a piece of sql code that its executed by the
data base server (take a look here
http://www.postgresql.org/docs/8.0/static/plpgsql.html), so you execute
that procedure from django with a raw sql statement.
Im not familiar with postgresql but in firebird you can do:
Hi Joey,
All of them are in different virtualenvs.
On 04/11/2013 11:02 PM, Joey Espinosa wrote:
>
> I meant Python libs/binary.
>
> --
> Joey "JoeLinux" Espinosa
> Python Developer
> http://about.me/joelinux
>
> On Apr 11, 2013 5:00 PM, "Joey Espinosa"
I meant Python libs/binary.
--
Joey "JoeLinux" Espinosa
Python Developer
http://about.me/joelinux
On Apr 11, 2013 5:00 PM, "Joey Espinosa" wrote:
> Do all your sites share the same Python, or are they in different
> virtualenvs?
>
> --
> Joey "JoeLinux" Espinosa
>
Do all your sites share the same Python, or are they in different
virtualenvs?
--
Joey "JoeLinux" Espinosa
Python Developer
http://about.me/joelinux
On Apr 11, 2013 3:39 PM, "Roberto López López" wrote:
>
> Hi everyone,
>
> We are trying to deploy a django application on
Hi everyone,
We are trying to deploy a django application on our apache server
(mod_wsgi) following
https://docs.djangoproject.com/en/1.4/howto/deployment/wsgi/modwsgi/ We
have different virtualhosts defined as well in httpd.conf.
We are now stuck, apache is throwing the following error:
Circular import itself isn't a problem--Python will deal with that.
Problems arise according to the order in which classes, etc. are loaded
from each module and where the required classes are used. As the
previous poster mentioned, you can get around this by moving one of the
import statements
Am sure many in this mailing list are running websites that send emails to
customers from their django applications. And also emails from the
operating system(like logwatch etc). I was wondering how you do you
achieve both?
For example, when i use a gmail id, i see that i am able to send an
You should always consider that circular imports may indicate problems with how
you structured your applications and/or models, however, if you're left with no
choice, you can have an import statement inside a function, which generally
solves most of these issues.
Enviado desde mi BlackBerry de
Hi Rafael,
Thank you for the reply. Not too sure if I undersatnd all of it, though.
My learning curve is more down than up.
You mentioned a possibly better process "using the store procedure". Do
you know of any examples of what you have in mind, perhaps?
I have not found a function in
Hi all,
I have a util file, which will do some stuffs and then, update a model (so
i have to import the models in this file). Also, in my models file, I
trigger a post_save signal to call the util file file (so I have to import
this file in the models file). Obviously, I will get a circle
Thank you...
On Thursday, April 11, 2013 8:50:06 AM UTC-4, arne^ wrote:
>
> Hi frocco,
>
> this filter condition works for me:
>
> {
> "groups__name": "A",
> "is_active": true
> }
>
> "A" is the name of the Group. This filter selects all actives users that
> are also member of the "A" group
I believe pillow supports python 3, you can use it as a drop in replacement
of PIL
On Thu, Apr 11, 2013 at 6:21 PM, Timothy Makobu wrote:
> From the release notes
> https://docs.djangoproject.com/en/dev/releases/1.5/"Django
> 1.6, will support Python 3 without
On Thu, Apr 11, 2013 at 3:42 PM, Matthieu Bouron
wrote:
> Hello,
>
> Is there a way to handle many-to-many relationship with raw sql queries ?
> I have the following model:
>
> from django.db import models
>
> class Tag(models.Model):
> name =
Hello,
Is there a way to handle many-to-many relationship with raw sql queries ?
I have the following model:
from django.db import models
class Tag(models.Model):
name = models.CharField(max_length=512, unique=True)
class Bookmark(models.Model):
link = models.CharField(max_length=512)
>From the release notes
https://docs.djangoproject.com/en/dev/releases/1.5/ "Django
1.6, will support Python 3 without reservations."
And from the release-process
https://docs.djangoproject.com/en/1.2/internals/release-process/ "Minor
release (1.1, 1.2, etc.) will happen roughly every nine
I develop my current project with python 2.7 and 3.3 and so far my problem
is not with django being 3.x compatible but critical/popular third-party
packages like PIL, django-debug-toolbar etc not being python 3 ready. I
hope those and several other packages will be ported to python 3, since
Python
Thanks guys, everything is much clearer now
And there is even a HOW-TO page
https://docs.djangoproject.com/en/1.5/howto/static-files/deployment/
that I also missed as well
Cool beans this Django malarky :)
On Thu, 11 Apr 2013 14:08:29 +0100
Tom Evans wrote:
> On
I understand that there is only experimental support for Python 3.x in
Django 1.5. Is there any feeling for how far out a stable version of
Django using Python 3.x might be? I understand that any answer is likely
to be conjecture and guessing and that is okay. I am just trying to gauge
if I am
Thanks. I appreciate the glimpse into how another developer organizes
their application. This will help me decide what I think might work for my
needs.
On Thu, Apr 11, 2013 at 5:44 AM, Tom Evans wrote:
> On Thu, Apr 11, 2013 at 1:22 PM, Mark Lybrand
On Thu, Apr 11, 2013 at 1:50 PM, Drew Ferguson wrote:
> On Thu, 11 Apr 2013 14:54:50 +0300
> Avraham Serour wrote:
>
>> you can create a subdomain (static.yourdomain.com) and serve static using
>> that, configure the second webserver to serve this
On Thu, 11 Apr 2013 14:54:50 +0300
Avraham Serour wrote:
> you can create a subdomain (static.yourdomain.com) and serve static using
> that, configure the second webserver to serve this subdomain
OK, but then all static references must be prefixed with the domain in
Hi frocco,
this filter condition works for me:
{
"groups__name": "A",
"is_active": true
}
"A" is the name of the Group. This filter selects all actives users that
are also member of the "A" group as recipients.
-Arne
Am Sonntag, 7. April 2013 14:49:23 UTC+2 schrieb frocco:
>
> Hello,
>
>
On Thu, Apr 11, 2013 at 1:22 PM, Mark Lybrand wrote:
> Sorry about that, here is the tuple in question:
>
> INSTALLED_APPS = (
> 'django.contrib.auth',
> 'django.contrib.contenttypes',
> 'django.contrib.sessions',
> 'django.contrib.sites',
>
Sorry about that, here is the tuple in question:
INSTALLED_APPS = (
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.sites',
'django.contrib.messages',
'django.contrib.staticfiles',
# Uncomment the next line to enable the
On Thu, Apr 11, 2013 at 12:41 PM, Mark Lybrand wrote:
> So, you have a management/commands structure in each app of your project and
> not in the main "app" (or whatever that thing is called). Here is the
> structure of my whole project thus far (I had just shown the part
Hello,
I need a way(form in admin) to allow user to select how he will upload a
file:
-- from local(his) machine
-- from filesystem(where django is running)
-- from external url
Does not matter what way user selects, I want to read that file and write
to custom location(path).
The model itself
you can create a subdomain (static.yourdomain.com) and serve static using
that, configure the second webserver to serve this subdomain
On Thu, Apr 11, 2013 at 2:01 PM, Drew Ferguson wrote:
> Hi
>
> The docs recommend serving static data from a second web server rather
Hi
The docs recommend serving static data from a second web server rather
than the one serving via WSGI
How do folks implement this? I can't figure how to serve data for the
same domain using 2 web servers. Am I missing something?
--
Drew
signature.asc
Description: PGP signature
Hi Django users,
We're trying to migrate a project from Django 1.4 to Django 1.5.1 ...
The web service has to be accessible both as authenticated and anonymous
user. And we use external authentication with an Apache module (which sets
"REMOTE_USER" env var in accordance with
To answer my own question: Yes, that works. Follow up question: does each
app need its own set of commands? It would seem funny to put all the
commands for a project into one of the apps. Or is that the idea? That
commands are meant to be app-specific?
On Thu, Apr 11, 2013 at 4:41 AM, Mark
So, you have a management/commands structure in each app of your project
and not in the main "app" (or whatever that thing is called). Here is the
structure of my whole project thus far (I had just shown the part that I
thought was important). As you can see I already had an app and the app is
Further debugging ... printed the HTML that is produced by the call to
render and the HTML is created correctly. Thus, I have concluded the
problem has nothing to do with Django. Closed.
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To
Sanjay!
On 11 April 2013 18:00, Sanjay Bhangar wrote:
> Lachlan,
>
> Not sure if I grokked your problem exactly, but just from personal
> experience when I found my brain turned to jelly with a similar-sounding
> issue before, I believe I found the answer in the
Mike,
thanks for your reply.
On 11 April 2013 17:55, Mike Dewhirst wrote:
> On 11/04/2013 4:41pm, Lachlan Musicman wrote:
>>
>> At the moment I have tables on the database:
>>
>> account_account
>> account_account_parents
>> account_account_children
>>
Lachlan,
Not sure if I grokked your problem exactly, but just from personal
experience when I found my brain turned to jelly with a similar-sounding
issue before, I believe I found the answer in the "symmetrical=False"
option .. I do believe setting symmetrical=False for your 'parents' and
On 11/04/2013 4:41pm, Lachlan Musicman wrote:
At the moment I have tables on the database:
account_account
account_account_parents
account_account_children
account_account_partners
account_account_siblings
Not wishing to throw a spanner in the works, but I have always had a
design in the
Hi,
I have a view that has a form and multiple formsets:
The formsets and their templates are not dependent on each other and can be
used separately in other views.
However, at least 1 form must be filled up. The form can be from any
formsets.
How can I validate this?
Should I be doing it
Django 1.5.1. I have a data model with a Django TextField:
notes=models.TextField(db_column='notes',blank=True) and in thy MySQL the
'notes' field is "TEXT".
When I output the 'notes' field in a Django Template in a for loop, the
template just stops. It does not go through the entire list of
I tried reading the code in django/db/models/fields/related.py but
quickly realised it was beyond me groking in a half hour.
BUT, for some reason I felt compelled to test through the admin
interface and it is working. ie, I can create and remove siblings and
partners from each other, error free
For first step you need create application, "manage.py startapp myapp".
'management' folder should be located in your application folder. And
don't forget add application in INSTALLED_APPS in your settings.py
(INSTALLED_APPS = ('myapp', ))
On Thu, Apr 11, 2013 at 4:52 AM, Mark Lybrand
Hi
In django you can change the public URL with out change the function call in
the view.py
The URL.py is flexible and can be just inside each app you create for reusable .
Mulianto
Sent from my iPhone
On 11 Apr 2013, at 13:11, surya wrote:
> I have an unstructured
On 11 April 2013 16:19, Lachlan Musicman wrote:
> Hi,
>
> I'm trying to implement a simple family tree type structure. I'm
> expanding on this example code base:
>
> https://github.com/mieows/familytree-django/blob/master/models.py
>
> (please ignore any errors in that
Hi,
I'm trying to implement a simple family tree type structure. I'm
expanding on this example code base:
https://github.com/mieows/familytree-django/blob/master/models.py
(please ignore any errors in that models.py, I've addressed many of them)
Ok, simply I have:
class Account(models.Model)
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