Title: Re: [python-win32] findwindow by its class name
If all
else fails, you could create a win32gui based hidden window with a
classname of your choice. pywin32's win32gui_taskbar.py does exactly
this. You would probably need to create this window in its own thread
running a win32gui mes
Title: Re: [python-win32] findwindow by its class name
Thanks,
Actually, app A is a commercial
engine, which written by VC++, but we can't change it at all.
app B is our application, which written by
wxPython, If we can't find a way to get the
classname of app B, it's no way for app A
Hi Le Dahut,
I use the following code for prgrams built with py2exe:
import sys
import os
print os.path.dirname(sys.executable)
This may work in your situation as well.
Regards,
Andre
http://www.burgaud.com/
On 10/21/05, le dahut <[EMAIL PROTECTED]> wrote:
In fact I build an SFX archive wit
At Friday 21/10/2005 16:26, you wrote:
>Thanks a lot! Yes, GetHandle() can return 'wxWindowClassNR', which is
>nice,
>but all wxPython apps return wxWindowClassNR as well, so when I Post
>Message, it goes to itself.
Application A can broadcast a private known message (using
RegisterWindowMessage
Thanks a lot! Yes, GetHandle() can return 'wxWindowClassNR', which is
nice,
but all wxPython apps return wxWindowClassNR as well, so when I Post
Message, it goes to itself.
James
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
Paul Moore
Sent: Friday, Oc
On 10/21/05, Steve Holden <[EMAIL PROTECTED]> wrote:
> > Is there any way to know this windows' class name? I need to find it by
[...]
> I'm not saying it can'ty be done (which is a pity for you, because
> that's usually a cue for someone to contradict me) but it's expecting
> quite a lot of win32g
Hi, Tim,
Your idea probably works as well, but I found another way to catch user
defined message. Thanks a lot!
For the handler of the second app, win32gui.FindWindow can do this job,
then win32gui.PostMessage. But for FindWindow, I can only find the
specific window by its title, not by its regi
On Thu, 20 Oct 2005 16:26:35 -0400, "James Hu" <[EMAIL PROTECTED]>
>There are 2 wxPython application, A and B and need to exchange msg.
>Sending WM_CLOSE, wxEVT_MOUSEWHEEL to B is OK, and sending user message
>like 1225 from A to B is also OK.
>
>But B didn't catch this message, note, B is runnin
James Hu wrote:
> Hi,
>
> For the simple code:
>
> from wxPython.wx import *
>
> class MyApp(wxApp):
> def OnInit(self):
> frame = wxFrame(NULL, -1, "Hello App")
> frame.Show(true)
> self.SetTopWindow(frame)
> return true
>
> app = MyApp(0)
> app.MainLoop()
Hi,
For the simple code:
from wxPython.wx import *
class MyApp(wxApp):
def OnInit(self):
frame = wxFrame(NULL, -1, "Hello App")
frame.Show(true)
self.SetTopWindow(frame)
return true
app = MyApp(0)
app.MainLoop()
Is there any way to know this windows' class
In fact I build an SFX archive with winrar where I specify a program to
launch once extraction has ended. The program is launched but don't find
it's sub-directory.
If I go to the extracted archive directory an dlbe-clic on "install.exe"
all runs fine, but whit winrar's "Run after extraction" optio
[le dahut]
> I try to get the program's directory, the one where the .exe (or .py)
is.
>From within Python, sys.argv[0] usually gives you the running
program (not sure what it does with py2exe etc.). So something
like (untested):
import os, sys
print os.path.dirname (sys.argv[0])
> With os.
hi
I try to get the program's directory, the one where the .exe (or .py)
is.
With os.getcwd() I get the directory from where the program is launched
not his directory. The program has to copy some files and thus I get an
error like "XX no such file or directory" (the DOS box closed to
quickly
[Jim McCoy]
> The only warning I would add here is that you should be aware of the
fact that your watcher
> thread will block waiting for a change to occur in the directory; you
cannot cancel the
> blocked ReadDirectoryChangesW call using the standard pywin32
bindings.
If it causes a problem i
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