Markus Hoenicka wrote:
Hi,
is the following behaviour intended? Are my queries wrong? The output
shows only the Extra field as the other fields are identical in all
cases.
EXPLAIN SELECT t_refdb.refdb_id FROM t_refdb WHERE t_refdb.refdb_id0
ORDER BY t_refdb.refdb_id;
= Using where; Using
Chris [EMAIL PROTECTED] was heard to say:
That is, if MySQL can't use an index to sort the result, DISTINCT
queries won't be sorted at all.
That doesn't make sense.
How many rows fit that criteria?
SELECT COUNT(DISTINCT t_refdb.refdb_id) FROM t_refdb WHERE refdb_type!='DUMMY'
AND
Hi All,
Anybody know how to install Mysql on GHS Integrity RTOS.
Where I will get the mysql package for the same. Or can I use the same
as for Linux.
Regards,
Ravi K
The information contained in this electronic message and any attachments to
this message are intended for
Just for the archives: looks like I bumped into bug #21456:
http://bugs.mysql.com/bug.php?id=21456
This bug has been fixed in 4.1.22 and 5.0.25, so I'll just have to upgrade.
Thanks anyway
Markus
Markus Hoenicka [EMAIL PROTECTED] was heard to say:
Chris [EMAIL PROTECTED] was heard to say:
Hi,
I am starting a site that enables people to purchase information using
credits bought on the site.
e.g. you buy 10 credits for £10 and they sit in your online account on the
site for you to spend whenever you like.
Does anyone know of a script or software already in existance that we can
I have a registration script that inserts data into the database, and
then emails you an activation code to activate your account. The
problem is that when I click on the link in the email, the account does
not get updated. The portion of the script that has a problem is this:
$query = UPDATE
Which error do you get in activation page?
Nicholas Vettese [EMAIL PROTECTED] escreveu na mensagem
news:[EMAIL PROTECTED]
I have a registration script that inserts data into the database, and
then emails you an activation code to activate your account. The
problem is that when I click on the
I can see something that can be the problem, in mysql 3 you don´t have
trigger, then you cannot use trigger_error function, try to use mysql_error
instead.
Nicholas Vettese [EMAIL PROTECTED] escreveu na mensagem
news:[EMAIL PROTECTED]
I have a registration script that inserts data into the
I get the following query:
select rt.team_id,count(p.race_id) as cnt,sum(p.points) as
sum_score,sum(p.points) / count(p.race_id) as avg_score from some tables,
joins and where-criterias group by rt.team_id order by avg_score desc;
which gives:
+-+--+---+---+
|
At 08:22 AM 9/6/2006, Nicholas Vettese wrote:
I have a registration script that inserts data into the database, and
then emails you an activation code to activate your account. The
problem is that when I click on the link in the email, the account does
not get updated. The portion of the
Try to use 'avg_score desc,sum_score desc'
Jørn Dahl-Stamnes [EMAIL PROTECTED] escreveu na mensagem
news:[EMAIL PROTECTED]
I get the following query:
select rt.team_id,count(p.race_id) as cnt,sum(p.points) as
sum_score,sum(p.points) / count(p.race_id) as avg_score from some tables,
joins and
2006/9/6, Jørn Dahl-Stamnes [EMAIL PROTECTED]:
I get the following query:
select rt.team_id,count(p.race_id) as cnt,sum(p.points) as
sum_score,sum(p.points) / count(p.race_id) as avg_score from some tables,
joins and where-criterias group by rt.team_id order by avg_score desc;
which gives:
On Wednesday 06 September 2006 15:20, you wrote:
the direction (desc/asc) order qualifier is per-sortfield and
defaults to asc, so to get what you're after you'd want:
order by avg_score desc, sum_score desc
or
order by avg_score desc, sum_score
if you're after 'asc' on sum_score.
2006/9/5, Ben Lachman [EMAIL PROTECTED]:
So possibly a better solution would be to create a temporary table
and then do a subquery on that table?
yes. Or do a :
SELECT id FROM t1 WHERE name LIKE '%s1%' OR name LIKE %'s2%' OR name
LIKE '%s3%'
but depending on your data, a table may be the way
2006/9/4, [EMAIL PROTECTED] [EMAIL PROTECTED]:
Hello all,
I need to perform an SQL statement over 5 different tables, with complex
request. To do so, i'm using subqueries.
SELECT ... FROM (SELECT .WHERE) as T1 LEFT JOIN (SELECT
.WHERE) as T2 WHERE .
The problem is that
Hi,
I want to get all records from Tab1 and the first 20 words for the fieldA
SELECT *, LEFT(fieldA, 20) AS fieldA FROM Tab1
But this query does not work: why?
thanks!
--
http://www.spacemarc.it
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$x and $y work perfectly, and I believe the problem is the trigger
function. Thanks to everyone who helped, and as soon as I get a chance
to update and fix, I will try it.
Thanks,
Nick
-Original Message-
From: Miles Thompson [mailto:[EMAIL PROTECTED]
Sent: Wednesday, September 06,
I've got a similar setup, total records across about 8 tables hoovers around
200 million.
To change a merge table just issue an alter table with a new union.
ALTER TABLE mergetable UNION=(table1, table2, table3,...);
- Original Message -
From: Jacob, Raymond A Jr [EMAIL PROTECTED]
At 10:55 AM 9/6/2006, spacemarc wrote:
Hi,
I want to get all records from Tab1 and the first 20 words for the fieldA
SELECT *, LEFT(fieldA, 20) AS fieldA FROM Tab1
But this query does not work: why?
thanks!
--
http://www.spacemarc.it
First of all - please reply to the list ..
I
2006/9/6, Miles Thompson [EMAIL PROTECTED]:
First of all - please reply to the list ..
I thought you wanted all fields, that's the way your SELECT statement is
constructed. If just the first 20 char from fieldA, then ...
SELECT LEFT(fieldA, 20) AS fieldA FROM Tab1
should do what you
You know, this works just fine for me -- when you say it is NOT working,
what do you mean exactly? Are you getting an error? Or results that you
don't expect?
Bill Tantzen
University of Minnesota Libraries
[EMAIL PROTECTED]
612-626-9949 (office) 612-250-6125 (cell)
Hello MySQL-User,
i need your help with the following query.
I want to get the next birthdays of my friends, but not only the one of
this year.
So when im in december ( or november ) i want to see the birthdays of
next year too
With my query i only see the birthdays of this year :
SELECT
Hello MySQL-User,
i need your help with the following query.
I want to get the next birthdays of my friends, but not only the one of
this year.
So when im in december ( or november ) i want to see the birthdays of
next year too
With my query i only see the birthdays of this year :
SELECT
2006/9/6, Bill Tantzen [EMAIL PROTECTED]:
You are actually selecting fieldA twice -- the first time (with '*') will
return the entire column. The second time with only the first 20 chars. If
you only want to see the first 20 chars, you will have to explicitly name
every column in your select
Hello,
My name is Chris Glavin. I emailed you because you are an educator. I run a
website which is all about Education Disabilities. It is geared towards
parents, students, teachers, district officials professionals. I ask that
you take a few minutes out of your busy schedule to visit my
Hi Dan,
Thanks for yur response. Does it makes sense to create an index on a
primary key ..as that is my smallest field ?
Regards
Prasad
-Original Message-
From: Dan Nelson [mailto:[EMAIL PROTECTED]
Sent: Monday, September 04, 2006 9:53 AM
To: Prasad Ramisetti (WT01 - Broadband
[EMAIL PROTECTED] wrote:
Hi Dan,
Thanks for yur response. Does it makes sense to create an index on a
primary key ..as that is my smallest field ?
A primary key already has an index.
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Hi Prasad
A primary key automatically creates an index and not-null and unique
constraints, too. So you don't need to explicitly create an index on
a primary key column.
If your queries are going to have WHERE clauses (as they most likely
are) I'm not sure how the small-index suggestion
In the last episode (Sep 07), [EMAIL PROTECTED] said:
Hi Dan,
Thanks for yur response. Does it makes sense to create an index on a
primary key ..as that is my smallest field ?
It might, because in an InnoDB table, your primary index also holds
your row data. So it's actually your largest
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