Hello,
I have a large number of time series, which needs to be transformed by
log or difference. Some of them are just processed by "level" (LV) without
any transformation. For that purpose, I produce a text file (.csv or .xls)
as follows:
DLN DLNDLN LV LV LV...
How can I read the
Dear R-list
I am having some trouble drawing a bar-graph with two groups, both of
which are stacked.
Here are my data in the dput format:
cs.not.log.bp <- (
structure(c(168, 69, 16, 69, 41, 6, 148, 6, 5, 4, 7, 4, 4, 2, 7, 2, 4,
2, 4, 2, 1, 0, 2, 0), .Dim = c(4L, 6L), .Dimnames = list(
I am mystified as to why you think you can source a snippet of one interpreted
language into a different compiled language.
Fortunately this is not the correct forum for your question, so I can punt.
Google suggests that you look at rdotnet.codeplex.com, and perhaps read their
documentation, an
Hello, I'm glad it worked.
You could have posted it in r-help, this may be of use to others...
Rui Barradas
Citando sb kr :
> Hi Rui Barradas, as you guessed the second option worked
>
>Thanks again
>
>lm
>
>> Date: Sun, 29 Apr 2012 16:52:45 -0700
> > From: ru
Hello
I would like to source an R script from within a C# .Net application equivalent
to:
source("my_r_code.r")
I can get this to run but am not sure how to retrieve R objects defined with
script my_r_code.r at runtime.
For example, if "my_r_code.r" contains
#-- contents of my_r_code.r---
Sounds like you have some text in your csv file. Open it with a text editor and
look at it. Some common problems are: alphabetic or symbol characters, spaces,
quotes around numbers. Also watch out for blank rows or columns.
Read the Posting Guide (mentioned at the bottom of every post). Tips: Th
Thank you for your example. I only skimmed it, but since both
solutions use nlevels and box.ratio it is no surprise we end up at the
same place (although I do think your g-median is nicer than my 3/4).
Thing is, I wouldn't call either of these "simple"... would be nice if
one could just query the
Hi all,
I'm hoping I might be able to get some help with some issues specifying priors
for MCMCglmm.
I'm trying to fit a gaussian glmm using MCMCglmm to a data set with two
(correlated) response variables. The response variables are both
logit-transformed proportions (there are a few reasons
I am a raw novice to R, playing around with a mini .csv dataset created in
Excel. I can read it in and the data looks OK in Excel and upon initial
inspection in R:
hikes <- read.csv("/Users/eproper/Desktop/hikes.csv", header=TRUE)
print(hikes)
does exactly what it is supposed to do.
Two of the v
Hi,
I have a bunch of data which is assumed to be instances of a geometric random
variable with outliers. How can I do a robust estimation of the parameter p so
that the effect of outliers is minimized?
As a part of the estimation process, I also need to know which are the outliers
in the data.
Hi,
In the following results I interpret exp(coef) as the factor that multiplies
the base hazard rate if the corresponding variable is TRUE. For example,
when the bucket is ks008 and fidelity <= 3, then the rate, compared to the
base rate h_0(t), is h(t) = 0.200 h_0(t). My question is then, to wha
hi all,can you help me? index moran is very difficut for me, i have data n
neighbor as enclosure:
please help me to make the program for find index moran value each
variabel,...thank very much
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That was it - detaching 'nlme' was the trick. Thanks Walmes and the rest.
David
On 5/1/2012 7:47 PM, David Stevens wrote:
> Yes - I also have nlme. Bad juju?
>
> David
>
> On 5/1/2012 1:32 PM, Walmes Zeviani wrote:
>> It could be a bad coexistence between packages in the same R session. Are
>> y
Yes - I also have nlme. Bad juju?
David
On 5/1/2012 1:32 PM, Walmes Zeviani wrote:
> It could be a bad coexistence between packages in the same R session. Are
> you using nlme and/or doBy packages too?
>
> Bests.
> Walmes.
>
> =
wlandres.net> writes:
>
> On 01-May-2012 19:58:41 Arnaud Mosnier wrote:
> > Dear UseRs,
> >
> > Is there a way to define the lower-upper bounds for parameters
> > fitted by optim using the Nelder-Mead method ?
> >
> > Thanks,
> > Arnaud
>
> The Nelder-Mead method does not provide built-in ca
? write.csv
Michael
On May 1, 2012, at 4:52 PM, PaulJr wrote:
> Hello R community,
>
>
>
> I basically created a normal distribution with mean 2500 and standard
> deviation = 450 with a sample of size 50 and assigned that to a variable
> named genvar2 with the following command:
>
>
>
> g
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of slipkid90515
> Sent: Tuesday, May 01, 2012 2:41 PM
> To: r-help@r-project.org
> Subject: Re: [R] Forecast Package for 2.15.0
>
> After poking around a little bit, I was able to i
Im sorry. I meant cor.test()
On Tue, May 1, 2012 at 6:16 PM, Aaditya Nanduri
wrote:
> Awesome! cor.text() is what I was looking for! Thank you Duncan!
>
>
> On Wed, Apr 25, 2012 at 9:43 AM, Duncan Murdoch
> wrote:
>
>> On 12-04-25 9:30 AM, Aaditya Nanduri wrote:
>>
>>> Hey everyone,
>>>
>>>
>>>
Awesome! cor.text() is what I was looking for! Thank you Duncan!
On Wed, Apr 25, 2012 at 9:43 AM, Duncan Murdoch wrote:
> On 12-04-25 9:30 AM, Aaditya Nanduri wrote:
>
>> Hey everyone,
>>
>>
>> I hope this finds you in good cheer.
>>
>> I just have a quick question: What is the function that outp
After poking around a little bit, I was able to install the package using the
"Install packages from local zip(s) files" command from the Packages menu.
I had to go grab the zip file from
"http://cran.stat.sfu.ca/bin/windows/contrib/2.15/"; because it looked like R
was going to a nonexistent URL w
Hello R community,
I basically created a normal distribution with mean 2500 and standard
deviation = 450 with a sample of size 50 and assigned that to a variable
named genvar2 with the following command:
genvar2<-rnorm(mean=2500, sd=450, n=50)
Now, the output of genvar2 generates de fol
On 01-May-2012 19:58:41 Arnaud Mosnier wrote:
> Dear UseRs,
>
> Is there a way to define the lower-upper bounds for parameters
> fitted by optim using the Nelder-Mead method ?
>
> Thanks,
> Arnaud
The Nelder-Mead method does not provide built-in capability
to set bounds on the range of paramater
On May 1, 2012, at 1:33 PM, Bert Gunter wrote:
AdvisoRs:
Is the following a bug, feature, hinky error message, or dumb Bert?
mtest <- matrix(1:12,nr=4)
dftest <- data.frame(mtest)
ix <- cbind(1:2,2:3)
mtest[ix] <- NA
mtest
[,1] [,2] [,3]
[1,]1 NA9
[2,]26 NA
[3,]3
No What have you tried?
OS? R build? Install method? Error messages?
Note this has some C++ dependencies so it might be a little tricky to compile
if you are missing necessary tools.
Michael
On May 1, 2012, at 2:05 PM, slipkid90515 wrote:
> Anyone else having problems installing this pa
?write.table
Googling it would find the same thing
-Roy
On May 1, 2012, at 1:41 PM, Paul Bernal wrote:
> Hello R community,
>
> I basically created a normal distribution with mean 2500 and standard
> deviation = 450 with a sample of size 50 and assigned that to a variable
> named genvar2 with
Hello R community,
I basically created a normal distribution with mean 2500 and standard
deviation = 450 with a sample of size 50 and assigned that to a variable
named genvar2 with the following command:
genvar2<-rnorm(mean=2500, sd=450, n=50)
Now, the output of genvar2 generates de following:
Hello,
Bert Gunter wrote
>
> Duncan:
>
> Maybe there **is** a bug, then.
>
> > zmat <- matrix(1:12,nr=4)
>> zdf <- data.frame(zmat)
>> ix <- cbind(c(FALSE,TRUE),c(TRUE,TRUE))
>> zmat[ix]
> [1] 2 3 4 6 7 8 10 11 12
>> zdf[ix]
> [1] 2 3 4 6 7 8 10 11 12
>> zmat[ix] <- NA
>> zmat
>
Hello,
I am using SSfol in nlme to fit some data for the change of N concentration
(N) in plant tissue over time (gdd). The model works nicely for 2 out of 3
treatments, so I would really like to use it, but it consistently has a bad
fit for my third treatment. I am pasting the figure for the th
I have two models, controlled by dummy variables to see if the models can be
combined into one model with similar intercepts and slopes. Has anyone tried
to conduct this type of test in R. I am utilizing the econometric idea of
hypothesis testing through the hypothesis of coincidence. I have tried
Hi all,
I am trying to create a list of all variable/value combinations in
environment().
When a function with unset arguments is called, the method I have been
using fails with a "missing argument" error. However it should be
possible to simply skip these missing objects in the generation o
Very helpful. One (possible) correction inline below...
On Thu, 30 Mar 2006, Ray Brownrigg wrote:
> > From: nhy303 at abdn.ac.uk
> >
> > I have plotted a map of the Barents Sea and surrounding coastline using:
> >
> > map('worldHires',ylim=c(50,85),xlim=c(5,65),fill=T,resolution=0)
> > map.axes()
P.S.
The way the logical matrix is constructed is NOT general purpose.
Quoting myself quoting Bert,
>
> Actually, it works, as long as the logical index matrix has the same
> dimensions as the data frame.
>
> zmat <- matrix(1:12,nr=4)
> zdf <- data.frame(zmat)
>
> # Numeric index matrix.
> ix <-
Anyone else having problems installing this package? Any ideas for fixing?
Thanks,
Jess
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Dear Users,
I have data that have different data columns (hair color, eye color, etc. )
with same item labels and I do not want to recode them like haircolor=brown,
etc. Is it possible to do it automatically?
Thanks right now for your tips and given directions.
--
Levent TERLEMEZ
[[al
Tom,
The sub argument will always put text at the bottom -- this is all plotting in
R not just image.plot
If you want two lines in the title just build in a new line:
z<- outer( 1:15, 1:10,"+")
image.plot( z, main="the title \n the subtitle")
Best,
Doug
Hi Rui,
You are awesome!!! It worked perfectly!!
Thanks
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On 12-05-01 3:57 PM, Nordlund, Dan (DSHS/RDA) wrote:
Bert,
I think this is what is needed for the data frame
ix<- cbind(1:2,2:3)
ixm<- matrix(FALSE,4,3)
ixm[ix]<- TRUE
zdf[ixm]<- NA
Hope this is helpful,
That's essentially what I did in adding the numeric indexing. The only
complication wa
Many thanks to all. I appreciate your kindness and patience.
The point is, of course, that matrix subscripting by logicals requires
different semantics than by numeric indices, as it must. I'd still say
this is a case of option 4, dumb Bert: I should have figured this out.
Duncan's proposed chang
On Wed, May 2, 2012 at 7:58 AM, Arnaud Mosnier wrote:
> Dear UseRs,
>
> Is there a way to define the lower-upper bounds for parameters fitted by
> optim using the Nelder-Mead method ?
>
It depends a bit on whether it's plausible that the solution is on the
boundary. If not, simply returning Inf
Dear UseRs,
Is there a way to define the lower-upper bounds for parameters fitted by
optim using the Nelder-Mead method ?
Thanks,
Arnaud
[[alternative HTML version deleted]]
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Bert,
I think this is what is needed for the data frame
ix <- cbind(1:2,2:3)
ixm <- matrix(FALSE,4,3)
ixm[ix] <- TRUE
zdf[ixm] <- NA
Hope this is helpful,
Dan
Daniel J. Nordlund
Washington State Department of Social and Health Services
Planning, Performance, and Accountability
Research and Dat
I have a repoducibe example here
http://ridiculas.wordpress.com/2011/11/23/media-e-desvio-padrao-de-muitas-variaveis-separado-por-grupos/
Sorry for it be in Portuguese.
Walmes.
==
Walmes Marques Zeviani
LEG (Laboratório de
It could be a bad coexistence between packages in the same R session. Are
you using nlme and/or doBy packages too?
Bests.
Walmes.
==
Walmes Marques Zeviani
LEG (Laboratório de Estatística e Geoinformação, 25.450418 S, 49.2317
On 01/05/2012 2:45 PM, Bert Gunter wrote:
Duncan:
Maybe there **is** a bug, then.
> zmat<- matrix(1:12,nr=4)
> zdf<- data.frame(zmat)
> ix<- cbind(c(FALSE,TRUE),c(TRUE,TRUE))
> zmat[ix]
[1] 2 3 4 6 7 8 10 11 12
> zdf[ix]
[1] 2 3 4 6 7 8 10 11 12
> zmat[ix]<- NA
> zmat
The difference is in recycling. If the logical matrix has the same
dimensions, it seems to work:
> jx <- cbind(c(FALSE, TRUE, FALSE, TRUE), c(TRUE, FALSE, TRUE, FALSE),
c(FALSE, TRUE, FALSE, TRUE))
> zmat[jx] <- NA
> zmat
[,1] [,2] [,3]
[1,]1 NA9
[2,] NA6 NA
[3,]3 NA
Can you give sessionInfo()? It is working fine for me.
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of David Stevens
> Sent: Tuesday, May 01, 2012 2:38 PM
> To: r-help@r-project.org
> Subject: [R] VarCorr procedure from lme4
>
Duncan:
Maybe there **is** a bug, then.
> zmat <- matrix(1:12,nr=4)
> zdf <- data.frame(zmat)
> ix <- cbind(c(FALSE,TRUE),c(TRUE,TRUE))
> zmat[ix]
[1] 2 3 4 6 7 8 10 11 12
> zdf[ix]
[1] 2 3 4 6 7 8 10 11 12
> zmat[ix] <- NA
> zmat
[,1] [,2] [,3]
[1,]159
[2,] NA N
Folks
In trying to use lmer for a hierarchical model, I encountered the
following message:
Error in UseMethod("VarCorr") :
no applicable method for 'VarCorr' applied to an object of class "mer"
foo.mer <- lmer(y ~ TP + (TP|M),data=joe.q)
> head(joe.q[,1:5])
TP M AB Trty
1 1
On Tue, May 1, 2012 at 2:12 PM, Nick Switanek wrote:
> Thank you, Sarah!
>
> Yes, unlist() looks like it will do just what I need. Thank you.
>
> I took a different tack. I'd changed the function returning A to coerce the
> row from the data.frame using as.numeric(). Any reason to prefer your way
On 01/05/2012 2:12 PM, Bert Gunter wrote:
Many thanks, Ista:
I only looked in "].default" so the answer is: Alternative 4: dumb
Bert. Rap knuckles with ruler.
Actually, indexing by a logical matrix doesn't make much sense to me
in either case, as it does not have the effect of selecting indivi
Thank you, Sarah!
Yes, unlist() looks like it will do just what I need. Thank you.
I took a different tack. I'd changed the function returning A to coerce the
row from the data.frame using as.numeric(). Any reason to prefer your way
or mine?
thanks again,
Nick
On Tue, May 1, 2012 at 2:08 PM, S
Many thanks, Ista:
I only looked in "].default" so the answer is: Alternative 4: dumb
Bert. Rap knuckles with ruler.
Actually, indexing by a logical matrix doesn't make much sense to me
in either case, as it does not have the effect of selecting individual
elements, which is what numeric matrix
Hi Nick,
On Tue, May 1, 2012 at 1:56 PM, Nick Switanek wrote:
> Thank you, Steve and Sarah, for your swift replies.
>
> I didn't know about dput(). class() returns "matrix" for A, B, and C, but
> here:
>
>> class(A)
> [1] "matrix"
>> class(B)
> [1] "matrix"
>> dput(A)
> structure(list(1239814462,
On 01-May-2012 17:33:23 Bert Gunter wrote:
> AdvisoRs:
>
> Is the following a bug, feature, hinky error message, or dumb Bert?
>
> mtest <- matrix(1:12,nr=4)
> dftest <- data.frame(mtest)
> ix <- cbind(1:2,2:3)
> mtest[ix] <- NA
> mtest
> [,1] [,2] [,3]
> [1,]1 NA9
> [2,]
Hi Bert,
The failure itself is the documented behavior: ?'[.data.frame' says
"Matrix indexing ('x[i]' with a logical or a 2-column integer
matrix 'i') using '[' is not recommended, and barely supported.
For extraction, 'x' is first coerced to a matrix. For
replacement, a logical m
Thank you, Steve and Sarah, for your swift replies.
I didn't know about dput(). class() returns "matrix" for A, B, and C, but
here:
> class(A)
[1] "matrix"
> class(B)
[1] "matrix"
> dput(A)
structure(list(1239814462, 1239814601, 14349, 3, 4, 0, 12, 46601,
17801, 12401, 106001), .Dim = c(1L, 1
AdvisoRs:
Is the following a bug, feature, hinky error message, or dumb Bert?
> mtest <- matrix(1:12,nr=4)
> dftest <- data.frame(mtest)
> ix <- cbind(1:2,2:3)
> mtest[ix] <- NA
> mtest
[,1] [,2] [,3]
[1,]1 NA9
[2,]26 NA
[3,]37 11
[4,]48 12
## But ...
Hi,
I think the issue is not "respecting the groups" but finding the
x-location of the center of bars in panel.barchart(groups,...). Don't
know about the memisc package, but doesn't look like it provides an
easy solution. This is how I do it:
http://www.mail-archive.com/r-help@r-project.org/msg1622
summary: how to make image.plot print a subtitle between the title and
the image, rather than under the image?
details:
I've got a project
https://github.com/TomRoche/ioapi-hack-R
that illustrates the use of (et al) the R packages {ncdf4, fields, M3}
for processing and visualizing IOAPI data.
Hi,
On Tue, May 1, 2012 at 11:52 AM, Nick Switanek wrote:
> Good morning,
>
> I'm running into trouble rbind-ing numeric matrices with differing numbers
> of rows. In particular, there seem to be issues whenever a one-row numeric
> matrix is involved.
>
> Assume A is a numeric matrix with 1 row a
Hi Nick,
We absolutely need a reproducible example, with code and data, to be
able to help you.
Because otherwise I can't replicate your problem:
> A <- matrix(1:5, nrow=1, ncol=5)
> B <- matrix(6:20, nrow=3, ncol=5)
> C <- rbind(A, B)
> A
[,1] [,2] [,3] [,4] [,5]
[1,]1234
Good morning,
I'm running into trouble rbind-ing numeric matrices with differing numbers
of rows. In particular, there seem to be issues whenever a one-row numeric
matrix is involved.
Assume A is a numeric matrix with 1 row and Y columns and B is a numeric
matrix with X rows and Y columns. Let C
Thank u!
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PLEASE
Hi
I have the following barchart to which I want to add error bars.
library(lattice)
barchart(Change~fTreat,groups=Process,change,
auto.key=list(points=FALSE,rectangles=TRUE),
panel=function(x, y,...){
panel.barchart(x,y,origin = 0,...);
Hello,
baconbeach wrote
>
> Thanks again for your swift response!!
>
> With your last line, I get
>
>> rowMeans(sapply(stor.confint, colMeans))
> 2.5 %97.5 %
> 0.3256882 0.4604677
>
> I need the values (2.5% and 97.5%) for each variable of my model. I don't
> think this what I am
Hi
I have the following barchart to which I want to add error bars.
library(lattice)
barchart(Change~fTreat,groups=Process,change,
auto.key=list(points=FALSE,rectangles=TRUE),
panel=function(x, y,...){
panel.barchart(x,y,origin = 0,...);
There is actually another approach which can do the job automatically;
see the function reformat_code() in R2roxygen (remember to back up
your Rd files before you use it).
If you document your package with roxygen2, things can be even easier
-- just call the function rab() to roxygenize and reform
On May 1, 2012, at 15:36 , R. Michael Weylandt wrote:
> I don't think you can do it within expand.grid() but something like
> this might work:
>
> rownames(x) <- apply(x, 1, paste, collapse = "")
>
Also
rownames(x) <- do.call(paste, c(x, sep=""))
or, in recent versions,
rownames(x) <- do.ca
Mike,
Try plot(pref, ..., scat1d.opts=list(frac=0.025, lwd=0.3, nhistSpike=i))
where i = 1 to always use spike histograms (default is to use them if n >=
2000) or i=1e7 to never use them and to always jitter instead. There are
many other scat1d options you can pass through scat1d.opts.
Frank
There's no reason that the optimum cannot be at the bounds. Bounded problems
really do
sometimes have solutions on those bounds.
Compute the unconstrained gradient of your objective function at the bounds and
see if the
function is reduced when going across the bounds. The function here is assum
I don't think you can do it within expand.grid() but something like
this might work:
rownames(x) <- apply(x, 1, paste, collapse = "")
Michael
On Tue, May 1, 2012 at 5:05 AM, Kelly Cool wrote:
> Hi,
>
> I am extremely new to R, and was wondering if someone would be able to help
> me with a ques
Yes, i have install the Package Bolstad. And it works (sintegral).
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Hi,
I am extremely new to R, and was wondering if someone would be able to help me
with a question regarding the expand.grid function. When I input
expand.grid.rep <- function(x, n=1) do.call(expand.grid, rep(list(x),n))
expand.grid.rep(c("a", "b", "c"), 3)
my output is as follows,
Var1 Var2 V
I know this is three months old, but I had put it on a mental TODO list to see
whether it was something that could be fixed, and I finally got a little spare
time for that sort of thing. It turns out that it can NOT be fixed (without
fundamental design changes), so I thought I'd better record th
> -Original Message-
> From: sarah.gos...@gmail.com
> Sent: Mon, 30 Apr 2012 17:06:19 -0400
> To: jrkrid...@inbox.com
> Subject: Re: [R] Different varable lengths
>
> Because of the missing comma.
I knew I needed new glasses !
>
> On Mon, Apr 30, 2012 at 4:56 PM, John Kane wrote:
>>>
On 30.04.2012 18:44, borinot wrote:
Hello to all,
I'm new to R so I have a lot of problems with it, but I'll only ask the main
one.
I have clustered an environmental matrix
We do not know what that is. Where is the example data? See the posting
guide.
with 2 different methods,
Which
Yes, sorting longitude and latitude correctly solves the problem! However, this
only works near the Canaries. When selecting the January data (probable
location: South African waters) sunrise time (but not sunset time) for the
given coordinates is about 4 hours later than the local sunrise.
Sys
On 01.05.2012 00:12, strycker wrote:
> I'm interested in this question, too, not so I can hide code, but so I can
> run R code faster. It's been my experience that compiled code always runs
> faster than interpreted code. Can you explain further how to compile a
> front-end?
>
> --
> View this me
On May 1, 2012, at 06:47 , Jeff Newmiller wrote:
> This is not the RStudio support forum. I use it, I like it, but you need to
> learn the difference between R and RStudio.
>
> In this case, the fact that you are using RStudio is probably irrelevant.
> What is more relevant is that you are not
On Apr 30, 2012, at 20:27 , Saint wrote:
> Trying to do a regression for four variables. I get information only for two.
> The rest is marked "NA". Why? And what does NA mean?
Your design matrix is singular since p is constant and
p+Sweden.infl.dev=Sweden.infl, so two coefficients are set to m
On May 1, 2012, at 09:06 , Ulfa Hasanah wrote:
> what is "nb2listw" in index moran?
Did you try help(nb2listw) ?
--
Peter Dalgaard, Professor
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk Priv: pda..
? nb2listw
- Mail original -
De : Ulfa Hasanah
À : "r-h...@stat.math.ethz.ch"
Cc : "r-h...@stat.math.ethz.ch"
Envoyé le : Mardi 1 mai 2012 16h06
Objet : [R] index moran
what is "nb2listw" in index moran?
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what is "nb2listw" in index moran?
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Hi everyone, I'm a bit new here (and new to R), and I was trying to do an
OLR, and testing the parallel slope assumption seems be very important. I
browsed through past postings, and didn't find much to help me in this area.
I was wondering if anyone knew how I could go about doing this. Thank you.
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