I'm little confused with the architecture of jquery. I tried to
understand it with Firebug, but I'm lost as it's just showing this
tree.
As far as I understand, $() creates a new jQuery object. So, if we
use $() many times, will it create as many objects for it? TIA
--
?php echo
Usually, he'll be posting this sort of links/news; now for a
change, I'm doing;)
http://ajaxian.com/archives/introducing-the-latest-ajaxan-rey-bango
--
?php echo 'Just another PHP saint'; ?
Email: rrjanbiah-at-Y!comBlog: http://rajeshanbiah.blogspot.com/
anyone?
Hi Olmo,
I'll add a signature from now on it seems.
Thanks. That helps out quite a bit. Kind of like I did when I posted in
the MooTools forum. Its always good to let people know where you're
coming from.
I don't need to waste my time in trying to lecture you. Should have
known better.
*blushes*. Thanks Rajesh. :)
Rey..
R. Rajesh Jeba Anbiah wrote:
Usually, he'll be posting this sort of links/news; now for a
change, I'm doing;)
http://ajaxian.com/archives/introducing-the-latest-ajaxan-rey-bango
--
?php echo 'Just another PHP saint'; ?
Email: rrjanbiah-at-Y!com
Hey Eric, that works like a charm. Thank you so much!
Emi Polak
On 9/2/07, Erik Beeson [EMAIL PROTECTED] wrote:
In fact, if you find yourself wanting to do a lot of stuff when scrolling
has stopped, you could add an event for it (again, untested):
(function($) {
var scrollTimeoutID;
The home of yShout is at http://yurivish.com/yshout/ Yuri only requires a
small donation and he will send you the link to a zip file.
Um, that's not really a donation then, is it?
--John
Hello,
Consider a blog apps like Blogger, you have a site like
http://abc.blogspot.com
each time, you want to leave a comment for an article, you will be
redirected to another page under the blogger domain, e.g.
https://www.blogger.com/comment.g.
I think one of the reason why Blogger
Um, that's not really a donation then, is it?
--John
This probably needs a new / better term. I read a while ago about some
independent musician making more money then he/she'd make on iTunes by
letting the people decide how much they pay for it. Theoretically you
could 'donate' $0.01.
John Resig wrote:
The home of yShout is at http://yurivish.com/yshout/ Yuri only requires a
small donation and he will send you the link to a zip file.
Um, that's not really a donation then, is it?
--John
No, it doesn't really seem like donation is the completely accurate word
for this. It
Congrats Rey!
Joel.
From: R. Rajesh Jeba Anbiah
I'm little confused with the architecture of jquery. I
tried to understand it with Firebug, but I'm lost as it's
just showing this tree.
As far as I understand, $() creates a new jQuery object.
So, if we use $() many times, will it create as many
My opinion is that the word payment is more than adequate for this
situation. I really do wonder how low he will go, considering jQuery and its
countless plugins are offered for free? ;)
That's what confuses me - it use to be open source/free software, back
when he first released it. But now
jman schrieb:
Hi,
I am not sure if this is talked about elsewhere, but I have a problem
using accordian 1.5 with the interface plugin.
The problem is that when I click to open a different part of the
accordian it does not show up. Following it in firebug the code jumps
to the interface plugin
Massimiliano Marini schrieb:
Hi Jorn,
this code works perfectly but I can manage the ajax response, a simple
json d,ata like in your example, firebug show me the response but I
can't manage why? My code is like your code ... but mine don't work.
Any suggest will be appreciated.
I've
Hi,
A number of folks have independently come across this issue. What I
would like to hear from John Resig or from other team members if the
change was intentional? and why?
In short, what I found is that $(document).ready() behaves differently
in 1.1.4 for FF and IE.
In appears to me that
When clicked on link 1.stāvsit doesn't load anything ands show error on
line: 1 char: 1 error: syntax error. Could not complete operation due to
error 80020101.
Example page: http://saite.fyfi.net/lat/info/apskatit-kvartalu/silmalu-17/
On Sep 2, 9:48 pm, Michael Geary [EMAIL PROTECTED] wrote:
From: R. Rajesh Jeba Anbiah
I'm little confused with the architecture of jquery. I
tried to understand it with Firebug, but I'm lost as it's
just showing this tree.
As far as I understand, $() creates a new jQuery
Can you post this to the jquery-dev list as opposed to the general
discussion list? Thanks.
http://groups.google.com/group/jquery-dev
--John
On 9/2/07, Pops [EMAIL PROTECTED] wrote:
Hi,
A number of folks have independently come across this issue. What I
would like to hear from John Resig
Done John.
Thanks
--
HLS
On Sep 2, 2:09 pm, John Resig [EMAIL PROTECTED] wrote:
Can you post this to the jquery-dev list as opposed to the general
discussion list? Thanks.http://groups.google.com/group/jquery-dev
--John
On 9/2/07, Pops [EMAIL PROTECTED] wrote:
Hi,
A number of
On 9/1/07, Michael Geary [EMAIL PROTECTED] wrote:
Also, it looks like you have a race condition. What happens if the entire
AJAX request completes in less than 100 milliseconds?
I assumed that $.ajaxStart() would be canceled and $.ajaxStop() would execute.
I looked over your code but I don't
If ajaxStop is called before the setTimeout callback in ajaxStart is run,
active will be false, so the addClass() on line 9 won't get executed.
Without this, if ajaxStop ran before the setTimeout callback, the
removeClass() would happen before the addClass(), so the class would never
get removed.
Hello,
I wrote a script that starts like this:
jQuery('/html/body//[EMAIL PROTECTED]//a').each(function(i){
var $hr = jQuery(this).attr(href);
.)};
What I noticed is the following for relative (ex: href=/mypage)
URLs:
var $hr = this.href; //returns URL with http://
From: Michael Geary
Also, it looks like you have a race condition. What
happens if the entire AJAX request completes in
less than 100 milliseconds?
http://www.pastebin.ca/678318
From: barophobia
I assumed that $.ajaxStart() would be canceled and
$.ajaxStop()
Hello,
it's the second time a send this message . But I can't see the first
one ... so sorry if you find it two time ...
My code work very well with mozilla but I doesn't with IE , I received
always the error message, if somme one could help me ...
/* Variable global */
var idFormat=new
Hello ,
Firstable , sorry for my English ... I'm French and for me it's not
simple to write this language.
I have a problem with IE when I used $.ajax fonction.
/* Variable global */
var idFormat=new Array();
var largeur=new Array();
var hauteur=new Array()
$(document).ready( function(){
I dont know if this is a problem in jquery or have I did something
wrong.
Please take a look at this code it is for a gallery of a sort,
What I want to achieve is that when image with class poster_image is
clicked the div with class poster_info is shown.
But what happens is that there are more of
Hello,
i have some problems:)
i want to load an loginequester into my page:
function loadLoginbox(Target) {
$(Target).load(index.php?m=loginc=loadLoginbox);
}
the loginbox is loaded but no events run.(
$('#openLogoutbox').click(function() {
Another common solution is to have an image or a div that you just
show while loading and hide using the callback function...
script type=text/JavaScript
$(document).ready(function(){
$('#loadImg').show();
var fCallback = function(){ $('#loadImg').hide(); }
$(#show).load(file.php,
Whats the error message you're receiving?
Rey...
sourrisseau wrote:
Hello,
it's the second time a send this message . But I can't see the first
one ... so sorry if you find it two time ...
My code work very well with mozilla but I doesn't with IE , I received
always the error message, if
Never mind I got it working by stumbling across using CDATA in the xml
response.
On Sep 2, 1:38 am, atomicnuke [EMAIL PROTECTED] wrote:
Is there a way to do this? I thought just placing the response in a
div with html() would work, but it ignored the br /'s.
Hi Am,
.attr('href') is supposed to return the actual href attribute of the
link. This was normalized quite a few versions ago. Can you tell us
which version you are using?
Also, you can really simplify your selector this way:
jQuery('div.node a').each(function(i) { // etc.
--Karl
On 9/2/07, Erik Beeson [EMAIL PROTECTED] wrote:
If ajaxStop is called before the setTimeout callback in
ajaxStart is run, active will be false, so the addClass() on line 9
won't get executed.
Without this, if ajaxStop ran before the setTimeout callback, the
removeClass() would
I'm trying in slideUp a div then fade in another when it has completed
the slide. I tried using the fadeIn as a callback function
$('slidediv').slideUp('slow', function() {
$('fadediv').fadeIn('slow');
});
Is there a way to delay the fade, everything happens so fast you can't
really tell the
Hello,
I would like to select elements with two class (eg: h5 class=next
open. I tried $(.next open) but it failed. Does anyone know how to
do it?
Thanks in advance. Xavier
$('.next,.open')
--Erik
On 9/2/07, xni [EMAIL PROTECTED] wrote:
Hello,
I would like to select elements with two class (eg: h5 class=next
open. I tried $(.next open) but it failed. Does anyone know how to
do it?
Thanks in advance. Xavier
I assume your selectors are just for example since $('slidediv') isn't a
valid selector (unless you have an element like slidediv.../slidediv,
which you probably don't have if you're doing HTML).
To delay the second effect, you can use setTimeout, like so (untested):
On Sep 2, 2007, at 8:25 PM, Erik Beeson wrote:
$('.next,.open')
--Erik
On 9/2/07, xni [EMAIL PROTECTED] wrote:
Hello,
I would like to select elements with two class (eg: h5 class=next
open. I tried $(.next open) but it failed. Does anyone know how to
do it?
Thanks in advance. Xavier
Thanks to both of you for your answer...
On 3 sep, 02:36, Karl Swedberg [EMAIL PROTECTED] wrote:
On Sep 2, 2007, at 8:20 PM, xni wrote:
Hello,
I would like to select elements with two class (eg: h5 class=next
open. I tried $(.next open) but it failed. Does anyone know how to
do it?
This sounds like the issue that is being discussed on the dev list in
the thread titled document.ready in jQuery 1.1.4 - IE and FF
inconsistent behavior
http://groups.google.com/group/jquery-dev/browse_thread/thread/d4e0edfa7764aecc
Hope that link works - I haven't tried linking to a discussion
$(.next.open)
The same works in normal CSS.
--John
On 9/2/07, xni [EMAIL PROTECTED] wrote:
Hello,
I would like to select elements with two class (eg: h5 class=next
open. I tried $(.next open) but it failed. Does anyone know how to
do it?
Thanks in advance. Xavier
Hi,
looking for help for creating the following:
1) textarea maxlenght check. When maxlenght is reached cannot type
anymore.
2) A counter digits display.
Someone has already made something like this?
Thanks
Andrea
Bah, I know better than that. I had an odd feeling I was doing something
wrong. Thanks for correcting it Karl.
--Erik
On 9/2/07, Karl Swedberg [EMAIL PROTECTED] wrote:
On Sep 2, 2007, at 8:25 PM, Erik Beeson wrote:
$('.next,.open')
--Erik
On 9/2/07, *xni* [EMAIL PROTECTED] wrote:
I am using the same css code from the thickbox(3.1) to create a faded
background however there are a few issues. The first one is in IE 7 the
faded background is only covering the entire visible screen the first
appears, if i scroll down the faded background is not there. The second
issue it
Still didn't seem to work
On Sep 2, 8:28 pm, Erik Beeson [EMAIL PROTECTED] wrote:
I assume your selectors are just for example since $('slidediv') isn't a
valid selector (unless you have an element like slidediv.../slidediv,
which you probably don't have if you're doing HTML).
To delay the
I'm using interface1.2 and jQuery1.4.
the problem is that cloned element is not draggable in IE6, but works
fine in firefox.
I defined a onDrop function in Droppable. In the onDrop function I
clone the draggable DOMElement, and append to the droppable
DOMElement. Then this cloned element is not
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