You forgot the assign the second time:
assign(paste(a,2,sep=), 4)
does what you want.
Hope this helps a little
Allan.
On 27/02/10 05:13, Joseph Lee wrote:
I created variables automatically like this way
for(i in 1:5){
nam- paste(a,i,sep=)
assign(nam,1:i)
}
and then, i want
On 27-Feb-10 03:52:19, Cardinals_Fan wrote:
Hi, I am a stata user trying to transition to R. Typically I
compute marginal effects plots for (example) probit models by
drawing simulated betas by using the coefficient/standard error
estimates after I run a probit model. I then use these
Hi,
I think I would follow this approach too, using updatelist() from the
reshape package,
updatelist - function (x, y)
{
common - intersect(names(x), names(y))
x[common] - y[common]
x
}
myfunction=function(list1=NULL, list2=NULL, list3=NULL){
list1=updatelist(list(variable1=1,
These functions (rpart, the mvpart wrapper, and summary.rpart) are
fairly complex doing many things.
For contributed packages you'd be best served by contacting the
author/maintainer. I've CC'd Glenn (the maintainer) here.
HTH
G
On Fri, 2010-02-26 at 13:55 +, Wearn, Oliver wrote:
Dear
On Fri, 2010-02-26 at 10:43 -0800, David Reinke wrote:
The length will remain the same no matter what expression appears in
the subscript.
No it won't! x == 1 evaluates to logical and when used to *subset* x, it
*will* return the required answer. As observed with this example:
set.seed(1)
x
Or use modifyList which is in the core of R.
On Sat, Feb 27, 2010 at 5:22 AM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Hi,
I think I would follow this approach too, using updatelist() from the
reshape package,
updatelist - function (x, y)
{
common - intersect(names(x),
Dieter Menne dieter.me...@menne-biomed.de [Fri, Feb 26, 2010 at 08:39:14AM
CET]:
Patrick Burns wrote:
* What were your biggest misconceptions or
stumbling blocks to getting up and running
with R?
(This derives partly from teaching)
[...]
The concept of environment. With
On 2010-02-27 1:38, (Ted Harding) wrote:
On 27-Feb-10 03:52:19, Cardinals_Fan wrote:
Hi, I am a stata user trying to transition to R. Typically I
compute marginal effects plots for (example) probit models by
drawing simulated betas by using the coefficient/standard error
estimates after I
Hullo
I'm trying to read some time series data of meteorological records
that are available on the web (eg http://climate.arm.ac.uk/calibrated/soil/dsoil100_cal_1910-1919.dat)
. I'd like to be able to read in the digital data directly into R.
However, I cannot work out the right function and
Hello,
I have plot in R (which is curve during time series) and it is working well.
i want to add a circle symbol to one place within the plot but i do not know
how to do that?
I used matplot() because i have many data in the plot.
any help please,
cheers
--
View this message in
Try this. First we read the raw lines into R using grep to remove any
lines containing a character that is not a number or space. Then we
look for the year lines and repeat them down V1 using cumsum. Finally
we omit the year lines.
myURL -
points(x, y, pch=1, cex=10)
adjust cex to the size circle you want.
On Sat, Feb 27, 2010 at 4:22 AM, abotaha yaseen0...@gmail.com wrote:
Hello,
I have plot in R (which is curve during time series) and it is working well.
i want to add a circle symbol to one place within the plot but i do
I don't think I am a tyro but neither am I a wizard. This being said R has a
number of aspects that make it difficult.
Error messages that are not helpful
Manual pages that are written in Martin.
Lack of examples on some manual pages
Lack of comments in code
There are other hurdles. The concept
I received zero responses to this post, so I guess this confirms that R is not
the correct target language for this project.
Maybe Octave is better suited...
Thank you again.
- Original Message
From: Jason Rupert jasonkrup...@yahoo.com
To: R-help@r-project.org
Cc: Me
On Sat, Feb 27, 2010 at 11:29 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
Or use modifyList which is in the core of R.
All these solutions appear to be adding on more and more code with
less and less semantics. Result: messy code which is harder to read
and debug.
It seems that the
Hi,
I'm working with randomForest package and i have 2 questions:
1. how can i drop a specific tree from the forest?
2. i'm trying to get the voting of each tree in a prediction datum using the
folowing code
pr-predict(RF,NewData,type=prob,predict.all=TRUE)
my forest has 300 trees and i get
I am very new to R and thus find those examples a bit confusing although I
believe the solution to my problems lies there.
Lets take for example an experiment in which I had two between subject
variables - Strain and treatment, and one within - exposure. all the
variables had 2 levels each.
I
On 2010-02-26 6:55, Wearn, Oliver wrote:
Dear all,
I'm getting an error in one of the stock examples in the 'mvpart' package. I
tried:
require(mvpart)
data(spider)
fit3-
rpart(gdist(spider[,1:12],meth=bray,full=TRUE,sq=TRUE)~water+twigs+reft+herbs+moss+sand,spider,method=dist)
#directly
Point well taken --- grid::gpar() is also a good example; I'll make
use of your suggestion in my future coding.
Best,
baptiste
On 27 February 2010 15:02, Barry Rowlingson
b.rowling...@lancaster.ac.uk wrote:
On Sat, Feb 27, 2010 at 11:29 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
Hello All,
I am trying to get cluster heatmaps using R from Java in my application.
I got the Rserve using which I am able to make TCP/IP connection to R.
I am trying to send a double[][] array (say 5x8 dimensions) to R and convert
it into matrix using as.matrix() function in R. Is it correct to
Thanks for the info -- I'll check it out ASAP.
Regards
Glenn
+++
Glenn De'ath
Principal Research Scientist
Australian Institute of Marine Science
Ph: +61-7-4758-1747; +61-7-4753-4314
In a world without walls and fences, who needs windows and gates.
paste(a,2,sep=) is simply creating a new character a2
Why not just
a2 - 4
?
--- On Sat, 2/27/10, Joseph Lee seokhyun...@gmail.com wrote:
From: Joseph Lee seokhyun...@gmail.com
Subject: [R] somebody help me about this error message...
To: r-help@r-project.org
Received: Saturday, February
Here is another approach (I think this is the simplest):
daylkp - c(SAT=1, SUN=2, MON=3, TUE=4, WED=5, THU=6, FRI=7)
tmp.in - sample( names(daylkp), 25, TRUE )
tmp.out - daylkp[tmp.in]
names(tmp.out) - NULL # optional
hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Would someone be so kind as to explain in English what the ANOVA code
(anova.lm) is doing? I am having a hard time reconciling what the text books
have as a brute force regression and the formula algorithm in 'R'. Specifically
I see:
p - object$rank
if (p 0L) {
p1 - 1L:p
I tried to implement Ista's procedure and would like to provide it as
a working example, with the intention to get feedback from the R
community:
The data contains three variables:
One dependent var: t.total
and two independent vars: group (between: D2C2, C2D2) and present.type
(within: C2, D2).
Dear all,
I am trying to read in big amounts of data with scan. It's only one variable,
numeric values, separated by tabs,.. and it's many of them. So I was thinking
that I could use the skip option and read in 10 values at a time - but skip
doesn't work, probably because I don't have line
On Feb 27, 2010, at 11:24 AM, Balzer Susanne wrote:
Dear all,
I am trying to read in big amounts of data with scan. It's only one
variable, numeric values, separated by tabs,.. and it's many of
them. So I was thinking that I could use the skip option and read in
10 values at a time
On 26/02/2010 3:22 PM, Peter Danenberg wrote:
This seems to be plain text help, right?
It is.
Does the html version give the same result?
Interestingly, the html seems to be whole; but it's less convenient to
access from ESS, though.
Do you know what program generates the plain text; and
On 2010-02-27 8:53, rkevinbur...@charter.net wrote:
Would someone be so kind as to explain in English what the ANOVA code
(anova.lm) is doing? I am having a hard time reconciling what the text books
have as a brute force regression and the formula algorithm in 'R'. Specifically
I see:
Look at the gsubfn package, it gives more options and will probably make what
you are trying to do easier.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org
Mark Leeds pointed out to me that the code wrapped around in the post
so it may not be obvious that the regular expression in the grep is
(i.e. it contains a space):
[^ 0-9.]
On Sat, Feb 27, 2010 at 7:15 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
Try this. First we read the raw
Here it is using strapply in gsubfn. x is the input, followed by the
regular expression which is just New York followed by a parenthesized
string of digits. The parenthesized portion is passed to the
function, as.numeric, and then everything is simplified using c
(otherwise we would get a list as
On 27/02/2010 12:43 AM, xlr82sas wrote:
Hi,
If I do the following
sprintf(%A,pi)
0X1.921FB54442D18
I have this 16 byte character string
hx-400921FB54442D18
This is the exact hex16 representation of PI in
IEEE float that R uses in Intel 32bit(little endian) Windows
SAS uses the same
On Feb 27, 2010, at 11:47 AM, Balzer Susanne wrote:
Hei David,
Thanks for your quick response, but unfortunately n and nmax alone
don't do the job. If I want to read items no. 11 to 20, the
n=10 option will work, but skip=10 (to NOT read the first
10 items) won't.
One last question. I'm trying to use the rnorm() function to draw a
distribution for my coefficient estimates. Let's say I have a model y* = a
+ b1x1. I have the coefficient estimate for b1 stored as b1 and the
standard error estimate for b1 stored as s1. I run rnorm function as
a -
Hi David,
That looks magic and works - if and only if you keep the file connection open.
Cool, that was the hint I needed!
scan(myfile.txt, nmax=10)
will always give you the first 10 items, obviously.
However, I did the workaround with tr under unix now and changed all the tabs
into line
David, Susanne,
There may be a misunderstanding here. As I understand it,
Susanne wants to be able to read the _second_ (and third, etc)
100K values after reading the first 100K, presumably to be
processed separately for reasons I can't imagine. If that is
correct, then I have no solution other
Hi,
I don't think you should split the list for beginners.
On the SAS list we get questions from novices such as secretaries,
janitorial services, human resources and even top executives.
They often approach SAS from a very intuitive standpoint. These questions
often shake the experts
On 2010-02-27 10:57, Cardinals_Fan wrote:
One last question. I'm trying to use the rnorm() function to draw a
distribution for my coefficient estimates. Let's say I have a model y* = a
+ b1x1. I have the coefficient estimate for b1 stored as b1 and the
standard error estimate for b1 stored
Talk about asleep at the switch.
My sincere apologies to both Susanne and David for my
stupid message and to group for wasting everyone's time.
Ouch, that headslap hurt.
-Peter
On 2010-02-27 11:05, Peter Ehlers wrote:
David, Susanne,
There may be a misunderstanding here. As I understand it,
On 27-Feb-10 17:57:56, Cardinals_Fan wrote:
One last question. I'm trying to use the rnorm() function to
draw a distribution for my coefficient estimates. Let's say
I have a model y* = a + b1x1. I have the coefficient estimate
for b1 stored as b1 and the standard error estimate for b1
Hi,
I don't think you should split the list for beginners.
On the SAS list we get questions from novices such as secretaries,
janitorial services, human resources and even top executives.
They often approach SAS from a very intuitive standpoint. These questions
often shake the experts
Jason:
What are you trying to do? Your reference link provides several Fortran
programs. Why can't you use those? Or you could translate them into R code
if you would like to take advantage of R's wonderful graphics and
multitudinous other statistical adjuncts.
Your request seems too broad to
Thanks
Nice code.
I appreciate the function. I don't know if you ever use SAS datasets but I
am working with the devloper of 'dsread' to create a lossless transfer from
SAS to R. I am also working on an in memory Java interface which would allow
me to mix SAS and R code.
Here is the link to
x - c(6.6493705109108, 7.1348436721241, 8.76886994525624,
6.12907548096037, 6.88379118678109, 7.17841879427688,
7.90737237492867, 7.1207373264833, 7.82949407630692,
6.90411547316105)
plot(ecdf(x), log=x)
It does the plot fine, but complains:
Warning message:
In
Greetings,
I am acquiring a new computer in order to conduct data analysis. I
currently have a 32-bit Vista OS with 3G of RAM and I consistently run into
memory allocation problems. I will likely be required to run Windows 7 on
the new system, but have flexibility as far as hardware goes. Can
Thank you for this simple help. It is sufficient for my plot.
cheers.
--
View this message in context:
http://n4.nabble.com/Overlap-plot-tp1571803p1572061.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing
Hei David,
Thanks for your quick response, but unfortunately n and nmax alone don't do the
job. If I want to read items no. 11 to 20, the n=10 option will
work, but skip=10 (to NOT read the first 10 items) won't.
Or with your example,
scan(textConnection('1 2 3 4 5 6 7'),
Charles Annis, P.E. wrote:
Jason:
What are you trying to do? Your reference link provides several Fortran
programs. Why can't you use those? Or you could translate them into R
code
if you would like to take advantage of R's wonderful graphics and
multitudinous other statistical
On Feb 27, 2010, at 12:47 PM, J. Daniel wrote:
Greetings,
I am acquiring a new computer in order to conduct data analysis. I
currently have a 32-bit Vista OS with 3G of RAM and I consistently
run into
memory allocation problems. I will likely be required to run
Windows 7 on
the new
Thanks, Gabor. My take away from this and Phil's post is that I'm
going to have to construct some code to do the parsing, rather than
use a standard function. I'm afraid that neither approach works, yet:
Gabor's gets has an off-by-one error (days start on the 2nd, not the
first), and the
On Fri, Feb 26, 2010 at 8:00 AM, Robert Baer rb...@atsu.edu wrote:
[...]
The things that led from frustration to independence was understanding
the difference between data types like matrix and dataframe and learning
there were commands to tell what you were working with at any given time.
Did
David Winsemius wrote:
Perhaps the fact that the stable CRAN version of R for (any) Windows
is 32-bit? It would expand your memory space somewhat but not as much
as you might naively expect.
(There was a recent announcement that an experimental version of a 64-
bit R was
there's a recode function in the Hmisc package, but it's difficult (at least
for me) to find documentation for it
library(Hmisc)
week - c('SAT', 'SUN', 'MON', 'FRI');
recode(week,c('SAT', 'SUN', 'MON', 'FRI'),1:4)
HTH
--
View this message in context:
Is it possible to run a Linux guest VM on the Wintel box so that you
can run the 64 bit code? I used to do this on XP (but not for R).
On 27 Feb 2010, at 20:03, David Winsemius wrote:
On Feb 27, 2010, at 12:47 PM, J. Daniel wrote:
Greetings,
I am acquiring a new computer in order to
No one else posted so the other post you are referring to must have
been an email to you, not a post. We did not see it.
By one off I think you are referring to the row names, which are
meaningless, rather than the day numbers. The data for day 1 is
present, not missing. The example code did
Lets take for example an experiment in which I had two between subject
variables - Strain and treatment, and one within - exposure. all the
variables had 2 levels each.
I found an interaction between exposure and Strain and I want to compare
Strain A and B under every exposure (first and
Sorry, I forgot to cc the group:
Tim -
Here's a way to read the data into a list, with one entry per year:
x =
read.table('http://climate.arm.ac.uk/calibrated/soil/dsoil100_cal_1910-1919.dat',
header=FALSE,fill=TRUE,skip=13)
cts = apply(x,1,function(x)sum(is.na(x)))
wh =
On Feb 27, 2010, at 4:33 PM, Gabor Grothendieck wrote:
No one else posted so the other post you are referring to must have
been an email to you, not a post. We did not see it.
By one off I think you are referring to the row names, which are
meaningless, rather than the day numbers. The data
Hi,
I don't know to solve this error that is returned, even though I understand it:
library(plotrix)
Ymd.format-%Y/%m/%d
gantt.info-list(labels=
c(First task,Second task (1st part),Third task (1st part),Second task
(2nd part),Third task (2nd part),
Fourt task,Fifth task,Sixth task),
Thank you both for your answers.
On Fri, Feb 26, 2010 at 7:58 PM, Duncan Murdoch murd...@stats.uwo.cawrote:
You aren't seeing the print method, you are seeing a newly created print
generic function. As Uwe mentioned, print() is not an S4 generic, so when
you create your print method, a new
Tim -
I don't understand what you mean about interleaving rows. I'm guessing
that you want a single large data frame with all the data, and not a
list with each year separately. If that's the case:
x =
read.table('http://climate.arm.ac.uk/calibrated/soil/dsoil100_cal_1910-1919.dat',
*Combining 2 columns into 1 column many times in a very large dataset*
The clumsy solutions I am working on are not going to be very fast if I can
get them to work and the true dataset is ~1500 X 45000 so they need to be
efficient. I've searched the R help files and the archives for this list
On 27/02/2010 6:15 PM, Joris Meys wrote:
Thank you both for your answers.
On Fri, Feb 26, 2010 at 7:58 PM, Duncan Murdoch murd...@stats.uwo.cawrote:
You aren't seeing the print method, you are seeing a newly created print
generic function. As Uwe mentioned, print() is not an S4 generic, so
I have grades data. I read them from a csv in letter-grade format. I
then converted them to levels
levels(grades$grade)=c('A+','A','A-','B+','B','B-','C+','C','C-','D+','D','D-')
And then to numbers
grades$gp=grades$grade
levels(grades$gp)=c(4.3,4.0,3.7, 3.3,3.0,2.7, 2.3,2.0,1.7, 1.3,1.0,0.7)
I wish to rearrange the matrix, df, such that all there are not repeated x
values. Particularly, for each value of x that is reated, the corresponded y
value should fall under the appropriate column. For example, the x value 3
appears 4 times under the different columns of y, i.e. y1,y2,y3,y4.
Try this:
df[!duplicated(df[,'x']),]
On Sun, Feb 28, 2010 at 8:56 AM, Juliet Ndukum jpnts...@yahoo.com wrote:
I wish to rearrange the matrix, df, such that all there are not repeated x
values. Particularly, for each value of x that is reated, the corresponded y
value should fall under the
On Feb 27, 2010, at 6:17 PM, Phil Spector wrote:
Tim -
I don't understand what you mean about interleaving rows. I'm
guessing
that you want a single large data frame with all the data, and not a
list with each year separately. If that's the case:
x =
On a more complicated note, is there a way to embed the station name in a
header or footer of the document? It seems there is no way to evaluate a
chunk or an inline \Sexpr{...} in a header or footer?
This would put station ID on every report page, making reading comparing
multiple reports
Thomas,
You could perhaps do a tad better by simply adding a right-hand-side
axis using axis():
axis(4, at=c(4.3,4.0,3.7, 3.3,3.0,2.7, 2.3,2.0,1.7, 1.3,1.0,0.7),
labels=c('A+','A','A-','B+','B','B-','C+','C','C-','D+','D','D-'),
las=1)
That way you have both numeric and grade scales.
if you
Hi Juliet,
Here is a suggestion using aggregate():
# aux function
foo - function(x){
y - sum(x, na.rm = TRUE)
ifelse(y==0, NA, y)
}
# result
aggregate(df[,-1], list(df$x), foo)
Here, df is your data.
HTH,
Jorge
On Sat, Feb 27, 2010 at 7:56 PM, Juliet
Yay! That's perfect. Thanks, Steve!
Tom
2010/2/27 S Ellison s.elli...@lgc.co.uk:
Thomas,
You could perhaps do a tad better by simply adding a right-hand-side
axis using axis():
axis(4, at=c(4.3,4.0,3.7, 3.3,3.0,2.7, 2.3,2.0,1.7, 1.3,1.0,0.7),
Sherri -
Here's one way:
nms = c('rs123','rs157','rs132')
lowf = function(one,two){
both = paste(pop[[one]],pop[[two]],sep='')
tt = table(both)
lowfreq = names(tt)[which.min(tt)]
ifelse(both == lowfreq,1,0)
}
res = mapply(lowf,nms,paste(nms,'.1',sep=''),SIMPLIFY=FALSE)
Hi,
The `system.time(expr)' command provide 3 different times for evaluating the
expression `expr'; the first two are user and system CPUs and the third one is
total elapsed time. Suppose I want to compare two different computational
procedures for performing the same task, which component
On Feb 27, 2010, at 8:43 PM, Jorge Ivan Velez wrote:
Hi Juliet,
Here is a suggestion using aggregate():
# aux function
foo - function(x){
y - sum(x, na.rm = TRUE)
ifelse(y==0, NA, y)
}
# result
aggregate(df[,-1], list(df$x), foo)
That does work in this
Try this:
system.time(Sys.sleep(60))
user system elapsed
0.000.00 60.05
pt - proc.time(); Sys.sleep(60); proc.time() - pt
user system elapsed
0.000.00 60.01
On Sat, Feb 27, 2010 at 9:33 PM, Ravi Varadhan rvarad...@jhmi.edu wrote:
Hi,
The `system.time(expr)'
I'm a bit confused on how to use lapply with a data.frame.
For example.
lapply(data, function(x) print(x))
WHAT exactly is passed to the function. Is it each ROW in the data
frame, one by one, or each column, or the entire frame in one shot?
What I want to do apply a function to each row
I have this
grades$grade
...
[4009] A B A- A- A- B+ A A- B+ B A B B B A A- A A- A- B+ A- A A B+
[4033] A- A- A- A A- B A A A- A
Levels: A A- A+ B B- B+ C C+
I want to change the order of the levels
reorder(grades$grade,c('A+','A','A-','B+','B','B-','C+','C'))
Error in
On Feb 27, 2010, at 9:49 PM, Noah Silverman wrote:
I'm a bit confused on how to use lapply with a data.frame.
For example.
lapply(data, function(x) print(x))
WHAT exactly is passed to the function. Is it each ROW in the data
frame,
No.
one by one, or each column,
Yes. Dataframes
x - read.table(textConnection(idgroupvalue
+ 1A3.2
+ 2A3.0
+ 3A3.1
+ 4B5.5
+ 5B6.0
+ 6B6.2), header=TRUE)
# dataframe is processed by column by lapply
lapply(x, c)
$id
[1] 1 2 3 4 5 6
$group
On Feb 27, 2010, at 10:01 PM, Thomas Levine wrote:
I have this
grades$grade
...
[4009] A B A- A- A- B+ A A- B+ B A B B B A A- A A- A- B+
A- A A B+
[4033] A- A- A- A A- B A A A- A
Levels: A A- A+ B B- B+ C C+
I want to change the order of the levels
Here is a continuation to turn DF into a zoo series: It depends on
the fact that all NAs are structural, i.e. they indicate dates which
cannot exist such as Feb 31 as opposed to missing data. dd is the
data as one long series with component names being the dates in the
indicated format. That
I am beginner to R.
I have written a function:
f= function(n=100,p=0.5){
X=rbinom(100,n,p)
(mean(X)-n*P)/sqrt(n*p*(1-p))
}
But I made a mistake by typing P instead of p. How do I edit this
function and improve my mistake. If I use edit(f) it opens an edit window
where I am able to change the
hello all,
Could someone please tell me how should I pass a double[][] (matrix of any
size) that I have in Java, into R using Rserve.
Thanks
Sashikiran
--
Sashikiran Challa
MS Cheminformatics,
School of Informatics and Computing,
Indiana University, Bloomington,IN
scha...@indiana.edu
Thanks a lot Deepayan, one question:
Is it possible to place these barplots side-by-side instaed of super
imposing? Something like this:
http://www.imachordata.com/wp-content/uploads/2009/09/boxplot.png
library(lattice)
bwplot(yield ~ variety, data = barley, col = 1, pch = 16,
panel =
learner1978 sakp4mcl at gmail.com writes:
I am beginner to R.
I have written a function:
f= function(n=100,p=0.5){
X=rbinom(100,n,p)
(mean(X)-n*P)/sqrt(n*p*(1-p))
}
But I made a mistake by typing P instead of p. How do I edit this
function and improve my mistake.
Two answers:
On Feb 27, 2010, at 11:15 PM, Ben Bolker wrote:
learner1978 sakp4mcl at gmail.com writes:
I am beginner to R.
I have written a function:
f= function(n=100,p=0.5){
X=rbinom(100,n,p)
(mean(X)-n*P)/sqrt(n*p*(1-p))
}
But I made a mistake by typing P instead of p. How do I edit this
function
Thanks, Gabor. Your reply is helpful, but it still doesn't answer whether I
should use the sum of the first two components of system.time (user + system
CPU) or only the first one (user CPU).
Ravi.
Ravi Varadhan, Ph.D.
Will this work for you:
x - read.table(textConnection( x y1 y2 y3 y4
+ 1 3 7 NA NA NA
+ 2 3 NA 16 NA NA
+ 3 3 NA NA 12 NA
+ 4 3 NA NA NA 18
+ 5 6 8 NA NA NA
+ 6 10 NA NA 2 NA
+ 7 10 NA 11 NA NA
+ 8 14 NA NA NA 8
+ 9 14 NA 9 NA NA
+ 10 15 NA NA NA 11
+ 11 50 NA NA 13 NA
+ 12
The last component seems the most meaningful since its the amount of
time you actually waited for the code to run.
On Sat, Feb 27, 2010 at 11:44 PM, Ravi Varadhan rvarad...@jhmi.edu wrote:
Thanks, Gabor. Your reply is helpful, but it still doesn't answer whether I
should use the sum of the
Also you might want to try out this which will repeatedly run your
benchmarks to average out the values and make comparisons easier:
http://rbenchmark.googlecode.com
On Sat, Feb 27, 2010 at 11:55 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
The last component seems the most
A lot depends on what you are trying to measure.
You should add the system and user CPU times to get a better idea of
the CPU utilization. For some classes of problems it might be good to
separate them if you were doing a lot of I/O or other system calls
that might be using time, but for 99% of
You might want to debug your data. Anytime there is an error message,
take a look at your data. You have some illegal dates in your 'end'
(2010/9/31 2010/6/31 are not legal and are probably causing your
error). Simply printing out your test data would have shown that:
gantt.info
$labels
[1]
Dear R-List,
My questions concerns missing values. Specifically, is is possible to
use different types of missingness in a dataset and not a
one-size-fits-all NA?
For example, data may be missing because of an outright refusal by a
respondent to answer a question, or because she didn't know an
if you don't mind having zeros instead of NAs, then yet another solution is:
df - read.table(textConnection(x y1 y2 y3 y4
1 3 7 NA NA NA
2 3 NA 16 NA NA
3 3 NA NA 12 NA
4 3 NA NA NA 18
5 6 8 NA NA NA
6 10 NA NA 2 NA
7 10 NA 11 NA NA
8 14 NA NA NA 8
9 14 NA 9 NA NA
10 15 NA NA
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