Your probability distribution is binomial
p = 0.51q = 0.49
In five trials, the distribution is ( p + q ) ^ 5
= p^5 + 5 p^4q + 10 p^3q^2 + 10 p^2q^3 + 5 pq^4 + q^5
So the probability for one power and four not is 5 pq^4 and
for at least one is 1 - q^5
Arto Huttunen
"Anon." <[EMAIL PRO
Thanks alot - it worked. How would you compose a short formula depicting:
P {Only 1} = [P (Power) x P (NotPower) x P (NotPower) x P (NotPower)
x P (NotPower)] +
[P (NotPower) x P (Power) x P (NotPower) x P (NotPower) x P
(NotPower)] +
[P (NotPower) x P (NotPower) x P (Power)
"@Home" wrote:
>
> I had the following to solve:
>
> 51% of all domestic cars being shipped have power windows. If a lot contains
> five such cars:
>
> a. what is probability that only one has power windows?
> b. what is probability that at least one has power windows?
>
> I solved each of the
Hai,
I want to know if there are any lineraly separable data sets in the
UCI repository. Ofcourse, there is iris data set, but I want larger
data sets which are linearly separable.
Thanks in advance,
Raja.
=
Instructions for joi
Dear all,
My problem might be of trivial nature but my little knowledge have
made it a giant task.
I want to use STARPAC subroutines for the problems like least square
fitting problems etc. The problem is that the subroutines has so many
other subroutines and functions that I find it hard to gras
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wanted to know about beauty, from Hair Care to Skin Care, Makeu
if A&B occurs, hasn't A occurred?
Paul R. Swank, Ph.D.
Professor
Developmental Pediatrics
UT Houston Health Science Center
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]On Behalf Of Nathaniel
Sent: Monday, September 17, 2001 12:38 PM
To: [EMAIL PROTECTED]
Subject:
Hello,
I've got a question. If A and B are idependent does it imply that event A
and (A&B) are independent too. My reasoning is: If A and (A&B) are
idependent then:
P(A|(A&B))=P(A),
but
P(A|(A&B))=P(A&(A&B))/P(A&B)=P(A&A&B)/P(A&B)=P(A&B)/P(A&B)=1.
What does it mean? Could anybody explain me thi
I had the following to solve:
51% of all domestic cars being shipped have power windows. If a lot contains
five such cars:
a. what is probability that only one has power windows?
b. what is probability that at least one has power windows?
I solved each of these problems in two ways, one using s
"Agent V.M." wrote:
>
> Hi,
>
> I have this program StatIt, version 5.0. I recently reinstalled my operating
> system and I lost my serial number for this program (Site ID and Password).
> I cannot find it anywhere. Can somebody help me?
Don't overlook the obvious. If you registered the program
>
>My main point was not about baseball or Bonds. It was about the
>cavalier way that people toss around the phrase, "regression to
>the mean," as if it were an immutable law that trumped all other
>differences in conditions.
>
>--Robert Chung
right ... reg. to the mean is not a cause of anythin
Rich Ulrich wrote:
>
> On Tue, 28 Aug 2001 21:32:02 +0200, Robert Chung <[EMAIL PROTECTED]>
> wrote:
>
> [ snip, earlier comments on Barry Bonds's home runs,
> then at 56, now at 63.]
> >
> > Hmmm. I would have suggested that Pac Bell Park was much more
> > conducive to a power-hitting lefty th
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