[jQuery] Re: Jquery, AJAX and MySQL update

2008-04-17 Thread cjant83
Hi Scott (and others), Thanks for all the posts and help ! It actually did make some sense in the end :). The success message was based on AJAX success function, so that was part of the confusion. It was giving me a success message but not actually doing anything. Changing 'serial.hash' to be 's

[jQuery] Re: Jquery, AJAX and MySQL update

2008-04-11 Thread Chris Jordan
Chris, The hash idea that the other site was talking about is what I was telling you in my previous post. I do this all the time: function myFunction(email){ var args = {}; args.name = $('#nameid').val(); args.location = $('#locationid').val(); args.email = email; args.someStringLi

[jQuery] Re: Jquery, AJAX and MySQL update

2008-04-11 Thread Scott Sauyet
Chris Jones wrote: The hash was a suggestion on another site. I have tried it without it as well but no joy. If I alert the "serial" on success I get what I would expect ie. item[]=2&item[]=3&item[]=10 > [ ... ] > data: serial.hash or data: serial, = nothing gets updated. > data: "name=John&lo

[jQuery] Re: Jquery, AJAX and MySQL update

2008-04-11 Thread Chris Jones
Hi Scott, The hash was a suggestion on another site. I have tried it without it as well but no joy. If I alert the "serial" on success I get what I would expect ie. item[]=2&item[]=3&item[]=10 At the moment the "updatesql.php" file is simply setup so if the page is called it connects to the d

[jQuery] Re: Jquery, AJAX and MySQL update

2008-04-11 Thread Chris Jordan
yeah, the other method of passing data via ajax is: ... url: "myurl.php", type: "post", data: {"variablename":"value", "variablename2":someJSValue}, ... you could declare an object that contains your arguments that you want to pass in to updatesql.php like this: var args = {} args.name = "John" a

[jQuery] Re: Jquery, AJAX and MySQL update

2008-04-11 Thread Scott Sauyet
Chris Jones wrote: $(document).ready(function(){ $("#list").sortable({ accept: 'item', update: function(sorted) { serial = $('#list').sortable('serialize'); $.ajax({ url:"updatesql.php", type:"POST", dat