Further to my earlier query
Im using this
SELECT dbo.members_.List_, COUNT(dbo.members_.EmailAddr_) AS nojgid
FROM dbo.members_ INNER JOIN
dbo.lists_ ON dbo.members_.List_ = dbo.lists_.Name_
INNER JOIN
dbo.topics_ ON dbo.lists_.T
Wonder if you can help
I have a table with a number of fields but the
List Name
Member
Info
Ever member in the table has a list and some members have something in the
info field, Im after a count by list name
So for instance the result im after would be something like
L
KT> The database has "Niño" in it. I want it to be returned if the user
KT> searched by using "nino" or "niño".
Normalize words before using mysql. Use regexp to convert 'n' -> 'ñ'.
1.Create columns with normalized data.
2.Fill it.
3.Use columns with normalized data for search and use normalizing
When sending form data via a form I get the following SQL error
ERROR:-- SQLException - Message: The url cannot be null
SQLState: 08001
ErrorCode :0
What does this mean? The row url, is not set to be not null.
--
Kind Regards
Schalk Neethling
Web Developer.Designer.Programmer.President
Volu
Hi,
Does anyone how I could accomplish this:
Basically, I have a MySQL database of names - some names have Spanish
accents in them. I want to build a web interface in PHP to search this
database. However, I want the names with Spanish accents to be shown
in the search results, regardless if the sea
The requirement is for a numeric counter which starts from a value, gets
incremented by one to a max value and then resets to the start value.
Currently, I keep these on a table of counters and do the lock, read, update,
unlock.
Is there a "better way" to implement this using mysql for keeping tr
Kernel panic: Fatal exception in interrupt...In Interrupt handler - not
syncing
message appears when the mysql-max stop is issued. Other than that everything
works. I changed hardware (everything new) and re-installed Linux and MySQL
and upgraded to latest 2.6.3 from mdk (It was happening with the
ÐÐÑÐÐÑÑÐÑÐÑÐ Michael, and ÐÐÐÑÐÐÐ. However, it didn't work. Whole
thing still takes about 1 second.
On the other hand, I realized I'm an idiot and that the reason it was running so fast
when I handled temporary tables myself is that I was using mysqlcc, which truncated
the first table to 1000
Hi,
> Dear friends,
> In this query what precisely needs to be added at alphabetical_field
> following ORDER BY
>
> SELECT * FROM mytable ORDER BY alphabetical_field
> so that I get output in alphabetical order.
>
> guidance, please.
I highly suggest reading a book (any book) on SQL (not MySQL
Hi
replace alphabetical_field with the name of the field you are ordering by.
If you are not sure, post your table structure and I will add it for you :)
bfn
Peter
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: 14 August 2004 19:06
To: [EMAIL PROTECTE
Dear friends,
In this query what precisely needs to be added at alphabetical_field
following ORDER BY
SELECT * FROM mytable ORDER BY alphabetical_field
so that I get output in alphabetical order.
guidance, please.
--
My Php
Right. If the employee ID in either the rep_no or entered_by columns does
not have a corresponding row in the global_employee table, then the regular
join won't match that row. In that case, as you found, you need a LEFT
JOIN, which guarantees you get the rows from the table on the left, and
Thanks a lot Michael.
A regular join did not seem to work. But when I tried a LEFT JOIN it worked.
A cut down example of it is the following.
SELECT global_lead.id, rep_no, es.fname as sales_name, em.fname as
marketing_name
FROM global_lead
LEFT JOIN global_employee es ON global_lead.rep_no = es.i
You need to join the employee table twice, once for each id lookup, like this:
SELECT es.name AS sales_name, em.name AS marketing_name, leads.id
FROM leads JOIN employee es ON leads.salesid = es.id
JOIN employee em ON leads.marketingid = em.id;
Michael
Michael J. Pawlowsky wrote:
I
Im not sure if this is possible or not.
I have a Sales leads table.
Part of the table has 2 employee_ids.
1. The Sales person the lead is assigned to.
2. The Marketing person that generated the lead.
Then there is a employee table that has ids and names.
When generating a report for leads I would
A defining feature of a relational database is that its data storage is
entirely independent of the physical order of rows. To specify row order in
a query, use an ORDER BY clause.
PB
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, August 14, 2004
SELECT * FROM mytable ORDER BY alphabetical_field
hth
Peter
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> Sent: 14 August 2004 08:57
> To: [EMAIL PROTECTED]
> Subject: MYSQL RECORDS AND ALPHABETICAL ORDER
>
>
> Dear Friends,
>
> I have mysql table which re
Hi,
> I have mysql table which retains names,Data is written to mysql table
using
> php query, however when I check the records, I amn't able to do the same
in
> alphabetical order.
> How do I make mysql to retain records in alphabetical order.
With an ORDER BY clause perhaps?
With regards,
Mar
Dear Friends,
I have mysql table which retains names,Data is written to mysql table using
php query, however when I check the records, I amn't able to do the same in
alphabetical order.
How do I make mysql to retain records in alphabetical order.
Any guidance, please.
Здравствуйте Matt
ME> CREATE TABLE `T1` (
ME> `guid` smallint(5) unsigned NOT NULL default '0',
ME> `qid` smallint(5) unsigned NOT NULL default '0',
ME> `a` tinyint(2) NOT NULL default '-2',
ME> `d` tinyint(2) NOT NULL default '-2',
ME> KEY `IX_FW_qid` (`qid`),
ME> KEY `IX_FW_d` (`d`)
Hi,
Everybody.
It's simple question. But i am in confusion. I have table with
huge number of records but only 3 columns (suppose col1, col2, col3). col1
is primary key and I have created the Index on the column (i.e. col2)
which is not a primary key.
Problem
1) is that
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