I agree with Bert. It is not clear what is generating a need for this
sequence, so it
is difficult to see what aspects need to be adjustable. If this specific
sequence is the only one you need, then Bert's code looks elegant to
me.
One note: c is a base function in R. Functions in R are
Elegance is in the eye of the beholder.
But I would have thought that anything you do would be some variation of:
c(rep(1:3,e=2,time=4),
rep(4:5,e=4,time=3),
rep(6:9,e=3,time=2) )
## yielding
[1] 1 1 2 2 3 3 1 1 2 2 3 3 1 1 2 2 3 3 1 1 2 2 3 3 4 4 4 4 5 5 5 5 4
4 4 4 5 5 5 5 4
[42] 4 4 4 5 5
Apologies. I assumed it was widely known. My mistake. The link is www.ta-lib.org
On May 23, 2015, at 5:57 PM, John Kane jrkrid...@inbox.com wrote:
We all know the power and usefulness of TA-Lib.
Well no, I've never even heard of it before. Can you give us a link or
something?
John
Hi, R-Help members,
I'm doing some webscraping. This time i need the image (url) of the
products of an ecommerce.
I can get the nodes where the urls are, but when trying to extract the URL,
i need to take 1
additional step:
src vs data-original: in the source code, some urls are in the src
Hi varun,
A few suggestions.
Learn to use the built in help system, whichever version (text, HTML,
PDF) you prefer.
Learn to use one of the search programs (see
http://cran.r-project.org/search.html)
Try to do every task that you can in R.
Jim
On Sat, May 23, 2015 at 9:01 AM, varun joshi
On 23.05.2015 11:10, Ragia Ibrahim wrote:
Dear group,
I have the following matrix
1 2 3 4 5 6 7 8 9 10
1 0 1 1 1 1 1 1 1 1 1
2 0 0 0 1 1 0 0 0 0 0
3 0 0 0 1 1 1 1 1 1 1
4 0 0 0 0 1 0 0 0 0 0
5 0 0 0 0 0 0 0 0 0 0
6 0 0 0 0 0 0 1 1 1 1
7 0 0 0 0 0 0 0 1 1 0
8 0 0 0 0 0 0 0 0
Hello,
Maybe something like the following. (Assuming your matrix is named 'mat')
mat[order(rowSums(mat)), ]
Hope this helps,
Rui Barradas
Em 23-05-2015 10:10, Ragia Ibrahim escreveu:
Dear group,
I have the following matrix
1 2 3 4 5 6 7 8 9 10
1 0 1 1 1 1 1 1 1 1 1
2 0 0 0 1 1 0 0
On 23.05.2015 01:07, Claire O'Quin wrote:
Hi There,
I am running a stepwise QTL for a backcross and got the following warning
message:
Warning message:
In lastout[[i]] - (max(lastout[[i]]) - dropresult[rn == qn[i], 3]) :
longer object length is not a multiple of shorter object length
So
Dear group,
I have the following matrix
1 2 3 4 5 6 7 8 9 10
1 0 1 1 1 1 1 1 1 1 1
2 0 0 0 1 1 0 0 0 0 0
3 0 0 0 1 1 1 1 1 1 1
4 0 0 0 0 1 0 0 0 0 0
5 0 0 0 0 0 0 0 0 0 0
6 0 0 0 0 0 0 1 1 1 1
7 0 0 0 0 0 0 0 1 1 0
8 0 0 0 0 0 0 0 0 1 0
9 1 1 1 1 1 1 1 1 1 1
10 0 0 0 0 0 0 0 0
Thanks to all who answered me,
After reading all the mails I got, I did the following:- I logged in as root in
Debian Jessie- I started Rcmdr. it told me that some files are missing, it
offered me to get them,I did not fill in anything, just said ok, I had to
choose a website from
Many thanks
Date: Sat, 23 May 2015 11:55:07 +0200
From: lig...@statistik.tu-dortmund.de
To: ragi...@hotmail.com; r-help@r-project.org
Subject: Re: [R] order matrix regarding its content.
On 23.05.2015 11:10, Ragia Ibrahim wrote:
Dear group,
I have the following matrix
1 2 3
On Fri, 22 May 2015, varun joshi wrote:
What should I do to learn gradually?
Not sure how one gradually learns; I suppose it depends on what sort of
applications one wants to develop and the most effective means by which one
learns. Regardless, a good place to start is by buying and reading
Hi Mohammad
Welcome to the R-help list.
There probably is a fairly easy way to what you want but I think we probably
need a bit more background information on what you are trying to achieve. I
know I'm not exactly clear on your decision rule(s).
It would also be very useful to see some
Dear Peter,
On Sat, 23 May 2015 08:40:52 +0200
Peter van Summeren peter_van_summe...@hotmail.com wrote:
Thanks to all who answered me,
After reading all the mails I got, I did the following:- I logged in as root
in Debian Jessie- I started Rcmdr. it told me that some files are missing,
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
and http://adv-r.had.co.nz/Reproducibility.html
John Kane
Kingston ON Canada
-Original Message-
From: lig...@statistik.tu-dortmund.de
Sent: Sat, 23 May 2015 09:36:15 +0200
To:
Read R-help. :) Seriously, you will see all kinds of problems and questions.
Some of the simpler ones you can try yourself and see how your approach matches
other peoples.
Google around for some R blogs and see if you find any that are useful.
https://learnr.wordpress.com/ might be useful.
Sorry, I'll try to provide more detail about what I have done so far with
code and any relevant output results.
library(qtl)
sawfly.cross - read.cross(format=csv,
file=~/Desktop/Sawfly_data/QTL/Sawfly_QTL.csv, na.strings=NA,
genotypes=c(A, B), alleles=c(A, B), estimate.map=F)
--Read the following
Thank you for that information. I have found an rQTL help group and will
try to see if folks over there can help. I apologize for not doing a very
good job of communicating my issues over here. I will try my best to
produce a reproducible example and post it here if I don't make any
progress on
Dear R users,
I'd like to create a sequence/vector, for example,
1 1 2 2 3 3 1 1 2 2 3 3 1 1 2 2 3 3 1 1 2 2 3 3 4 4 4 4 5 5 5 5 4 4 4
4 5 5 5 5 4 4 4 4 5 5 5 5 6 6 6 7 7 7 8 8 8 9 9 9 6 6 6 7 7 7 8 8 8 9
9 9
So I did like this below.
a - 4
b - 3
c - 2
grp - c( rep(1:b, each=c,
Hello,
i need some help to use urnsamples from the package prob.
At the moment i use it in this way
A-as.matrix(urnsamples(1:25, size = 7,ordered=FALSE,replace=TRUE))
So I get the numbers 1 to 25 and choose 7 of them, but it is possible to get
one number more than one time.
But I want
Dear members,
We all know the power and usefulness of TA-Lib. There is a python wrapper for
it but, despite all my searching, I am unable to find it for R. Does anyone
know why? I am starting learning and using RStudio and would really like to be
able to call the TA-Lib functions from RStudio.
We all know the power and usefulness of TA-Lib.
Well no, I've never even heard of it before. Can you give us a link or
something?
John Kane
Kingston ON Canada
-Original Message-
From: c_c_ribe...@hotmail.com
Sent: Sat, 23 May 2015 17:13:15 +0200
To: r-help@r-project.org
Hi Clare,
I suspect that we need to see some data in dput() format. See the links I sent
earlier or have a look at ?dput for more information.
John Kane
Kingston ON Canada
-Original Message-
From: claire.oq...@uky.edu
Sent: Sat, 23 May 2015 07:40:03 -0400
To:
forgot to include the list on cc
Forwarded Message
Subject:Re: [R] compiling R with tuned BLAS
Date: Fri, 22 May 2015 10:40:13 -0400
From: Michael Gooch gooc...@gmail.com
To: Charles Determan cdeterma...@gmail.com
I am not an administrative user. I'm using a
Terribly uninformative web-site but it does give us some idea. Thanks
John Kane
Kingston ON Canada
-Original Message-
From: c_c_ribe...@hotmail.com
Sent: Sat, 23 May 2015 19:50:26 +0200
To: jrkrid...@inbox.com
Subject: Re: [R] Looking for help finding a wrapper/package to use
Actually your approach doesn't get around making a matrix of that size. If you
look at the code of urnsamples, (in prob:::urnsamples.default), you'll find
that it creates an intermediate object using expand.grid(). So you might as
well create the matrix yourself, extract all rows for which
Hi Kathryn,
Well, there's always:
make_num_seq-function(x=list(c(from=1,to=1,by=1,each=1,times=1))) {
return(c(unlist(lapply(x,
function(x) return(rep(seq(x[1],x[2],by=x[3]),each=x[4],times=x[5]))
}
make_num_seq(list(c(1,3,1,2,4),c(4,5,1,4,3),c(6,9,1,3,2)))
Jim
On Sun, May 24, 2015 at
Hi,
I am trying to fit the parameters of a distribution to my data using
entropy optimization. For this I am using the first 4 moments of my data
and trying to calibrate them to the most suitable distribution by
maximizing entropy. Since the moment constraints are nonlinear, I am trying
to use
Hello ,
I want to try R for statistics.
Therefore, I defined a function f with parameters m and k, which calculates
a to sqrt(x) proportional density function:
f - function(m,k)((1/(sum(sqrt(1:m*sqrt(k))
A function F sums the results in order to get a distribution function:
F -
29 matches
Mail list logo