On 4/8/04 1:05 PM, "Michael Stassen" <[EMAIL PROTECTED]> wrote:
>
> James McConnell wrote:
>
>> On 4/8/04 9:18 AM, "Barry ." <[EMAIL PROTECTED]> wrote:
>>
>>
>>> Hi
>>>
>>> I recently began to work through the Book entitled PHP & MySQL For Dummies
>>> and i am currently stuck towards the end
James McConnell wrote:
On 4/8/04 9:18 AM, "Barry ." <[EMAIL PROTECTED]> wrote:
Hi
I recently began to work through the Book entitled PHP & MySQL For Dummies
and i am currently stuck towards the end of the forth chapter ive done
everything as said so in the book but i keep getting an error messa
Typo petColor is meant to be color
From: James McConnell <[EMAIL PROTECTED]>
To: "Barry ." <[EMAIL PROTECTED]>,MySQL Mailing List
<[EMAIL PROTECTED]>
Subject: Re: Learner Here Getting Frustraighted
Date: Thu, 08 Apr 2004 09:34:36 -0500
On 4/8/04 9:18 AM,
Barry Smith writes:
>i have 2 tables one pet containing petName and petType other table is color
>containgin petName and petColor. The code which i keep getting errors on is:
>
>Select * from pet outer join color using (pet.petName=petcolor.petName) ;
Unfortunately petcolor is not a table. Based
For starters look at pet.petName=petcolor.petName
Try changing it to.
pet.petName=color.petName
You are referencing the color table as petcolor.
Thanks,
Andrew
From: "Barry ." <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Subject: Learner Here Getting Frustraighted
Date: Thu, 08 Apr 2004 14:18:10 +
On 4/8/04 9:18 AM, "Barry ." <[EMAIL PROTECTED]> wrote:
> Hi
>
> I recently began to work through the Book entitled PHP & MySQL For Dummies
> and i am currently stuck towards the end of the forth chapter ive done
> everything as said so in the book but i keep getting an error message. Here
> is
