I'm using the CRRBinomialTreeOption function (in package "fOptions") with a
loop for pricing a large number of options. But I can't transfer the values
obtained from this function to a "numeric" matrix as the outcome of this
function is not a simple numeric.
The following is the piece of code:
#
Hello,
I'm hoping someone may know the most likely R package for a multivariate
population model for comparing groups? That is, I'd like to estimate a
(stochastic) model for one batch of experiments against a different batch
growing under different conditions. I'm a bit familiar with grofit, but
Dear list
I am sorry to have to ask this question, but I have not been able to
find a solution to what seems a simple problem. I have created a
lattice plot of
a number of regression points and lines using a function containing
panel.xyplot and panel.lmline. The result is what is expected ,
He guys,
I'm trying to fit an arma(1,1)-garch(1,1) model with gaussian innovations, by
manually implementing the likelihoodfunction, and subsequently using maxLik()
to find the required estimates of the parameters. I know there is a
garchFit()-command that does the same, and I use this comma
On Dec 23, 2010, at 6:41 PM, David Winsemius wrote:
On Dec 23, 2010, at 5:55 PM, Eric Hu wrote:
Thanks David. I am reposting the data here.
Jorge has already responded masterfully. He's apparently less lazy
that I and did all the editing. A log transformation as he
illustrated can be v
On Dec 23, 2010, at 5:55 PM, Eric Hu wrote:
Thanks David. I am reposting the data here.
Jorge has already responded masterfully. He's apparently less lazy
that I and did all the editing. A log transformation as he illustrated
can be very useful with bivariate skewed distributions. The onl
Probability propragation is provided in the gRain package.
Regards
Søren
Fra: r-help-boun...@r-project.org [r-help-boun...@r-project.org] På vegne
af Michael Bedward [michael.bedw...@gmail.com]
Sendt: 24. december 2010 00:01
Til: Data AnalyticsCorp.
Cc: r-
Hi Eric,
You can try
plot(x, y, log = 'xy')
fit <- lm(log(y)~log(x))
abline(fit, col = 2, lty = 2)
summary(fit)
par(mfrow = c(2,2))
plot(fit)
HTH,
Jorge
On Thu, Dec 23, 2010 at 5:55 PM, Eric Hu <> wrote:
> Thanks David. I am reposting the data here.
>
> Eric
>
>
> > Hi,
> >
> > I would like t
On Fri, Dec 24, 2010 at 12:01 AM, Michael Bedward
wrote:
> Hello Walt,
>
> Have a look at the bnlearn and deal packages.
>
> Michael
Dear Walt,
take a look also to the catnet/mugnet and pcalg packages,
and if you have questions about bnlearn feel free to ask.
Regards,
Marco, author and main
On Thu, Dec 23, 2010 at 5:06 PM, Vadim Ogranovich
wrote:
> Dear R-users,
>
> I am somewhat puzzled by how R treats data frames with nested data frames.
> Below are a couple of examples, maybe someone could help explain what the
> guiding logic here is.
>
> ## construct plain data frame
>> z <- d
On Dec 23, 2010, at 5:06 PM, Vadim Ogranovich wrote:
Dear R-users,
I am somewhat puzzled by how R treats data frames with nested data
frames.
Speaking as a fellow user, why? Why would we want dataframes
inside dataframes? Why wouldn't lists of dataframes be more
appropriate if you
Hello Walt,
Have a look at the bnlearn and deal packages.
Michael
On 24 December 2010 01:29, Data Analytics Corp.
wrote:
> Hi,
>
> Does anyone know of a package for or any implementation of a Bayesian Belief
> Network in R?
>
> Thanks,
>
> Walt
>
>
>
> Walter R. Paczkow
Thanks David. I am reposting the data here.
Eric
> Hi,
>
> I would like to plot a linear relationship between variable x and y.
> Can anyone help me with scaled plotting and axes so that all data
> points can be visualized somehow evenly? Plaint plot(x,y) will
> generate condensed points n
On Dec 23, 2010, at 5:37 PM, Eric Hu wrote:
Hi,
I would like to plot a linear relationship between variable x and y.
Can anyone help me with scaled plotting and axes so that all data
points can be visualized somehow evenly? Plaint plot(x,y) will
generate condensed points near (0,0) due t
Hi,
I would like to plot a linear relationship between variable x and y. Can anyone
help me with scaled plotting and axes so that all data points can be visualized
somehow evenly? Plaint plot(x,y) will generate condensed points near (0,0) due
to several large data points. Thank you.
Eric
> x
Dear R-users,
I am somewhat puzzled by how R treats data frames with nested data frames.
Below are a couple of examples, maybe someone could help explain what the
guiding logic here is.
## construct plain data frame
> z <- data.frame(x=1)
## add a data frame member
> z$y <- data.frame(a=1,b=2)
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Mike Harwood
> Sent: Thursday, December 23, 2010 9:19 AM
> To: r-help@r-project.org
> Subject: [R] Reconcile Random Samples
>
> Is there a way to generate identical random samples
Hi.
First, you might have more success with turnpoints() in the pastecs package.
Next, consider an approach which makes your peaks truly flattopped.
The sample dataset appears to show that the data on each side of your
peaks are down by at least 6 counts or so, so try running the phase
values
On Thu, Dec 23, 2010 at 7:15 PM, Horace Tso wrote:
> Barry, my reporting error, my ubuntu is 10.04, which is Hardy I believe. It
> was a straight build from the source. No funny stuff done on it.
My lsb_release says my 10.04 is Lucid.
# lsb_release -a
No LSB modules are available.
Distribu
Barry, my reporting error, my ubuntu is 10.04, which is Hardy I believe. It was
a straight build from the source. No funny stuff done on it.
H
-Original Message-
From: b.rowling...@googlemail.com [mailto:b.rowling...@googlemail.com] On
Behalf Of Barry Rowlingson
Sent: Thursday, December
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Charles C. Berry
> Sent: Thursday, December 23, 2010 9:39 AM
> To: rballen
> Cc: r-help@r-project.org
> Subject: Re: [R] forcing evaluation of a char string argument
>
> On Wed,
On Thu, Dec 23, 2010 at 6:30 PM, Horace Tso wrote:
> Following the official instructions to install R on ubuntu 10.04, I issued
> this command on the prompt,
>
> sudo apt-get install r-base
> The following packages have unmet dependencies:
> r-base: Depends: r-base-core (>= 2.12.1-1hardy0) but
Following the official instructions to install R on ubuntu 10.04, I issued this
command on the prompt,
sudo apt-get install r-base
Here is the error msg,
Reading package lists... Done
Building dependency tree
Reading state information... Done
Some packages could not be installed. This may mean
Thanks Patrick for you input. That is what I wanted. I must have read the
R-Inferno long time back.
-Original Message-
From: Patrick Burns [mailto:pbu...@pburns.seanet.com]
Sent: 23 December 2010 15:01
To: r-help@r-project.org; bogaso.christofer
Subject: Re: [R] R-
Is there a way to generate identical random samples using R's runif
function and SAS's ranuni function? I have assigned the same seed
values in both software packages, but the following results show
different results. Thanks!
R
===
> set.seed(6)
> random <- runif(10)
> random
[1] 0.6062683 0.9
On Wed, 22 Dec 2010, rballen wrote:
Why does x in "assign(x)" correctly evaluate to "rank" where
UseMethod(func) does not get correctly evaluated?
Because it is the body of a function definition.
If you want to plug in the value of 'func' in the body of that function,
you need to do somethi
Hello,
Thank you to all those great folks that have helped me in the past
(especially Dennis Murphy).
I have a new challenge. I often generate time-series data sets that look
like the one below, with a variable ("Phase") which has a series of
flat-topped peaks (sample data below with 5 "peaks"). I
Thanks!
On Thu, Dec 23, 2010 at 3:24 PM, Henrique Dallazuanna wrote:
> Try this:
>
> x$second <- NULL
>
>
> On Thu, Dec 23, 2010 at 3:21 PM, Eduardo de Oliveira Horta <
> eduardo.oliveiraho...@gmail.com> wrote:
>
>> Hello,
>>
>> say I have an object
>>
>> > x = list(first = 10, second = 20, thir
Thanks!
On Mon, Dec 13, 2010 at 7:10 PM, Yihui Xie wrote:
> I tried hard to write an automagic script to configure LyX so that you
> don't need to go to the instructions on CRAN
> (http://cran.r-project.org/contrib/extra/lyx/):
>
>
> http://yihui.name/en/2010/10/how-to-start-using-pgfsweave-in-l
Try this:
x$second <- NULL
On Thu, Dec 23, 2010 at 3:21 PM, Eduardo de Oliveira Horta <
eduardo.oliveiraho...@gmail.com> wrote:
> Hello,
>
> say I have an object
>
> > x = list(first = 10, second = 20, third = "Yeah!")
>
> and want to remove the $second element of that list. My first try was,
Hello,
say I have an object
> x = list(first = 10, second = 20, third = "Yeah!")
and want to remove the $second element of that list. My first try was, of
course,
> rm(x$second)
which gave me the following error message
> Error in rm(x$second) : ... must contain names or character strings
An
On Thu, Dec 23, 2010 at 8:07 AM, Amy Milano wrote:
> Dear R helpers!
>
> Let me first wish all of you "Merry Christmas and Very Happy New year 2011"
>
> "Christmas day is a day of Joy and Charity,
> May God make you rich in both" - Phillips Brooks
>
> ##
>
>> input <- do.call(rbind, lapply(fileNames, function(.name){
> + .data <- read.table(.name, header = TRUE, as.is = TRUE)
> + # add file name to the data
> + .data$file <- .name
> + .data
> + }))
You can simplify this a little with plyr:
fileNames <- list.files(pattern = "file.*.c
Hi:
There appear to be several options, but it also seems that the amount of
work required to achieve the goal varies among options.
In situations like this, the sos package comes in handy. For example, it
showed me that your vioplot() function was in package vioplot (unmentioned):
library(sos)
Actually the issue is not the size of memory that is consumed, but that
memory allocation takes place and the object is copied in each iteration
of the "bad" loop you have given below. This is not required for the
second loop, where R can allocate the memory at once and does not need
to copy th
Hi all,
This subject treats exactly what I am looking for, thank you. Only I would
like to include the p-values (or t-values) in the dataframe, like this:
.id (Intercept) p-value(intercept) quartile
p-value(intercept)
1 CBP090802020.92140 0.00
Looks liek there was no answer to this question.
If you are installing R, you can select to install the tests directory
in the installer (default is not to install the tests).
Uwe Ligges
On 06.12.2010 12:21, elliott harrison wrote:
Hi,
I typically install new versions of R on windows usi
Dave,
I am a little confused. You ask about a triangle distribution, but
describe the situation as a relation between y and x. Do you really want a
piecewise linear fit of y to x? That could be gotten using nonlinear least
squares.
Dave
From:
Jinsong Zhao
To:
r-help@r-project.org
Date:
12/
On Wed, Dec 22, 2010 at 7:05 PM, Martin Morgan wrote:
> On 12/22/2010 05:49 PM, Paul Rigor wrote:
>> Hi,
>>
>> I was wondering if anyone has played around this this package called
>> "rdict"? It attempts to implement a hash table in R using skip lists. Just
>> came across it while trying to look f
Hi,
Does anyone know of a package for or any implementation of a Bayesian
Belief Network in R?
Thanks,
Walt
Walter R. Paczkowski, Ph.D.
Data Analytics Corp.
44 Hamilton Lane
Plainsboro, NJ 08536
(V) 609-936-8999
(F) 609-936-3733
w...@dataana
Hi,
Does anyone know of a package for or any implementation of a Bayesian
Belief Network in R?
Thanks,
Walt
Walter R. Paczkowski, Ph.D.
Data Analytics Corp.
44 Hamilton Lane
Plainsboro, NJ 08536
(V) 609-936-8999
(F) 609-936-3733
w...@dataana
Hi,
I have some data (lots of year,distance pairs), which I can
straightforwardly boxplot:
dists <- read.table("movedists.dat")
with(dists,plot(as.factor(V1),V2))
If I want to plot these data as violin plots using vioplot, this
approach doesn't work:
> with(dists,vioplot(as.factor(V1),V2))
Erro
Hi,
I'm just starting out with R and came across R_inferno.pdf by Patrick Burns
just yesterday - I recommend it!
His description of how 'growing' objects (e.g. obj <- c(obj,
additionalValue) eats up memory prompted me to rewrite a function (which
made such calls ~210 times) so that it used index
On 23/12/2010 9:03 AM, John Sorkin wrote:
Windows Vista
R 2.10 - I know it is old, I will update later today.
How might I perform a piece-wise linear regression where two linear segments
are separated by a single knot? In addition to estimating the slopes of the two
segments (or the slope in o
On Thu, 23 Dec 2010, John Sorkin wrote:
Windows Vista
R 2.10 - I know it is old, I will update later today.
How might I perform a piece-wise linear regression where two linear
segments are separated by a single knot? In addition to estimating the
slopes of the two segments (or the slope in on
Windows Vista
R 2.10 - I know it is old, I will update later today.
How might I perform a piece-wise linear regression where two linear segments
are separated by a single knot? In addition to estimating the slopes of the two
segments (or the slope in one segment and the difference between the sl
On 2010-12-23 2:19, David Bapst wrote:
Hello,
I have some xy data which clearly shows a non-monotonic, peaked
triangular trend. You can get an idea of what it looks like with:
x<-1:20
y<-c(2*x[1:10]+1,-2*x[11:20]+42)
I've tried fitting a quadratic, but it just doesn't the data-structure
with th
This should get you close:
> # get file names
> setwd('/temp')
> fileNames <- list.files(pattern = "file.*.csv")
> fileNames
[1] "file1.csv" "file2.csv" "file3.csv" "file4.csv"
> input <- do.call(rbind, lapply(fileNames, function(.name){
+ .data <- read.table(.name, header = TRUE, as.is = TRUE
I don't know if any specific package has a triangular distribution, but I
know you can fit a model using first degree b-splines with a single knot.
library(splines)
?bs
x <- 1:100
y <- rnorm(100, ifelse(x <50, x, 100-x), 15)
fit <- lm(y ~ bs(x, knots = 50, degree = 1))
--
Dear R helpers!
Let me first wish all of you "Merry Christmas and Very Happy New year 2011"
"Christmas day is a day of Joy and Charity,
May God make you rich in both" - Phillips Brooks
##
---
Hi all,
I study epidemiology of soilborne disease.
I have this ode model
dS/dt = - (rp(t) X + rs(t) I) * S
with X=1 ; rp(t) = ap exp( - bp*t) ;
rs(t) = as exp (-0.5 ( ln (t/ds) / bs)² )
The data I have are not directly the infected individuals (which is a
hidden state) but the Diseases ones (
Actually, this is described in "R Installation and Administration".
Best,
Uwe Ligges
On 21.12.2010 05:51, Andy Zhu wrote:
Never mind. Found the solution: the package coded the rtools path in
Makevars.win. So I was able to compile (but have another problem though). But
not sure if there is a
Thanks for your answers on R-help, although it is not very helpful
- not to cite / quote the original question
- not to answer to the questioner who may not be subscribed to the
mailing list and hence may not recognize your answer at all.
Best wishes,
Uwe Ligges
On 21.12.2010 10:42, Angel Sa
On 21.12.2010 08:15, SNV Krishna wrote:
Hi Dennis,
I am looking for similar function and this post is useful. But a strange
thing is happening when I try which I couldn't figure out (details below).
Could you or anyone help me understand why this is so?
df = data.frame(date = seq(as.Date("20
On 23.12.2010 02:17, Raquel Rangel de Meireles Guimarães wrote:
Hi all,
Hope someone could help me.
I am trying to run automatically the conversion of an Rwn file to a tex
file.
I am using windows 7, and cygwin.
I tried to run automatically the Sweave.sh script, in its the most
recent versi
Since we do not have the data, it is hard for us to reproduce and debug.
Uwe Ligges
On 21.12.2010 23:48, Dennis wrote:
Just curious if anyone else has got this error before, and if so,
would know what I could do (if anything) to get past it:
mtry<- tuneRF(training, trainingdata$class, ntre
On 21.12.2010 00:25, AlexZolot wrote:
See library(reshape)
Thanks for your answers on R-help, although it is not very helpful
- not to cite / quote the original question
- not to answer to the questioner who may not be subscribed to the
mailing list and hence may not recognize your answer
On Tue, Dec 21, 2010 at 8:40 AM, Gabor Grothendieck
wrote:
> On Tue, Dec 21, 2010 at 7:53 AM, Marius Hofert wrote:
>> Hi,
>>
>> I found the thread
>> http://r.789695.n4.nabble.com/Matrix-as-input-to-xyplot-lattice-proper-extended-formula-syntax-td896948.html
>> I used Gabor's approach and then t
Thanks Jorge, for your reply. In the end I changed my approach and used a
sub() strategy I found on this forum to recover the prefixes as below.
IDs.prefix <- sub("([^*])(_.*)", "\\1" , sampleIDs )
IDs.split <- cbind(sampleIDs , IDs.prefix)
Regards
M
--
View this message in context:
http://r.
Thanks Peter, for your succinctly helpful reply
The way R works is still a learning experience for me. I hope I'll be asking
fewer of these type of questions as I get to grips with R. In the meantime,
thanks for the help (and patience)
regards
M
--
View this message in context:
http://r.78969
If I understand your question
properly, then you are looking
for 'try' or 'tryCatch'. There
is an example of using these on
page 89 of 'The R Inferno'.
On 23/12/2010 04:13, Bogaso Christofer wrote:
Dear friends, hope I could be able to explain my problem through following
example. Please consid
Hi,
I'm currently using the 'rpart' package, and curious on whether we can enforce
the package to utilize some specified attributes, rather than having it choose
on its own.
Thanks.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/lis
62 matches
Mail list logo
