On 18/04/2014 21:46, David Winsemius wrote:
On Apr 18, 2014, at 12:59 PM, Prof Brian Ripley wrote:
On 18/04/2014 19:46, Rui Barradas wrote:
Hello,
The reason why is that you've misspelled CET (not CEST)
Neither CET nor CEST are portable time-zone names. We have not been given the
'at a
On 20/04/2014 08:50, Prof Brian Ripley wrote:
On 18/04/2014 21:46, David Winsemius wrote:
On Apr 18, 2014, at 12:59 PM, Prof Brian Ripley wrote:
On 18/04/2014 19:46, Rui Barradas wrote:
Hello,
The reason why is that you've misspelled CET (not CEST)
Neither CET nor CEST are portable
Dear all,
I am getting data columnwise that I need to divide by the mean of another
column
If the column is the previous one this code works perfectly well:
fun1 - function(beginColumn, by, data) { indx - seq(beginColumn,
ncol(data), by = by) as.data.frame(t(100 - (t(data[,
Brian Willis b.h.willis at bham.ac.uk writes:
Hi All,
I need to be able to manipulate the names of the coefficients from
*ranef()*.
If there is any missing data when fitting a mixed model using lmer, no
estimate is returned for the associated level for that random effect. Thus
if the
Hi Boris,
yes I tried this way and it worked. The fact is that I wanted to be
compliant with the old code, I did not want to change anything. So I wanted
to find a new way to rewrite the code.
Thanks
~ Francesco Brundu
On 19 April 2014 23:18, Boris Steipe boris.ste...@utoronto.ca wrote:
Have
Thanks Boris for the detailed answer. I thought to make it backward
compatible because I did not know if gamma parameter would change the
result if absent. As far as I can see changes in my results are not
relevant, so I think to follow your advice to update the old code.
Thanks
~ Francesco
Hi Arul,
Thanks for your reply. I am trying your approach now. I will reply once
again with my result.
Regards,
Sathish
On Sat, Apr 19, 2014 at 6:43 PM, arun smartpink...@yahoo.com wrote:
Hi,
Without a reproducible example using ?dput() or the package name, it is a
bit difficult to
Hi AK,
First, your timely response is greatly appreciated.
Contrary to what you are getting, I am getting the below when I enter the
same code
lines1 - readLines(spares.csv)
head(lines1)
[1] Cust_ID,Parts1,FENDERS2,FENDERS
[4] 3,OIL FILTERS4,BMW SERVICE FLUIDS
R has no cells.
You need to do your homework by reading An Introduction to R , which
ships with R, or one of the many R web tutorials of your choice. What
you describe is trivial once you have made a minimal effort to learn
R. In particular, ?[ explains how to index data frames; but a
tutorial
Hi,
May be this helps:
fun1 - function(beginColumn, by, data) {
indx - seq(beginColumn, ncol(data), by = by)
dataNew - data[, indx[1]:ncol(data)]
indx1 - cumsum(seq(ncol(data)) %in% indx)
indx2 - indx1[indx1 != 0]
lst1 - lapply(split(seq_along(indx2), indx2), function(i) {
Hi Andre,
A slight correction:
fun1 - function(beginColumn, by, data) {
indx - seq(beginColumn, ncol(data), by = by)
dataNew - data[, indx[1]:ncol(data)]
indx1 - cumsum(seq(ncol(data)) %in% indx)
indx2 - indx1[indx1 != 0]
lst1 - lapply(split(seq_along(indx2), indx2),
Hello,
Please could anyone tell me the significance of the graded red-black color
when using scatterplot3d?
At first I thought it was just going from the very 'near' to the back of the
chart area, but as you can see from the pictures some of the points in the
back are bright red. The
On 20.04.2014 17:51, mfbx9jhy wrote:
Hello,
Please could anyone tell me the significance of the graded red-black color
when using scatterplot3d?
At first I thought it was just going from the very 'near' to the back of the
chart area, but as you can see from the pictures some of the points in
On Apr 20, 2014, at 2:16 AM, Prof Brian Ripley wrote:
On 20/04/2014 08:50, Prof Brian Ripley wrote:
On 18/04/2014 21:46, David Winsemius wrote:
On Apr 18, 2014, at 12:59 PM, Prof Brian Ripley wrote:
On 18/04/2014 19:46, Rui Barradas wrote:
Hello,
The reason why is that you've
I keep on trying from various networks but I still get the same error. I
don't this this has anything to do with network or ability to download the
package (as I can install other packages fine). This must be something in
base R or dependencies issues (that R is not spelling out).
I know R is
On 20/04/2014, 2:45 PM, Alpesh Pandya wrote:
I keep on trying from various networks but I still get the same error. I
don't this this has anything to do with network or ability to download the
package (as I can install other packages fine). This must be something in
base R or dependencies issues
Hard to help you when the problem simply does not happen for others.
As for Windows being not a focus, that is not at all true. I use it regularly
on Windows at work. That being said, there are thousands of packages and those
each involve their own subset of R users. There are also many
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