Olivier,
The following works fine for me:
$(document).ready(function() {
$("#top").children(".one, .two").each(function() {
alert(this.id);
});
});
Can you post your code?
--rob
On 5/31/07, Olivier Percebois-Garve <[EMAIL PROTECTED]> wrote:
Hi rob
It seems to m
Hi rob
It seems to me that children() does not accept a params separated with a
comma
would that make sense ?
On 5/31/07, Rob Desbois <[EMAIL PROTECTED]> wrote:
Olivier,
The .siblings() function excludes the elements selected, e.g.:
$("#myId").siblings();
will select all siblings of the el
Olivier,
The .siblings() function excludes the elements selected, e.g.:
$("#myId").siblings();
will select all siblings of the element with ID "myId", and will exclude
that element from the results.
--rob
On 5/30/07, Olivier Percebois-Garve <[EMAIL PROTECTED]> wrote:
Thanks a lot.I'll test
Thanks a lot.I'll test that tomorrow back at work.It looks correct.
I never used children(), and its seems to solve issues I had on other
scripts.
I also dream on a brothers() method (all other siblings except itself) ...
Olivier
Rob Desbois wrote:
Yes you're absolutely correct.
Try this:
Yes you're absolutely correct.
Try this:
jQuery.fn.accordionQuizz = function(accordion) {
this.children('[EMAIL PROTECTED], label').each(function(){
I haven't tested it though.
--rob
On 5/30/07, Olivier Percebois-Garve <[EMAIL PROTECTED]> wrote:
I dont get it working properly. I tr
I dont get it working properly. I tried:
$('#accordion').accordionQuizz();
jQuery.fn.accordionQuizz = function(accordion){
jQuery(this+' [EMAIL PROTECTED], '+this+'
label').each(function(){
I guess that here is returning the object, wheras I need the
selector name.
the plugin should a
Olivier,
If you call $(...).accordionQuizz() then the jQuery object (result of
$(...)) is accessible via the 'this' object in your function:
jQuery.fn.accordionQuizz = function(accordion) {
alert(this.length); // use the jQuery object
If you call that with:
$('#accordion').accordionQu
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