Nice one - didn't think of the array at all as my brain was fixated on lists...
Thanks,
Murali
> Date: Fri, 24 May 2013 21:54:22 +0100
> From: ruipbarra...@sapo.pt
> To: fean...@hotmail.com
> CC: r-help@r-project.org
> Subject: Re: [R] matrix of random variables from a matrix of means and matrix
On 24/05/2013 15:21, Ulrike Grömping wrote:
Dear helpeRs,
I would like to include generation of a potentially large number of
plots, and modify the ask settings using the devAskNewPage function, and
return it back to its original state afterwards.
It is not unlikely that the user escapes from th
What you call "continuous" I call "cyclic" (with period NROW(x) in this case).
An easy to way to deal with this is to repeat the column three times, do the
original analysis, and return the results corresponding to the middle part of
the
repeated x. I think the following does the right thing, but
Hi List,
I'm not sure what I'm doing wrong here and would appreciate some help. I
create a NetCDF dataset as follows:
library(ncdf)
combined.ncdf <- with(new.env(), {
nLat <- 7
nLon <- 8
nTime <- 9
missing.val <- -999
filename <- file.path(tempdir(), 'combined_d6fg4s64s6g4l.nc
Have a look at Brian Ripleys polr in library(MASS) and multinom in
the library(nnet)
There are other packages as well so a search will give you more choices
Be careful to read the help pages carefully and make sure that you
know what you are testing.
HTH
Duncan
Duncan Mackay
Department of
Bingo!!!
This time it worked
Thanks arun
Thankyou very much indeed..
:D
Elisa
> Date: Fri, 24 May 2013 17:03:33 -0700
> From: smartpink...@yahoo.com
> Subject: Re: [R] Continuous columns of matrix
> To: eliza_bo...@hotmail.com
> CC: wdun...@tibco.com; r-help@r-project.org
>
> Hi,
>
> I c
Dear Rui,
i just noticed that there is one slight problem in the William' code. If you
see the results of column number 4 which are
[[4]] IndexValue
1 12.061959
2122.245474
where as we already dicussed that columns are continuous and 1 and 12 cant be
picked together.
so the
On 05/25/2013 06:08 AM, Jose Narillos de Santos wrote:
I have a 8 Groups composed by A,B, c, D components. The Group 9 is composed
by the 8 Groups but only components A and C.
I want to chart a plot with 1 big plot of the total Groups (from 1 to 8) on
the right and 8 mini pies on the left compo
Thanks rui.
you really are an R genius...
it might have taken me 1000 years to figure it out..
thanks
Elisa
> Date: Fri, 24 May 2013 23:38:51 +0100
> From: ruipbarra...@sapo.pt
> To: wdun...@tibco.com
> CC: eliza_bo...@hotmail.com; r-help@r-project.org
> Subject: Re: [R] Continuous columns of ma
Hello,
Just use
apply(mat, 2, f)
Rui Barradas
Em 24-05-2013 23:25, William Dunlap escreveu:
Are you trying to identify the highest point in each run of points higher than
a threshold,
akin to the problem of naming mountains so that each minor bump on a high ridge
does not
get its own name?
Dear William,
You loop worked well in case when i work with only one column. but wat if i
have the following data. how will i do it then?
structure(c(0.706461987893674, 0.998391468394261, 0.72402995269242,
1.70874688194537, 1.93906363083693, 0.89540353128442, 0.328327645695443,
0.427434603701202
Are you trying to identify the highest point in each run of points higher than
a threshold,
akin to the problem of naming mountains so that each minor bump on a high ridge
does not
get its own name? The following does that:
f <- function (x, threshold = 0.8 * max(x), plot=FALSE)
{
if (plot
The help page "?Startup" gives details on the startup procedures and the
order in which different files, variables, etc. are read/executed. That
may give you insight into where to set and option so that it is in place
when needed.
On Fri, May 24, 2013 at 3:46 PM, Benjamin Tyner wrote:
> Hi,
>
Hi,
I have some functions defined within etc/Rprofile.site which contain
embedded comments, but it seems the comments get stripped out when the
site profile is sourced into the base namespace. I'm thinking I need to
enable options(keep.source=TRUE) somewhere prior to the actual sourcing
of the sit
It is not OK.
Post to a statistical list, like stats.stackexchange.com , instead.
-- Bert
On Fri, May 24, 2013 at 1:55 PM, Troels Ring wrote:
> Dear friends - I hope it is OK to ask a question on the principles of
> survival analysis. I'm a medical person in this project, but wonders about
> t
Dear Rui,
Regarding your last reply there is a small additional question which i want to
ask. For the following column
> dput(mat[,1])c(0.563879907485297, 0.749077642331436, 0.681023650957497,
> 1.30140773002346, 1.46377246795771, 1.20312609775816, 0.651886452442823,
> 0.853749099839423, 1.04160
Dear friends - I hope it is OK to ask a question on the principles of
survival analysis. I'm a medical person in this project, but wonders
about the statistical methods proposed. We have a huge dataset and
assumption of proportional hazard is said to be fulfilled if survival
time is fractionate
Hello,
The first instruction doesn't call rnorm just once but it seems more
appropriate for your problem;
The second instruction calls rnorm just once.
set.seed(59187)
res1 <- replicate(10, matrix(rnorm(4, mean = a, sd = b), ncol = 2))
set.seed(59187)
res2 <- array(rnorm(40, mean = a, sd = b
Hello,
Can you please use ?dput to post your data?
The dataset you've posted doesn't make sense, you say you have 4
components but each row has 5 values, and that includes Group 9, which
should have only 2 values (or 4 values with 2 zeros).
Rui Barradas
Em 24-05-2013 21:08, Jose Narillos de
Hello,
I am analyzing a time series trajectory with many outliers.
When I model the outliers using arima (TSA library), the following program
statement runs like a charm:
m3.m495<-arima(Rate,order=c(1,0,1),seasonal=list(order=c(1,0,1),period=5),
xreg=data.frame(t74=1*(seq(Rate)==74),t107=1*(
I have a 8 Groups composed by A,B, c, D components. The Group 9 is composed
by the 8 Groups but only components A and C.
I want to chart a plot with 1 big plot of the total Groups (from 1 to 8) on
the right and 8 mini pies on the left composed by the 4 components (the
size of each pie of group sh
i knew it was something stunningly stupid. Thanks a lot.
John Kane
Kingston ON Canada
> -Original Message-
> From: marc_schwa...@me.com
> Sent: Fri, 24 May 2013 14:41:52 -0500
> To: jrkrid...@inbox.com
> Subject: Re: [R] xtable() with booktabs option problem
>
> On May 24, 2013, at 2:3
On May 24, 2013, at 2:36 PM, John Kane wrote:
> I could have sworn that yesterday xtable(file, booktabs = TRUE) was giving me
> toprule , midrule and bottomrule outout. Today :
>
> library(xtable)
> aa <- table( sample(letters[1:9], 100, replace = TRUE))
> xtable(aa,
> booktabs = TRU
I could have sworn that yesterday xtable(file, booktabs = TRUE) was giving me
toprule , midrule and bottomrule outout. Today :
library(xtable)
aa <- table( sample(letters[1:9], 100, replace = TRUE))
xtable(aa,
booktabs = TRUE)
gives me
\begin{table}[ht]
\centering
\begin{tabular}{r
Lines1<- readLines(textConnection("[1] 1.000 0.000 0.3425584 0.000
[1] 1.000 0.3425584 1.6693396 0.000
[1] 1.00 1.669340 9.918513 0.00
[1] 1.00 9.918513 24.00 0.00
-- more lines-
-
folks,
if i have a matrix of means:
a <- matrix(1:4, 2)
and a matrix of std deviations:
b <- matrix(5:8, 2)
and i want to create a matrix X of random variates such that X[i, j] is a draw
from normal distribution with mean = a[i, j] and std dev = b[i, j], i think i
can do this?
X <- matrix(rnorm(
David Winsemius comcast.net> writes:
>
>
> On May 24, 2013, at 8:29 AM, Simmons, Susan J. wrote:
>
> > In the newest release of R (R 3.0.0), the "glm" package
> no longer supports logistic nor probit regression.
> Was this intentional? What package is best to use in the
> newest version of
This is exactly what I want! Thank you very much!
2013/5/24 Greg Snow <538...@gmail.com>
> Look at the 'system.file' function.
>
>
> On Fri, May 24, 2013 at 11:27 AM, John Pellman <
> john.samoylovich.pell...@gmail.com> wrote:
>
>> Hi!
>>
>> I'm trying to set up an R library for a common analys
Hello,
When considering linear function where dependent variable is a function of
lags of dependent variables ( co-variates are kind of auto
regressive).Question is .Can i take entire data set for rpart . Then
split data into training and testing and validate the model for testing
data.In test
Thankyou very very much arun.:Delisa
> Date: Fri, 24 May 2013 11:08:56 -0700
> From: smartpink...@yahoo.com
> Subject: Re: [R] Continuous columns of matrix
> To: eliza_bo...@hotmail.com
> CC: r-help@r-project.org; ruipbarra...@sapo.pt
>
> Hi,
> You may also try:
> mat: data
>
> lst1<-lapply(
Hi,
You may also try:
mat: data
lst1<-lapply(split(mat,col(mat)),function(x) {x1<- which(x>=0.8*max(x));x2<-
which.max(x);x1[abs(x1-x2)==1|length(x)-abs(x1-x2)==1]<-NA;rbind(index=x1[!is.na(x1)],values=x[x1[!is.na(x1)]])})
names(lst1)<-NULL
lst2<-apply(mat,2,function(x) do.call(rbind,fun2(x))) #
Look at the 'system.file' function.
On Fri, May 24, 2013 at 11:27 AM, John Pellman <
john.samoylovich.pell...@gmail.com> wrote:
> Hi!
>
> I'm trying to set up an R library for a common analysis that my lab does.
> This analysis involves the use of an external bash script, which I would
> like t
Is it possible to use function "glm" in case when my outcome variable has 5
different classes? I have seen examples only when using binomial outcome
variable.
What about using function "multinom"? How do I to get the signifigance and
the confidence levels of the coefficients and the value of goo
I'm trying to run a logit model in R which has only one predictor. I then
want to construct a data frame with the predictor values on one column and
the probabilities in another column.
Using LDA methodology, I'm able to do the following.
# RUN LDA
r <- lda(y ~ x)
## FIND AND PLOT MODEL PROBABIL
Hi!
I'm trying to set up an R library for a common analysis that my lab does.
This analysis involves the use of an external bash script, which I would
like to encapsulate within the R library. I have been looking at tutorials
that detail how to create packages, and many of them mention an
experi
I dont know of any package called "glm". Did you try
?glm
Kjetil
On Fri, May 24, 2013 at 5:29 PM, Simmons, Susan J. wrote:
> In the newest release of R (R 3.0.0), the "glm" package no longer supports
> logistic nor probit regression. Was this intentional? What package is
> best to use in the
On May 24, 2013, at 8:29 AM, Simmons, Susan J. wrote:
> In the newest release of R (R 3.0.0), the "glm" package no longer supports
> logistic nor probit regression. Was this intentional? What package is best
> to use in the newest version of R to perform logistic or probit regression?
>
I
In the newest release of R (R 3.0.0), the "glm" package no longer supports
logistic nor probit regression. Was this intentional? What package is best to
use in the newest version of R to perform logistic or probit regression?
[[alternative HTML version deleted]]
__
Thanks rui..That was all i wanted...
Elisa
> Date: Fri, 24 May 2013 17:02:56 +0100
> From: ruipbarra...@sapo.pt
> To: eliza_bo...@hotmail.com
> CC: b...@xs4all.nl; r-help@r-project.org
> Subject: Re: [R] Continuous columns of matrix
>
> Hello,
>
> No problem. Just change <0 to >= and Inf to -Inf
Hello,
No problem. Just change <0 to >= and Inf to -Inf:
fun2 <- function(x){
n <- length(x)
imx <- which.max(x)
if(imx == 1){
x[2] <- x[n] <- -Inf
}else if(imx == n){
x[1] <- x[n - 1] <- -Inf
}else{
x[imx -
Dear Rui,
I infact wanted to have something like the following..
suppose the columns are
structure(c(0.706461987893674, 0.998391468394261, 0.72402995269242,
1.70874688194537, 1.93906363083693, 0.89540353128442, 0.328327645695443,
0.427434603701202, 0.591932250254601, 0.444627635494183, 1.444077
I would suggest asking this on R-sig-geo.
https://stat.ethz.ch/mailman/listinfo/r-sig-geo
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Galina: The AIC, delta AIC, and AIC weights all reference an entire model
and provide no information on how you should interpret the individual
parameters within a model. If you believe based on your AIC weights that
the model with ZONE + LABRADOR TEA + YEAR + ZONE x LABRADOR TEA is a
reasonable
Hello,
Something like this?
fun2 <- function(x){
n <- length(x)
imx <- which.max(x)
if(imx == 1){
x[2] <- x[n] <- Inf
}else if(imx == n){
x[1] <- x[n - 1] <- Inf
}else{
x[imx - 1] <- Inf
x[im
Many thanks to Dirk and Brian!
The tips helped me a lot.
Kind regards!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
Dear helpeRs,
I would like to include generation of a potentially large number of
plots, and modify the ask settings using the devAskNewPage function, and
return it back to its original state afterwards.
It is not unlikely that the user escapes from the long list of plots
before reaching the e
Actually I think the one you want is 'FRED/DCOILWTICO'
-- David
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David Reiner
Sent: Friday, May 24, 2013 8:46 AM
To: Christofer Bogaso; r-help
Subject: Re: [R] Download data
Quandl p
I am working with spatial data in ggmap, generally with great success. I have a
huge data set with the coordinates in NAD 83 UTM Zone 11 (meters). To map the
data the coordinates were converted to Lat Long in GIS prior to use in R and
ggmap/ggplot. I am using hexagonal binning to aggregate the
Quandl package is your friend:
library(Quandl) # download and install if necessary
oil <- Quandl('FRED/WCOILWTICO', type='xts')
# Search the quandl.com site to make sure this is the data you want.
# I just put in your text string 'WTI - Cushing, Oklahoma' and got several
results which might be the
Dear Rui,Thankyou very much for your help. just for my own knowledge what if
want the values and index, which are less than or equal to 80% of the maximum
value other than those in the neighbors?? like if maximum is in row number 5 of
any column then the second maximum can be in any row other th
Probably you need to put the par() function after the postscript() function
- the par changes apply only to the current device, and there's no
postscript device until you start it.
But since you haven't provided an example, it's impossible to be certain.
Sarah
On Friday, May 24, 2013, Öhagen Pat
Hello,
Berend is right, it's at least confusing. To get just the index of the
maximum value in each column,
apply(mat, 2, which.max)
To get that index and the two neighbours (before and after, wraping
around) if they are greater than or equal to 80% of the maximum, try
fun <- function(x){
Hi Asis,
On 24 May 2013 at 11:10, Asis Hallab wrote:
| Dear R experts,
|
| recently I started developing a Rcpp package "OpenMPTest".
| Within that package I want to use OpenMP, as in the following code example:
|
| // header file
| #include
| using namespace Rcpp ;
| RcppExport SEXP testOpenM
I am printing three graphs into the same page using par(mfrow=c(1,3)) and the I
want to save the file as postscript format using postscript()
When input the postscript file into the manuscript the three graphs appear on
separate pages. What have I missed and done wrong?
Thank you in advan
There you go!!!
structure(c(0.706461987893674, 0.998391468394261, 0.72402995269242,
1.70874688194537, 1.93906363083693, 0.89540353128442, 0.328327645695443,
0.427434603701202, 0.591932250254601, 0.444627635494183, 1.44407704434405,
1.79150336746345, 0.94525563730664, 1.1025988539757, 0.94472640
On 24-05-2013, at 12:24, eliza botto wrote:
> Dear useRs,If i have a matrix, say, 12 rows and 6 columns. The columns are
> continuous. I want to find the index of maximum values and the actual
> maximum values. The maximum values in each column are the highest values and
> the values greater
This really is the wrong list: have you looked at the posting guide?
The non-Rcpp aspects belong on R-devel.
But in short, you cannot control whether the R installation supports
OpenMP. 'Writing R Extensions' tells you how to set up Makevars, so the
example has already been documented for you
Dear useRs,If i have a matrix, say, 12 rows and 6 columns. The columns are
continuous. I want to find the index of maximum values and the actual maximum
values. The maximum values in each column are the highest values and the values
greater than or equal to 80% of the maximum value. Moreover, i
Dear R experts,
recently I started developing a Rcpp package "OpenMPTest".
Within that package I want to use OpenMP, as in the following code example:
// header file
#include
using namespace Rcpp ;
RcppExport SEXP testOpenMP( SEXP nThreads ) ;
// cpp file
SEXP testOpenMP( SEXP nThreads ) {
BE
Hi
Beside of what Uwe recommends. You probably use some cycle. Why not to use
multipage pdf? I remember I once created pdf with more than 1000 pages without
any problem.
Regards
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On B
Hi,
I'm currently combining multiple plots using something along the lines
of the following pseudo-code:
library(grid)
grid.newpage()
tmpLayout <- grid.layout(
nrow=4,
ncol=2)
pushViewport(viewport(layout = tmpLayout))
and than proceeding with filling the viewports ... works fine, but f
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