Unbanned.
- Dave
On Fri, Sep 4, 2009 at 18:22, David Andersondander...@google.com wrote:
That would work. Get one of the owners of the project to ping me at my
google address (see email header).
- Dave
On Fri, Sep 4, 2009 at 15:39, coldahuntdes...@gmail.com wrote:
Haha I see. Would it
hello,
I work on an open source project hosted at Google Code.
I also offer commercial services using this project. So, am I
permitted to mention this service on the Google Code project page?
thanks,
Richard
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On Mon, Sep 7, 2009 at 00:29, Richardrichar...@gmail.com wrote:
I work on an open source project hosted at Google Code.
I also offer commercial services using this project. So, am I
permitted to mention this service on the Google Code project page?
As long as the software you host is open
On Sat, Sep 5, 2009 at 5:20 PM, Bartholomew Furrow fur...@gmail.com wrote:
Per rules you have to solve at least one small and one large input,
not score =33 pts.
While this seems to be same - ACRush. (with dot) will or will not
advance based on this.
Per current rules he will not (and there
If the array size is unpredictable and large, you can use data structures
like vectors if the language you're using supports it
On Sun, Sep 6, 2009 at 3:06 AM, sap30 sap.qu...@gmail.com wrote:
hi i am very new to coding first of all i want to know the solution of
the first problem how you
On Fri, 2009-09-04 at 20:51 -0700, dionysus wrote:
the programming language used by contestant be
displayed in the scoreboard
find contestants of the same country,
I think it's been mentioned a couple of times on the list, but if you've
missed it you can go to http://www.go-hero.net/jam/
Hi sap queue/sap30, the array bounds are based on the limits specified
in the problem for the large dataset. This way the program can handle
up to the maximum-sized data fed to it in testing. So, in this case
5000 max words in the dictionary, and 15 max characters per word + 1
end of string
http://code.google.com/codejam/contest/dashboard?c=90101#
Log in if necessary.
Click on View my submissions. You can download the input and output.
If that doesn't shed any light, then attach them to your reply to this
message, and I'll try and help.
On Sun, Sep 6, 2009 at 3:37 AM,
No. You are nearly correct. Assuming that regardless of skill level,
each person is equally likely to pick group A, B or C:
In Round 1A, 500 people will qualify from group A and 500 people will
qualify from group B.
Then when Round 1B starts, the 500 top people from group C will be
better than
Java is more verbose than C++, but it's still possible to be in top
with it. For example, this year's ACM ICPC champions are using Java.
And I think writing short solutions is more about finding the simplest
algorithm that solves problem than choosing the 'right' programming
language.
On Sep 5,
Do anyone have CLRS?
On Sun, Sep 6, 2009 at 12:24 PM, Viswanath viswanat...@gmail.com wrote:
Yes, CLRS is a good book, but a really big one. You can also use the
algorithms tutorials in topcoder.
On Sun, Sep 6, 2009 at 5:03 AM, Satyajit Malugu malugu.satya...@gmail.com
wrote:
CLRS is
Well, it was a stupid question from my side. I just didn't understand the
abbreviation CLRS. I actually have it :)
Thanks
On Sun, Sep 6, 2009 at 3:34 PM, Aditya V Daga avd...@gmail.com wrote:
Search and download cormen from 4shared.com
On Sun, Sep 6, 2009 at 2:58 PM, qasim zeeshan
Your solution is same as mine. Only difference is that I am traversing test
string backward and using hash map to improve running time.
You can improve the running time of your code by avoiding inner loop which
traverse 0 to 18. We can keep each distinct characters of target string
welcome to
What I get from the explanation is for the equation below
( 2 1 )( r' ) = ( r )
( 1 2 )( c' ) = ( c )
given r, c a integer solution must exist for r' c' for reachability.
Am I correct ?
On Sep 6, 3:16 pm, decor avdb...@gmail.com wrote:
In the contest analysis of the problem, it is written
See http://projects.csail.mit.edu/clrs/ .
Textbook, *Introduction to Algorithms* (Second Edition) by Thomas H.
Cormen http://www.cs.dartmouth.edu/%7Ethc, Charles E.
Leisersonhttp://theory.lcs.mit.edu/%7Ecel,
Ronald L. Rivest http://theory.lcs.mit.edu/%7Erivest, and Cliff
I also need the .in file.
On Sun, Sep 6, 2009 at 12:41 PM, togguillaume.all...@gmail.com wrote:
Hi Luke
Thanks for the help, this is what I did before posting on the list.
Here is (my far from optimal code) and the solution I got.
One question: What is checked ? The solution or the code ?
I added few more :)
I was bit afraid that my server will run out of juice. The scores resides in
a separate mysql table(for searching by correct submissions) and the
doctrine ORM uses 1 query for each contestant displayed :(
Regards,
Sandaruwan
On Sun, Sep 6, 2009 at 2:57 PM, rem
Here it is ...
On Sun, Sep 6, 2009 at 5:34 PM, Luke Pebodyluke.peb...@gmail.com wrote:
I also need the .in file.
On Sun, Sep 6, 2009 at 12:41 PM, togguillaume.all...@gmail.com wrote:
Hi Luke
Thanks for the help, this is what I did before posting on the list.
Here is (my far from optimal
on the icpc contest, when the input or output is big, they recomend to use
printf/scanf insted of cout/cin ... i'm not sayng that they make diference
on inputs like those, but, when we have peculiar inputs, a little constant
on the time is crucial..
2009/9/5 romanr goo...@romanr.info
gustavo
Hi furrow,
I didn't get your last point that who is being eliminated because of
registration under false name??
On Sep 6, 11:58 am, Bartholomew Furrow fur...@gmail.com wrote:
On Sat, Sep 5, 2009 at 5:20 PM, Bartholomew Furrow fur...@gmail.com wrote:
Per rules you have to solve at least one
Can any one explain how to formulate a solution for this? I mean what is the
algorithm and the premise?I've seen one top coders(jonick) solution and he
solved it with dynamic programming all the way. But what is mystic for me is
how was
he able to find the relation between the current problem and
Thats my output with my accepted program,
On Sun, Sep 6, 2009 at 9:45 AM, tog guillaume.all...@gmail.com wrote:
Here it is ...
On Sun, Sep 6, 2009 at 5:34 PM, Luke Pebodyluke.peb...@gmail.com wrote:
I also need the .in file.
On Sun, Sep 6, 2009 at 12:41 PM,
I prefer to use fprintf ^_^ lol
2009/9/6 gustavo pacianotto gouveia gustavo.paciano...@gmail.com
on the icpc contest, when the input or output is big, they recomend to use
printf/scanf insted of cout/cin ... i'm not sayng that they make diference
on inputs like those, but, when we have
Can i change the time for round 1 at this time???i was not able to update b4
5th sep.
plz help me...
Kiran
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Comparing to my small output file your generated output is incorrect...check
it again...
On Sun, Sep 6, 2009 at 6:15 PM, tog guillaume.all...@gmail.com wrote:
Here it is ...
On Sun, Sep 6, 2009 at 5:34 PM, Luke Pebodyluke.peb...@gmail.com wrote:
I also need the .in file.
On Sun, Sep
This book is the most awesome literature available on algorithms in the
market. Also used as text book in a lot of universitites.
On Sun, Sep 6, 2009 at 5:19 PM, Peter Smit pe...@smitmail.eu wrote:
See http://projects.csail.mit.edu/clrs/ .
Textbook, *Introduction to Algorithms* (Second
You should use a cin.ignore() after cini; because cin don't ignore
the last '\n'
#include iostream
using namespace std;
int main()
{
int i;
string s;
cin i;
cin.ignore();
getline(cin, s);
cout i endl;
cout s endl;
return 0;
}
On Sep
The top-scoring 1000 finalists from each sub-round, totaling 3000 skilled
programmers, will advance to Round 2. Correct me if I'am not right.
2009/9/6 Luke Pebody luke.peb...@gmail.com
No. You are nearly correct. Assuming that regardless of skill level,
each person is equally likely to pick
Thank you for the pointer. Please send any reports where you think someone
has cheated or is ineligible for the contest to
programmingcontestfeedb...@google.com.
On Sun, Sep 6, 2009 at 1:13 AM, Doron doron.neum...@gmail.com wrote:
How come there is a participant from Iran?
I didn't get your last point that who is being eliminated because of
registration under false name??
There's a contestant who took the nickname ACRush. -- NOT ACRush, who
won last year's Code Jam -- who provided a name that was clearly false, so
he was eliminated. This sort of thing happens
i have started programming in java(netbeans ide) so as to use data
structures available easily . i donot understand its debugging
features completely i am comfortable with using (F7,F8-stepover/into)
options and add-watch otions comfortably but could not understand how
to use breakpoints. i also
@rem - hey rem enligtened to see at the top again this year. i am
actually quite behind in coding. without wasting your precious time , i will
request u to give me some suggestions on programming. on java part, i thinks
it better for me because u need not learn a whole lot knew c++stl library of
This blog here has a detailed explanation for that problem:
http://blog.puzzlearena.com/search/label/GoogleCodeJam
On Sun, Sep 6, 2009 at 7:21 PM, Satyajit
Malugumalugu.satya...@gmail.com wrote:
Can any one explain how to formulate a solution for this? I mean what is the
algorithm and the
Thanks! Nice website.
On Sun, Sep 6, 2009 at 3:53 PM, Luke Pebody luke.peb...@gmail.com wrote:
This blog here has a detailed explanation for that problem:
http://blog.puzzlearena.com/search/label/GoogleCodeJam
On Sun, Sep 6, 2009 at 7:21 PM, Satyajit
Malugumalugu.satya...@gmail.com wrote:
hats off to u all .for me , can somebody give a comprehensive list
of all different currently known techniques of programming . also if
possible plz explain me about, from where to prepare questions
particular to each technique(branch and bound especially).
On Sep 6, 3:03 am, sameer mhatre
@vexorian
I agree with you, everybody who achieved 99 score is more meaningful.
I have removed the top 100 and top 50...
Instead I added the list with all participants who achieved 99 score grouped
by country...
http://siddiq-technology.blogspot.com/2009/09/google-code-jam-qualification-round.html
@anusha i will recommend to find it free on esnips.com
On Sep 6, 11:51 am, Anusha K una@gmail.com wrote:
is there a ebook of this CLRS..
On Sun, Sep 6, 2009 at 5:43 PM, Mayank Jaiswal msjais...@gmail.com wrote:
This book is the most awesome literature available on algorithms in the
Note also that shorter code does not necessarily equal faster to code
or easier to debug.
On Sep 6, 12:27 pm, flaming flaminglaw...@gmail.com wrote:
Note that Java is a very verbose language, like rem said. What you
might do in 4 lines in Java might take you only 3 in Python or
similar. Java
Hi Siddiq,
Nice job! BTW, how did you extract the data from code jam dashboard?
Did you use any script again?
I am learning on some web stuff. So, want to know :-)
Thanks,
Vivek
On Sep 6, 1:09 pm, Siddiq Akbar sid...@gmail.com wrote:
@vexorian
I agree with you, everybody who achieved 99
Dear Administrator:
Since I would be free all day, I nearly made the choice randomly,
and now I forget what is my choice.
Will there be any letter to notify those with importance ?
Thank you.
Yours sincerely,
linyufly
September 7th, 2009
Ya, I think you are right.
On Sun, Sep 6, 2009 at 5:11 PM, Luke Pebody luke.peb...@gmail.com wrote:
No. You are nearly correct. Assuming that regardless of skill level,
each person is equally likely to pick group A, B or C:
In Round 1A, 500 people will qualify from group A and 500 people
Hi sagar, I have not read CLRS (yet ;)) and in fact no other
math books. But, felt that I may be missing something and to get interest in
all this, I've taken Masters ;) and I HAVE to read now :(. Our Prof. is
following 'Kenneth Rosen' for Discrete Maths, which is a good book, with lot
while I think that the three sub rounds are there for level (i.e.
asia, america, europe as mentioned) no one's really stopping you from
signing up for any two of the three sub round schedules.
the problems will be different on each sub round, and there's really
no way to tell which one's going
Hi,
I understand that this query has been raised time and again, even I have
asked before.
But it is 7th today and its been 5 days since the contest, and I haven't
seen any change on the main site indicating my qualification or otherwise.
My rank is shown as 6000 with a score of 33 and a lot of
Can anyone explain How to solve 2008 Practice Round Square Fields
Problem? I m not getting even the slightest of idea of how to go about
it??
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To
I think i cant give a complete list of all programming techniques,
because i dont know them at all =D. But Here is a list, hope its
helps:
** Dinamic Programming (read knapsack problem, coins problems, min-
max, ...), and for other cases like the C problem, i recommend you try
to find a recursive
We'll have to ask for your patience here -- we're working our way through a
large number of cheating claims. Plus it's a weekend, so a lot of the team
is recovering from a very hectic week. :-) Rest assured that if you have 33
points (and didn't cheat, of course), you qualified.
Regards,
Very similar story :(
Can´t wait to the next codejam!
Raquel
On Sep 4, 10:14 am, Ran (neko) ran.halp...@gmail.com wrote:
I agree with weekend, and more time slots are a must spread across the
weekend and its surroundings. The weekend is not the same all over the
world. 1 of round 1 slots
Hello any one received the invitation for the second round
Regards
Jawahar
On Mon, Sep 7, 2009 at 6:46 AM, Chen Mingcheng linyu...@gmail.com wrote:
Dear Administrator:
Since I would be free all day, I nearly made the choice randomly,
and now I forget what is my choice.
Will there be
I agree with you seriously
2009/9/6 rem mullakha...@gmail.com
Java is more verbose than C++, but it's still possible to be in top
with it. For example, this year's ACM ICPC champions are using Java.
And I think writing short solutions is more about finding the simplest
algorithm that solves
My fault :) I did not realize that the input was changing for every
trial ... I kept on trying to upload the same result because I knew it
was correct ... but for the previous input set.
Next year, I will be more careful about this :)
Good luck for the next round ... I will keep on playing but
hey folks, good job with gcj.
i couldn't understand something in prob B 'watersheds'.
in following case in sample input,
[2 3]
7 6 7
7 6 7
now upper 6 and downer 6 has same altitude.
So what i thought was i should follow NORTH WEST EAST SOUTH rule,
so upper 6 must be the sink, and the basin
Hi Bartholomew,
Thanks for your reply. I will be more patient :).
Thanks Regards,
Dhruva Sagar.
Pablo Picassohttp://www.brainyquote.com/quotes/authors/p/pablo_picasso.html
- Computers are useless. They can only give you answers.
On Mon, Sep 7, 2009 at 9:20 AM, Bartholomew Furrow
Well I think that since 6 is a sink you can not move to the other one ...
You cannot move to a place being at the same height (of your current
position) - no slope ;)
On Mon, Sep 7, 2009 at 8:25 AM, jzcmpdebug...@gmail.com wrote:
hey folks, good job with gcj.
i couldn't understand something
According to the rules, water will not flow from the 6 in the first row to
the 6 in the second row.Hence the second row will take up 'b' because none
of the paths from the second row end up in the first row, it is a completely
different/new path.
Hope that makes it at least a bit more clear.
No
4 сентября 2009 г. 23:15 пользователь Fernando Cezar
netcrip...@gmail.comнаписал:
Wouldn't it be a good idea to keep conversations in English as much as
possible?
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Hi Andriy,
I am unable to open that link.
Thanks Regards,
Dhruva Sagar.
Samuel Goldwynhttp://www.brainyquote.com/quotes/authors/s/samuel_goldwyn.html
- I'm willing to admit that I may not always be right, but I am never
wrong.
On Mon, Sep 7, 2009 at 10:52 AM, Andriy G. Tereshchenko
i think it depend on the definition of flow, either from (high) to (low)
or from (high) to (equal or lower).
based on the definition given in the question For each cell, if none of its
4 neighboring cells has a lower altitude than the current cell's, then the
water does not flow, and the current
yeah same here..
On Sep 7, 10:27 am, Dhruva Sagar dhruva.sa...@gmail.com wrote:
Hi Andriy,
I am unable to open that link.
Thanks Regards,
Dhruva Sagar.
Samuel
Goldwynhttp://www.brainyquote.com/quotes/authors/s/samuel_goldwyn.html
- I'm willing to admit that I may not always be right,
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