Moses,
If I understand correctly, you are installed R and Rstudio.Please do find the
package(s) you would like to use.Once you run rstudio, you can search and
install the package(s) using the bottom right corner menu:Packages> Install>
install from Repository (Cran)> search the package you woul
Posting in HTML makes a mess of your code... learn to post in plain text.
Not sure what you thought you would accomplish by using as.vector... perhaps
you should read the help file ?as.vector.
Did you look at str( dat1 )?
Factors are more closely akin to integers than to characters. Indexing w
> On 2 Mar 2016, at 22:22, David L Carlson wrote:
>
> Another way would be to use matplot() or matlines():
>
>> lx<-c(0.4, 0.5, 0.6, 0.7)
>> x <- seq(1, 8, length.out=100)
>> myfun <- function(x, k) {(log(k)-(0.37273*log(x)-1.79389))/0.17941}
>> y <- sapply(lx, function(k) myfun(x, k))
>> matpl
Please, I need help from you. I am new to R.
I installed R, Rstudio and R Crans or packages that I will like to
use. Thanks for your help on that.
Right now, what do I do? Will I upload the CRAN packages already
installed, so that a GUI interface will come up.
I am working on Location Model and
Hi,Here i have written an example to explain my problem
## Data Generationdat<-data.frame(matrix(1:50,ncol=5))
rownames(dat)<-letters[1:10]
colnames(dat)<- c("SA1","SA2","SA3","SA4","SA5")
dat1<-data.frame(matrix(letters[1:20],ncol=4))
colnames(dat1)<-c("AA","BB","CC","DD")
## Row names
v1<-dat1[
Hi,
When very simple models are tested in step.gam, I have observed the some
difference in the final output result based upon the version of the
package tested. Is this an expected behavior or a bug in the latest
version of the gam package?
With gam 1.4:
> data(gam.data)
> gam.object <- gam
> On Mar 2, 2016, at 10:00 AM, John Hillier wrote:
>
>
> Dear All,
>
>
> I am a relative newbie to R, and am struggling to install packages on my
> laptop (although I have managed to on my desktop and a borrowed departmental
> laptop).
>
The words "my laptop" is rather uninformative. Base
Ruofei Mo【莫若飞】 <911mruofei tongji.edu.cn> writes:
>
> Hi, All,
>
> I have a question about how to generate correlated data with non-normal
> distribution? Basic, I have a variable a that follows a normal distribution,
> a ~ N(0,1), then I want to generate another variable b that follows a
> uni
Hi Jinggaofu,
Try this:
for(u in 1:9) {
pdffile<-paste(g[u],".pdf",sep="")
pdf(pdffile)
...
mtext(g[u],side=4)
If you index the vector g, it will return one or more character strings.
Jim
On Thu, Mar 3, 2016 at 9:52 AM, Jinggaofu Shi wrote:
> Hi, there
> I am new to R, here is an urgent que
1. Please spend some time with an R tutorial or two to become familiar
with R basics.
2. Please do not post in HTML. This is a plain text email list.
3. See e.g. ?sprintf or ?paste for your problem.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming al
Thanks again to all. This was highly educational for me. As it turned out
Mikiko's suggestion turned out to be most easily adaptable to my real problem.
I’m not at all able to evaluate relative efficiency at this point, but
fortunately this isn’t
an important factor (so far) in what I’m trying t
Hi, All,
I have a question about how to generate correlated data with non-normal
distribution? Basic, I have a variable a that follows a normal distribution,
a ~ N(0,1), then I want to generate another variable b that follows a
uniform distribution, b ~ U(0, 1). Most importantly, I want the cor
Thank you very much prof. Ravi,
That was very helpful. Is there a way to get the t and p value for the
coefficients?
Thanks
Alaa
> On Mar 2, 2016, at 10:05 AM, Ravi Varadhan wrote:
>
> There is nothing wrong with the optimization. It is a warning message.
> However, this is a good example
Hi, there
I am new to R, here is an urgent question.
I want to save several graphs by a for loop. But I don't know how to refer
the variable in the quotes.
Here is my code.
g<-c("g1","g2","g3","g4","g5","g6","g7","g8","g9")
for (u in 1:9) {pdf("g[u]".pdf")
+ plot(1,1, xlim=range(x), ylim=c(-5,5),
Dear All,
I am a relative newbie to R, and am struggling to install packages on my laptop
(although I have managed to on my desktop and a borrowed departmental laptop).
I have tried various packages with the same result. Illustration for
> install.packages("outliers")
leads to .
tRY HEGY.test() in R package pdr.
John C Frain
3 Aranleigh Park
Rathfarnham
Dublin 14
Ireland
www.tcd.ie/Economics/staff/frainj/home.html
mailto:fra...@tcd.ie
mailto:fra...@gmail.com
On 29 February 2016 at 19:14, Sarah Goslee wrote:
> Checking Rseek.org turns up this discussion thread:
> http:/
Another way would be to use matplot() or matlines():
> lx<-c(0.4, 0.5, 0.6, 0.7)
> x <- seq(1, 8, length.out=100)
> myfun <- function(x, k) {(log(k)-(0.37273*log(x)-1.79389))/0.17941}
> y <- sapply(lx, function(k) myfun(x, k))
> matplot(x, a, type="l", col="black", lty=1)
Sorry, I was assuming your data was a matrix (as you indicated in your
question).
Try:
write.table(as.matrix(PRdist), file = 'clipboard', sep = '\t', row.names =
F, col.names = F)
-Dan
On Wed, Mar 2, 2016 at 1:01 PM, Michael wrote:
> I got an error message.
>
>
> > write.table(PRdist, file =
Hi Michael,
If you are working in Windows:
# You can put the matrix directly into the clipboard
write.table(PRdist, file = 'clipboard', sep = '\t', row.names = F,
col.names = F)
The "sep" argument tells what character to use for separating columns.
Default for Excel is tab (i.e. '\t')
Default fo
Hi Michael,
Googling "export R data to Excel" gives LOTS of advice, including
packages that can write your data directly to Excel spreadsheets.
I don't use Excel, so I haven't tried any of those, but using
write.csv() to export your data will create something that my
colleagues who use Excel have
I can get R to calculate the distance that I want between my data points.
However, I am stuck trying to get R to output the data so I can paste it into
Excel. Instead, R outputs a matrix mess in the console.
Below are the steps I am taking to calculate the distance between my data.
Also, I h
Thanks, Roger:
I think Duncan's approach is far more efficient, but I believe the
following replicates your result and may be a bit easier to
understand.
f <- function(u) function(x) u * x^2
g <- function(u) function(x) u * log(x)
set.seed(3)
a <- runif(5)
h <- list()
hit <- list()
h[[1]] <- f(a[
On 02.03.2016 18:47, Roger Koenker wrote:
> I have a (remarkably ugly!!) code snippet (below) that, given
> two simple functions, f and g, generates
> a list of new functions h_{k+1} = h_k * g, k= 1, …, K. Surely, there are
> vastly
> better ways to do this. I don’t particularly care about th
This manufactures the functions without using eval by using substitute
to substitute i-1 and a[i] into an expression for the body which is
then assigned to the body of the function:
hh <- vector("list", 5)
hh[[1]] <- f(a[1])
for(i in 2:5) {
hh[[i]] <- hh[[1]]
body(hh[[i]]) <- substitute(
Or, if you want easy labels, you can play around with contour graphs.
?contour # will give you info on how to make contour plots
The basic idea is to construct a matrix of z-values...one z for every
combination of x and y
contour(x,y,z)
The x's would then be the x-values you want in
(0.37273*log
Thanks, Duncan and Bert,
Duncan’s version does replicate my result, Bert’s does something a bit
different,
now I just need some time to digest what you have done, and try to see how
and why. Many thanks!!!
Roger
url:www.econ.uiuc.edu/~rogerRoger Koenker
emailrkoen...@uiuc.e
On 02/03/2016 11:47 AM, Roger Koenker wrote:
I have a (remarkably ugly!!) code snippet (below) that, given
two simple functions, f and g, generates
a list of new functions h_{k+1} = h_k * g, k= 1, …, K. Surely, there are
vastly
better ways to do this. I don’t particularly care about the ret
Does this do what you want:
f <- function(u) function(x) u * x^2
g <- function(u) function(x) u * log(x)
set.seed(3)
a <- runif(5)
h <- list()
hit <- list()
h[[1]] <- f(a[1])
hit[[1]] <- f(a[1])
for(i in 2:5)h[[i]] <- eval(bquote(function(x).(h[[i-1]])(x) * g(a[i])(x)))
x <- 1:99/10
plot(x, h[[1]]
A simple solution that will give you an idea of some of the plot parameters:
x<-seq(1,10,length=1000) # values for x-axis
x0<-c(0.4,0.5,0.6,0.7)
miny<-(log(min(x0))-(0.37273*log(max(x))-1.79389))/0.17941 # minimum
y-value to show on graph
maxy<-(log(max(x0))-(0.37273*log(min(x))-1.79389))/0.17941
Hi, there I am new on R. I want to plot a graph like this.
The curves are created by these equations :
(log(0.4)-(0.37273*log(x)-1.79389))/0.17941,
(log(0.5)-(0.37273*log(x)-1.79389))/0.17941,
(log(0.6)-(0.37273*log(x)-1.79389))/0.17941, etc. The equations are
similar, the only difference is the f
I have a (remarkably ugly!!) code snippet (below) that, given
two simple functions, f and g, generates
a list of new functions h_{k+1} = h_k * g, k= 1, …, K. Surely, there are
vastly
better ways to do this. I don’t particularly care about the returned list,
I’d be happy to have the final h_K
On 03/02/2016 05:00 AM, r-help-requ...@r-project.org wrote:
I'd very much appreciate your help in resolving a problem that I'm having with
plotting a spline term.
I have a Cox PH model including a smoothing spline and a frailty term as
follows:
fit<-coxph(Surv(start,end,exit) ~ x + pspl
Hello all,
I'd like to run a simple discriminant analysis to jump into the topic with the
following dataset provided by a textbook:
Gruppe Einwohner Kosten
1 1642 478,2
1 2418 247,3
1 1417 223,6
1 2761 505,6
1 3991 399,3
1 2500 276
1 6261 542,5
1 3260 308,9
1 2516 453,6
1 4451 430,2
1 3504 413,8
There is nothing wrong with the optimization. It is a warning message.
However, this is a good example to show that one should not simply dismiss a
warning before understanding what it means. The MLE parameters are also large,
indicating that there is something funky about the model or the da
Hi Carol,
carol white via R-help writes:
> Hi,I have R v 3.0 installed /usr/... and the new version R-3.2.3 in my
> home under ubuntu. Is it correct to copy the R-3.2.3 directory into
> /usr/local/lib/R/ or should I reconfig and remake into
> /usr/local/lib/R/?
> Regards,
> Carol
The standard w
Hi,I have R v 3.0 installed /usr/... and the new version R-3.2.3 in my home
under ubuntu. Is it correct to copy the R-3.2.3 directory into
/usr/local/lib/R/ or should I reconfig and remake into /usr/local/lib/R/?
Regards,
Carol
[[alternative HTML version deleted]]
__
Hi Jean
As I said I am not a programmer, although I made some stuff with old languages
like Basic (not Visual) or some kind of assembly language from late 80s.
So your questions are out of my depth.
I hope others can give you better insight.
Cheers
Petr
> -Original Message-
> From: MA
Hi Martin,
And you forgot Git !
So for now, I gave up (abandonned ?) Git
And if Rstudio annoys me once more, I'll abandon it (skip it ?)
I like when things are simple and when I error occurs I like to have a message
...
Jean
PS I know something complicated that is very simple to use : SBB CFF
> MAURICE Jean <- externe >
> on Wed, 2 Mar 2016 08:50:50 + writes:
> The message with the bomb is R session .. see picture
> Jean
> De : jdnew...@dcn.davis.ca.us [mailto:jdnew...@dcn.davis.ca.us]
> Envoyé : mercredi 2 mars 2016 09:10
> À : MAURICE Jean - exter
> from late 80s
The good old time
Jean
-Message d'origine-
De : petr.pi...@precheza.cz [mailto:petr.pi...@precheza.cz]
Envoyé : mercredi 2 mars 2016 09:51
À : MAURICE Jean - externe; r-help@r-project.org
Objet : RE: path + name of the running R file
Hi Jean
As I said I am not a p
The message with the bomb is R session .. see picture
Jean
De : jdnew...@dcn.davis.ca.us [mailto:jdnew...@dcn.davis.ca.us]
Envoyé : mercredi 2 mars 2016 09:10
À : MAURICE Jean - externe; petr.pi...@precheza.cz; r-help@r-project.org
Objet : Re: [R] how to get the 'starting directory'
I am guessin
You can write "fill = NA" in the argument of element_rect(), that should
solve your problem.
On Tue, Mar 1, 2016 at 3:46 PM, Hoji, Akihiko wrote:
> A quick question. How come data points disappear when
> “theme(panel.border=element_rect()) is used and how could I get those
> points back on the
I suppose (think) that, in RStudio the shorcut alt+ctrl+R is converted to a
source command so it can work : I try.
Thanks
Jean
-Message d'origine-
De : drjimle...@gmail.com [mailto:drjimle...@gmail.com]
Envoyé : mercredi 2 mars 2016 09:13
À : MAURICE Jean - externe; r-help@r-project.org
I didn’t know that Rstudio was a separate tool ! So now, I have a new field to
manage !
Thanks
Jean
De : jdnew...@dcn.davis.ca.us [mailto:jdnew...@dcn.davis.ca.us]
Envoyé : mercredi 2 mars 2016 09:10
À : MAURICE Jean - externe; petr.pi...@precheza.cz; r-help@r-project.org
Objet : Re: [R] how
Hi Maurice,
If you have used "source" to run an R script, perhaps you could try
something like this:
get.running.file<-function(pattern="source",...) {
file1 <- tempfile("Rrawhist")
savehistory(file1)
rawhist <- readLines(file1)
unlink(file1)
last.source<-grep(pattern,rev(rawhist),value=TRUE)
I am guessing that it is RStudio that bombs... I have seen that bomb dialog
from RStudio but never from R. However, this is not the RStudio support
forum... you should be asking someone involved with that software.
--
Sent from my phone. Please excuse my brevity.
On March 1, 2016 11:38:00 PM P
Hi Petr,
I am an old FORTRAN programmer and new to R. The 'philosophy' of R is very very
far from FORTRAN ! So, may be I am wrong but :
I want to test 3 projects. In fact, these 3 projects are identical but not in
the same directory : one within Git (a source management), one on the server
and
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