his helps,
>
> Rui Barradas
>
> Às 15:31 de 06/05/20, Ana Marija escreveu:
> > Hi Rui,
> >
> > Thank you for getting back to me. Is there is a better way to
> > calculate Z scores if I have p values, SE and Beta?
> >
> > Thanks
> > Ana
>
I guess I can have
z-score=Beta/StdErr
On Wed, May 6, 2020 at 9:37 AM Ana Marija wrote:
>
> thanks, can you please tell em what would be the way not to get the
> absolute (always positive values)
>
> On Wed, May 6, 2020 at 9:33 AM Rui Barradas wrote:
> >
> > Hel
's all you need/want, then the
> > answer is yes, you can.
> >
> > Hope this helps,
> >
> > Rui Barradas
> >
> > Às 14:28 de 06/05/20, Ana Marija escreveu:
> >> Hello,
> >>
> >> Can I apply the
Hi Rui,
Thank you for getting back to me. Is there is a better way to
calculate Z scores if I have p values, SE and Beta?
Thanks
Ana
On Wed, May 6, 2020 at 9:27 AM Rui Barradas wrote:
>
> Hello,
>
> That gives the *absolute* t-scores. If it's all you need/want, then the
> ans
Hello,
Can I apply the quantile function qt() this way?
qt(pvals/2, 406-34, lower.tail = F)
to get the T-scores?
Thanks
Ama
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PLEASE do
"Patrick (Malone Quantitative)" <
> mal...@malonequantitative.com> wrote:
> >"I tried this but I am not sure if this is correct:"
> >
> >Does it provide the expected result for all possible combinations of
> >1/2/NA
> >for both variables?
> &g
e(b$PLASER==2 |
b$FLASER==2,2,NA))
Thanks
Ana
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2] <- 2
>
> #set the plaser
>
> b$pheno[b$plaser == 2] <- 2
>
>
> On 29 Apr 2020 22:44, Ana Marija wrote:
>
> Hi Rui,
>
> thanks for getting back to me
> so I tried your method and I got:
> > sum(b$PHENO==2, na.rm=T)
> [1] 828
> > sum(b$P
t;
> Hope this helps,
>
> Rui Barradas
>
> Às 20:42 de 29/04/20, Ana Marija escreveu:
> > Thanks, I did this:
> > b$PHENO<- ifelse(b$FLASER ==2 | b$PLASER ==2, 2, 1)
> >
> > On Wed, Apr 29, 2020 at 2:36 PM Ivan Krylov wrote:
> >>
> >>
Thanks, I did this:
b$PHENO<- ifelse(b$FLASER ==2 | b$PLASER ==2, 2, 1)
On Wed, Apr 29, 2020 at 2:36 PM Ivan Krylov wrote:
>
> On Wed, 29 Apr 2020 14:19:18 -0500
> Ana Marija wrote:
>
> > My conditions for creating a new column PHENO would be this:
> >
> > if
1 22
4: fam1005 G1005 1 11
5: fam1009 G1009 2 1 2
6: fam1052 G1052 1 1 1
...
Thanks
Ana
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this solved it:
m=merge(a,b,by="ID_1",all.y = T)
On Tue, Apr 21, 2020 at 9:53 AM Ana Marija wrote:
>
> Hello,
>
> > head(a)
>ID_1 pheno
> 1 0 B
> 2 fam1000_G1000 0
> 3 fam1001_G1001 0
> 4 fam1003_G1003 1
> 5
ease let me know how would I do that?
Thanks
Ana
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and provide com
inciertos que vivimos.
Ana
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at 7:01 PM Rasmus Liland wrote:
>
> On 2020-04-10 18:46 -0500, Ana Marija wrote:
> > so if I understand correctly you would just remove sep=" " from my codes?
> >
> > Thank you so much for working on this.
> > Is there is any chance you can change my origin
# adjust for the orders of sample pair
pair.samp <- paste(ibdlist$ID1, ibdlist$ID2, sep=" ")
plink.genome <- plink.genome[match(
paste(plink.genome$IID1, plink.genome$IID2, sep=" "), pair.samp), ]
On Fri, Apr 10, 2020 at 6:03 PM Rasmus Liland wrote
553.
On Fri, Apr 10, 2020 at 4:24 PM Rasmus Liland wrote:
>
> On 2020-04-10 15:38 -0500, Ana Marija wrote:
> | Hi,
> |
> | I have this code:
>
> Dear Ana,
>
> none of the ID tuples in the head
> outputs you provided matches, so I added
> two lines in ibdlis
NA NA
NA.4 NA NA NA NA NA NA NA NANA NA NA
NA.5 NA NA NA NA NA NA NA NANA NA NA
So nothing is matching here. Can you please advise,
Thanks
Ana
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h
Got it, thanks!
On Fri, Apr 10, 2020 at 2:54 PM Duncan Murdoch wrote:
>
> On 10/04/2020 3:46 p.m., Ana Marija wrote:
> > Hello,
> >
> > I would like to try this example in this link:
> > https://www.rdocumentation.org/packages/SNPRelate/versions/1.6.4/topics/snp
file(filename, "rb") :
file("") only supports open = "w+" and open = "w+b": using the former
On Fri, Apr 10, 2020 at 2:46 PM Ana Marija wrote:
>
> Hello,
>
> I would like to try this example in this link:
> https://www.rdocumentation.org
am running this?
Also do I need to have .gz format of output4.bed?
Thanks
Ana
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Thank you so much!
On Fri, Apr 10, 2020 at 12:00 PM Rasmus Liland wrote:
>
> On 2020-04-10 11:15 -0500, Ana Marija wrote:
> > I have a data frame (tot) with about
> > 2000 columns. How can I extract from
> > it all strings that start with E14?
> >
> >
E14?
Thanks
Ana
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and provide commented, minimal, self-contained,
009 11 1 2
6 fam1052_G1052 11 1 2
...
I would like to create a new column called PHENO which would satisfy these
conditions:
if CURRELIG=1 and RTNPTHY=1 than PHENO=1
if PLASER=2 than PHENO=2
otherwise is -9
Thanks
Ana
[[alternative HTML vers
GAAAC[A/G]TTTGACAGAGAATACA,Sty,+,-,y,,,127,phs18
1,769185,SNP_A-4303947,ss66273559,rs4040617,36.2,A,G,A,G,A,GCTGTGAGAGAGAACA[A/G]TGTCCCAAGCCC,Sty,+,+,n,,,127,phs18
1,775852,SNP_A-1886933,ss66317030,rs2980300,36.2,T,C,A,G,A,GAATGACTGTGTCTCT[C/T]TGAGTTAGTGAAGTCA,Nsp,-,+,y,,,127,phs18
rs4245756TC 0.07923 3496
I tried doing this in bash but I got empty file:
vi tst.awk
NR==FNR { map[$1,$2]=$5; next }
($1,$4) in map { $2=map[$1,$4]; print }
awk -f tst.awk FS=',' marker-info FS='\t' output11.frq > output11X.frq
Can this be done in R?
Thanks
d call:
>
> > ..., pch=16, col = c ("red", "blue"), ...
>
> And remove the fill argument.
>
>
>
> On 3/13/20, Ana Marija wrote:
> > I could make legend via this:
> > qq(fdr2_sorted$FDR.q.val2, main = "RG_All", pch = 16,
> > col=f
e this code in order
to have circles in the legend?
On Thu, Mar 12, 2020 at 11:04 AM Ana Marija wrote:
>
> Also how would I add legend to this plot?
>
> I searched qqman pages and there is no mention of that
>
> qq(fdr2_sorted$FDR.q.val2, main = "RG_All", pch = 16,
> co
Also how would I add legend to this plot?
I searched qqman pages and there is no mention of that
qq(fdr2_sorted$FDR.q.val2, main = "RG_All", pch = 16,
col=fdr1_sorted$group, cex = 0.8, las = 1)
On Thu, Mar 12, 2020 at 9:30 AM Ana Marija wrote:
>
> Hi Michael,
>
> can you
Hi Michael,
can you please send me a line of code showing how it would be done.
Thanks
Ana
On Thu, Mar 12, 2020 at 9:16 AM Michael Dewey wrote:
>
> Dear Ana
>
> You can specify the first three parameters to text() as vectors so it is
> all done in one call. That may or may
RANK AT MAX` = c(L,
1516L, 1427L, 1819L, 1216L, 491L), `LEADING EDGE` = c("tags=43%,
list=10%, signal=47%",
"tags=39%, list=13%, signal=45%", "tags=54%, list=12%, signal=61%",
"tags=45%, list=16%, signal=52%", "tags=38%, list=11%, signal=42%",
> Assuming that it's using the base graphics system, look at the
>> > graphics::text function.
>> >
>> > text (1:10, 1:10, LETTERS [1:10])
>> >
>> > If it's a different graphics system, then I don't know, but hopefully
>> > someone else wil
Thanks for getting back to me but I would need this text labels added in
this particular instance
On Wed, 11 Mar 2020 at 19:37, Abby Spurdle wrote:
> > and I would like to get the plot like the one in attach.
> > Please advise,
>
> This is a bad idea.
> Plots should be *easy* to interpret.
>
>
t=11%, signal=42% NA
1e-10
6: 0 0 491 tags=28%, list=4%, signal=29% NA
1e-10
and I would like to get the plot like the one in attach.
Please advise,
Ana
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Hi Jim,
I have in my code:
abline(0,1,col='red')
can you please tell me how to change my code to have it indeed running
from 0 to 1?
Thanks
Ana
On Fri, Feb 28, 2020 at 3:34 PM Jim Lemon wrote:
>
> Hi Ana,
> Look carefully at that red line. It goes through (0,0) and scoots off
&
t; head(biob272)
V1 V2
1 rs2089177 0.581204
2 rs4360974 0.418456
3 rs6502526 0.416670
4 rs8069906 0.568030
5 rs9895995 0.266746
6 rs9905280 0.510032
But the red, abline doesn't look like it is 1:1 line.
Can you please advise?
Thanks
Ana
__
R-
uot;,
plot.points=FALSE,
auto.key=TRUE)
and it is attached. The only thing I need to do is to make a line in
between peaks of the curves and put the star above that line. Not a p
value but just a star symbol.
Please advise,
Thanks
On Tue, Feb 11, 2020 at 3:46 PM Ana Marija wrote:
>
p value with t test, say it is 0.005
But how to add that p value in between distribution of the curves?
Thanks
Ana
On Tue, Feb 11, 2020 at 12:54 PM Ana Marija wrote:
>
> Hi,
>
> I have data like this:
>
> > head(a)
>X geneID inter.individual.variance
Hi,
Thanks for getting back to me. I need to have there two groups:
"nPDR.rg and "PDR.rg"
can you please let me know how my loop would look like just with those
two groups?
Thanks
Ana
On Mon, Feb 10, 2020 at 2:03 PM John Kane wrote:
>
> I must admit that I do no
g
5 0.635 -0.112 -0.0503 nPDR.rg
6 -0.723 0.153 -0.245 nPDR.rg
> tail(mds)
# A tibble: 6 x 4
Dim.1 Dim.2 Dim.3 cols
1 0.760 -0.732 0.568 NoD.rg
2 -0.0918 0.645 -0.189 NoD.rg
3 -0.336 0.756 0.120 NoD.rg
4 -0.439 -0.557 0.556 NoD.rg
5 -1.90 -0.858 -0.949 NoD.rg
6
4586251989901 0.0818947419096577 -0.6788584605>>
my original dat matrix has 132 columns and around 15000 rows
Can you please advise on this?
Thanks
Ana
On Tue, Feb 4, 2020 at 4:45 PM Bert Gunter wrote:
>
> Yes, a clear thinko... Thanks for the correction.
>
> -- Bert
>
> On
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along and
> sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Tue, Feb 4, 2020 at 12:41 PM Ana Marija
> wrote:
>>
Basically I would just reshuffle column names in each of 1000 permutations
how to do that and perform everything I described in my initial email
On Tue, 4 Feb 2020 at 14:46, Ana Marija wrote:
> Hi Bert,
>
> thanks for getting back to me. I have to permute those 132 columns
>
Hi Bert,
thanks for getting back to me. I have to permute those 132 columns
1000 times and perform the code given in the previous email.
Can you please show me how you would do that in the loop? This is also
a huge data set ...
Thanks
Ana
On Tue, Feb 4, 2020 at 2:34 PM Bert Gunter wrote
would have P.Value column and
these I would have plotted on the end to find the distribution of all
p values generated in those 1000 permutations.
Please advise,
Ana
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sided")
If not which test you would recommend in this case?
Thanks
Ana
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/O error
Use `synchronous` = NULL to turn off this warning.
Please advise,
Ana
On Sat, Feb 1, 2020 at 8:55 AM John Kane wrote:
>
> Hi Ana
> Stolen from https://gist.github.com/jwolfson/72bc7d7fd8d339955b38
> I cannot remember if you will need to install any other packag
Hi Ivan
Thanks for getting back to me. Can you please share with me some code I
would use to see what is in my database?
On Sat, 1 Feb 2020 at 06:19, Ivan Krylov wrote:
> On Fri, 31 Jan 2020 17:02:16 -0600
> Ana Marija wrote:
>
> > I have a database DGN-WB_0.5.db is there is a
Hello,
I have a database DGN-WB_0.5.db is there is a way to explore its
content in R? I don't know anything about this data base.
Thanks
Ana
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>
> Bert Gunter
>
>
>
>
> On Tue, Jan 28, 2020 at 9:29 AM Ana Marija
> wrote:
>>
>> Hello,
>>
>> I tried doing:
>> > library(vcfR)
>> > vcf <-
>> > read.vcfR("ALL.chr1.phase3_shapeit2_mvncall_integrated_v5a.20130502.genotyp
Hello,
I tried doing:
> library(vcfR)
> vcf <-
> read.vcfR("ALL.chr1.phase3_shapeit2_mvncall_integrated_v5a.20130502.genotypes.vcf",
> verbose = FALSE )
but this takes forever to load and I am not sure it is even working.
Any other suggestion on how I can read in .v
Hi Jim,
thanks for getting back to me.
Can you please confirm if you can see this plot in attach?
Thanks
Ana
On Thu, Jan 23, 2020 at 8:06 PM Jim Lemon wrote:
>
> Hi Ana,
> You seem to be working on an identification or classification problem.
> Your sample plot didn't come thro
Hello,
I have a data frame which looks like this:
> head(a,20)
rs pvalue
1: rs185642176 0.267407
2: rs184120752 0.787681
3: rs10904045 0.508162
4: rs35849539 0.875910
5: rs141633513 0.787759
6: rs4468273 0.542171
7: rs4567378 0.539484
8: rs7084251 0.126445
9:
Hello,
I have my normalized data matrix in file:normalizedDataMatrix_filtered.RData
how do I have that in .csv format?
Thanks
Ana
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PLEASE
("rect", xmin = 1, xmax = 2, ymin = 270, ymax =270,
alpha=0.3,colour = "black")
I am getting this error:
> p + annotate("text", x = 1.5, y = 280, label = "p = 0.008", size = 3.5) +
+ annotate("rect", xmin = 1, xmax = 2, ymin = 270, ymax =270
= 3.5) +
+ annotate("rect", xmin = 1, xmax = 2, ymin = 1, ymax =1,
alpha=0.3,colour = "black")
Error in annotate("text", x = 1.5, y = 1.2, label = "p = 2e-16", size = 3.5) :
unused arguments (x = 1.5, y = 1.2, label = "p = 2e-16", size = 3.5)
Als
2e-16")
I am getting:
Error in annotate("text", x = 1.5, y = 1.2, label = "p = 2e-16") :
unused arguments (x = 1.5, y = 1.2, label = "p = 2e-16")
On Thu, Jan 16, 2020 at 2:51 PM Ana Marija wrote:
>
> Hello,
>
> I have a code like this:
>
>
element_line(size = 0.1, color = "grey"),
panel.grid.major.y = element_blank(),
panel.grid.minor = element_blank(),axis.text.x =
ax.11.text,axis.text.y=ay.11.text
)
p
I was wondering is there is any way to decrease the amount of white
spaces around the bars?
Thanks
Ana
On T
") +
theme(aspect.ratio = 2/1,axis.title.x=element_text(size=1,face="bold"))
p
On Wed, Jan 8, 2020 at 12:52 PM Ana Marija wrote:
>
> Hello,
>
> I have this plot in attach. I was wondering how can I change my
> plotting code in order to remove these gray horiz
Hello,
I have this plot in attach. I was wondering how can I change my
plotting code in order to remove these gray horizontal background
lines but keep these two vertical lines? These two vertical lines
don't need to be gray, can be any other type of lines but they must be
at the same place. Also
were only a total of 4 multiple tests in your experiment,
> so FDR is low.
>
> Ding
>
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Ana Marija
> Sent: Tuesday, January 07, 2020 2:18 PM
> To: r-help
> Subject: [R] adjusted
just(pval,method="BH")
[1] 0.0001228876 0.0001503739 0.0002612551 0.0003900822
Can someone please explain what might be the issue.
Thanks
Ana
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Hello,
the error was in the code:
D = read.table(opt_input, head = FALSE, stringsAsFactors = FALSE)
I should have there header=TRUE
Sorry for bothering with this,
Ana
On Wed, Dec 18, 2019 at 2:44 PM Ana Marija wrote:
>
> Hi Ivan,
>
> here it is:
>
> > str(a)
> 'd
2
[13] 11073 11074 11075
> which(is.na(as.numeric(as.character(a[,19]
[1] 10757 11062 11063 11064 11065 11066 11067 11068 11069 11070 11071 11072
[13] 11073 11074 11075
columns 18 and 19 seems to be numeric, what is could be the issue?
On Wed, Dec 18, 2019 at 1:49 PM Ivan Krylov wrote:
>
&
002893770 0.340855 0.638936
6 T 404 338.232 1.05240 180.879 0.001846080 -0.458547 0.528947
V19
1 0.198142
2 0.529105
3 0.199394
4 0.261441
5 0.633917
6 0.524186
Please advise,
Ana
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Thanks for getting back to me, I resolved my problem with this:
library(reshape2)
c=dcast(a, rs ~ GENE)
d=merge(c,b,by="rs")
d[is.na(d)] <- 0
On Sun, Dec 8, 2019 at 11:03 PM Jim Lemon wrote:
>
> Hi Ana,
> Is this what you want?
>
> a<-read.table(text
315177
…
Please advise,
Ana
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-con
oaded my ENSG0154803.ld file in R as matrix (a) and:
library(matrixcalc)
is.singular.matrix(a, tol = 1e-08)
TRUE
Seems that my matrix is singular. What do you advice in this case?
Thanks
Ana
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p("File
not found: ", file)
filecluster<-read.table(file,header=T,sep=" ",dec=".")
beta<-as.matrix(filecluster[,2:(length(filecluster[1,])-1)])
when I was running it with just 3 columns in .matrix file.
Please advise, is it something wrong with the format
trix(filecluster[,2:(length(filecluster[1,])-1)])
now my input is like this:
https://github.com/eleporcu/TWMR/blob/master/ENSG419.matrix
so 4 columns instead of 3 like it was before and when I run it I get that
error above.
Please advise,
Ana
[[alternative HTML version deleted]]
than 2 genes sharing the same
rs.
Can you please advise about this
On Tue, Dec 3, 2019 at 2:16 PM Ana Marija
wrote:
> would this make sense for the previous:
> mt=na.omit(m, cols = c("V1.1","V1.2","V1.3","V1.4","V1.5"))
>
> On Tu
would this make sense for the previous:
mt=na.omit(m, cols = c("V1.1","V1.2","V1.3","V1.4","V1.5"))
On Tue, Dec 3, 2019 at 2:09 PM Ana Marija
wrote:
> I can perhaps do this:
>
> m=Reduce(function(x, y) merge(x, y, all=TRUE), list(s11
NA NA
ENSG0141030
V3.3 V4.3 V1.4 V3.4 V4.4 V1.5 V3.5 V4.5
6 3.06126e-28 0.726948NA NANA NA
...
but how to filter out this output (m) in order to remove all rows where I
have NA in any of these columns: V1.1,V1.2,V1.3,V1.4,V1.5
On Tue, Dec 3, 2019 at 1:48 PM Ana Mar
ENSG0127914
rs1208998 -0.0337989326337439 -0.00106024397995199
rs4729008 0.0630831868839983 0.00890783698397027
rs11772754 0.181375539335959 0.0012636115921931
rs10257459 0.0369962603988132 0.00509887844657462
rs17164876 0.0307882763321834 -0.00188979524322732
On Tue, Dec 3, 2019 at 1:40 PM Ana Marija
as one unique value in respective V1
I am trying to merge all at once all 5 data frames by the "rs" column.
Can you please help with this,
Ana
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HI Jeff,
the issue got resolved after I converted data in as.data.frame.
Thank you for the useful input!
Ana
On Tue, Dec 3, 2019 at 12:46 PM Jeff Newmiller
wrote:
> My guess would be that your key columns are factors with different levels.
> You have to be very careful manipulating f
TRUE
6: 5.46479e-05 -0.329785 0 5.962828e-05 TRUE
Please advise,
Thanks
Ana
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PLEASE do read the
x",sep=".")
> if (!file.exists(file)) stop("File not found: ", file)
> filecluster<-read.table(file,header=T,sep=" ",dec=".")
> ...
>
> The call the script from the command line as:
>
> $ Rscript MR.R ENSG0154803
>
> Th
154803.matrix
[1] "ENSG0154803.ld" "ENSG0154803.matrix"
Error: File not found: NA.matrix
Execution halted
On Sat, Nov 23, 2019 at 2:08 PM Henrik Bengtsson
wrote:
>
> Maybe it would help to add:
>
> file<-paste(gene,"matrix",sep=&quo
file(file, "rt") :
cannot open file 'NA.matrix': No such file or directory
Execution halted
Please advise
On Sat, Nov 23, 2019 at 12:13 PM Duncan Murdoch
wrote:
>
> On 23/11/2019 11:05 a.m., Ana Marija wrote:
> > Hi Ben,
> >
> > I am not sure what you mean wh
ble -> file
In addition: Warning message:
In file(file, "rt") :
cannot open file 'NA.matrix': No such file or directory
Execution halted
Please advise,
Ana
On Sat, Nov 23, 2019 at 9:44 AM Duncan Murdoch wrote:
>
> On 23/11/2019 10:26 a.m., Ana Marija wrote:
> > HI Ben
e.matrix': No such file or directory
Execution halted
Please advise,
Ana
On Sat, Nov 23, 2019 at 4:16 AM Ben Tupper wrote:
>
> Hi,
>
> I think you want this order...
>
> Rscript [options for R] script_file.R argument_1 argument_2 ...
>
> So, like this ...
>
> Rscript --n
t 7:44 PM Ben Tupper wrote:
>
> Hi,
>
> You might check the order of your arguments. Options come before the
> script filename. See the details here...
>
> https://www.rdocumentation.org/packages/utils/versions/3.6.1/topics/Rscript
>
> Ben
>
> On Fri, Nov 22
in file(file, "rt") : cannot open the connection
Calls: read.table -> file
In addition: Warning message:
In file(file, "rt") :
cannot open file '--no-restore.matrix': No such file or directory
Execution halted
Please advise,
Thanks
Ana
so improvement!
Regards,
Ana
On Fri, Nov 15, 2019 at 8:01 PM Peter Langfelder
wrote:
>
> Try hclust(as.dist(1-calc.rho), method = "average").
>
> Peter
>
> On Fri, Nov 15, 2019 at 10:02 AM Ana Marija
> wrote:
> >
> > HI Peter,
> >
> &
rs8071007
rs56044345
rs17804843
On Fri, Nov 15, 2019 at 12:03 PM Ana Marija wrote:
>
> HI Peter,
>
> Thank you for getting back to me and shedding light on this. I see
> your point, doing Jim's method:
>
> > keeprows<-apply(calc.rho,1,function(x) return(sum(x>0.8
quot;) :
missing value where TRUE/FALSE needed
Please advise.
Thanks
Ana
On Thu, Nov 14, 2019 at 7:37 PM Peter Langfelder
wrote:
>
> I suspect that you want to identify which variables are highly
> correlated, and then keep only "representative" variables, i.e.,
&g
the variables with at most one absolute value greater than
> 0.8 ignoring the diagonal values because I don't care about those". If
> so:
>
> colnames(calc.jim)[colSums(abs(calc.jim)>0.8)<3]
>
> Any more tricks?
>
> Jim
>
> On Fri, Nov 15, 2019 at 8:1
what would be the approach to remove variable that has at least 2
correlation coefficients >0.8?
this is the whole output of the head()
> head(calc.rho)
rs56192520 rs3764410 rs145984817 rs1807401 rs1807402 rs35350506
rs56192520 1.000 0.976 0.927 0.927 0.927
g an open mind is that people keep coming along and
> sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Thu, Nov 14, 2019 at 10:50 AM Ana Marija
> wrote:
>>
>> Hello,
>>
>> I have a
246
I would like to remove from this data all highly correlated variables,
with correlation more than 0.8
I tried this:
> data<- calc.rho[,!apply(calc.rho,2,function(x) any(abs(x) > 0.80))]
> dim(data)
[1] 246 0
Can you please advise,
Thanks
Ana
But this rem
Hi Michael,
Thank you so much for that valuable idea!
I will try first to clump or remove SNPs in LD and maybe the situation
would improve.
But this procedure of yours is definitely something that would come
handy in future!
Cheers,
Ana
On Wed, Nov 13, 2019 at 5:47 AM Michael Dewey wrote
why I selected only those with P<0.003 to put on QQ plot is because
the original data set contains 5556249 points and when I extract only
P<0.001 I am getting 3713 points. Is there is a way to plot the whole
data set, or choose only the representative points?
On Tue, Nov 12, 2019 at 3:42
the smallest p value in my dataset goes to 9.89e-08. How do I make
that known on the new QQ plot with multiplied with 1000 values
On Tue, Nov 12, 2019 at 3:37 PM Ana Marija wrote:
>
> Just do I need to change the axis when I multiply with 1000 and what
> should I put on my axis?
>
&
Just do I need to change the axis when I multiply with 1000 and what
should I put on my axis?
On Tue, Nov 12, 2019 at 3:07 PM Ana Marija wrote:
>
> Hi Duncan,
>
> yes I choose for QQ plot only P<1e-3 and multiplying everything with
> 1000 works great!
> This should no
Hi Duncan,
yes I choose for QQ plot only P<1e-3 and multiplying everything with
1000 works great!
This should not in my understanding influence the interpretation of
the plot, it is only changing the scale of axis.
Thank you so much,
Ana
On Tue, Nov 12, 2019 at 2:51 PM Duncan Murdoch wr
Hi,
what I know so far that this kind of QQ plot is an indication that
data has non zero mean:
https://stats.stackexchange.com/questions/280634/how-to-interpret-qq-plot-not-on-the-line
but is that an indication that something is wrong with the analysis?
Thanks
Ana
On Tue, Nov 12, 2019 at 2:00
details about my data if it is helpful:
> median(dd$P,na.rm = FALSE)
[1] 0.000444
> mean(dd$P,na.rm = FALSE)
[1] 0.000461
> min(dd$P,na.rm = FALSE)
[1] 9.89e-08
> max(dd$P,na.rm = FALSE)
[1] 0.001
On Tue, Nov 12, 2019 at 2:07 PM Ana Marija wrote:
>
> Hi,
>
> what I kn
Hi,
I was using this library, qqman
https://cran.r-project.org/web/packages/qqman/vignettes/qqman.html
to create QQ plot, attached. How would I change this default abline to
start from the beginning of my QQ line?
This is my code:
qq(dd$P, main = "Q-Q plot of GWAS p-values")
the - sign
>>
>> If you prefer, the "Tidyverse" world has what are purported to be more
>> user-friendly versions of such data handling functionality that you can use
>> instead.
>>
>>
>> Bert
>>
>> On Fri, Nov 8, 2019 at 7:38 AM A
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