Hello!
On Wed, Mar 25, 2009 at 6:00 PM, Karl Swedberg wrote:
> Hi Lay,
> You could do it like this:
> $('table').filter(function() {
> return this.style.tableLayout == 'fixed';
> });
> Not sure what happens when you try it in a browser that doesn't support the
> tableLayout property, though.
Hi Lay,
You could do it like this:
$('table').filter(function() {
return this.style.tableLayout == 'fixed';
});
Not sure what happens when you try it in a browser that doesn't
support the tableLayout property, though.
--Karl
Karl Swedberg
www.englishrules.com
www.learningj
sorry, of course... did look too much at it to see the most obvious solution.
Karl Swedberg-2 wrote:
>
> Hi Manuel,
>
> You have to concatenate the rest of the selector, which is a string,
> and the variable:
>
> $('.removeFav[adld=' + adId + ']').show();
>
>
> --Karl
>
>
Hi Manuel,
You have to concatenate the rest of the selector, which is a string,
and the variable:
$('.removeFav[adld=' + adId + ']').show();
--Karl
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Jan 23, 2009, at 10:44 AM, aldana wrote:
hi, how do i let a
Thanks. I will need to apply that tiny patch.
Brian J. Cardiff
bcardiff(?)gmail.com
.
On Sun, Nov 9, 2008 at 10:02 AM, Balazs Endresz <[EMAIL PROTECTED]>wrote:
>
> There's a ticket on this issue: http://dev.jquery.com/ticket/3023
>
> On Nov 7, 11:48 pm, "Brian J. Cardiff" <[EMAIL PROTECTED]> wr
There's a ticket on this issue: http://dev.jquery.com/ticket/3023
On Nov 7, 11:48 pm, "Brian J. Cardiff" <[EMAIL PROTECTED]> wrote:
> thanks but that it isn't working in this scenario
>
> for:
> Lorem
>
> the expression:
> $('span').filter(function(){return $(this).attr("x:foo");})
> returns the
I also took a stab at this and...had no luck. If it wasn't obvious, I
think jQuery is getting tripped up on the : because of :'s association
with filters. Not sure if there'll be an easy workaround.
Max
On Nov 7, 3:21 pm, MorningZ <[EMAIL PROTECTED]> wrote:
> Hmmm.. interesting the second one
Hmmm.. interesting the second one there didn't work...
Well, I tried (and even just worked up a little page trying some other
things) good luck getting it rollin'
On Nov 7, 5:48 pm, "Brian J. Cardiff" <[EMAIL PROTECTED]> wrote:
> thanks but that it isn't working in this scenario
>
> for
thanks but that it isn't working in this scenario
for:
Lorem
the expression:
$('span').filter(function(){return $(this).attr("x:foo");})
returns the span element
but neither:
$('[x:foo]')
no:
$('[x\\:foo]')
find it
any clue?
Brian J. Cardiff
bcardiff(?)gmail.com
.
On Fri, Nov 7, 2008 at 6:11
http://docs.jquery.com/Frequently_Asked_Questions#How_do_I_select_an_element_that_has_weird_characters_in_its_ID.3F
On Nov 7, 2:06 pm, "Brian J. Cardiff" <[EMAIL PROTECTED]> wrote:
> Is there a way to specify an AttributeFilter for attributes within a certain
> namespace? I try some alternati
Got a link to that part of the XHTML spec ?
Ouch, Atribute --> Attribute.
--
Ariel Flesler
http://flesler.blogspot.com
On Oct 21, 1:07 pm, ricardobeat <[EMAIL PROTECTED]> wrote:
> Brackets are an invalid character in attributes, for XHTML served as
> text/html, which I guess accounts for most o
You have some oddly mismatched quotes, but otherwise, yes, that works.
Here's a test done in firebug on jquery.com:
>>> $('[EMAIL PROTECTED]:][href*=book]').each(function() { console.log(this.href
);});
http://www.packtpub.com/jQuery/book/mid/1004077zztq0
http://www.packtpub.com/jQuery/book/mid/10
Appears fixed as of 1.1.3
On Jan 10, 2:54 pm, truent <[EMAIL PROTECTED]> wrote:
> Im seeing this too.
>
> This Works.
>
> $(document).ready(
>
> function() {
>
> $("input").each(
>
> function(i){
> alert('hi');
>
> }
>
> );
>
> This does not:
>
> $(document).ready(
>
> function() {
>
> $("input[i
Im seeing this too.
This Works.
$(document).ready(
function() {
$("input").each(
function(i){
alert('hi');
}
);
This does not:
$(document).ready(
function() {
$("input[id]").each(
function(i){
alert('hi');
}
);
php webpage snippit
Categories
Aid Year: *
2006-072007-082008-0
I have been following the docs and using a very recent version of
jQuery. The docs don't mention the @ thing at all and I was wondering
why my selector didn't work...
Well obviously I'll upgrade and leave out the @ but it would have been
handy to learn this just by reading the docs...
> > The do
On Oct 10, 2007, at 2:54 PM, Chris Scott wrote:
Karl Swedberg wrote:
Hi Chris,
The docs are correct as of jQuery version 1.2. Previous versions
use @. Actually, you can get by using @ even in 1.2, but it's
deprecated.
Ever have one of those times when you *swore* you checked the
versio
Karl Swedberg wrote:
Hi Chris,
The docs are correct as of jQuery version 1.2. Previous versions use @.
Actually, you can get by using @ even in 1.2, but it's deprecated.
Ever have one of those times when you *swore* you checked the version and
*swore* you double-checked your code? This was
Hi Chris,
The docs are correct as of jQuery version 1.2. Previous versions use
@. Actually, you can get by using @ even in 1.2, but it's deprecated.
--Karl
_
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Oct 10, 2007, at 1:44 PM, Chris Scott wrote:
In the
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