Gabor Grothendieck ggrothendieck at gmail.com writes:
Microsoft Word's graphics editor can edit R graphics saved in
metafile format, wmf. That includes x axis labels, etc.
In theory, yes, in practice: not really. Vertical texts are horizontal after
editing, and clipped points may
Hi there,
I would like to design a graphical user interface to provide the functionality
of my R-scripts to other users (not knowing anything about R...)
Can anybody give me some hints which possibilities I have (advantages /
disadvantages)?
What do you use to build applications?
Ciao,
Antje
On Tue, 5 Aug 2008, Dieter Menne wrote:
Gabor Grothendieck ggrothendieck at gmail.com writes:
Microsoft Word's graphics editor can edit R graphics saved in
metafile format, wmf. That includes x axis labels, etc.
In theory, yes, in practice: not really. Vertical texts are horizontal after
The 'final model' returned by stepAIC is just a model fit, so you do this
the same way as any fit. I'll assume you want to know for lm() fits, but
this is fairly general.
library(MASS)
example(stepAIC)
formula(quine.stp)
attr(terms(quine.stp), term.labels)
(You are making a habit of asking
There is quite a few discussions on this in the list archives,
particularly on the R-SIG-GUI mailing list.
It would help to know something about your application...
* how complex is it?
* how are the results to be presented?
* is it intended to be used be only a few people in one location, or
Hi all,
I have the following data in which I want to parse and
store them in a list
__DATA__
print(comp.ll)
[1] \tGene 11340 211952_at RANBP5 k= 1 LL= -970.692
[2] \tGene 11340 211952_at RANBP5 k= 2 LL= -965.35
[3] \tGene 11340 211952_at RANBP5 k= 3 LL= -963.669
[4]
Hi Felix,
thanks a lot for the hint with the mailing list. I was not aware of its
existence... I'll give it a closer look.
To answer your questions:
- Complexity: I would prefer to be able to design on each level of complexity.
- Results: TextFiles and Graphs, ... also open
- Usage: Only for a
On Tue, 5 Aug 2008, Antje wrote:
Hi there,
I would like to design a graphical user interface to provide the
functionality of my R-scripts to other users (not knowing anything about
R...)
Can anybody give me some hints which possibilities I have (advantages /
disadvantages)?
Can you first
Prof Brian Ripley ripley at stats.ox.ac.uk writes:
On Tue, 5 Aug 2008, Dieter Menne wrote:
Gabor Grothendieck ggrothendieck at gmail.com writes:
Microsoft Word's graphics editor can edit R graphics saved in
metafile format, wmf. That includes x axis labels, etc.
In theory,
I really like the ease of use with the boxplot command in R. I would
rather have a boxplot that shows the average value and the standard
deviation then the median value and the quartiles.
Is there a way to do this?
Chad Junkermeier, Graduate Student
Dept. of Physics
West Virginia
Hi Benjamin,
Creating 0 correlations is easier and always possible, but creating arbitrary
correlations can be done as well (when possible - see below).
Suppose that x1,x2,x3,x4 have mean 0 and suppose that the desired correlations
are r = (r1,r2,r3,r4). Let A be an orthogonal 4x4 matrix such
Yep, sorry I forgot it :wistle:
so the data are data frames with dim(8,1000) called DATA.ValX and DATA.ValY
(part of the files attached as a xls file)
http://www.nabble.com/file/p18826528/ValX.xls ValX.xls
http://www.nabble.com/file/p18826528/ValY.xls ValY.xls
When I call the function Test
Use bxp() and feed it with data that is not from boxplot.stats().
Therefore you might want to invent some alternative function along the
lines of boxplot.stats().
Uwe Ligges
Chad Junkermeier wrote:
I really like the ease of use with the boxplot command in R. I would
rather have a boxplot
Does this get you close to what you want:
x - read.table(textConnection(Gene 11340 211952_at RANBP5 k= 1 LL=
-970.692
+ Gene 11340 211952_at RANBP5 k= 2 LL= -965.35
+ Gene 11340 211952_at RANBP5 k= 3 LL= -963.669
+ Gene 12682 213301_x_at TRIM24 k= 1 LL= -948.527
+ Gene 12682
Thanks Jim,
But how can I modify this line of yours
y - lapply(split(x, x$V3), [[, 8)
to suit my 'comp.ll'
I tried this but fail:
p - \tGene 11340 211952_at RANBP5 k= 1 LL= -970.692
y - lapply(split(p, p[3]), [[, 8)
y
list()
- Gundala Viswanath
Jakarta - Indonesia
On Tue, Aug
Dear,
We are trying to determine the (one-sided) CI for the coefficient of
variation in a small sample (say n = 10), with mean 100 and standard
deviation 21.
It appears though that the R-function ci.cv() and our simulation do not
agree.
The R-code:
library(MBESS)
n = 10
ci.cv(mean = 100, sd =
I have a data vector x. When I try
qqline(x)
I get the following error:
Error in int_abline(a = a, b = b, h = h, v = v, untf = untf, ...) :
plot.new has not been called yet
And a blank plot appears.
Can anybody help? What am I doing wrong?
Thanks,
Scotty
boxplot itself is hardwired to produce the boxplot.stats list, and that
is not easy to change.
To get a different set of stats, you would need to do things in rwo
stages:
i) create a boxplot object of the type returned by boxplot, but using
your own stats
ii) call bxp on that object.
That's kind
I think that you need:
p - scan(textConnection(p), what = )
On Tue, Aug 5, 2008 at 7:41 AM, Gundala Viswanath [EMAIL PROTECTED] wrote:
Thanks Jim,
But how can I modify this line of yours
y - lapply(split(x, x$V3), [[, 8)
to suit my 'comp.ll'
I tried this but fail:
p - \tGene 11340
Try,
expression(Delta)
On Tue, Aug 5, 2008 at 8:14 AM, michael watson (IAH-C)
[EMAIL PROTECTED] wrote:
Hi
I am running an R script that creates 100s of graphs, and I need to use
the greek CAPITAL letter delta in the mtext() function.
I got as far as expression(delta) but this gives me the
If I understand you need this:
plot(rnorm(10), main = bquote(Delta == .(delt)))
On Tue, Aug 5, 2008 at 8:20 AM, michael watson (IAH-C)
[EMAIL PROTECTED] wrote:
Excellent! I even tried DELTA but not Delta
Now, how do I go about pasting that with some text that I have in various
other
Where delt should be your variable.
On Tue, Aug 5, 2008 at 8:23 AM, Henrique Dallazuanna [EMAIL PROTECTED] wrote:
If I understand you need this:
plot(rnorm(10), main = bquote(Delta == .(delt)))
On Tue, Aug 5, 2008 at 8:20 AM, michael watson (IAH-C)
[EMAIL PROTECTED] wrote:
Excellent! I
Dear Deepayan,
thanks for the hint with the wrapper in latticeExtra, it is very convenient
and the plot looks fine. Just from intuition i think that it would look
even nicer if the strips at the left side appear at the right site of the
plot, as it is implemented in ggplot2.
Is there a way to
Hi
qqline does not do the plot. It adds a line to an existing plot.
So you have to do something else first, like:
qqnorm(x)
qqline(x)
JS
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Scotty Nelson
Sent: 05 August 2008 09:58
To:
tiu == tolga i uzuner [EMAIL PROTECTED]
on Mon, 4 Aug 2008 20:04:15 +0100 writes:
tiu Dear R Users, Can anyone point me to a package for R
tiu vrsion 2.7.1 which implements some Hurst exponent
tiu estimation methods ?
o fracdiff -- has been the first package to do so,
o
Please read the R for Windows FAQs.
Uwe Ligges
zack holden wrote:
Dear list,
After searching many old posts, I can't find the solution to a simple problem.
can someone tell me how to create a character string with multiple backslashes, as in:
file_dir - c(C:\files\data\)
I need to
Hi
I am running an R script that creates 100s of graphs, and I need to use
the greek CAPITAL letter delta in the mtext() function.
I got as far as expression(delta) but this gives me the lowercase
version.
Can anyone help? I'm using R 2.7 on Windows XP
Mick
Head of Informatics
Institute for
Dear R users,
I have run into a very unexpected problem and I was hoping someone could
explain it to me.
I have a 650 000 by 12 matrix and I want to perform a rolling regression on
it, width 36 or 48, using the package performanceAnalytics.
ie:
You need to read in the line with read.table to parse the string. The
solution assumes a dataframe .
Sent from my iPhone
On Aug 5, 2008, at 7:16, Henrique Dallazuanna [EMAIL PROTECTED]
wrote:
I think that you need:
p - scan(textConnection(p), what = )
On Tue, Aug 5, 2008 at 7:41 AM,
If you use loess instead of lowess, you can get standard errors and
hence approximate confidence bands by using predict.
Example:
plot(cars)
plx-predict(loess(dist~speed, data=cars), se=T)
lines(cars$speed,plx$fit)
lines(cars$speed,plx$fit+2*plx$s, lty=2) #rough ready CI
On Tue, 5 Aug 2008, michael watson (IAH-C) wrote:
Excellent! I even tried DELTA but not Delta
?plotmath says
'Alpha' - 'Omega' uppercase Greek symbols
How could that be made clearer?
(Note it carefully says Greek *symbols* not *character*: they are not the
same
Katrien Baert katrien.baert at gmail.com writes:
Dear,
We are trying to determine the (one-sided) CI for the coefficient of
variation in a small sample (say n = 10), with mean 100 and standard
deviation 21.
It appears though that the R-function ci.cv() and our simulation do not
agree.
On Tue, Aug 5, 2008 at 3:16 AM, Dieter Menne
[EMAIL PROTECTED] wrote:
Prof Brian Ripley ripley at stats.ox.ac.uk writes:
On Tue, 5 Aug 2008, Dieter Menne wrote:
Gabor Grothendieck ggrothendieck at gmail.com writes:
Microsoft Word's graphics editor can edit R graphics saved in
I'm trying to use fine axis controls in lattice for each panel.
Specifically, within each panel, I want to set the limits for x and y
equal to each other since it is paired data (using the max value of the
two). Of course, I have no problems setting the limits for the entire
plot but I am having
If interested in the very very good looking Graphics , try silverlight
graphics using this open source package-
http://www.visifire.com/silverlight_chart_designer.php
On Tue, Aug 5, 2008 at 6:00 PM, Gabor Grothendieck
[EMAIL PROTECTED]wrote:
On Tue, Aug 5, 2008 at 3:16 AM, Dieter Menne
Please don't cross-post. I've replied in R-devel.
On 8/5/2008 8:47 AM, subramanian R wrote:
Hi All,
I have a few queries regarding Random Number generation in R.
according to the help(Random.User) i defined my own functions for
user_unif_rand and user_norm_rand (uniform
Hi,
How can I extract the names of the following
list:
str(y)
List of 815
$ 200052_s_at : num [1:5] -1067 -1064 -1063 -1062 -1059
$ 200071_at: num [1:5] -960 -954 -954 -949 -975
$ 200084_at: num [1:5] -1136 -1133 -1128 -1129 -1126
...
Thus in the
Hi All,
i have a dataset that i want to dynamically inspect for the number of
variables that start with Exposure_ and then for these count the entries
across each case i.e
ID Exposure_1 Exposure_2 Exposure_3
1y yy
2y y
On Tue, 5 Aug 2008, Prof Brian Ripley wrote:
This relates to the order of things being done. See ?Startup.
Note that the default packages are not loaded until after the
Rprofile file has been run, and postscript() is in package
grDevices, not in graphics. Using grDevices::postscript will
Another option is to modify panel.bpplot in the Hmisc package and specify
library(lattice)
bwplot(..., panel=mypanel)
Note that panel.bpplot will show the mean. It shows more quantiles than
a standard box plot so you get more than a 3-number summary.
If you show the mean and standard
names(y)
On Tue, Aug 5, 2008 at 10:14 AM, Gundala Viswanath [EMAIL PROTECTED] wrote:
Hi,
How can I extract the names of the following
list:
str(y)
List of 815
$ 200052_s_at : num [1:5] -1067 -1064 -1063 -1062 -1059
$ 200071_at: num [1:5] -960 -954 -954 -949
Hi,
I try to put an arrow to a filled.contour plot. I make this:
filled.contour(volcano, color = terrain.colors,key.axes=F)
arrows(0.95,0,0.95,1,lwd=2)
This work, but the problem is that I find the coordinates at random try, for
other graphic with other scale is other fight with coordinates.
Hi David,
Specifically, within each panel, I want to set the limits for x and y
equal to each other since it is paired data (using the max value of the
two).
In addition to the code Chuck Cleland sent you, you may want to square
things up by adding the argument: aspect = iso before the
I saw your post on 7/29, and I have not seen a reply, so I will
attempt a response to the question at the start of your email:
obtain the smallest value of 'n' (sample size)
satisfying both inequalities:
(1-alpha) = pbinom(c, n, p1) pbinom(c, n, p2) = beta,
where alpha, p1,
Try this:
data.frame(ID = x$ID,
Max_Exposure = max(rowSums(x[,-1] == y)),
Unique_Exposure = rowSums(x[,-1] == y))
On Tue, Aug 5, 2008 at 10:21 AM, Michael Pearmain [EMAIL PROTECTED] wrote:
Hi All,
i have a dataset that i want to dynamically inspect for
I am not sure where the Max comes from, but this might be a start for you:
x - read.table(textConnection(ID Exposure_1 Exposure_2 Exposure_3
+ 1y yy
+ 2y y-
+ 3y - -),
Hi all,
I have the following named list:
print(y)
$`200052_s_at`
[1] -1066.975 -1063.893 -1062.815 -1062.121 -1059.004
$`200071_at`
[1] -959.823 -953.980 -953.886 -948.781 -974.890
$`200084_at`
[1] -1135.804 -1132.863 -1128.197 -1128.633 -1125.890
What I want to do is to iterate this name
It looks like x is not a numeric. Try
str(testground)
to see what the data set looks like.
--- On Mon, 8/4/08, Alessandro [EMAIL PROTECTED] wrote:
From: Alessandro [EMAIL PROTECTED]
Subject: [R] R: log and Log Histogram
To: 'David Scott' [EMAIL PROTECTED]
Cc: r-help@r-project.org
Don't worry about the warning. R is just telling you that you're appending
something :) I'm not sure why it does that. Perhaps just to make sure that you
know that you reallly want to append ?
--- On Mon, 8/4/08, pacomet [EMAIL PROTECTED] wrote:
From: pacomet [EMAIL PROTECTED]
Subject:
'lapply' is your friend:
lapply(y, function(.element) {...process each element of the list})
y - list(a=1:10, b=letters, c=LETTERS)
invisible(lapply(y, function(.ele) {print(.ele); cat(--\n)}))
[1] 1 2 3 4 5 6 7 8 9 10
--
[1] a b c d e f g h i j k l m n o p
q r s t u v w
Hi R users,
I am trying to create a matrix, but R has problem with the size of dim,
wondering if there is anything that I can do?
a - diag(147456)
Error in array(0, c(n, p)) : 'dim' specifies too large an array
Thanks for your help
Rostam
[[alternative HTML version deleted]]
Thanks for the help guys,
i think i needed to be a bit more explicit however (sorry)
There are lots of variables between each exposure and the values are nominal
with upto 6 values..
And to add to the problem the datasets i deal with range from anything upto
5G.
My guess is that the melt
Are you aware that that matrix will have 147456^2 elements each of
size 8 bytes (double) resulting in R trying to allocate
(147456^2)*8/1024^3 = 162 GB of RAM?
If you are aware of this and still trying to allocate a large matrix,
it is unfortunately too large due to technical limitations in R.
On Tue, 5 Aug 2008, John Kane wrote:
Don't worry about the warning. R is just telling you that you're
appending something :) I'm not sure why it does that. Perhaps just to
make sure that you know that you reallly want to append ?
Correct: such a file is close to unreadable (e.g. not by
Just a quick follow up to Spencer's post, you might want to look at the
AcceptanceSampling package on CRAN:
http://cran.r-project.org/web/packages/AcceptanceSampling/index.html
HTH,
Marc Schwartz
on 08/05/2008 09:00 AM Spencer Graves wrote:
I saw your post on 7/29, and I have not seen
On 8/5/08, Henning Wildhagen [EMAIL PROTECTED] wrote:
Dear Deepayan,
thanks for the hint with the wrapper in latticeExtra, it is very convenient
and the plot looks fine. Just from intuition i think that it would look even
nicer if the strips at the left side appear at the right site of the
Hi All,
I've hit a problem using nls. I think it may be a restriction in the
applicability of nls and I may have found a fix, but I've been wrong before.
This example is simplified to the essentials. My real application is much
more complicated.
Take a function of matrix 'x' with additional
On 8/5/08, Chuck Cleland [EMAIL PROTECTED] wrote:
On 8/5/2008 8:37 AM, Chosid, David (FWE) wrote:
I'm trying to use fine axis controls in lattice for each panel.
Specifically, within each panel, I want to set the limits for x and y
equal to each other since it is paired data (using the max
Hi Ramya,
Perhaps
pdf(C:/100plots.pdf)
for(i in 1:100) plot(rnorm(10), type='b', main='My 100 plots')
dev.off()
HTH,
Jorge
On Tue, Aug 5, 2008 at 12:41 PM, Rajasekaramya [EMAIL PROTECTED]wrote:
hi there,
Is there any function to append the pdf file.
I want to write in a pdf file some
Just put all the commands within the pdf()- dev.off() ?
--- On Tue, 8/5/08, Rajasekaramya [EMAIL PROTECTED] wrote:
From: Rajasekaramya [EMAIL PROTECTED]
Subject: [R] PDF append help
To: r-help@r-project.org
Received: Tuesday, August 5, 2008, 12:41 PM
hi there,
Is there any function to
Hi, just don't turn if off immediately, see example below:
Cheers,
Gary
# example
pdf(file=/home/user/tmp/moreplots.pdf)
for (i in 1:5) plot(rnorm(100))
dev.off()
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Rajasekaramya
Sent: Tuesday, August 05,
On Tue, 5 Aug 2008, Rajasekaramya wrote:
Is there any function to append the pdf file.
I want to write in a pdf file some 100 plots(in one single pdf containing
100 plots) while all the plot are created using a for loop.
I can create 100 pdf one for each for each plot using a for loop but i
Or, maybe I could just draw it with lines()
-Original Message-
From: [EMAIL PROTECTED] on behalf of michael watson (IAH-C)
Sent: Tue 05/08/2008 1:37 PM
To: Prof Brian Ripley
Cc: r-help@r-project.org
Subject: Re: [R] Greek characters in plots
OK, I am definitely struggling here.
Try bquote / substitute as has been mentioned:
tag - A)
suffix - stbA::cat
plot(1, main = bquote(.(tag) ~ Delta * .(suffix
2008/8/5 michael watson (IAH-C) [EMAIL PROTECTED]:
OK, I am definitely struggling here.
The text I am trying to plot isn't a mathematical expression, it's:
A)
Dear all,
for those of you who have too much time (nobody) and those who enjoy
participating in programming contests (maybe some of you), I found an
interesting site linked from reddit's programming section:
http://www.reddit.com/r/programming/
The actual contest is at the site:
This is still too wide-open a question. :) However there is any number of
packages that deal with binary data. Again it depends on what you want to do
with it. If you just want some scoring of binary data you can do this with
tables ( ?tables). From there you can do about anything you want
Hi All,
I am a PhD student in forestry science and I am working with LiDAR data set
(huge data set). I am a brand-new in R and geostatistic (SORRY, my
background its in forestry) but I wish improve my skill for improve myself.
I wish to develop a methodology to processing a large data-set
I have a set of data that is basically sales figures for a given year. It has
columns for Yeaqr, Day Of Year, Sku, SubCatetory, and Category. The first few
lines of data look like:
Year DayOfYearSku Quantity CatId Category SubCategory
1 2007 1 1000911 10862
I think that you have to be a little more explicit with a description
of your data. I am not clear as to what this means:
There are lots of variables between each exposure and the values are nominal
with upto 6 values..
Can you provide a more complete description. How many columns of
Hello,
I apologize in advance as this example seems really elementary. Below I
have created a simple scatterplot with lines. I would like to label
each line with the name of the village, instead of using a legend. Can
someone please let me know how to do it.
Thanks in advance -- John
Hi,
I have a data set collected from 10 measurements (response variables)
on two groups (healthy and patient) of subjects performing 4 different
tasks. In other words there are two fixed factors (group and task),
and 10 response variables. I could analyze the data with aov() or
lme() in package
On Tue, Aug 5, 2008 at 11:15 AM, John Poulsen [EMAIL PROTECTED] wrote:
Hello,
I apologize in advance as this example seems really elementary. Below I
have created a simple scatterplot with lines. I would like to label each
line with the name of the village, instead of using a legend. Can
Hi Brian
Thanks again for the advice, it is appreciated.
I had come across U0394 code through the character map, but I get:
\u0394
Error: invalid \u sequence
So when I execute your code, I get:
a - A)
b - stbA::cat
paste(a, \u0394, b)
Error: invalid \u sequence
This is on both
Excellent, many thanks, that works a treat!
But I don't understand how...
bquote(.(tag) ~ Delta * .(suffix))
A) ~ Delta * stbA::cat
Yet when I use:
plot(1, main = bquote(.(tag) ~ Delta * .(suffix)))
It works fine in the plot.
Must be magic ;)
-Original Message-
From: Gabor
Deepayan,
Thanks for your help, works great!
Cheers -- John
Deepayan Sarkar wrote:
On Tue, Aug 5, 2008 at 11:15 AM, John Poulsen [EMAIL PROTECTED] wrote:
Hello,
I apologize in advance as this example seems really elementary. Below I
have created a simple scatterplot with lines. I would
My notebook is:
Hp Pavilion dv6700 notebook PC
Intel() Core 2 Duo CPU T9300 °2.50gHz 2,50GHz
RAM: 4.00 GB
OS: 32bit
Windows (TERRIBLE!) VISTA
Da: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Per conto di
Matt Oliver
Inviato: martedì 5 agosto 2008 12.02
A: Alessandro
Cc:
You need R = 2.7 on Windows, but it works for me on both XP and Vista.
As the posting guide says, we assume that you have an up-to-date R.
On Tue, 5 Aug 2008, michael watson (IAH-C) wrote:
Hi Brian
Thanks again for the advice, it is appreciated.
I had come across U0394 code through the
Gang
If you want to analyze all variables simultaneously and account for some
correlational structure among the different response variables, then the best
strategy is to pre-whiten the data and then use lmer. The methods for
pre-whitening are described in detail in Pinhiero and Bates in the
I found this link to resolve: '3 GB Switch Windows Vista'
http://usa.autodesk.com/adsk/servlet/ps/item?siteID=123112
http://usa.autodesk.com/adsk/servlet/ps/item?siteID=123112id=9583842linkID=9242018
id=9583842linkID=9242018
Da: Adam Terando [mailto:[EMAIL PROTECTED]
Inviato:
The following is a summary of what I have gathered about hypothesis
testing with mixed-effects models.
I would appreciate it if someone can clarify or correct this, or make
any further comments on the topic.
To test a single fixed effect:
1) Likelihood-ratio test (anova) using ML (not REML) is
Hi Jim,
Thanks very much for your reply and suggestions. Although the statement
Preg[,k]-coef(lm(tt~sel_col)) is applying lm() between the same vectors,
the contents of one of the vectors (sel_col) should be changing with each
cycle through the outer loop. My mistake is that I didn't specify
R/Splus Advanced Programming Course in Seattle: August 14-15
Payment due after the class! Email Sue Turner: [EMAIL PROTECTED]
Cheers,
Elvis Miller, PhD
Manager Training.
XLSolutions Corporation
206 686 1578
www.xlsolutions-corp.com
[EMAIL PROTECTED]
I just wanted to let everyone know the good news, that I was approved to use
R at work by legal and compliance. Now to begin learning here.
Speaking of, is there anyone who is an expert at R and would be willing to
have our company pay them as a consultant to come to my place of work (in
On Tue, Aug 5, 2008 at 1:53 AM, Karin Lagesen [EMAIL PROTECTED] wrote:
I have a problem regarding the colors assigned to the lines in the key
to an xy plot. I specify the plot like this:
xyplot(numbers~sqrt(breaks)|moltype+disttype, groups = type, data = alldata,
layout = c(3,2), type
you can try
memory.limit(size=4000)
only if you have 4GB of memory on the system
This is not guaranteed to solve your problem though
With big datasets like lidar, you are much better off getting access to a
64bit system with a ton of RAM (64GB).
Cheers
Matt
On Tue, Aug 5, 2008 at 1:47 PM,
Hello,
I have been working with various probability distributions in R, and it
seems the gamma distribution is inaccurate for some inputs.
For example, qgamma(1e-100, 5e-101, lower.tail=FALSE) gives: 1.0. However,
it seems this is incorrect; I think the correct answer should be
On Tue, Aug 5, 2008 at 11:59 AM, [EMAIL PROTECTED] wrote:
I have a set of data that is basically sales figures for a given year. It has
columns for Yeaqr, Day Of Year, Sku, SubCatetory, and Category. The first few
lines of data look like:
Year DayOfYearSku Quantity CatId
do you want just a date time stamp or do you want other things. There
are many ways to skin this cat, but we are going to need more
information... as a first start try looking at the zoo package.
stephen
On Tue, Aug 5, 2008 at 5:47 PM, Gareth Campbell [EMAIL PROTECTED] wrote:
Hello,
I
For the first part: Create a two-column data frame of which one contains
your data (Y) and the other the time index (time). Then do:
plot(Y~time,type=l) ##lower case L
if you want a least-squares line, run a linear regression of Y on time and
add that line together with lines for the confidence
The zoo package can represent time and plot such time series
using both classic and lattice graphics
There are three vignettes that come with the package that you
can read for more info. Also see ?zoo ?plot.zoo ?xyplot.zoo
Regarding ols see ?lm or the dyn or dynlm packages both of
which work
hi there
Can i write two objects in one file.
one is a list and another is a vector.
The vector here is the names of the list.so can i write
for(i in 1:60) # i have 60 list elements.
{
write.table(names(mylist[[i]],mylist[[i]],filename=test.txt,sep=\t,append=TRUE)
}
my testfile.txt should have
On Tuesday 05 August 2008, Alessandro wrote:
Thank you Dylan
Do you think Kriging method is not valid to processing a large data-set as
LiDAR data?
About RST interpolation and NNI do you know a code in R?
ale
Please reply to the list next time.
I would suggest going over the available
Dear R People:
Is there a predict method for garch methods, please?
I tried the usual predict(d1.garch,n.ahead=3)
but only got values for the original data.
Thanks,
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
I'm making some plots on the same page and would like to include an overall
title instead of individual main titles as they are similar and their x and
y axis labels are sufficient to distinguish them.
Is there a way to assign an overall main to this page of plots?
Mark
--
Mark W. Kimpel MD **
on 08/05/2008 06:05 PM Mark Kimpel wrote:
I'm making some plots on the same page and would like to include an overall
title instead of individual main titles as they are similar and their x and
y axis labels are sufficient to distinguish them.
Is there a way to assign an overall main to this
That doesn't make sense. Which version of Tinn-R are you using?
From Options-Main-Application
do you get a dialog box with a tab R, and within that a tab General?
At the bottom of the General tab there is a button under Rgui. That
should bring up a file selection box. Proceed to the location
Look at this disscussion from two weeks ago:
http://www.nabble.com/adding-the-mean-and-standard-deviation-to-boxplots-td15271398.html
Chad Junkermeier wrote:
I really like the ease of use with the boxplot command in R. I would
rather have a boxplot that shows the average value and the
Thanks!
--
View this message in context:
http://www.nabble.com/qqline-function-doesn%27t-plot-tp18827175p18842548.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Ouch! I had searched the archives and read over ?par and ?plot, but sure
missed the post of today. Thanks, Mark
On Tue, Aug 5, 2008 at 7:27 PM, Marc Schwartz [EMAIL PROTECTED]wrote:
on 08/05/2008 06:05 PM Mark Kimpel wrote:
I'm making some plots on the same page and would like to include an
on 08/05/2008 08:55 PM [EMAIL PROTECTED] wrote:
Hi folks,
Can anyone enlighten me as to why I get the following when I search for
.csv at the end of a string?
grep(\.csv$,Blah.csv,value=TRUE)
[1] Blah.csv
Warning messages:
1: '\.' is an unrecognized escape in a character string
2:
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