On Monday 23 June 2008 00:19:14 Moritz Lenz wrote:
> Will Coleda wrote:
Hi,
> > Which implementation of Perl 6 are you using here? In Rakudo,
> > everything works as you describe except for the last example which
> > dies on the last line with:
Erm, totally forgot that.
I am using a recent (rea
Moritz Lenz wrote:
> Will Coleda wrote:
>> On Sun, Jun 22, 2008 at 2:59 PM, Frederik Schwarzer
>> <[EMAIL PROTECTED]> wrote:
...
>>> But if I do:
>>>my @arr = (23, 42);
>>>my $temp = @arr[0]; # copy?
>>>@arr[0] = @arr[1];
>>>say $temp; # 42
>>> $temp is 42 ...
>>> I expected $te
Will Coleda wrote:
> On Sun, Jun 22, 2008 at 2:59 PM, Frederik Schwarzer
> <[EMAIL PROTECTED]> wrote:
>> Hi,
>>
>> there is something I do not understand.
>> I reduced the code to a minimal case.
>>
>> If I do:
>>my $a = 23;
>>my $b = $a; # copy
>>$a = 42;
>>say $b; # 23
>> $b i
On Sun, Jun 22, 2008 at 2:59 PM, Frederik Schwarzer
<[EMAIL PROTECTED]> wrote:
> Hi,
>
> there is something I do not understand.
> I reduced the code to a minimal case.
>
> If I do:
>my $a = 23;
>my $b = $a; # copy
>$a = 42;
>say $b; # 23
> $b is 23,
> and if I do:
>my $a =
Hi,
there is something I do not understand.
I reduced the code to a minimal case.
If I do:
my $a = 23;
my $b = $a; # copy
$a = 42;
say $b; # 23
$b is 23,
and if I do:
my $a = 23;
my $b := $a; # reference
$a = 42;
say $b; # 42
$b is 42 because it is just a r
