hi.
I have worked for django using pagination on async function
but it seems to having errors cause of default Paginator.
(like in the counting functions)
is there any plan to make it support async by Paginator itself?
or is it already has kind of functionalities but I just have not found one
ards, David
>
>> On Fri, Nov 26, 2021 at 6:41 AM Eugene TUYIZERE
>> wrote:
>> Dear Team,
>>
>> I have 4 cards on a single html page. I want to display data on each one but
>> since the data has many rows I want to apply pagination on each card. How
&
nce the data has many rows I want to apply pagination on each card.
> How can I achieve this? I was thinking of using ListView but this displays
> pagination on the whole page. I did not try any other codes because I have
> no idea
>
> Kindly assist.
> --
> *Eugene*
>
>
>
Dear Team,
I have 4 cards on a single html page. I want to display data on each one
but since the data has many rows I want to apply pagination on each card.
How can I achieve this? I was thinking of using ListView but this displays
pagination on the whole page. I did not try any other codes
bro try to send a intended code
On Tue, Jul 28, 2020 at 5:16 PM Harvindar Singh Garcha <
garchaama...@gmail.com> wrote:
> I am new to Django, and trying to paginate a dictionary objects,
> However I am unable to so and not getting what's wrong with my code,
> Its still printing whole data on a si
I am new to Django, and trying to paginate a dictionary objects,
However I am unable to so and not getting what's wrong with my code,
Its still printing whole data on a single page. Above I have posted my View
along with template code.
class Search(ListView):
paginate_by = 5
def get(self, re
I am new to Django, and trying to paginate a dictionary objects, I am
calling stackoverflow API where I want the result to get paginated. However
I am unable to so and not getting what's wrong with my code. Above I have
posted my View along with template code.
>
>
> class Search(ListView):
> p
on the page.
>>
>> I was not using paginations and I have thousands of products so the page
>> was obviously loading very slow.
>>
>> I added pagination and let python manage the query instead of it
>> happening on the server-side. This increased the page load but
on the platform
> with hundreds of sellers.
>
> I was randomizing the product category page when loaded so that items from
> all sellers could appear on the page.
>
> I was not using paginations and I have thousands of products so the page
> was obviously loading very slow.
>
paginations and I have thousands of products so the page
was obviously loading very slow.
I added pagination and let python manage the query instead of it happening
on the server-side. This increased the page load but I lost my
randomization.
The first page is the only page getting random items
lists, categoies and Post list. the homepage will be contained couple of
> blocks or boxes. each box will have different query list like Post list,
> User List, category list. But only one context will have pagination and
> other won't and ofcourse the pagination will be working on Post l
list like Post list,
> User List, category list. But only one context will have pagination and
> other won't and ofcourse the pagination will be working on Post list.
>
> here is the views.py:
>
> class BlogappListView(ListView):
> model = Category,CustomUs
in django, i am trying to list some queries of several objects like user lists,
categoies and Post list. the homepage will be contained couple of blocks or
boxes. each box will have different query list like Post list, User List,
category list. But only one context will have pagination and
I think there might be a way around, below is the code modified for views.py
@login_required
def home_view(request):
"""Display all the post of friends and own posts on the dashboard"""
posts = Post.objects.order_by('-date_posted')
media: MEDIA_URL
# 'post':Post.objects.filter(Q(author=request.use
Dear Sir,
it shows all the text on all the pages.
if there are total 5 posts, then it shows all the 5 posts on all the pages.
Thanks,
Akshat Zala
On Saturday, 30 May 2020 20:54:35 UTC+5:30, maninder singh Kumar wrote:
>
> Views.py looks fine !
>
> regards
> willy
>
>
> On Sat, May 30, 2020 at
dd:'4' %}
{{ num }}
{% endif %}
{% endfor %}
{% if page_obj.has_next %}
arrow_right
Last
{% endif %}
{% endif %}
It only shows pagination and posts are not seen in template.
On Saturday, 30 May 2020 21:39:52 UTC+5:30, RyuCoder wrote:
>
> Hi akshat,
> What is the difficulty?
&g
Hi akshat,
What is the difficulty?
Where have you defined the variable is_paginated? Is it present in the
context?
On Sat, May 30, 2020, 8:53 PM maninder singh Kumar <
maninder.s.ku...@gmail.com> wrote:
> Views.py looks fine !
>
> regards
> willy
>
>
> On Sat, May 30, 2020 at 7:22 PM Akshat Zal
Views.py looks fine !
regards
willy
On Sat, May 30, 2020 at 7:22 PM Akshat Zala wrote:
> Hello,
>
> I am finding it difficult to paginate through all the posts
>
> My views.py :
>
> @login_required
> def home_view(request):
> """Display all the post of friends and own posts on the dashboard"""
On Saturday, 30 May 2020 19:20:47 UTC+5:30, Akshat Zala wrote:
>
> Hello,
>
> I am finding it difficult to paginate through all the posts
>
> My views.py :
>
> @login_required
> def home_view(request):
> """Display all the post of friends and own posts on the dashboard"""
> posts = Post.objects.
Hello,
I am finding it difficult to paginate through all the posts
My views.py :
@login_required
def home_view(request):
"""Display all the post of friends and own posts on the dashboard"""
posts = Post.objects.all().order_by('-date_posted')
media: MEDIA_URL
# 'post':Post.objects.filter(Q(author
one that is providing data to the
page + options in dropdown menus.
Also, the pagination has been implemented in the page which also changes
when the dropdown option is chosen.
Is there a way that instead of managing this from template side, can I
manage the pagination(when dropdown is chosen and
Does anyone have some example code to achieve pagination to display a model
with many records in Admin, please?
admin.py –
class CurrencyAdmin(admin.ModelAdmin):
paginate_by=10
list_display = ('id', 'currency_Code', 'currency_Description')
ist.number }} of {{
>>> object_list.paginator.num_pages }}.
>>
>>
>>
>>
>>> {% if object_list.has_next %}
>>
>> next
>>
>> last »
>>
>> {% endif %}
>>
>>
&g
Would you send your html codes relating to pagination
در تاریخ چهارشنبه ۲۵ سپتامبر ۲۰۱۹، ۱۵:۰۳ leb dev
نوشت:
> i tried your answer and display an error :
>
> That page number is not an integer
>
> --
> You received this message because you are subscribed to the Google Grou
i tried your answer and display an error :
That page number is not an integer
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"Django users" group.
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to django-users+unsubscr...@googlegro
nator.page(1)
except EmptyPage:
# If page is out of range (e.g. ), deliver last page of results.
queryset = paginator.page(paginator.num_pages)
Sent from Mail for Windows 10
From: leb dev
Sent: Wednesday, September 25, 2019 2:32 PM
To: Django users
Subject: where is the error in pagi
no i am using function based views
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To view this discussion on the web
Hi,
Do you use Class Based View ?
Sent from Mail for Windows 10
From: leb dev
Sent: Wednesday, September 25, 2019 2:32 PM
To: Django users
Subject: where is the error in pagination?
i have a django project and it includes pagination i do not know where is the
error in my code but once i
i have a django project and it includes pagination i do not know where is
the error in my code but once i tired to go to the next or previous page it
crash and display the below error :
> can only concatenate str(not ""NoneType) to str
query=request.GE
_staff`, `auth_user`.`is_active`, `auth_user`.`date_joined`
FROM `auth_user` WHERE `auth_user`.`username` LIKE BINARY %alpha%
1:
https://docs.djangoproject.com/en/2.2/topics/db/sql/#performing-raw-queries
--
Regards
Deep L Sukhwani
On Wed, 25 Sep 2019 at 00:47, leb dev wrote:
> I now how
I now how to use django pagination with ORM django after filtering the
required data and put in into *pagination div*
*queryset_list = employee.objects.all()*
*query=request.GET.get("q")*
*if query:*
*queryset_list=queryset_list.filter(*
* Q(name__icont
/benfred/py-spy) which
produced the attached charts.
Basically it seems like there are many extra function calls, seemingly
related to pagination, and the control flow here is different following the
upgrade.
Any ideas / help would be amazing!
Thanks
--
You received this message because you are
8 AM drone4four wrote:
> As part of the official Django doc on Pagination
> <https://docs.djangoproject.com/en/2.2/topics/pagination/#using-paginator-in-a-view>,
> take a look at the listing function:
>
> def listing(request):
> contact_list = Contacts.objects.all()
>
As part of the official Django doc on Pagination
<https://docs.djangoproject.com/en/2.2/topics/pagination/#using-paginator-in-a-view>,
take a look at the listing function:
def listing(request):
contact_list = Contacts.objects.all()
paginator = Paginator(contact_list, 25) # S
ute
>> return self._execute_with_wrappers(sql, params, many=False,
>> executor=self._execute)
>> File "(...)\.env\lib\site-packages\django\db\backends\utils.py", line
>> 76, in _execute_with_wrappers
>> return executor(sql, params, many, context)
>
ends\utils.py", line
> 76, in _execute_with_wrappers
> return executor(sql, params, many, context)
> File "(...)\.env\lib\site-packages\django\db\backends\utils.py", line
> 84, in _execute
> return self.cursor.execute(sql, params)
> File "(...)\.
ecute(sql, params)
File "(...)\.env\lib\site-packages\django\db\utils.py", line 89, in
__exit__
raise dj_exc_value.with_traceback(traceback) from exc_value
File "(...)\.env\lib\site-packages\django\db\backends\utils.py", line 84,
in _execute
return self.cursor.
Thanks a lot. I worked that out by making the Load More as a clickable
button which when pressed will show the contents.
On Tue, Feb 19, 2019 at 9:00 PM Godson Rapture wrote:
> Check out simple is better than complex blog. It should have a topic on
> pagination to help you
>
> On
It did not work. I tried making it using JavaScript like in websites if you
might have seen when you press the button then only it shows the content or
scrolls down.
On Tue, Feb 19, 2019 at 2:01 PM Siddharth Tamang <
tamangsiddhart...@gmail.com> wrote:
> Can you try this in your views.py?
>
> fr
Check out simple is better than complex blog. It should have a topic on
pagination to help you
On Tue, Feb 19, 2019, 9:20 AM Aakash Baranwal wrote:
> Hello,
>
> Thanks for offering me your help, but the problem is I can't upload it on
> internet as I have signed a Non Disclos
Can you try this in your views.py?
from django.core.paginator import EmptyPage, PageNotAnInteger, Paginator
views.py
feedTextAll = feedText.objects.order_by('-feedTexDate')
pages = Paginator(feedTextAll,5)
pageNum = request.GET.get('page')
feedtext = pages.get_page(pageNum)
return render(request
lving this issue.
I am extremely sorry about this.
On Tue, Feb 19, 2019 at 1:38 PM Godson Rapture wrote:
> Can you upload your code on github let me check where your problem is?
>
> On Tue, Feb 19, 2019, 6:43 AM Siddharth Tamang <
> tamangsiddhart...@gmail.com> wrote:
>
&g
Can you upload your code on github let me check where your problem is?
On Tue, Feb 19, 2019, 6:43 AM Siddharth Tamang
wrote:
> Are you trying pagination using JavaScript or Django?
>
> On Mon, Feb 18, 2019 at 11:47 PM Aakash Baranwal
> wrote:
>
>> Hello Everyone,
>>
set in the beginning, but not
> going beyond that.
>
> On Tue, Feb 19, 2019 at 11:13 AM Siddharth Tamang <
> tamangsiddhart...@gmail.com> wrote:
>
>> Are you trying pagination using JavaScript or Django?
>>
>> On Mon, Feb 18, 2019 at 11:47 PM Aakash Baranwal
&g
I have also used Ajax with that. It's load more button is not working, it
is showing the 10 posts which is the limit I set in the beginning, but not
going beyond that.
On Tue, Feb 19, 2019 at 11:13 AM Siddharth Tamang <
tamangsiddhart...@gmail.com> wrote:
> Are you trying pa
I am trying to do it using Django. I used Django Rest Framework API
Guide-Pagination for reference
On Tue, Feb 19, 2019 at 11:13 AM Siddharth Tamang <
tamangsiddhart...@gmail.com> wrote:
> Are you trying pagination using JavaScript or Django?
>
> On Mon, Feb 18, 2019 at 11:47 PM
Are you trying pagination using JavaScript or Django?
On Mon, Feb 18, 2019 at 11:47 PM Aakash Baranwal
wrote:
> Hello Everyone,
>
> I am new to Django and working towards developing a web app where 10 posts
> appear at a time with a "Load More" option given at last whic
I'm building a page with pagination and a filter form (2 GET requests). If
the URL includes both pagination and filter results, something like
`/questions/?page=2&all_questions=on`, it works fine. It also works if it
just has filter results, something like `/questions/?all_que
On Tue, Nov 28, 2017 at 3:00 PM, Daniel Jewett wrote:
> I just noticed that the URL get string in my admin app is off by one from
> the auto generated pagination links. It appears that the pagination URLs
> are zero based.
>
> For example if I'm on page 4 of results accordi
I just noticed that the URL get string in my admin app is off by one from
the auto generated pagination links. It appears that the pagination URLs
are zero based.
For example if I'm on page 4 of results according to the pagination links,
the URL looks like '?p=3'
Is th
ken, but I think the wizard link below requires a “static” or
semi-static forms flow path (form1, form2, …, formlast). Generally, when you do
pagination, there is no preset number of pages - it depends upon the data being
requested or available. So, I think that option would not work. But, if I’m
27;s how you're supposed to program in JS? Been doing it that
way for years. ;-)
I may be mistaken, but I think the wizard link below requires a “static” or
semi-static forms flow path (form1, form2, …, formlast). Generally, when
you do pagination, there is no preset number of pages - it depends
semi-static forms flow path (form1, form2, …, formlast). Generally, when you do
pagination, there is no preset number of pages - it depends upon the data being
requested or available. So, I think that option would not work. But, if I’m
wrong, I’d love to know. Thanks.
And, as for using Java just so
r the
full category or individual flashcards to be added to their practice
account.
To maintain user inputted checkboxes on multiple pages, I must use POST.
But, pagination only uses GET. So, a hack on pagination is to wrap the
Next/Previous buttons in a sub-form and POST using the buttons. This
their practice account.
To maintain user inputted checkboxes on multiple pages, I must use POST. But,
pagination only uses GET. So, a hack on pagination is to wrap the Next/Previous
buttons in a sub-form and POST using the buttons. This works for pagination,
but then my normal “I’m done, submit
Yep. My solution is a custom template tag
from django.template.defaulttags import register
from urllib.parse import urlencode
@register.simple_tag(takes_context=True)
def querystringmod(context, *args):
"""Modify current querystring:
{% querystringmod name value [name value [...]] %}
The code for rendering pagination controls in my app is the same everywhere:
{% if is_paginated %}
{% if page_obj.has_previous %}
Previous
{% endif %}
{% if page_obj.has_next %}
Previous
{% endif
On Monday, February 13, 2017 at 1:03:23 AM UTC+5:30, Kazi Atik wrote:
>
> here is my views/
>
> from django.contrib.auth.models import User
>
> from django.core.paginator import Paginator,EmptyPage, PageNotAnInteger
> from friends.models import Friendship,UserProfile
> from django.http import Htt
here is my views/
from django.contrib.auth.models import User
from django.core.paginator import Paginator,EmptyPage, PageNotAnInteger
from friends.models import Friendship,UserProfile
from django.http import HttpResponse, HttpResponseRedirect, Http404
from django.shortcuts import render
def das
er
>> scroll the browser another batches will be append to the browser.
>> Below are the 3 ways am aiming to achieve this:
>>
>> 1. Using django pagination feature.
>>
>> 2. Everytime records need to be appended to the browser , an ajax call is
>> made to the view, t
can take minutes. I have experienced that issue with two different
> project.
>
> Django pagination by itself won't give you the infinite scroll you are
> expecting. But it should give you an easy interface for slicing the
> data from your db.
>
> An easier way might be
his:
>
> 1. Using django pagination feature.
>
> 2. Everytime records need to be appended to the browser , an ajax call is
> made to the view, then the queryset is slice using appropriate lower and
> upper band. Then the returned record is appended to the browser.
>
> 3. Fetch
I would use 1 + 2 from your list.
3 might work on 1000 record, depending on how much data there is per
record. But if you grow to more than 10,000 record, the page loading
can take minutes. I have experienced that issue with two different
project.
Django pagination by itself won't give yo
the 3 ways am aiming to achieve this:
1. Using django pagination feature.
2. Everytime records need to be appended to the browser , an ajax call is
made to the view, then the queryset is slice using appropriate lower and
upper band. Then the returned record is appended to the browser.
3. Fetch
i find solutio
using https://docs.djangoproject.com/en/1.9/topics/pagination/ thnX
Τη Τρίτη, 26 Ιανουαρίου 2016 - 3:10:06 μ.μ. UTC+2, ο χρήστης pa xapy έγραψε:
>
> you want to paginate both querysets at the same page?
> i believe it's a pretty strange idea and if so, you shoul
i foolow the steps but i have again error my new view :
def index(request):
try:
page = request.GET.get('page', 1),
except PageNotAnInteger:
page = 1,
objects = ['john', 'edward', 'josh', 'frank']
p = Paginator(objects,request=request)
people = p.page(page)
that method is Confusing,i try to understand,i create new view or i work
with current?i not understand it the using 'people' and object on they view
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post l
are you using python 3?
that's actually what i talking about - it's too old
try another one, like
this https://github.com/jamespacileo/django-pure-pagination - follow
the instructions and i hope you'll be fine
On Tuesday, January 26, 2016 at 5:09:29 PM UTC+3, Xristos Xristo
i follow the simpe steps but i take error invalid syntax
(pagination_tags.py, line 225)
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my probl
thnx you i try to use that now
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specific, because on my view
> i have two Querys
s for
package you choose
but i'm afraid that this particular app is too old and you can experience
some troubles with it
anyways, you can try: pip install django-pagination
On Tuesday, January 26, 2016 at 4:44:05 PM UTC+3, Xristos Xristoou wrote:
>
> one more question how to install this
one more question how to install this ?autopagination ?i dont see anything
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specif
you can read the usage doc i sent linked, but yes - you don't need to do
anything with you queryset in view only pass it to template
On Tuesday, January 26, 2016 at 4:39:17 PM UTC+3, Xristos Xristoou wrote:
>
> if i use {autopagination} i dont need quyre on my view ?
>
> Τη Δευτέρα, 25 Ιανουαρίου
if i use {autopagination} i dont need quyre on my view ?
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specific, because on my
if you'll decide to use some app for pagination, you can do it in template,
like
so https://github.com/ericflo/django-pagination/blob/master/docs/usage.txt
({% autopaginate posts 10 %})
or you can choose one of
these https://www.djangopackages.com/grids/g/pagination/
there is no actual ne
can you show me one examples with my view ?
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specific, because on my view
> i hav
you want to paginate both querysets at the same page?
i believe it's a pretty strange idea and if so, you should think how to
refactor it
if you want only paginate posts, i'll recommend you to use
django-pagination app of some sort, it's can be used in template
On Monday, Januar
i want to using Paginator in my main page for my post list. i see docs and
examples for that but i thing my problem is a specific, because on my view
i have two Querys not one.
def index(request):
return render_to_response("blog/posts_list.html", {
'categories': Category.objects.all
Hi,
If you have the request context processor installed, you can do this:
{% bootstrap_paginate object_list range=request.GET.range %}
Collin
On Thursday, March 5, 2015 at 4:35:33 AM UTC-5, SHINTO PETER wrote:
>
> {% load bootstrap_pagination %}
> {% bootstrap_paginate object_list range=10 %
{% load bootstrap_pagination %}
{% bootstrap_paginate object_list range=10 %}
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copy/pasting from a recent website I worked on for an example...
we actually just had a "load more" button without showing the total number
of pages. Not saying you should do it this way, but it's one possible way.
def listing(request):
new_list = NewPost.objects.all()
if request.GET.get(
I need to make ajax pagination in my project and not allowed to use side
modules like dajax or endless-pagination.
Code in my views.py is following
def listing(request):
news_list = NewPost.objects.all()
paginator = Paginator(news_list, 2)
page = request.GET.get('page'
I'm trying to set up dajax pagination in py app. The problem is when I add
import dajaxwebsite.examples.views
to views.py
My css stop working.
Maybe I should use another ajax pagination plugin? like endless-pagination
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Sir I will mail my appointment modal please give me a sample solution
On Aug 27, 2014 8:36 PM, "Camilo Torres" wrote:
> This is basically a DB query issue. Follow these general directions:
>
> 1. In your page add a form with a select with the filtering options.
> 2. In your view, instead of getti
This is basically a DB query issue. Follow these general directions:
1. In your page add a form with a select with the filtering options.
2. In your view, instead of getting all the instance of your model, filter by
the selected option.
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I want to do pagination using filter on same page which show all on same
page
On Aug 25, 2014 7:26 PM, "Collin Anderson" wrote:
> What do you have so far?
>
> --
> You received this message because you are subscribed to a topic in the
> Google Groups "Django users
I have model with date time pk appointment details
On Aug 25, 2014 7:26 PM, "Collin Anderson" wrote:
> What do you have so far?
>
> --
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> Google Groups "Django users" group.
> To unsubscribe from this topic, visit
> https://g
What do you have so far?
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hello friend
i want to use pagination for today appointment tommorows appoint and past
appointment can any1 help me out in quite greater need
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I've created a paginator for RawQuerySets.
https://github.com/seamusmb/django-paginator-rawqueryset
On Tuesday, March 26, 2013 5:51:41 AM UTC-4, chambe...@gmail.com wrote:
>
> I'm trying to implement Django's built in pagination feature with a raw
> query set. I've
Thanks for the help guys, I managed to solve, so I did:
* queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)*
*
*
*try: *
* page = int(request.POST.get('page','1')) *
*except ValueError: *
* page = 1 *
*try:
thus still giving the same error
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On 10/03/2013 04:13 PM, Roberto López López wrote:
> *return HttpResponse(json.dumps([players]) ,
> content_type='application/json')*
better without the square brackets
*return HttpResponse(json.dumps(players) ,
content_type='application/json')*
--
Roberto López López
System Developer
Paral
doing so:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)*
*
*
*page = request.GET.get('page')*
*try:*
*players = paginator.page(page)*
*except PageNotAnInteger:*
*players = paginator.page(1)*
*exc
Try this (I have not tried the code myself, but I think that it should
work):
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)
page = request.GET.get('page')
try:
players = paginator.page(page)
except PageNotA
Better to say:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)
page = request.GET.get('page')
try:
players = paginator.page(page)
except PageNotAnInteger:
players = paginator.page(1)
excep
Already got it, I did so:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)*
*return HttpResponse(json.dumps([item.get_json() for item in
paginator.object_list]) , content_type='application/json')*
But I return all the records ... I should not retur
Already got it, I did so:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 1)*
*return HttpResponse(json.dumps([item.get_json() for item in
paginator.object_list]) , content_type='application/json')*
But I return all the records ... I should not retur
I'm doing this:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 20)*
*return json.dumps([item.get_json() for item in paginator.object_list])*
And my Document is thus:
http://plnkr.co/edit/FHH2hZh26OiLMKTk2ToO
But it gives me the following error:
'st
Hi Hélio,
It looks like you're applying pagination to the rendered JSON string itself.
You want to be paginating the queryset itself.
queryset = Player.objects.filter(name=namepost)
paginator = Paginator(queryset, 20)
return json.dumps([item.to_dict() for it
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