Dennis, David, The code I'm running is from here:
http://www.r-bloggers.com/nonparametric-copula-density-estimation/
s comes from here:
s {mgcv}
*Defining smooths in GAM formulae*
*Package: *
mgcv
*Version: *
1.7-24
*Description*
Function used in definition of smooth terms within
Hi All,
I want to simulate a random variable X which takes values 1 and 0 with
probabilities 75% and 25% respectively and then repeat the procedure 1
times.
I am sure this is trivial, I tried to look at the help pages online, but I
can't quite find it.
Appreciate your help.
Thanks and
Summary of my question:
I have a 5-way factorial design, two levels per factor, so 32 cells, and
I mostly just want the means and standard deviations for the contents of
every cell. Similarly, it would be nice to also have the range and maybe
some percentiles, if there is a function that
On 08/04/2013 03:34 PM, Berend Hasselman wrote:
...
I had a go with Google Translate and translated into Dutch.
The result is terrible. Garbage. Laughable.
It also translated R function names in the examples and some of the Rd
directives.
And look at the last line and admire what Google
Hello,
See the help page for ?sample.
X - sample(0:1, 1, replace = TRUE, prob = c(0.25, 0.75))
Hope this helps,
Rui Barradas
Em 04-08-2013 08:51, Preetam Pal escreveu:
Hi All,
I want to simulate a random variable X which takes values 1 and 0 with
probabilities 75% and 25% respectively
Hello again,
I am exploring the option how I can display my plot (generated within R) in
Browser (like IE, Chrome). Obviously one option is with googleVis. However
in that case I need to have internet access to display.
What are other choices available?
Thanks for your pointer.
Thanks and
So you looked at some unspecified help pages online and tried some unspecified
stuff? Try being more specific next time you post. For example, try reading the
footer of any R-help email. Note that it says read the Posting Guide, and
provide a reproducible example (at least of what you tried
So, I found a solution: First in the initialize method of class C coerce the
C object into a B object. Then call the next method in the list with the B
class object. Now, in the initialize method of class B the object is a B
object and the respective generateSpec method is called. Then, in the
On 08/04/2013 06:34 PM, Christofer Bogaso wrote:
Hello again,
I am exploring the option how I can display my plot (generated within R) in
Browser (like IE, Chrome). Obviously one option is with googleVis. However
in that case I need to have internet access to display.
What are other choices
On 04/08/2013 09:34, Christofer Bogaso wrote:
Hello again,
I am exploring the option how I can display my plot (generated within R) in
Browser (like IE, Chrome). Obviously one option is with googleVis. However
in that case I need to have internet access to display.
What are other choices
Thank you very much guys
On Sun, Aug 4, 2013 at 3:51 PM, Prof Brian Ripley rip...@stats.ox.ac.ukwrote:
On 04/08/2013 09:30, Rui Barradas wrote:
Hello,
See the help page for ?sample.
X - sample(0:1, 1, replace = TRUE, prob = c(0.25, 0.75))
Hope this helps,
?rbinom would have been
On 04/08/2013 09:30, Rui Barradas wrote:
Hello,
See the help page for ?sample.
X - sample(0:1, 1, replace = TRUE, prob = c(0.25, 0.75))
Hope this helps,
?rbinom would have been a better answer since simpler, faster,
algorithms are available in that case.
Or even
look at the shiny package on CRAN.
it is from RStudio
Rich
Sent from my iPhone
On Aug 4, 2013, at 4:34, Christofer Bogaso bogaso.christo...@gmail.com wrote:
Hello again,
I am exploring the option how I can display my plot (generated within R) in
Browser (like IE, Chrome). Obviously one
Because that exposes the identically named functions and forces the
user to sort them out, inviting mistakes, especially when trying to
maintain/update them. My view is that one should try to program to
make code as robust and maintainable as possible. Nevertheless, as I
said, maybe this approach
I tried it in French and there a few hiccups but it's not too bad.
Personally I'd like to see the help tranlated into English too.l
John Kane
Kingston ON Canada
-Original Message-
From: j...@bitwrit.com.au
Sent: Sun, 04 Aug 2013 10:28:42 +1000
To: tomas.gr...@collectionspro.eu
Bruce,
use the is.na function, e.g.,
Bats.cast[is.na(Bats.cast)] - 0
Bill
On Jul 28, 2013, at 8:12 AM, Bruce Miller batsnc...@gmail.com wrote:
Hi all,
I am using reshape2 to reformat a data frame and all is great using:
Bats.melt - melt(data = Bats)
Bats.cast - dcast(data =
... and learn to use the Help system to avoid wasting space on this
list and wasting your time waiting for an answer.
?NA
(what else?!) would have immediately gotten what you were looking for.
Cheers,
Bert
On Sun, Aug 4, 2013 at 9:09 AM, William Revelle li...@revelle.net wrote:
Bruce,
use
That instance of 's' is a function and you were offering it (multiplied by 5)
as a data argument to the theta parameter of 'persp'. I can't intuit what your
reasoning might have been because you haven't explained why you thought that
would succeed.
--
David
Sent from my iPhone
On Aug 3,
Hi,
I want to convert following string to a Date format (mm/dd/):
MyString - c(Sun Sep 01 00:00:00 EDT 2013, Sun Dec 01 00:00:00 EST 2013)
Can somebody point me if it is possible to do that?
Thank you.
__
R-help@r-project.org mailing list
Hello, I have a data.frame with repeating rows and corresponding value. For
instance, z will be an example of that.
x = c(a,a, a, b,b,b)
y = c(1.0, 1.2, 1.1, 1.01, 1.03, 1.0)
z = as.data.frame(cbind(x,y))
z
xy
1 a1
2 a 1.2
3 a 1.1
4 b 1.01
5 b 1.03
6 b1
Hello,
First of all, do _not_ create a data frame with
as.data.frame(cbind(...))
Instead, use
z = data.frame(x, y)
As for your question, try the following.
library(reshape2)
fun - function(z){
zs - split(z, x)
n - length(zs)
m - nrow(zs[[1]])
zz - cbind(id =
Hello,
You're insisting in as.data.frame(cbind(...)). Don't do that. Just see
the difference:
z = data.frame(x, y)
str(z)
'data.frame': 8 obs. of 2 variables:
$ x: Factor w/ 3 levels a,b,c: 1 1 1 2 2 2 3 3
$ y: num 1 1.2 1.1 1.01 1.03 1 2 3
z2 = as.data.frame(cbind(x,y))
str(z2)
On Sun, 4 Aug 2013, Ron Michael wrote:
Hi,
I want to convert following string to a Date format (mm/dd/):
MyString - c(Sun Sep 01 00:00:00 EDT 2013, Sun Dec 01 00:00:00 EST 2013)
Can somebody point me if it is possible to do that?
I think the answer to is it possible is a qualified
On 03/08/2013 10:27 PM, Martin Batholdy wrote:
I have to import multiple R-files.
Each file consists of several functions with the same function name across the
R-files.
When I import all files one by one (with source()) I overwrite the function
definition of the previous file until only the
Perhaps she forgot that you have to call the function by putting parentheses
and arguments after the function name.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.us
Wow... great and really compact solution. One follow-up question. How do I
solve the problem if the number of repeating values are different. For
instance, in the following z, the data value a and b are repeating 3
times, but c is only repeating 2 times. Hence, I will get an error. I am
fine if I
Hi gurus!
What I need to do is to find a model, which can predict what the *
observation* should look like given a *factor* input.
i am doing a simple linear fit in R:
lm(observation~0+factor, data=d), the R^2 is 0.002, which is really small.
however, when I do a 'SELECT AVG observation by
#actually, this would be more compact
data.frame(split(z[,-1],z$x))
A.K.
- Original Message -
From: arun smartpink...@yahoo.com
To: Brijesh Gulati brij...@gmail.com
Cc: R help r-help@r-project.org
Sent: Sunday, August 4, 2013 1:27 PM
Subject: Re: [R] question: data.frame data conversion
Hi,
May be:
z-data.frame(x,y,stringsAsFactors=FALSE)
simplify2array(split(z[,-1],z$x))
# a b
#[1,] 1.0 1.01
#[2,] 1.2 1.03
#[3,] 1.1 1.00
as.data.frame(simplify2array(split(z[,-1],z$x)))
A.K.
- Original Message -
From: Brijesh Gulati brij...@gmail.com
To:
Hi Brijesh,
No problem.
z- data.frame(x,y,stringsAsFactors=FALSE)
v1-max(with(z,tapply(x,list(x),length)))
res-data.frame(lapply(split(z[,-1],z$x),function(.x) {x1-if(length(.x)!=v1)
c(.x,rep(NA,v1-length(.x))) else .x;x1} ))
res
# a b c
#1 1.0 1.01 2
#2 1.2 1.03 3
#3 1.1 1.00 NA
HI,
May be this helps:
MyString1 - c(Sun Sep 01 00:20:00 EDT 2013, Sun Dec 01 00:00:00 EST 2013)
as.POSIXct(gsub(EDT|EST,,MyString1), format=%a %b %d %H:%M:%S %Y)
#[1] 2013-09-01 00:20:00 EDT 2013-12-01 00:00:00 EST
as.Date(gsub(EDT|EST,,MyString1), format=%a %b %d %H:%M:%S %Y)
#[1]
Hello Rui: Thanks for the solution. It does work to the specification. Just
one follow-up. I get an error if the number of repeating values are
different. For instance, in the following example, c is repeated only 2
times; whereas a and b three times. I am fine with the output shows NA
for the
You could also try:
z$id-with(z,ave(x,x,FUN=seq))
library(reshape2)
dcast(z,id~x,value.var=y)[-1]
# a b c
#1 1.0 1.01 2
#2 1.2 1.03 3
#3 1.1 1.00 NA
A.K.
- Original Message -
From: Rui Barradas ruipbarra...@sapo.pt
To: Brijesh Gulati brij...@gmail.com
Cc: r-help@r-project.org
Hi,
I need an advice.
I'm writing a Markov Chain Monte Carlo subroutine in F95 which should be
called from R. I noticed that the subroutine RANDOM_NUMBER takes the
seed from R (is that correct?).
I was wondering if is better initialize the random seed inside the F95
subroutine or use the R
Hello,
Hoe did you get 0.002? Can you ?dput your data?
d - read.table(text =
factor observation
-0.003 -2
-0.002 -2
-0.001 -1
0.000 1
0.001 0
0.002 1
0.003 2
, header = TRUE)
fit - lm(observation ~ 0 + factor, data = d)
summary(fit) # R2 is
The model given, ~0 +factor, omitted an intercept. R^2 is meaningless
without an intercept.
Further discussion should go to a statistics list like
stats.stackexchange.com, as these are statistics, not R, issues.
Cheers,
Bert
On Sun, Aug 4, 2013 at 1:41 PM, Rui Barradas ruipbarra...@sapo.pt
On 04/08/2013 21:38, Filippo wrote:
Hi,
I need an advice.
I'm writing a Markov Chain Monte Carlo subroutine in F95 which should be
called from R. I noticed that the subroutine RANDOM_NUMBER takes the
seed from R (is that correct?).
It is not correct.
I was wondering if is better initialize
Hi Filippo,
I would advice you to use the RcppArmadillo package - maybe in combination with
the inline package. It is extremely fast and very flexible. A simple RNGScope()
lets you take the RNG from R. I myself programmed an MCMC sampler with this
package and it is much faster, than the one I
Hi,
My question is how to make panel sizes variable in box plots. I mean if a panel
has 10 box plots and another has only two, I need to make the later panel
thinner than the first.
Regards,
Fayez
Grad Student
UIUC, USA
__
R-help@r-project.org
Hi,
My question is how to make panel sizes variable in box plots. I mean if a panel
has 10 box plots and another has only two, I need to make the later panel
thinner than the first.
Regards,
Fayez
Grad Student
UIUC, USA
__
R-help@r-project.org
On 05/08/13 03:15, John Kane wrote:
(In a discussion on translating R help pages into other languages.)
SNIP
Personally I'd like to see the help tranlated into English too.
Fortune nomination.
cheers,
Rolf Turner
__
There are a variety of ways to make box plots (e.g. base graphics, lattice, and
ggplot2). As the message footer says, you should be reading the Posting Guide
and providing a reproducible example (with sample data).
---
Jeff
On 08/05/2013 08:01 AM, Aziz, Muhammad Fayez wrote:
Hi,
My question is how to make panel sizes variable in box plots. I mean if a panel
has 10 box plots and another has only two, I need to make the later panel
thinner than the first.
Hi Fayex,
Try this:
Hi Jeff,
Thank you for your response. Pardon my lapse. Please find attached the code,
data and output. I have used bwplot.
Fayez
From: Jeff Newmiller [jdnew...@dcn.davis.ca.us]
Sent: Sunday, August 04, 2013 5:29 PM
To: Aziz, Muhammad Fayez;
Hi Jim,
Your example works perfectly. Any possibility that the sizing could be
automated. I am using bwplot. I can also use a prepanel function if needed.
Please find attached the code, data and output.
Fayez
From: Jim Lemon [j...@bitwrit.com.au]
Thanks for your reply!
Sorry I did not clarify that I was using base64encode and base64decode
functions provide from caTools package. It seems that if I convert the
string to the raw type first, it still solves my problem.
My original problem actually is that I have a string:
secret -
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