Agree. I think that with() should only be used with object references only,
and $_ should be set accordingly.
Ilya
-Original Message-
From: John Porter
To: [EMAIL PROTECTED]
Sent: 07/19/2001 1:01 PM
Subject: Re: aliasing - was:[nice2haveit]
Sterin, Ilya wrote:
But I thought
Bart Lateur wrote:
So, in this case, a with synonym for for would work.
But this only works for scalars. You can't have a %foo alias to
%Some::Other::hash this way, or a @bar alias to @Some::Other::array.
Sounds like what we really want is a form of for which can iterate
over a list of
Sounds like what we really want is a form of for which can iterate
over a list of hashes or arrays:
for my @a ( @foo, @bar ) { ...
for my %h ( %foo, %bar ) { ...
Yes.
Isn't the underlying issue in the above how perl6 handles manipulation
and aliasing of multi-dimensional arrays into
/19/2001 11:31 AM
Subject: Re: aliasing - was:[nice2haveit]
Then how would you write I am not a coward
with ($foo)
{
print I am not a; ##What do I use here or do I have to issue a
##separate print like...
print;
}
Ilya
Well in Perl5, for the print to use default
Stuart Rocks wrote:
CWith would also make the [variable, alias, whatever]
default, but not replace the $_:
$_ = monkey ;
$foo = coward;
with ($foo){
print;
print $_;
}
would output monkey coward.
okay, coward is default but $_ has not been replaced, so would not
the
Sterin, Ilya wrote:
But I thought this was related to more than just with(), so if we have
### Would now have to be printed as
print This is number ;
print;
print of 10\n;
I still believe that although not defining a variable source will use the
temp variable there is still a need
