Hello,
I've got a table which containes two date colomns.
The first one is called `date` and the second `update`
In the first one I put the ticket creation date, and on update I add or
change the update value.
So the update colomn does not contain a value until the first update has
been done.
I
mysql version?
http://dev.mysql.com/doc/refman/5.0/en/case-statement.html
order by case when updated is not null then updated else created end desc;
/Kristian
On Tue, Apr 8, 2008 at 1:04 PM, Richard [EMAIL PROTECTED] wrote:
Hello,
I've got a table which containes two date colomns.
The
Hello I've tried the following with mysql 4.1.11
SELECT * FROM quick_contact WHERE (`status` = '0') OR (`status` = '2'
AND `update` '.(time()-864000).') CASE WHEN `update` = '' THEN ORDER
BY `date` DESC ELSE ORDER BY `update` DESC END CASE;
It does not work but, is it my code that is wrong
Can't you do Something like:
ORDER BY (update,date)
The major column of ordering would be update and the second date.
I'm not sure about this solution
On Tue, Apr 8, 2008 at 8:54 AM, Richard [EMAIL PROTECTED] wrote:
Hello I've tried the following with mysql 4.1.11
SELECT * FROM
Thanks,
I think that your solution will be sufficient for my needs, however I
would still like to know for my personal knowledge how to manage
correctly this kind of need.
And to make it more complicated I've just rearlised that there is
another element to take into account, I would need to
A modification to my last email, try:
SELECT
*, IF(update != '', update + 10, date) AS o
FROM
my_table
ORDER BY o DESC;
+-+--++--+
| num | date | update | o|
+-+--++--+
| 5 | 40 | 90 | 100 |
| 2 | 10 | 60 | 70 |
| 6 | 50 |
I think the easiest is to create a new logical column with the correct
ordering, something like:
SELECT *, IF(update != '', update, date) AS o
FROM my_table ORDER BY o DESC;
I note that both 'update' and 'date' are reserved works :)
Also worth noting that this cannot be assigned an index
Thanks, it works like a charm :)
Ben Clewett a écrit :
A modification to my last email, try:
SELECT
*, IF(update != '', update + 10, date) AS o
FROM
my_table
ORDER BY o DESC;
+-+--++--+
| num | date | update | o|
+-+--++--+
| 5 | 40 | 90
Richard,
No problem, glad it works. But note: this is not scalable. If you have
more than a few hundred rows, you may want to think about a better
solution, like storing the order field permanetly and giving it an index :)
Ben
Richard wrote:
Thanks, it works like a charm :)
Ben Clewett
Thanks,
This is for the unanswered list of questions, so the output list (not
the list stored in the mysql database) should never go over 100.
by scalable, do you mean alot of ressources being used or a long wait
for the answer? Because I belive I Could just use a simple limit if I
needed
On Tue, 8 Apr 2008, Richard [EMAIL PROTECTED] wrote:
Kristian Myllym?ki a ?crit :
mysql version?
http://dev.mysql.com/doc/refman/5.0/en/case-statement.html
order by case when updated is not null then updated else created
end desc;
Hello I've tried the following with mysql 4.1.11
SELECT *
Not sure, but perhaps an even simpler method would be to consider the
initial insert an update as well... so the update column would always have
a value. Then the sort would (I believe) always be in the order you want,
and if you need to differentiate between rows that are new vs rows that
are
Richard,
The query I gave you required the column 'o' to be calculated for each
row at the time of gathering the data. When all rows have been
gathered, the data will be stored and sorted in a temporary table. This
temporary table will be in memory or on disk depending on the setting of
Yes that would be easier, except that I would still have to create a
tempory table to add 10 days onto the ones which have a status waiting
for answer from customer and have not been answered for more than 10 days.
This system is for customers who do not have an account yet to contact
me. And
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