I'm sure I can calculate how much off the the DRO is from actual movement and
get the OUTPUT_SCALE right, I was just thinking that the X and Y axis is off by
a factor of 5, that maybe I was missing something.
>>>bidirectional lead screw compensation<<< What is this?
>>>Having gears between the
On Sat, 2013-02-23 at 22:19 -0600, Jon Elson wrote:
> Bruce Klawiter wrote:
> > I have just switch my mill over from linear scales to rotary encoders and I
> > can't get my input scale right. OUTPUT_SCALE is 1, Units-inch
> >
> > X axis has a 1250 CPR differential encoder, motor 14 tooth gear, scr
Gentlemen,
To be truthful with you I don't bother calculating an encoder count very
accurate. I just want to get it close so I can put an indicator on the
slide and adjust the count so the joint moves as close to the commanded
move as I can get it. I then use the bidirectional lead screw compensa
Bruce Klawiter wrote:
> I have just switch my mill over from linear scales to rotary encoders and I
> can't get my input scale right. OUTPUT_SCALE is 1, Units-inch
>
> X axis has a 1250 CPR differential encoder, motor 14 tooth gear, screw 21
> tooth gear, .200 pitch screw. 1250 X 4 X 1.5 X 5 = IN
How far off is it? High low what? Are you certain of your screw pitches?
- Original Message -
I have just switch my mill over from linear scales to rotary encoders and I
can't get my input scale right. OUTPUT_SCALE is 1, Units-inch
X axis has a 1250 CPR differential encoder, motor 14 to
On 19 February 2013 18:31, John Thornton wrote:
> If I had to guess I'd say there is 20 times more traffic here than on
> the forum but so much is not on topic it is hard to stay focused. Then
> you have abby normal people like me that prefer top posting because I
> like to see the reply first an
On 23 February 2013 16:30, Klemen Dovrtel wrote:
> I noticed that at the index the rotor angle is set to 0. Is it possible that
> there should be some offset regarding to real motor angle? I did not find any
> rotor angle offset input in bldc.component. Is this the way to solve this?
The rotor
I have just switch my mill over from linear scales to rotary encoders and I
can't get my input scale right. OUTPUT_SCALE is 1, Units-inch
X axis has a 1250 CPR differential encoder, motor 14 tooth gear, screw 21 tooth
gear, .200 pitch screw. 1250 X 4 X 1.5 X 5 = INPUT_SCALE = 37500
Y axis 5000
I solved this problem, now I can home the the motor.
Now i would like to control the motor with PID. The problem is, that when i set
some maximum value to bldc.value input, the motor does not accelerate, but
stays still (the motor winding are powered). If i print the bldc.rotor-angle
and bldc.p
