Hi there
Getting a weird issue with MySQLi fetch when using bound variables.
First of all here is some example code.
prepare('SELECT `id`, name FROM MYTABLE WHERE id = ?)
{
if ($stmt->bind_param('i', $pID))
{
if ($stmt->bind_result($recordID, $name)
{
if ($stmt->execute())
{
$stmt->fe
On Mon, Jul 4, 2011 at 7:11 AM, Karl DeSaulniers wrote:
> Hello Stuart,
> After some closer look at the RFC Compliant manuals you suggested,
> I have determined that the creator of that code was in fact RFC821
> Compliant.
> Being that this was a code I found several years ago,
On Sun, Jul 3, 2011 at 11:22 PM, Karl DeSaulniers wrote:
> @Stuart,
> Actually that is what made me look into the PHP_EOL Stuart. Wanting to do
> things right.
> Did you not read my initial email? I am not suggesting anyone adopt my
> code.
> The question was directed to what t
you accept" - if it wasn't like that the internet would fall apart. I
encourage you to do your part to do things right, but it's completely up to
you if you don't want to follow the users' manual.
-Stuart
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http://3ft9.com/
On Jul 2, 2011, at 8
mented mail servers (rare these days, but it happens).
Incidentally, CR only applies to Mac OS9 and earlier. OSX uses LF due to its
BSD roots. For a near-complete list, see "Representations" here:
http://en.wikipedia.org/wiki/Newline.
-Stuart
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http://3ft9.com/
hi chris,
right. if i run 'psql -d soma' and then type the first SELECT, i get
results ... if i type the second SELECT, i get zero rows. this seemed
odd to me ... i wouldn't think that postgres would care. but perhaps it
does
hmm. ok, i just tried this again ... and now i'm getting resul
p
Zend Engine v1.3.0, Copyright (c) 1998-2004 Zend Technologies
production> cd /usr/share/pear
production> grep -i version DB.php
[...]
* @version Release 1.7.6
[...]
v8.1.4 PostGreSQL. OpenSuSE 10.1
--sk
stuart kendrick
fhcrc
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utput was a good
first step ... encourages me to believe that my SQL syntax is correct
and that my database contains data. what steps might i take next, to
figure out what is happening here?
production> php -v
PHP 4.3.10 (cli) (built: Mar 22 2005 19:34:44)
Copyright (c) 1997-2004 The PHP Group
Ze
e account was
allowed , that being the superuser i.e. all
privelages.
Stuart
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he same recordset and parameters and
put them on another page , using a form with post
/hidden values to pass the same values over. I've also
tried posting to the same page. The weird thing is
"code" and "$totalRows_rsLPINDS" come back empty. PN
remains intact. Totally mind boggling.
Stuart
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ble for IndID like this :
$IndID = $rsLPINDS->Fields('IndID');
which when I do a print_r($IndID), prints out the
first record.
So at this point I'm trying to figure out what I need
to make $IndID an array.
Stuart
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Next();
}
$rsInds->MoveFirst();
I've added this in the script, which prints out fine
once I've submitted the page. Not sure if I need
something similar for the records that already exist ?
if (count($inds) > 0 AND is_array($inds)) {
$ind = "'".implode(&
Having a problem here with updating multiple records
in a table.
First the table is like such:
+-+--+
| RecordID [int] | IndID [int] |
+-+--+
There is no auto inc column. User has a record number
and then can have multiple rows in tabl
--- Andrew Kreps <[EMAIL PROTECTED]> wrote:
> On Thu, 6 Jan 2005 07:28:32 -0800 (PST), Stuart
> Felenstein
> <[EMAIL PROTECTED]> wrote:
> >
> > The problem I'm having a hard time getting my
> hands
> > around are those areas where they can have
>
well if many users though.
Any suggestions ?
Thank you,
Stuart
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this one. Sounds
like a lot of code. I'm not complaining :)
> 2. storing the last used filter (i.e. the last given
> set of WHERE clause
> related values) in the session, a DB, file*** or
> whatever in order to
> remain state - in this case you need to retrieve the
> valu
e where array is
getting wiped out, values are gone. I get a "divison
by zero" error. I'm assuming this is becasue the
order by statement is issued with no parameters.
Hope this makes sense and while I think it through
perhaps someone has an idea of remedy.
Stuart
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If I put it in the select statement , the it's out of
place with the where clause.
If I put it at the end of the where clause, obviously
it is not seen.
Any ideas how I can set this up correctly ?
Stuart
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break these
particular "where" conditions off into a seperate
array.
Something like: $bWHERE = array();
then -
$query_rsCS .= ' WHERE '.implode(' OR ',$bWHERE);
Or is it possible there is another work around I'm not
seeing yet ?
Thanks in advance.
Stuart
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--- Stuart Felenstein <[EMAIL PROTECTED]> wrote:
>
> --- Jason Wong <[EMAIL PROTECTED]> wrote:
>
> >
> > Also just to be certain that you *are* running
> those
> > lines of code change the
> > echo $to, to echo "Before $to" &
ere
is something funky with the trigger.
When I removed the trigger function -
to = $rsVendorJobs->Fields('Conmail'); sent me an
email and returned the correct value.
So I'll now be debugging the trigger function to find
out what is up. The road is never straight.
Stuart
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$to;
>
Same thing: Call to a member function on a non-object
in..
Stuart
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e page I can do a
fields('Conmail');?>
And it will echo out the correct value,
But! as soon as I do a
$to = $rsVendorJobs->fields('Conmail');
I get a "Fatal error: Call to a member function on a
non-object in /ho...."
So I tried adding global $
g(11) "Entry Clerk" ["JobTitle"]=>
string(11) "Entry Clerk" [6]=> string(6) "A99839"
["OptRefCode"]=> string(6) "A99839" } ["blobSize"]=>
int(100) ["canSeek"]=> bool(true) ["sql"]=>
string(5
, although from your code
> it should exactly
> match a dump of $rsVendorJobs.
>
Yeah , the sql is cool Everything returns as
expected.
Stuart
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sVendorJobs);
$rsVendorJobs =
$->SelectLimit($query_rsVendorJobs) or
die($->ErrorMsg());
$totalRows_rsVendorJobs =
$rsVendorJobs->RecordCount();
// end Recordset
%s = the JobID I've selected on the previous page and
passed over with $_POST
Hope this is enough. Not sure what else to send.
Stuart
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'Conmail');
>
> 2) change
> $body = '$cl';
> To
> $body = $cl;
>
Well I'm sure this is not the syntax, but since I've
written it both ways I get a :
Fatal error: Call to a member function on a non-object
in /home/xxx/public_html/appjobb.php
e saying, how does that actually look ?
Maybe something like this
$myvar = select field from table where id = 2 ?
Something as simple as that perhaps ?
Stuart
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27;Conmail')";
$subject = $rsVendorJobs->Fields('RefEm');
$body = '$cl';
$headers = "From: [EMAIL PROTECTED]";
mail($to,$subject,$body,$headers);
echo "Mail sent to $to";
}
K...so you know this didn't work. I'm googling around
but haven't
f the check box to:
(and by the way, that is Adoob syntax, so don't let
the value throw you)
While it returns from the correct field it is not
returning the correct record. I read somewhere to
name checkbox as an array. checkbox[]
Perhaps this is what I need to do.
Stuart
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es. Many articles,
forum post, etc were about "deletes" and insertions
using checkboxes.
Stuart
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r can choose this
profile (check) and this document (check) hit submit
and those are returned.
I'm having no luck though and perhaps I'm unclear
about the use of checkboxes or even radio buttons.
Anyone understand how to accomplis this task ?
Stuart
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gt; No Matches
> Found
> exit;
>}
>
e...cause I have no idea what i'm doing :)
Not to be funny though, I'm at this 4 months , with no
previous experience with php, any database and html.
I think I'm slowly catching on. Code is no longer a
fuzzy mess of char
here ?
if ($row_rsCS == false) {
exit;
}
Thank you
Stuart
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--- Stuart Felenstein <[EMAIL PROTECTED]> wrote:
> The reason the close is there is because the next
> line
> of code is the print_r , and I put some html in
> there.
>
So this works great:
if ($row_rsCS == false) {
print_r ("No Matches Found");
exit;
}
But b
is point.
>
> You need to mark the block controlled by the if,
> using either {-} or
> :-endif, according to your taste.
>
The reason the close is there is because the next line
of code is the print_r , and I put some html in there.
Stuart
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(while the message is sharp and
centered ;)), it is not to right place, since it sends
the message and exits whether records / matches exist
or not. Any suggestions ?
Thank you
Stuart
$query_limit_rsCS = sprintf("%s LIMIT %d, %d",
$query_rsCS, $startRow_rsCS, $maxRows_rsCS);
//print_r($quer
John! Your the man! It works!
if (!empty(var))
Excellent. I think this is a good lesson in isset. I
assumed they were the same. I guess reading the
manual more would help.
Thank you.
Stuart
> --- John Holmes <[EMAIL PROTECTED]> wrote:
>
> > You need to check if $stateRel
t; we would have seen if you'd just posted the query...
>
I should probably ask -
is this the way to use if(!empty(var)) ?
Stuart
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--- John Holmes <[EMAIL PROTECTED]> wrote:
> Stuart Felenstein wrote:
> > if(isset($stateReloc2)) $aWHERE[] = "Prof.State1
> IN
> > ($stateReloc2)";
>
> You need to check if $stateReloc2, etc are empty()
> instead of set.
> If the variable is s
> > print_r($aWHERE);
>
> HTH
>
> Graham
>
Didn't do it. :(
Stuart
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--- Bastien Koert <[EMAIL PROTECTED]> wrote:
>
> can you post the code that creates the sql
> statement
>
> bastien
>
I'm posting the entire script. I hope it comes
through legible. If not I can do an attachment so the
format, line breaks will remain.
0 AND is_array($taxType)) {
$s_
--- John Holmes <[EMAIL PROTECTED]> wrote:
> Stuart Felenstein wrote:
> Print out the entire query before you run it. Syntax
> errors are usually
> pretty obvious. If not, post the actual query here.
I found one possible syntax error and fixed it though
it seemed to ha
.implode(' AND ',$aWHERE);
Now I've printed out the query, but it only prints out
right up to the where clause. To me it looks like the
where clause is not taking correctly but I'm not sure
why or how to know for usre.
I'm tried print_r ($query_rsCS) but it's returnin
basically took this code from a search
that is working - what I wonder is if the where
statement is correct .
Well let me start here and see.
Thank you
Stuart
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a left right , outter
inner, full join. So, the builder gets all the other
stuff out of the way, all the code, and would let you
focus on the join type. A click of the mouse and you
can switch the join type, run the query and see the
difference in results. Kind of neat.
Stuart
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he options - would that potentially make a huge hit
on the system.
Stuart
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Sorry ..hit the wrong button
--- Stuart Felenstein <[EMAIL PROTECTED]> wrote:
I posted this over on mysql list. Not trying to be
redundant, but would like to get some feedback.
Basically I'm wondering.
I am creating a search form , dynamic query, that
could potentially have in
I posted this over on mysql list. Not trying to be
redundant, but would like to get some feedback.
Basically I'm wondering.
I am creating a search form , dynamic query, that
could potentially have in the area of 40+ where
statements.
i.3. 1- where x = y and
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these fields are optional and in the db
set to allow null. I went ahead and put '' around all
the values so just in case. Though I know for a fact
it was working without them before.
Oh and yes it seems to be working now.
Stuart
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1062 : Duplicate entry
> '0-f' for key 1
>
> And again on this line -- twice, in fact, since the
> previous line ends with
> a comma, too.
>
Mike are you saying that I should put single quotes
around all values regardless of the type ?
The double commas are h
--- Stuart Felenstein <[EMAIL PROTECTED]> wrote:
One last thing to add on this issue. This table was
created using tabletype InnoDB. Now I discovered
earlier that this table and (many others) had switched
over to MyISAM. I'm still trying to trace down the
cause with my ISP.
Anyw
d the Insert statement into a mysql gui it
spit back a syntax error , apparently for the blank
values ..,'', yet those are set to allow null.
I went ahead and tried just an insert on the first 4
columns , that worked.
Stuart
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--- Stuart Felenstein <[EMAIL PROTECTED]> wrote:
> I know recently the server was update from PHP 4.3.8
> to 4.3.9 but that shouldn't have effected anything.
>
> Code:
>
> $query = "INSERT INTO table1 (ProfileID, LurkID,
> ProfileName, Ed
unset($all session variable, $LID, );
}else{
...
Puzzling since this script was working great. We did
also upgrad MySQL from 4.0.21 to 4.0.22-standard
Thank you,
Stuart
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x27;", $link);
>
Where did this code go though ? Meaning, was it in a
seperate script / page or was it part of a bigger
query that first got the results based on certain
criteria , the did the update?
Stuart
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is set too 3)
...etc.
So I have a vauge idea of the sql statement but where
to place is the question. My thoughts are that it
should be in the loop that generates the result rows
return. In other words -
Maybe here :
Or maybe here ?:
Hope what I'm asking is clear.
Thank you ,
S
--- Stuart Felenstein <[EMAIL PROTECTED]> wrote:
> I have a search page and a results page. It's a
> dynamic search. It works great with just the main
> table, but as soon as I add in the table joins (to
> translate the codes) it just dumps out all the
> record
I have a search page and a results page. It's a
dynamic search. It works great with just the main
table, but as soon as I add in the table joins (to
translate the codes) it just dumps out all the records
regardless of criteria.
Here is the script without the joins:
http://www.w3.org/TR/html4/lo
I have a textarea field that will allow users to copy
and paste text into , it might be plain text, or it
might come out of word.
I'm wondering what type of validations I should
perform on this field ?
Any suggestions / ideas ?
Thank you,
Stuart
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Sorry about the two lists. The echo's are fine. The
problem was iterating through the 3 arrays.
Stuart
--- Graham Cossey <[EMAIL PROTECTED]> wrote:
> Stuart, now I'm confused.
>
> You seem to be posting slightly different versions
> of problems relating to
>
Changed my direction somewhat but keep getting a parse
error and although I know where it is , I can't seem
to figure out what I need to do to make it syntax
correct:
This is how I am passing the arrays:
if ( empty( $_SESSION['l_skill'] ) ) {
$_SESSION['l_skill']=array();
}
if ( is_array( $_REQU
to nest all the "if ( is_array"
but that produced some funky loop.
So then I formatted as aboved. Problem is all i'm
getting is the last element from each array into the
database.
I'm thinking then, perhaps not nested , but the if is
arrays need to be formatted differently.
Stuart
--- Graham Cossey <[EMAIL PROTECTED]> wrote:
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See interspersed:
--- Graham Cossey <[EMAIL PROTECTED]> wrote:
> Have you tried naming your form elements such as
> skill[], sky[] and slu[] ?
> (You could also use skill[1], skill[2], skill[3]
> etc... within your form.)
Yes that makes sense.
> You can just as easily store the arrays in your
($i+1).'a']);
if (!empty($HTTP_SESSION_VARS['f41'.($i+1).'a'])){
$_SESSION('skil', $_SESSION['f41'.($i+1).'a']);
$_SESSION('yrs', $_SESSION['f41'.($i+1).'b']);
I had that suspicion that I was only calling it for
the last query. Thank you for confirming and for the
code!
Much appreciated.
Stuart
--- Graham Cossey <[EMAIL PROTECTED]> wrote:
> Stuart, you are calling your rollback function only
> if $result is false.
>
> This check
until I have a better understanding of
PHP plain but I think it's worth looking into . I've
also considered Adodb with "smart transactions".
Stuart
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user input into form, my validations will
be in the form.
I've also thought about checking for effected rows and
then if == 0 , stopping the transaction, but that
seems redundant to what I believe is the way mysql
transactions should work.
Stuart
--- Martín Marqués <[EMAIL PROTECTED
My statements are all working but I'm not sure if
things are set up correctly. I say this because at
one point the first $query failed, yet the rest of
inserts wre committed. Now I believe I need to set
autocommit to 0 , yet the query failed due to a syntax
error. Hence 0 records effected wouldn'
You also
> need to have the database function to insert into
> the database.
> Assuming it MySQL:
> ...
> foreach(...) {
> $query = "INSERT INTO ...";
> mysql_query($query);
> }
>
> On Oct 15, 2004, at 4:40 PM, Stuart Felenstein
> wrot
Actually it did just loop. I need to test again.
The insert statement is the the one $query =
So it's after yes, but contained in the braces, like
you diagram below.
Stuart
--- "Matt M." <[EMAIL PROTECTED]> wrote:
> where is your insert statement? I am guessing
Yep, I had found it shortly before.
Only it's not looping. It is taking last value only.
Stuart
--- "Matt M." <[EMAIL PROTECTED]> wrote:
> if ( is_array( $_SESSION['l_industry'] ) ) {
> foreach ( $_SESSION['l_industry'] as $p ) {
>
Where would that go?
Stuart
--- "Matt M." <[EMAIL PROTECTED]> wrote:
> > if ( is_array( $_SESSION['l_industry'] ) ) {
> > foreach ( $_SESSION['l_industry'] as $p )
> {
> > $query = "INSERT INTO Profiles_Industries
> (Profi
#x27;l_industry'] ) ) {
foreach ( $_SESSION['l_industry'] as $p ) {
$query = "INSERT INTO Profiles_Industries (ProfileID,
IndID)
VALUES ($LID, $p)";
}
Stuart
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hoping for suggestions.
Thank you
Stuart
--- John Holmes <[EMAIL PROTECTED]> wrote:
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John,
Big thank you! for your help. I had been trying out
the mysql_insert_id and was not having luck. It's
working great (with just a few more bumps to get
over).
--- John Holmes <[EMAIL PROTECTED]> wrote:
> Stuart Felenstein wrote:
>
> > But - I want to co
as an
auto-inc column. So I'm thinking then the third
insert will get the LAST_INSERT_ID from table 2 / 2nd
insert.
Perhaps I need to declare it the first time as a value
(app code) or add "where" conditions to all the
subsequent insertions ?
Thank you,
Stuart
--- John Holmes
If you see the code I have the begin , then the $query
follows. With both statements present, only the
second one does the insert. If I // or remove the
second, the first one takes.
Am I missing something here ?
Stuart
Code:
function begin()
{
mysql_query("BEGIN");
}
funct
Yes, my apologies to the list!
Stuart
--- David Robley <[EMAIL PROTECTED]> wrote:
> May I suggest that as well as echoing mysql_error()
> you also echo your
> query; that way you can see _exactly_ what is being
> passed to mysql and you
> can resolve problems like th
$f3j, $f3k,
$f3l)";
Outside of the date I don't see where the error could
be coming from. Fields with quotes are string values.
I have no idea.
Stuart
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_POST['DateAvailable'];
to
$_SESSION['f3k'] = date('Y-m-d',
mktime(0,0,0,substr(3,5,$_POST['newdate']),
substr(0,2,$_POST['newdate']),
substr(6,10,$_POST['newdate'])));
I now tried to pass 'newdate' into
Yes, actually my apologies to everyone. I figured out
the error.
So , yep, I'm down to a problem with the date.
The column is set to date. I'll go ahead and add the
quotes.
Stuart
--- [EMAIL PROTECTED] wrote:
> Stuart,
>
> The date has forward slashes. These are not
&g
s
//needed though it doesn't make a diff
begin(); // transaction begins
$result = mysql_query($query);
--- Stuart Felenstein <[EMAIL PROTECTED]> wrote:
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Quote as in "string" or quote as in 'string' ?
Those two confuse me.
Stuart
--- [EMAIL PROTECTED] wrote:
> If any of the variables used to insert data are
> strings ($f1a, $f2a,
> etc...), you'll need to have quotes around them.
>
> dave
>
>
>
to use near 'id #2).
I think this means the second ID column in the table?
Stuart
--- Graham Cossey <[EMAIL PROTECTED]> wrote:
> Stuart, you need to define $link if you're going to
> use it ;)
>
> >
> > Not much luck here on placing the
> mysql_error($link
Not much luck here on placing the mysql_error($link);
I know the server and database is reachable. So I
imagine the error is happening in the query. I've
moved the $link around with no luck.
Stuart
Revised code below:
--- Graham Cossey <[EMAIL PROTECTED]> wrote:
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First time setting something like this up. So probably
making some major mistakes.
Anyway I get this message : "mysql_error(Resource id
#2)"
I know it's pointing me to something but not sure what
.
My suspicion since I'm driving blind :) is that I'm
attempting an insert using invalid or incorrect
/
user input exists. If it didn't then fail before
start. But my main concern is if after this first
committ and errors occur, is rollback to late on the
MainTable ?
Stuart
--- Bastien Koert <[EMAIL PROTECTED]> wrote:
> If you are usiing the INNOdb table type/engine in
> the
Are there any tutorials , good books that go into this
type of depth ? Is it really simple and Im just scared
? :)
I'm open to listening ,
Thank you ,
Stuart
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I apologize, fixed this problem a short while ago. I
need to move the post statement a page ahead. Now all
is working fine.
Thank you ,
Stuart
--- [EMAIL PROTECTED] wrote:
> Have you assigned the values in the
> $_SESSION['l_industry'] array to those
> specific local var
7;m guessing that for
whatever reason, insert into say the 3rd table failed,
it's going to take a decent amount of code to delete
the records from the first 2 tables ?
Basically I'm open to any ideas on this, while I
search out the manual.
Thank you
Stuart
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;
echo $l_industry['2']."";
echo $l_industry['3']."";
echo $l_industry['4']."";
echo $l_industry['5']."";
Thank you,
Stuart
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Jason, thank you for all the help today!
It's all working now.
However, warning: I maybe back when I try to slam it
all into the database.
Stuart
--- Jason Wong <[EMAIL PROTECTED]> wrote:
> On Monday 11 October 2004 19:42, Stuart Felenstein
> wrote:
> > I think I fou
I think I found the correct way. By registering the
session variable in the "next" page is how they take.
Form Page 1 -
collect user input
Form Page 2 -
$_SESSION['name'] = $POST['myane'];
This sound right?
Stuart
--- Stuart Felenstein <[EMAIL PROTECTED]>
;"> or is
that where my mistake is happening ?
MyName is the value not the variable
so I think this is the right way to register the
variable: $_SESSION['name'] = $_POST['myname'];
Maybe I leave the value blank and rely on the field
name ?
Stuart
>
> --
> J
= 'something'; // to register
> a session variable
Alright , I guess the light isn't shining through
here. 'Something' is setting the variable to something
the user can change with the form input ?
Stuart
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et the funtion) to see if $myname is a registered
session value and it returns 1 (true), so what gives ?
Thank you
Stuart
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oveFirst();
?>
So the php is doing the feed of the dynamic table, but
I have no idea where to set the session variable.
It's not an array, but does it get treated like one ?
Stuart
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K ..my problem seems to be combining echo on the menu
values with the print array. If I echo $array[0];
that seems to work fine !?
Stuart
--- Stuart Felenstein <[EMAIL PROTECTED]> wrote:
> Back again , sorry :)
>
> I had my form set up with 7 multi selects , on the
>
Back again , sorry :)
I had my form set up with 7 multi selects , on the
return page, all 7 arrays were returned correctly.
Now that I've changed back 5 to regular menu selects
(1 selection), the 2 arrays left won't return the
values. The menus work fine.
Here is my code:
Page 1:
Page 2
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