Hello can anyone tell me the best way to accomplish this? I am porting a
legacy app I maintain to use MVC. On the auth query I join a customer info
table to store some other info in the session.
// Login Attempt
$sql = "SELECT
*,
Hello can anyone tell me the best way to accomplish this? I am porting a
legacy app I maintain to use MVC. On the auth query I join a customer info
table to store some other info in the session.
// Login Attempt
$sql = "SELECT
*,
the problem is i dont want to use viewscript, because my jquery decorator
wont be working I guess, any one can fix my approach?
swilhelm wrote:
>
> Coincidentally, I was testing subforms on Monday. Here is a somewhat
> contrived login form created from two subforms.
>
> I took a slightly diff
Use SVN trunk and you can work with them.
Greetings
Thomas Weidner, I18N Team Leader, Zend Framework
http://www.thomasweidner.com
- Original Message -
From: "Gabriel Malkas"
To: "Thomas Weidner"
Cc:
Sent: Wednesday, January 14, 2009 10:37 PM
Subject: Re: [fw-general] New feature: En
Hi,
Thanks a lot for those components, that's a great job you've done there.
Is it possible to download the code yet ?
Greetings.
Gabriel Malkas.
Thomas Weidner wrote :
Hy friends of Zend Framework,
I am pleased to announce that Zend Framework is from now on able to
encrpyt and decrypt con
Hi guys,
I have tried to measure bottlenecks in my application and I've noticed
that Zend_Date seems to be an heavy component. I have enabled the
cache and applied most of the performances tips suggested in the
manual, however this component seems to be slow yet.
I have also found the fol
Hy friends of Zend Framework,
I am pleased to announce that Zend Framework is from now on able to encrpyt
and decrypt content and files with it's Zend_Filter component.
I added support for Mcrypt and also OpenSSL which will be used for the
detail work in background.
For details about the usag
Hi,
I'm trying to setup some JavaScript on a page using Jquery, to make a remote
request on my site and return results.
Using Jquery syntax, I have:
$.get('/remote/delete',{id:option.attr('name')},function(data,sender) {
//check if the request succeeded and update as necessary
});
This seems
I am using the Zend_View_Helper_Translate for i18n integration into a
project and have a need to overwrite it's default functionality for
translate(). For consistency sake, I'd rather not create a new helper
like My_View_Helper_Translator because I would have to change all the
translate() call
Coincidentally, I was testing subforms on Monday. Here is a somewhat
contrived login form created from two subforms.
I took a slightly different approach in that I wanted the form and subforms
created by config files and I am using a form viewscript to render the form.
Code fragments below. Ho
maybe if you post some code we can see where you go wrong... unless you got
nothing up till now :-D
-
visit my website at http://www.phpscriptor.com/ http://www.phpscriptor.com/
--
View this message in context:
http://www.nabble.com/Zend_Form%3A-more-DisplayGroup-inside-a-%3Cdiv%3E-tp2145
HI
I have one main form, and two sub forms, and I want to have a common submit
button. But it really doesnt display that button after render action.
got:
$this->setDecorators(array(
'FormElements',
array('TabContainer', array(
Try use subform.
On Wed, Jan 14, 2009 at 10:30, Michel Morelli wrote:
> Hi all. I have 3 DisplayGroup Elements. I need to enclose these elements in
> a .
>
> I have tryed to create a DisplayGroup of these 3 DisplayGroup but does not
> work (Zend Framework error).
>
> Tnx.
>
> --
> Michel 'ZioBudd
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
The config writers are not intended to write configs which do not
contain sections (except the array writer). Tho it is correct that no
errors should be thrown at that point.
...
: ___ _ ___ ___ ___ _ ___:
: |
Hi all,
I created an issue:
http://framework.zend.com/issues/browse/ZF-5544
It is about an ini file that can not be written if the Zend_Config
object passed to the writer does not contain any sections.
I also supplied a patch. Would appreciate if all of you ini writers
would try if this patc
ZF has had native FirePHP support since 1.6
See:
http://www.christophdorn.com/Blog/2008/09/02/firephp-and-zend-framework-16/
Christoph
Bart McLeod wrote:
> What I think is that you should do more promotion about firePHP
> offering ZF integration: I did regular firePHP and even put the
> librar
Here's what I believe I'm needing to do:
1) capture the cookieJar
$client->getCookieJar()->getAllCookies(Zend_Http_CookieJar::COOKIE_STRING_CONCAT)
2) store for retrieval upon script call
Problem is I'm not sure what format I should be capturing the cookieJar in,
and how to set the cookieJar
perfect thx, must have documentation blindness today...
2009/1/14 Tobias Gies :
> whoops. typo. "pass an array".
>
> 2009/1/14 Tobias Gies :
>> Hey Keith,
>>
>> if I remember correctly, you can bass an array of IDs as $categoryId.
>> This should result in the query you want.
>>
>> Best regards,
>>
Hey Michael,
I accomplish this with a combination of decorators, display groups, and css.
I set up some custom decorators as protected properties of my form, apply
them to my fields in the display group, apply custom decorators to the
display group itself, and css takes care of the rest. Here's
whoops. typo. "pass an array".
2009/1/14 Tobias Gies :
> Hey Keith,
>
> if I remember correctly, you can bass an array of IDs as $categoryId.
> This should result in the query you want.
>
> Best regards,
> Tobias
>
> 2009/1/14 keith Pope :
>> Hi,
>>
>> How do you add an IN() to a where using selec
Hey Keith,
if I remember correctly, you can bass an array of IDs as $categoryId.
This should result in the query you want.
Best regards,
Tobias
2009/1/14 keith Pope :
> Hi,
>
> How do you add an IN() to a where using select? I am getting
> IN('1,2,3') rather than IN(1,2,3), which gives incorrect
Hi,
How do you add an IN() to a where using select? I am getting
IN('1,2,3') rather than IN(1,2,3), which gives incorrect result.
$select->from('product')
->where('categoryId IN(?)', $categoryId)
Thx
I'm trying to make a generic router to type less when using url helper.
But, the url generated is wrong.
My router:
$roteadorContato = new Zend_Controller_Router_Route(
':language/:contato/'
,
array('language' => $idiomaSigla
Thank you for your answers!
Are there any plans to include a more advanced formatter in PDT? And when
will the PDT 2.0 included in the Zend Studio for Eclipse?
Tom
On Tue, Jan 13, 2009 at 7:44 PM, Roy Ganor wrote:
> ZF formatter rules are applied by Zend Studio for Eclipse formatter, so
> us
Hi.
I try use ZF 1.72 with jquery 1.2.6 and autocomplete 1.1pre.
Autocomplete dosen't work.
My application generate code like this:
in head:
//
Hi all. I have one form with some DisplayGroup Elements.
Some of these need that the elements must to be rendered in a 2 columns.
Like:
--Legend
| Element 1Element 2 |
| Element 3Element 4 |
-
How
Hi all. I have 3 DisplayGroup Elements. I need to enclose these elements
in a .
I have tryed to create a DisplayGroup of these 3 DisplayGroup but does
not work (Zend Framework error).
Tnx.
--
Michel 'ZioBudda' Morelli mic...@ziobuddalabs.it
Consulenza sistemistica in am
What I think is that you should do more promotion about firePHP
offering ZF integration: I did regular firePHP and even put the
libraries on the server, while I now understand they are actually in
the framework (? or are the libraries still needed, will have to read
more docs :-) where
do I f
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