RE: Mersenne: GIMPS client output

1999-09-19 Thread Rick Pali
From: Eric Hahn > P.S. At the 79.3M range, you'll probably not want to set it > at 100 iterations... Per iteration time on 266MHz PII with > 64MB RAM is 58.781 seconds!!! The only question that comes to mind is if you had to plough through factoring before you got to the LL test...but then I re

Re: Mersenne: GIMPS client output

1999-09-19 Thread Eric Hahn
>Iteration: 164000 / 8410531 [1%]. Clocks: 115665753 = 0.496 sec. > >Might be nice to display the percentage out to an accuracy that changes >every hundred iterations. Hmm, looks like that's an integer of the >percentage, not rounded. Guess it doesn't matter. For the one I'm >working on it lo

Re: Mersenne: M(M(127)) and other M(M(p))

1999-09-19 Thread Chris Nash
Hi Jeff > >prime, unless we find a factor. Interestingly enough, when we find the next > >Mersenne prime, searching for a factor of M(M(p)) might allow us to find an > >even bigger prime. If for example, 6*M(p)+1 divides M(M(p)), then it must > >be prime! > Which one must be prime? 6*M(p)+1,

Re: Mersenne: GIMPS client output

1999-09-19 Thread Lucas Wiman
> Might be nice to display the percentage out to an accuracy that changes > every hundred iterations. Hmm, looks like that's an integer of the > percentage, not rounded. Guess it doesn't matter. For the one I'm > working on it looks like 3 decimal places would be needed to see a change > every

RE: Mersenne: GIMPS client output

1999-09-19 Thread Rick Pali
From: Darxus > Iteration: 164000 / 8410531 [1%]. Clocks: 115665753 = 0.496 sec. > > Might be nice to display the percentage out to an accuracy that > changes every hundred iterations. If you're using version 19, add "PercentPrecision=3" to the prime.ini file. If you want more than three decimal

Mersenne: GIMPS client output

1999-09-19 Thread Darxus
Iteration: 164000 / 8410531 [1%]. Clocks: 115665753 = 0.496 sec. Might be nice to display the percentage out to an accuracy that changes every hundred iterations. Hmm, looks like that's an integer of the percentage, not rounded. Guess it doesn't matter. For the one I'm working on it looks l

Mersenne Digest V1 #628

1999-09-19 Thread Mersenne Digest
Mersenne Digest Sunday, September 19 1999 Volume 01 : Number 628 -- Date: Fri, 17 Sep 1999 19:42:05 -0700 From: Greg Hewgill <[EMAIL PROTECTED]> Subject: Re: Mersenne: v19 DNS(?) crash... On Fri, Sep 17, 1999 at

Re: Mersenne: M(M(127)) and other M(M(p))

1999-09-19 Thread Chris Nash
Hi there Lucas... > The reason is relativly clear: the work of checking *even one* factor of > M(M(p)) is greater than the work required for an LL test on that number. > This is because of the need for p squarings modulo some number greater > than M(p). Yes, however there is a rather curious com

Re: Mersenne: M(M(127)) and other M(M(p))

1999-09-19 Thread Chris Nash
> even bigger prime. If for example, 6*M(p)+1 divides M(M(p)), then it must > be prime! Before anybody gets overexcited at the last posting... It is TRUE that if 2k.M(p)+1 divides M(M(p)), M(p) is prime, and k<2M(p)+2, then 2k.M(p)+1 is prime. However, unless I'm mistaken, non-divisibility doe

Re: Mersenne: M(M(127)) and other M(M(p))

1999-09-19 Thread Jeff Woods
At 08:51 PM 9/19/99 -0400, you wrote: >prime, unless we find a factor. Interestingly enough, when we find the next >Mersenne prime, searching for a factor of M(M(p)) might allow us to find an >even bigger prime. If for example, 6*M(p)+1 divides M(M(p)), then it must >be prime! Which one must b

Re: Mersenne: M(M(127)) and other M(M(p))

1999-09-19 Thread Lucas Wiman
> Of course, the sequence that still remains unknown is > > 2 > M(2)=3 > M(3)=7 > M(7)=127 > M(127)=170141183460469231731687303715884105727 > M(170141183460469231731687303715884105727)=??? Yes, this sequence is interesting, but if someone finds a way to prove/ disprove the primality of M(M(127))

Mersenne: M(M(127)) and other M(M(p))

1999-09-19 Thread Chris Nash
Hi folks, After Lucas Wiman's (re)discovery of the factor of M(M(31)), I made some comment about M(M(p)), something which of course has been long known to not always be a prime whenever M(p) is. (M(M(13)) is the first counterexample and even has a factor found by Keller). Of course, the sequence

Mersenne: Factor of M(M(31))

1999-09-19 Thread Lucas Wiman
Ok, I should have researched a bit more. Many many people have informed me of will's site about M(M(p)) for various p's. I apreciate the link, but I have it now, I don't need any more of them. -Lucas P.S. Warut, I hope you enjoy your money! :)

Re: Mersenne: Factor of 2^(2^31-1)-1 found ($)

1999-09-19 Thread Chris Caldwell
On Sun, 19 Sep 1999, Lucas Wiman wrote: > All (and especially Chris), > > Yesterday (and the day before), I went to the Illinois number theory conference. > There (2nd talk of yesterday) J. P. Selfridge announced that he would > give away $1000 US for any factor found of a number which ought to b

Mersenne: Re: Factor of 2^(2^31-1)-1 found ($)

1999-09-19 Thread George Woltman
Hi, >On Sun, 19 Sep 1999, Lucas Wiman wrote: >> I began searching for a factor of this number in mersfacgmp at around >> 12:10 Central standard time. I thought that mersfacgmp was malfunctioning, >> because it terminated too quickly, but I was wrong, it had found a factor! >> 295257526626031 div

Re: Mersenne: Re: primes source

1999-09-19 Thread Henrik Olsen
On Sun, 19 Sep 1999, poke wrote: > > I would NOT encourage using the gpl for this, it's far too restrictive, > > and the fact that the security stuff isn't included in the public code > > would actually be in direct violation of it. > > I am curious, what about the GPL do you find restrictive? A

Re: Mersenne: primes source

1999-09-19 Thread John R Pierce
> It would be easier to convert the source from MASM to NASM. Both use > intel syntax. NASM is free and its source code available. This is a list > of the object formats it supports. if I recall correctly, the assembler code also makes extensive use of the MASM macro facilities to generate h

Mersenne: Re: Factor of 2^(2^31-1)-1 found ($)

1999-09-19 Thread Chris Nash
Hi Lucas > Yesterday (and the day before), I went to the Illinois number theory conference. > There (2nd talk of yesterday) J. P. Selfridge announced that he would > give away $1000 US for any factor found of a number which ought to be > prime (he provided a list). On that list was 2^(2^31-1)-1.

Mersenne: Re: Factor of 2^(2^31-1)-1 found ($

1999-09-19 Thread Lucas Wiman
Oopsy. That should have read J. L. Selfridge -lucas _ Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm Mersenne Prime FAQ -- http://www.tasam.com/~lrwiman/FAQ-mers

Mersenne: Factor of 2^(2^31-1)-1 found ($)

1999-09-19 Thread Lucas Wiman
All (and especially Chris), Yesterday (and the day before), I went to the Illinois number theory conference. There (2nd talk of yesterday) J. P. Selfridge announced that he would give away $1000 US for any factor found of a number which ought to be prime (he provided a list). On that list was 2

Mersenne: Re: primes source

1999-09-19 Thread Steinar H. Gunderson
On Sun, Sep 19, 1999 at 03:02:34AM -0500, Conrad Curry wrote: > Though if the object file is available and can be converted, I don't >see the advantage of compiling from the source. The main advantage the ability to change it in any way, especially if you don't _have_ MASM at all (ie. building w

Re: Mersenne: primes source

1999-09-19 Thread Jason Stratos Papadopoulos
On Sun, 19 Sep 1999, Conrad Curry wrote: > There are several programs that can convert between intel and gas, but > usually require some help in converting. One that can convert between > NASM or MASM or Gas is at http://hermes.terminal.at/intel2gas/ Note that this program was designed to con

Re: Mersenne: primes source

1999-09-19 Thread Conrad Curry
On Sat, 18 Sep 1999, George Woltman wrote: > At 03:01 PM 9/18/99 -0400, Darxus wrote: > >I have a question though. Why make the Linux source dependant on code > >which needs to be assembled under DOS, when there is an assembler for > >Linux (as) ? > > There is a ton of assembly source code.

Re: Mersenne: Factors Everywhere

1999-09-19 Thread Eric Hahn
>> What I'm looking for is the following two items for *all* >> Mersenne numbers 2^p-1 where p is prime and p>1: > > It can be proven that there are an infinite number of these. Yeah, right, I knew that... I guess I should've clarified and said for all of them that the information is known :