Dear Vanessa,
Glad to know that it works.
Sorry, I misunderstood ur question initially because there were no duplicates
for "product" from response=="buy" in your initial dataset (tt).
Regarding the code: what i did in brief is:
1. Find the rows with response=="buy
indx<- which(dat[,colName]=="bu
The following minimal example Sweave file compiled properly in RStudio.
\documentclass{article}
\begin{document}
Example text outside R code here; we know the value of pi is \Sexpr{pi}.
<>=
set.seed(1213) # for reproducibility
x = cumsum(rnorm(100))
mean(x) # mean of x
plot(x, type = 'l') # B
I am using a MacBook Pro, 10.6.8, R version 3.0.1. and RStudio 0.97.551. I
entered your command in the Console Window in RStudio and got the following
reply:
> install.packages('tikzDevice', repos='http://r-forge.r-project.org',
> type='source')
Warning in install.packages :
package ‘tikzDevice’
It seems I can still install from source under Ubuntu:
install.packages('tikzDevice', repos='http://r-forge.r-project.org',
type='source')
If you are under Windows, I think you have to install RTools.
I'm cc'ing its author to see if there is still hope to get it back to
CRAN, or if someone else
All,
What is the current method for installing tikzDevice in R version 3.0.1? I'd
like to use it with knitr and RStudio.
Thanks.
D.
--
View this message in context:
http://r.789695.n4.nabble.com/tikzDevice-tp4672523.html
Sent from the R help mailing list archive at Nabble.com.
_
If you wanted to wrap it in a function:
fun1<- function(dat,colName,newColumn){
indx<- which(dat[,colName]=="buy")
dat[,newColumn]<-0
dat[unique(unlist(lapply(seq_along(indx),function(i){
x1<- if(i==length(indx)){
seq(indx[i],nrow(dat))
}
HI,
May be this is what you wanted.
#using tt1
indx<-which(tt1$response=="buy")
tt1$newcolumn<-0
tt1[unique(unlist(lapply(seq_along(indx),function(i){x1<-if(i==length(indx))
seq(indx[i],nrow(tt1)) else if((indx[i+1]-indx[i])==1) indx[i] else
seq(indx[i]+1,indx[i+1]-1);x2<-
tt1[unique(c(indx[1:i]
Dear all,,
thank you all for your help..Its been such a help but its not really
exactly what I am looking for. Apparently I havent explained the condition
very clearly. I hope this can works.
If the data on column product is duplicated from the previous row, (its
applied for response==buy and ==sa
Perhaps: ?findInterval
(you may need to do some type conversion first)
-- Bert
On Sat, Jul 27, 2013 at 3:28 PM, John Helly wrote:
> Hi.
>
> I've been puzzling about how to replace the nested loops below. The idea is
> that the B dataframe has rows with a posix datetime and the C dataframes has
On 13-07-27 2:50 PM, Jean-Luc Dupouey wrote:
Dear R-helpers,
I compared various programs for cubic spline smoothing, and it appeared
that smooth.spline ( stats version 3.0.1) seems to behave surprisingly.
For enough long series and low values of lambda (or spar), the results
of smooth.spline see
Dear R-helpers,
I compared various programs for cubic spline smoothing, and it appeared
that smooth.spline ( stats version 3.0.1) seems to behave surprisingly.
For enough long series and low values of lambda (or spar), the results
of smooth.spline seem to be different from those of sreg ( packa
Hi.
I've been puzzling about how to replace the nested loops below. The idea
is that the B dataframe has rows with a posix datetime and the C
dataframes has posix Start and End times. I want to assign a value to
the observations in B based in intersecting the appropriate
time-interval in C.
HI,
I couldn't get any error message with the data you provided.
return<- read.table(text="
ATI AMU
-1 0.734 9.003
0 0.999 2.001
1 3.097 -1.003
2 NA NA
3 NA 3.541
",sep="",header=TRUE)
median<- read.table(text="
ATI AMU
-1 3.224
Hi
Thanks for your hints. I would like to describe my problem better and give an
examle of the data that I use.
I conduct the event study and I need to create abnormal returns for the daily
stock prices. I have for each stock returns from time period of 8 years. For
some days I don't have the
Stanislav Aggerwal gmail.com> writes:
>
> I have searched the r-help archive and saw only one
> unanswered post related
> to mine.
Take a look at the r-sig-mixed-models (@r-project.org)
mailing list and archive ...
>
> My design is as follows.
>
>- y is Bernoulli response
>- x1 is
I have searched the r-help archive and saw only one unanswered post related
to mine.
My design is as follows.
- y is Bernoulli response
- x1 is continuous variable
- x2 is categorical (factor) variable with two levels
The experiment is completely within subjects. That is, each subject
r
I have not tried anything like that but have a look at
www.google.ca/url?sa=t&rct=j&q=&esrc=s&source=web&cd=3&ved=0CDkQFjAC&url=http%3A%2F%2Fstackoverflow.com%2Fquestions%2F7476022%2Fgeom-point-and-geom-line-for-multiple-datasets-on-same-graph-in-ggplot2&ei=MfHzUej7FoSergG1_ICYAw&usg=AFQjCNH2b72a6
HI,
set.seed(28)
dat1<- as.data.frame(matrix(sample(c(NA,1:20),100,replace=TRUE),ncol=10))
set.seed(49)
dat2<- as.data.frame(matrix(sample(c(NA,40:80),100,replace=TRUE),ncol=10))
lapply(seq_len(ncol(dat1)),function(i) {lm(dat2[,i]~dat1[,i])}) #works bcz the
default setting removes NA
Regarding
I did indeed install the r-base-dev.
However, I did not send to the Debian mailing list.
Thanks,
Erin
On Sat, Jul 27, 2013 at 12:27 AM, David Winsemius wrote:
>
> On Jul 26, 2013, at 9:45 PM, Erin Hodgess wrote:
>
> > Hello!
> >
> > I have just installed R on an Ubutnu machine (13.04)
>
> Did
So, I downloaded the source files of Hmisc and changed in the file latex.s line
688 'rotate' to 'sideways'. This does the work for landscape ctables in Latex.
I also wrote an email to the package maintainer. I consider this thread as
solved.
Best
Simon
On Jul 26, 2013, at 5:34 PM, Simon Ze
On Sat, Jul 27, 2013 at 3:08 PM, Duncan Murdoch
wrote:
> Your question is a little ambiguous. All characters are allowed in object
> names, but the parser will only recognize some of them if they are quoted in
> backticks.
>
> The ones it recognizes without the backticks are ones that the C isaln
On 13-07-27 7:36 AM, Liviu Andronic wrote:
Dear all,
Could someone please point me to the definitive list of valid
characters that are allowed in object names in R? I believe that the
following list covers them:
_.abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
but I would like to
Hi
Quick question. I am running a multiple regression function for each column of
two data sets. That means as a result I get several coefficients. I have a
problem because data that I use for regression contains NA. How can I ignore NA
in lm function. I use the following code for regression:
Hello,
(Apologies for the repost, but it appears that the original text was
garbled.)
I have recently discovered the modeest library, and am trying to understand
how to use it with non-numeric data (e.g. determining the most common last
name, or analysing customer demographics by zip code).
I ha
Dear all,
Could someone please point me to the definitive list of valid
characters that are allowed in object names in R? I believe that the
following list covers them:
_.abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
but I would like to make sure.
Thank you,
Liviu
--
Do you kn
Prof Brian Ripley stats.ox.ac.uk> writes:
> Basically Remote Desktop restricts the number of colours when connecting
> to a Windows Server machine, and interpolating rasters needs a lot of
> colours.
Hi Brain,
I looked into this further and have a solution.
1. On the server launch Remote Des
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