Hi R,
Can I perform a stepwise method for robust regression? In other words,
how do I combine the methods step and rlm together?
Thanks and Regards,
Shubha
This e-mail may contain confidential and/or privileged i...{{dropped:13}}
__
Hi List!
I’m using regsimq() from the “lmomRFA”-package to calculate error bounds for
diverse distributions. For example:
regsimq(gumfit$qfunc, nrec = lmom.data$n, f = lcdfgum, boundprob = c(0.025,
0.975))
Several times I got this error massage:
Fehler in quantile.default(ou, probs =
I am trying to get documentation about the random number generator used in
sample. The help for sample does not mention it. Can anyone point me in
the right direction.
Thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org
On Sun, Aug 15, 2010 at 10:58:51AM -0400, Data Analytics Corp. wrote:
I have an upcoming project that will involve a large text file. I want to
1. read the file into R one line at a time
2. do some string manipulations on the line
3. write the line to another text file.
You already
Dear R users,
I seek for a more elegant manner to manipulate my data that that I
produced so far.
Data is in a data frame THC515.DATA -sample at the end of this mail- of
5 variables, a string and 4 continuous numeric variables.
I need to get the mean of two variables Q and T at the levels of
Le 16/08/10 09:35, Linda Eaton a écrit :
I am trying to get documentation about the random number generator used in
sample. The help for sample does not mention it. Can anyone point me in
the right direction.
Thanks
Hi,
You can follow the white rabbit into the code burrow.
sample
On 16-Aug-10 07:35:58, Linda Eaton wrote:
I am trying to get documentation about the random number generator
used in sample. The help for sample does not mention it. Can
anyone point me in the right direction.
Thanks
The place the read all about it is
?RNG
Agreed that ?sample gives no
Hi:
Assuming I interpreted your intentions correctly, here are three different
ways to get means of Q and T by combinations of dP and n. Your data were
read into a data frame named dd. (Note that there are other ways to do this
as well...)
(1) aggregate():
with(dd, aggregate(cbind(Q, T) ~ dP +
I have been using the pvclust package to perform hierarchical clustering
with bootstrapped p-values. I am using it to compare the numbers of
clusters identified between different datasets. However, the numbers are
not comparable because pvclust calculates p-values for the optimal
number of
Dear all,
I have an xts object , t.xts with 4 columns: v1 DD1 v2 DD2 and
created a data frame :
t - as.data.frame(t.xts)
I would like to extract data and create a new data frame for when the values
in column DD1 falls between 0 and 30 and extract the corresponding v1 value.
How can I do
On 08/16/2010 03:27 PM, Dong-Hee Koh wrote:
Hello,
I am trying to read a database exported from SAS.
It is form of csv, and the date format reads '02-Feb-99'.
I used following code to convert character to date format,
db$dob-as.Date(db$dob, format=%d-%b-%y).
but it doesn't work, only seems NA.
On 08/16/2010 08:22 PM, Jim Lemon wrote:
On 08/16/2010 03:27 PM, Dong-Hee Koh wrote:
Hello,
I am trying to read a database exported from SAS.
It is form of csv, and the date format reads '02-Feb-99'.
I used following code to convert character to date format,
db$dob-as.Date(db$dob,
Dear All
At institutes where there are PC labs used by Masters and undergraduate
students and software is maintained /managed by a central IT services,
do you always update R every time a new version is released - around
beginning of April and October? Do you also ask them to install all
patch
Hello!
I need to find a simple scalar value:
Scal = ((1/R) - T) / (P - T),
where R, T, and P are vectors in a data.frame.
Please, can anyone tell me how to solve that in R?
Best,
PM
__
R-help@r-project.org mailing list
Dear List,
Ben's recommendation to MuMIn is of great importance to research with over
ten independent variables.
However, the criteria in this package for model selection are AICc
(second-order AIC) and QAIC (quasi-AIC).
Please kindly share if it is possible to carry AIC rather than the metrics
On Aug 16, 2010, at 12:39 PM, Fiona Mary Underwood wrote:
Dear All
At institutes where there are PC labs used by Masters and undergraduate
students and software is maintained /managed by a central IT services,
do you always update R every time a new version is released - around
beginning
Hello, I have a question regarding bootstrap confidence intervals.
Suppose we have a data set consisting of single measurements, and that
the measurements are independent but the distribution is unknown. If
we want a confidence interval for the population mean, when should a
bootstrap confidence
On Aug 15, 2010, at 11:14 PM, Marius Hofert wrote:
Dear David,
thanks for the quick response. Yes, I tried formula, but this gives the
error Multivariate data inputs require lhs for the formula.
library(fGarch)
spec - garchSpec(model = list(alpha = 0.1, beta = c(0.4, 0.4)))
data -
Hi,
I want to thank all the suggestions sent, especially that of
Hans.
Thanks,
--
Silvano Cesar da Costa
Departamento de Estatística
Universidade Estadual de Londrina
Fone: 3371-4346
--
- Original Message -
You probably need to look up on how to write functions.
Try
scal.fn - function(P, R, T){
out - ( 1/R - T ) / ( P - T )
return(out)
}
Here is a fake example:
df - cbind.data.frame( P=rnorm(10), R=rnorm(10), T=rnorm(10) )
scal.fn( df$P, df$R, df$T )
Or are you trying to solve other
Thank you every one.
Caveman
On Mon, Aug 16, 2010 at 4:00 AM, David Winsemius dwinsem...@comcast.netwrote:
To improve your further efforts at searching you should take note of the
fact that it is ASCII, not ASCI.
On Aug 15, 2010, at 8:50 PM, Orvalho Augusto wrote:
Thank you!!
Caveman
On Aug 16, 2010, at 5:53 AM, Lily_stats wrote:
Dear all,
I have an xts object , t.xts with 4 columns: v1 DD1 v2 DD2 and
created a data frame :
t - as.data.frame(t.xts)
t is not the best choice of names for an object because it is the
name of a commonly used function
Let's instead
Thanks for the answer!
However, if I would have scal.fn() like below, how would I apply
uniroot() or optimize() or the like?
Best,
PM
On 16/08/10 13:24, Adaikalavan Ramasamy wrote:
You probably need to look up on how to write functions.
Try
scal.fn - function(P, R, T){
out - ( 1/R - T )
From: Stephen Liu
Hi JesperHybel,
Thanks for your advice.
If you're trying to follow the youtube video you have a
typing mistake here:
InsectSprays.aov -(test01$count ~ test01$spray)
I think this should be:
InsectSprays.aov -aov(test01$count ~ test01$spray)
Your advice
Dear all,
I have an error in the simple prediction function for lm().
Maybe someone experienced the same?
xma - matrix(data = 0, nrow = 100, ncol = 2)
xma[, 1] - rnorm(100)
xma[, 2] - rchisq(100, df = 3)
m1 - lm(xma[, 1] ~ xma[, 2])
predict(m1, as.data.frame(seq(-13, 13, 0.5)))
Thanks a lot,
better try it this way:
DF - data.frame(y = rnorm(100), x = rchisq(100, df = 3))
m - lm(y ~ x, DF)
predict(m, data.frame(x = seq(-13, 13, 0.5)))
I hope it helps.
Best,
Dimitris
On 8/16/2010 2:37 PM, Trafim Vanishek wrote:
Dear all,
I have an error in the simple prediction function for
Hi all,
How to convert following simple python script to R
if x in a_list:
print x
OR
simply, how to test if a vector contain a value?
Thank you in advance,
Hyunchul
[[alternative HTML version deleted]]
__
R-help@r-project.org
You can also write
x[match(z,x[,2]),].
Leila
on 2010/08/16 06:36 AM RICHARD M. HEIBERGER said the following:
Yes,
x[order(order(z)),]
Two uses of order are needed, as shown.
Rich
On Sun, Aug 15, 2010 at 11:47 PM, Leon Yee yee.l...@gmail.com wrote:
Dear all,
I have a data frame
Sorry for chiming in a tad late (I was incommunicado for two weeks)
Le lundi 02 août 2010 à 18:50 +, Ben Bolker a écrit :
Prof Brian Ripley ripley at stats.ox.ac.uk writes:
Here is how I do it:
write(
model {
for (year in 1:N) {
D[year] ~ dpois(mu[year])
Hello all,
I'm kind of surprised that searching the archives and Googling haven't given
me a result for this...
I've got a large amount of data that is a good fit for CouchDB; it's
reasonably unstructured, and such structure that exists is quite fluid. I
want to slice the data in many different
I am running R 2.10.1 on Windows Server 03 in an effort to increase my memory
limit. The memory limit on my machine is 4 gb and 8 gb on our server. However,
when I run R within the server and try to increase my memory R still says I am
limited to 4 gb. Any thoughts?
Thank you in advance for
Hi,
Anybody can tell me why I don't have colors in my picture?
library(lattice)
my.pch-c(17,16,15,18,20,9,10,12)
my.fill-c('yellow','black','green','red','blue','cyan','magenta','pink')
wzorzec1- c(1,3,2,4,6,4,2,3)
wzorzec2- c(5,3,6,6,2,3,4,1)
a-factor(wzorzec1)
b-factor(wzorzec2)
Hi Hyunchul,
See ?match
-Ista
On Mon, Aug 16, 2010 at 1:06 PM, Hyunchul Kim
hyunchul.kim@gmail.com wrote:
Hi all,
How to convert following simple python script to R
if x in a_list:
print x
OR
simply, how to test if a vector contain a value?
Thank you in advance,
Hyunchul
Try this:
is.element(2, c(1, 2, 4))
On Mon, Aug 16, 2010 at 10:06 AM, Hyunchul Kim
hyunchul.kim@gmail.comwrote:
Hi all,
How to convert following simple python script to R
if x in a_list:
print x
OR
simply, how to test if a vector contain a value?
Thank you in advance,
mylist = c(1,2,3)
if (any(mylist == 3)) { print(3) }
[1] 3
On 08/16/2010 03:06 PM, Hyunchul Kim wrote:
Hi all,
How to convert following simple python script to R
if x in a_list:
print x
OR
simply, how to test if a vector contain a value?
Thank you in advance,
Hyunchul
Just based on my limited understanding of bootstrapping and statistics in
general, bootstrapping is effective but not magical - you can't reasonably
expect any reliable inference to be drawn about the population based on a
sample of 10, without any distributional assumptions. Your t interval
On Mon, Aug 16, 2010 at 2:06 PM, Hyunchul Kim
hyunchul.kim@gmail.com wrote:
Hi all,
How to convert following simple python script to R
if x in a_list:
print x
OR
simply, how to test if a vector contain a value?
if(any(a_list == x)){
print(x)
}
Or use %in%:
elaine kuo elaine.kuo.tw at gmail.com writes:
[re: MuMIn package]
However, the criteria in this package for model selection are AICc
(second-order AIC) and QAIC (quasi-AIC).
Please kindly share if it is possible to carry AIC rather than the metrics
above using this package.
Thank you.
I
On 16.08.2010 15:07, McEachron, Luke wrote:
I am running R 2.10.1 on Windows Server 03 in an effort to increase my memory
limit. The memory limit on my machine is 4 gb and 8 gb on our server. However,
when I run R within the server and try to increase my memory R still says I am
limited to
On 16 August 2010 at 21:40, David Mitchell wrote:
| Hello all,
|
| I'm kind of surprised that searching the archives and Googling haven't given
| me a result for this...
There is a project called 'R4CouchDB' on github:
http://github.com/wactbprot/R4CouchDB
Hth, Dirk
|
| I've got a
On Mon, Aug 16, 2010 at 12:40 PM, David Mitchell monch1...@gmail.com wrote:
What's the best way to go about extracting data from CouchDB databases, so
that I can process it using R? There don't seem to be any specific R
modules for CouchDB, but I find it hard to believe that I'd be the first
http://rwiki.sciviews.org/doku.php?id=developers:projects:gsoc2010:nosql_interface
http://github.com/wactbprot/R4CouchDB
On Mon, Aug 16, 2010 at 7:40 AM, David Mitchell monch1...@gmail.com wrote:
Hello all,
I'm kind of surprised that searching the archives and Googling haven't given
me a
Thanks a lot, Dimitris!
I see - data should be defined precisely as data.frame.
On Mon, Aug 16, 2010 at 2:47 PM, Dimitris Rizopoulos
d.rizopou...@erasmusmc.nl wrote:
better try it this way:
DF - data.frame(y = rnorm(100), x = rchisq(100, df = 3))
m - lm(y ~ x, DF)
predict(m, data.frame(x
Do not worry, I found the solution.
I had a list, as follows :
x - list()
x$i - 5
x$j - 9
x$k - 15
names(x$i) - a
names(x$j) - b
names(x$k) - b
And I wanted to obtain a list, as follows :
$a
i
5
$b
j k
9 15
My solution :
n - sapply(x, names)
m - sapply(x, c, use.names = FALSE)
tapply(m,
1. Bootstrap will do poorly for small sample sizes (less than 25 or
so). Parametric methods (t) have the advantage of working down to a
sample size of less than 5.
2. You need to have the number of resamples reasonably large, say
10,000, for poorly behaved distributions. Otherwise extreme
- Original Message
From: Liaw, Andy andy_l...@merck.com
To: Stephen Liu sati...@yahoo.com; r-help@r-project.org
Sent: Mon, August 16, 2010 8:22:33 PM
Subject: RE: [R] Learning ANOVA
- snip -
Well-written model fitting functions should be called like this:
modelfn(var1 ~ var2 +
Stephen Liu wrote:
- Original Message
From: Liaw, Andy andy_l...@merck.com
To: Stephen Liu sati...@yahoo.com; r-help@r-project.org
Sent: Mon, August 16, 2010 8:22:33 PM
Subject: RE: [R] Learning ANOVA
- snip -
Well-written model fitting functions should be called like this:
The set runs fine without the fixed effects. However, once I add the
+factor(HostCode)-part, it throws out two variables. The africa-dummy
thrown out certainly does not exhibit perfect multicollinearity, I checked
that. The litrate variable is continuous and therefore cannot be perfectly
related
- Original Message
From: Erik Iverson er...@ccbr.umn.edu
To: Stephen Liu sati...@yahoo.com
Cc: r-help@r-project.org
Sent: Mon, August 16, 2010 11:41:34 PM
Subject: Re: [R] Learning ANOVA
modelfn(count ~ spray, data=test01)
Error: could not find function modelfn
What will be +var3 ?
Hello R-list!
I'm developing a prognostic model for a medical problem (event yes/no).
So I used the patrty package and did a Random Forest:
ctrl - cforest_unbiased(ntree=1000, mtry=3, minsplit=100)
set.seed(675)
rf - cforest( ph ~. , data=train, controls=ctrl)
print(rf)
and calculated the
modelfn(count ~ spray, data=test01)
Error: could not find function modelfn
What will be +var3 ?
I think the general advice applied to your specific situation was meant to
suggest using the construct:
InsectSprays.aov - aov(count ~ spray, data=InsectSprays)
rather than:
InsectSprays.aov -
Hello.
I don't uderstant when to use textConnection and when not.
Some examples do it, some not.
I've even seen something like
con - textConnection(rev(rev(ReadLines('data.txt'))[-(1:2]))
data - read.table(con)
close(con)
--
View this message in context:
Thanks Chuck,
I was trying to implement something more complicated than what I had to and
after finding the reduce() function in bioconductor, everything went
smoothly.
Thanks again
--
View this message in context:
http://r.789695.n4.nabble.com/merge-function-in-R-tp2324684p2327133.html
At 21:20 15/08/2010, Duncan Murdoch wrote:
On 15/08/2010 10:24 AM, Stephen Liu wrote:
- Original Message
From: Michael Bedward michael.bedw...@gmail.com
To: Stephen Liu sati...@yahoo.com
Cc: r-help@r-project.org
Sent: Sun, August 15, 2010 3:43:55 PM
Subject: Re: [R] About .RData
Hi,
One useful case is when data is sent in an email. For instance:
T1 T2 T3
-0.24 -0.26 -0.67
-1.58 0.04 0.14
-1.21 1.55 -0.45
0.31 0.48 -1.39
One could read it in via
con - textConnection(
T1 T2 T3
-0.24 -0.26 -0.67
-1.58 0.04 0.14
-1.21 1.55 -0.45
0.31 0.48 -1.39)
Also, many R functions are designed to operate on R connections, to
input and output text. Alternatively, we may wish to provide the input
text as an R character vector, or output text to a character vector. The
textConnection makes a character vector look like a connection, so R
routines that
OK, thanks
Some time ago I asked in the forum how to read data from a file in order to
use it with zoo.
Someone suggested to use textConnection
That's why I'm a little bit confused.
I guess I don't need to use textConnection in order to read from files, it's
just for text copied from other
I have a large dataset and I would like to make some kind of flowchart
from this dataset. The idea is to show rowcounts from data subsets:
data1
rows= 10
|
/ \
/ \
males females,
Colleagues,
R 2.11.1, OS X. Please forgive my ignorance of some issues related to ANOVA.
I am trying to replicate some SAS analyses that use type 3 sum of squares. The
model that I am using is:
lm(YVAR ~ DATA$SEQ + DATA$SEQ %in% DATA$ID + DATA$PERIOD +
FRAME$FORMULATION)
The intent
http://cran.r-project.org/web/packages/diagram/vignettes/diagram.pdf
It might be difficult to include very large amounts of data, but names and
counts should be fine.
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-make-flowchart-in-R-tp2327246p2327273.html
Sent from the
On Aug 16, 2010, at 12:59 PM, johannes rara wrote:
I have a large dataset and I would like to make some kind of flowchart
from this dataset. The idea is to show rowcounts from data subsets:
data1
rows= 10
|
/ \
Hello
On Mon, 16 Aug 2010 11:17:41 -0700
Dennis Fisher fis...@plessthan.com wrote:
Colleagues,
R 2.11.1, OS X. Please forgive my ignorance of some issues related
to ANOVA.
This has already been discussed at length on this list. You might try
searching the archives and using Rseek.
You have a lot of different way
a-c(1,2,3,NA,3,4,3)
is.na(a)
[1] FALSE FALSE FALSE TRUE FALSE FALSE FALSE
a==2
[1] FALSE TRUE FALSENA FALSE FALSE FALSE
Look at here:
http://cran.r-project.org/doc/manuals/R-intro.html
--
View this message in context:
Dear Grzesiek
Only pch 21 to 25 can be filled. Pairing fill with plot characters 1:20
will be ignored. You could try overlaying points to increase the number
of unique colour/shape combinations.
Cheers
Chris
Hadley Wickham, Creator of ggplot2 - teaching in the UK. 1st - 2nd
November 2010.
Dear All
I'm having problem with some script which worked a few months ago (on a
different computer that might well have had a different version of R
installed, so perhaps it has to do with the old version of R?):
library(reshape)
Loading required package: plyr
tble.data - melt.array(interp,
Negate is in the base package, although apparently not in the
prehistoric version of R you're using here! Updating to the
latest R should work.
Jock Currie wrote:
Dear All
I'm having problem with some script which worked a few months ago (on a
different computer that might well have had a
Thanks! My LaTeX knowledge is quite limited, I don't even know which
one of these
http://www.ucc.ie/cgi-bin/uncgi/ctan?term=PSTricks
I should install to get PSTricks working. I have used TeXShop once or
twice on my Mac. So, I maybe prefer plain R solution.
-J
2010/8/16 Marc Schwartz
The R Journal article by Paul Murrell may be of interest:
http://journal.r-project.org/2009-1/RJournal_2009-1_Murrell.pdf
The documentation for the Diagram Package may also be of interest:
http://cran.r-project.org/web/packages/diagram/diagram.pdf
Hi,
When I plot, the axis ticks are printed as 50.00 25.00 10.00 1.00 0.05
0.01, is there any way to print them as 50 25 10 1 0.05 0.01 instead?
Thanks
John
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Hi,
If you should decide to pursue the LaTeX approach, you would want to install
MacTeX on your Mac. More information here:
http://www.tug.org/mactex/2009/
MacTeX is a self contained distribution of TeX Live 2009. It also provides an
easy to use GUI based maintenance tool to add packages
On Aug 16, 2010, at 3:53 PM, array chip wrote:
Hi,
When I plot, the axis ticks are printed as 50.00 25.00 10.00
1.00 0.05
0.01, is there any way to print them as 50 25 10 1 0.05 0.01
instead?
No example, so we don't even know which of the three plotting
paradigms you might be
sorry that I didn't give more details, thought it's going to be the same for
all
plots. It's the bxp() for boxplot. I have about couple of 10 such plots in a
for() loop, so would like to automate the process. Using labels= certainly
works, but it's manual work - plot by plot. Any other
On Aug 16, 2010, at 4:33 PM, array chip wrote:
sorry that I didn't give more details, thought it's going to be the
same for all
plots. It's the bxp() for boxplot. I have about couple of 10 such
plots in a
for() loop, so would like to automate the process. Using labels=
certainly
works,
How about this:
x - c(50,25,5,1,.1,.05)
ifelse(x = 1, sprintf(%.0f, x), sprintf(%.2f, x))
[1] 50 25 510.10 0.05
On Mon, Aug 16, 2010 at 4:33 PM, array chip arrayprof...@yahoo.com wrote:
sorry that I didn't give more details, thought it's going to be the same for
all
plots.
Try this:
x - c(50,25,5,1,.1,.05)
prettyNum(x)
On Mon, Aug 16, 2010 at 4:53 PM, array chip arrayprof...@yahoo.com wrote:
Hi,
When I plot, the axis ticks are printed as 50.00 25.00 10.00 1.00 0.05
0.01, is there any way to print them as 50 25 10 1 0.05 0.01
instead?
Thanks
John
On Sat, 2010-08-14 at 21:17 +0800, elaine kuo wrote:
Thanks
I wanna to add the species labels in a cca biplot
based on species and environment conditions (maybe sites are of less
relevance here).
0. It would help your learning if you actually read the help pages for
the functions I used,
On Mon, Aug 16, 2010 at 1:40 PM, skan juanp...@gmail.com wrote:
OK, thanks
Some time ago I asked in the forum how to read data from a file in order to
use it with zoo.
Someone suggested to use textConnection
That's why I'm a little bit confused.
I guess I don't need to use textConnection
Hello,
I've been trying to use R-2.11.1 but I get the following error when trying to
run R on linux:
error while loading shared libraries: libRblas.so: cannot open shared object
file: No such file or directory
How can I solve this problem?
Best,
Katy
Hi John,
formatC will do your work. Hope it helps.
x - y - c(50.00,25.00,10.00,1.00,0.05,0.01)
plot(x,y,log = xy,axes = F)
axis(1, x, formatC(x))
axis(2, y, formatC(y))
Regards,
Wu
-
A R learner.
--
View this message in context:
Hi, I am really puzzled by this. hope someone can help me
I have a 2 small data frames a and b derived from a larger data frames.
They
look exactly the same to me, but identical() always returns FALSE.
a
a b
2 10011048 L
4 10011048 R
6 10011049 L
8 10011049 R
b
a b
1
Katayoon Kasaian wrote:
Hello,
I've been trying to use R-2.11.1 but I get the following error when trying to
run R on linux:
error while loading shared libraries: libRblas.so: cannot open shared object file:
No such file or directory
How can I solve this problem?
Did you install this
Thank you all for the suggestions. They all worked. Now, those numbers on the
ticks are produced by default plot function bxp(), i.e. they are different in
each plot, is there any functions I can retrieve them so I can use formatC() or
prettyNum() etc?
Thanks again,
John
- Original
Hello,
array chip wrote:
Hi, I am really puzzled by this. hope someone can help me
I have a 2 small data frames a and b derived from a larger data frames. They
look exactly the same to me, but identical() always returns FALSE.
a
a b
2 10011048 L
4 10011048 R
6 10011049 L
8
On Mon, Aug 16, 2010 at 5:47 PM, array chip arrayprof...@yahoo.com wrote:
Hi, I am really puzzled by this. hope someone can help me
I have a 2 small data frames a and b derived from a larger data frames.
They
look exactly the same to me, but identical() always returns FALSE.
a
a b
Oops, I overlooked the row names. Sorry for my carelessness.
Thanks
- Original Message
From: Erik Iverson er...@ccbr.umn.edu
To: array chip arrayprof...@yahoo.com
Cc: r-h...@stat.math.ethz.ch
Sent: Mon, August 16, 2010 2:53:37 PM
Subject: Re: [R] identical()
Hello,
array chip
Hi John,
They are different as Erik said.
identical(a,b)
[1] FALSE
row.names(a)
[1] 2 4 6 8
row.names(b)
[1] 1 3 5 7
row.names(a) - NULL
row.names(b) - NULL
identical(a,b)
[1] TRUE
Regards,
Wu
array chip wrote:
a
a b
2 10011048 L
4 10011048 R
6 10011049 L
8
Hi,
Take a look at this:
identical(a,b)
[1] FALSE
all.equal(a,b)
[1] Attributes: Component 2: 4 string mismatches
rownames(a) - rownames(b) - NULL
identical(a,b)
[1] TRUE
all.equal(a,b)
[1] TRUE
HTH,
Jorge
On Mon, Aug 16, 2010 at 5:47 PM, array chip wrote:
Hi, I am really puzzled by
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of array chip
Sent: Monday, August 16, 2010 2:54 PM
To: Wu Gong; r-help@r-project.org
Subject: Re: [R] print numbers
Thank you all for the suggestions. They all worked. Now,
Bill et al,
See ?axTicks
plot(3^(0:5), 0:5, log=x,axes=FALSE)
axTicks(1)
[1] 1 2 5 10 20 50 100 200
axTicks(2)
[1] 0 1 2 3 4 5
HTH,
Marc Schwartz
On Aug 16, 2010, at 5:17 PM, William Dunlap wrote:
-Original Message-
From: r-help-boun...@r-project.org
Marc, this works perfectly!
Thanks
John
- Original Message
From: Marc Schwartz marc_schwa...@me.com
To: William Dunlap wdun...@tibco.com
Cc: array chip arrayprof...@yahoo.com; r-help@r-project.org
Sent: Mon, August 16, 2010 3:23:33 PM
Subject: Re: [R] print numbers
Bill et al,
See
Gabor Grothendieck wrote:
Note that zoo does have the read.zoo function which can read a file
returning a zoo object. See help(read.zoo) .
I know, but there are many different ways to read and I wanted to know
what's the proper in my case.
For example I've seen these ones, what's
Thanks for Ben.
Model selection by AIC is feasible by the code below.
One more question, when is it appropriate to carry out model averaging and
parameter averaging?
code
library(MuMIn)
data(Cement)
lm1 - lm(y ~ ., data = Cement)
dd - dredge(lm1, beta = TRUE, eval = TRUE, rank =
I've just seen that sep sep cannot be , because there are not commas in
the file.
but I want it to take the first and second columns (date and time) as a
whole, the index.
--
View this message in context:
http://r.789695.n4.nabble.com/when-to-use-textConnection-tp2327132p2327622.html
Sent
On Mon, Aug 16, 2010 at 8:00 PM, skan juanp...@gmail.com wrote:
I've just seen that sep sep cannot be , because there are not commas in
the file.
but I want it to take the first and second columns (date and time) as a
whole, the index.
In the latest version of zoo index.column= can be a
Error in .subset(x, j) : invalid subscript type 'list'
Maybe is because I'm using Revolution Analytics and is based on an older
version of R.
I use it because I need to manage very big files and the common version of R
shows me an out of memory error.
--
View this message in context:
On Mon, Aug 16, 2010 at 8:36 PM, skan juanp...@gmail.com wrote:
Error in .subset(x, j) : invalid subscript type 'list'
Maybe is because I'm using Revolution Analytics and is based on an older
version of R.
I use it because I need to manage very big files and the common version of R
shows
Oh, I got it with these code:
tmp - read.table(file.txt)
mydata - zoo(z$V3, as.chron(paste(z$V1,z$V2)))
but that way I cannot specify the format of the date
cheers
--
View this message in context:
http://r.789695.n4.nabble.com/when-to-use-textConnection-tp2327132p2327656.html
Sent from the
- Original Message
From: Michael Dewey i...@aghmed.fsnet.co.uk
To: Duncan Murdoch murdoch.dun...@gmail.com; Stephen Liu sati...@yahoo.com
Cc: r-help@r-project.org
Sent: Tue, August 17, 2010 12:50:51 AM
Subject: Re: [R] About .RData
- snip -
You probably set the startup directory in the
On Mon, Aug 16, 2010 at 8:50 PM, skan juanp...@gmail.com wrote:
Oh, I got it with these code:
tmp - read.table(file.txt)
mydata - zoo(z$V3, as.chron(paste(z$V1,z$V2)))
but that way I cannot specify the format of the date
The default method of as.chron has a format= argument which uses the
On Mon, Aug 16, 2010 at 8:07 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Mon, Aug 16, 2010 at 8:00 PM, skan juanp...@gmail.com wrote:
I've just seen that sep sep cannot be , because there are not commas in
the file.
but I want it to take the first and second columns (date and
1 - 100 of 119 matches
Mail list logo
