Dear MySQL users,
MySQL Server 5.7.9 (GA) is a new version of the world's
most popular open source database. This is the first official release
of MySQL 5.7.
[Due to size limitations on forum/email, this announcement had to be
split into two parts. This is part 1.]
The new features in this
[This is part 2 of the announcement]
Bugs Fixed, cont.
* Replication: The group replication applier channel does
not support DATABASE as the slave_parallel_type; when
group replication is started, this is checked for
explicitly, and handled correctly. However, it
On 10/22/2015 11:48 AM, Don Wieland wrote:
On Oct 20, 2015, at 1:24 PM, shawn l.green wrote:
Which release of MySQL are you using?
Version 5.5.45-cll
How many rows do you get if you remove the GROUP_CONCAT operator? We don't need
to see the results.
I'm not at a terminal but have you tried grouping by p.pk_ProductID instead
of i.fk...? It is the actual value you are selecting as well as being on
the primary table in the query.
On Thu, Oct 22, 2015, 5:18 PM Don Wieland wrote:
> Hi gang,
>
> I have a query:
>
> SELECT
>
> On Oct 22, 2015, at 2:41 PM, Michael Dykman wrote:
>
> I'm not at a terminal but have you tried grouping by p.pk_ProductID instead
> of i.fk...? It is the actual value you are selecting as well as being on
> the primary table in the query.
Yeah I tried that - actually the
Hi gang,
I have a query:
SELECT
p.pk_ProductID,
p.Description,
i.Quantity
FROM invoice_invoicelines_Product p
JOIN invoice_InvoiceLines i ON p.pk_ProductID = i.fk_ProductID AND
i.fk_InvoiceID IN (1,2,3)
WHERE p.pk_ProductID IN (1,2,3);
It produces a list like the following:
One more guess:
Try explicitly aliasing the fields of interest and using those aliases
exclusively throughout the rest of the expression.
SELECT
p.pk_ProductID as pid,
p.Description as dsc,
SUM(i.Quantity) as totl
FROM invoice_invoicelines_Product p
JOIN invoice_InvoiceLines i ON pid =
Dear MySQL users,
The MySQL developer tools team announces 6.3.5 as our GA release for
MySQL Workbench 6.3.
For the full list of changes in this revision, visit
http://dev.mysql.com/doc/relnotes/workbench/en/changes-6-3.html
For discussion, join the MySQL Workbench Forums:
> On Oct 20, 2015, at 1:24 PM, shawn l.green wrote:
>
> Which release of MySQL are you using?
Version 5.5.45-cll
> How many rows do you get if you remove the GROUP_CONCAT operator? We don't
> need to see the results. (sometimes it is a good idea to look at the raw,