Dear David,
I also use excel files for R. This is what I do
install.packages("readxl")
library(readxl)
mydata=read_excel('mydata.xlsx')
Hope this helps.
Best,
Maria
Στις Σάββατο 23 Σεπτεμβρίου 2023 στις 09:23:43 π.μ. GMT+1, ο χρήστης Parkhurst,
David έγραψε:
Hi Ivan,
yes you are right. I have many values close to zero and if I use log, they are
instantly transformed to negative values and then the bars show above. The sqrt
trans worked ok but when I used the pseudo_log_trans, it did the work!
Many thanks.
Kind regards,
Maria
Στις Δευτέρα
Dear Bert,
Thank you very much for the tip. The reason that I took the initiative to write
here is because I receive here as well questions about ggplot. Next time I will
use the ggplot help.
Maria
Στις Δευτέρα 17 Ιουλίου 2023 στις 12:20:25 π.μ. GMT+1, ο χρήστης Bert Gunter
έγραψε
I will find the ggplot help.
But I have tried everything, including what you have suggested and nothing
works.
Kind regards,
Maria
Στις Κυριακή 16 Ιουλίου 2023 στις 11:22:36 μ.μ. GMT+1, ο χρήστης CALUM POLWART
έγραψε:
Try adding
scale_y_log10()
This is a general R help list
e = "Dark2") + scale_color_brewer(palette = "Dark2")
I would very much appreciate your help. I am stuck.
Kind regards,
Maria
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= FALSE
strip.right = TRUE
likert(t(hellisheidi), ReferenceZero=.5, xlab="X-lab", ylab="Y-lab",
main="Stacked bar chart", col=c("#E94E1B", "#F7AA4E", "#BEBEBE", "#6193CE",
"#00508C", "#E94E1B", "#
for Component, instead of being the variable in the Samples.
I was hoping if you could help me on that.
Thank you very much in advance.
Kind regards,Maria
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Hi,
Could I please unsubscribe from the R-help mailing list?
Thanks
Eva
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PLEASE do read the
w = listw1), R= 500, zstats =
TRUE,zero.policy=TRUE)
I don't know if it is for my panel data, the missing values or
something else.
I tried also in Stata having similar issues.
thanks in advance and my apologies if it is very naive question, but I
am stuck.
all the best
Maria Je
Hi! I'm trying to perform propensity score matching on survey data and so
for each individual observation I have a statistical weight attached. My
question is: is there a way within the package to consider these weights in
the matching procedure?
Thank you very much.
--
Maria Cristina Mau
ackexchange.com
> >not here; I am pretty sure you'll receive lots of answers there.
> >
> >Cheers,
> >Bert
> >
> >
> >Bert Gunter
> >
> >"The trouble with having an open mind is that people keep coming along
> >and
> >
Hi R-list,
We have constructed a hurdle model some time ago.
Now we were able to gather new data in the same city (38 new sites), and
want to do an external validation to see if the model still performs ok.
All the books and lectures I have read say its the best validation option
but...
I have made
Hello,
I'm using the package pROC in RStudio to create my ROC-curves and I have
patients in my data - healthy or sick - in the column "Status" and the value
"SUVmax" to examine it.
I used the following code:
plot.roc(daten$Status,daten$SUVmax,percent=TRUE,ci=TRUE,print.auc=TRUE,main="ROC-Kurve
Dear Walter,
I tried to use scale_x_continuous but the arguments that I found was to change
the labels, the limits and the breaks. I was only able to increase the number
of the tick marks.
Best,Maria
Στις 3:14 μ.μ. Πέμπτη, 28 Ιουνίου 2018, ο/η Walter Pina
έγραψε:
Dear Maria, you
Dear Ulrik and all,
Thank you all so much; well, Ulrik's suggestion worked better. Very much
appreciated.
Best,Maria
Στις 11:17 π.μ. Δευτέρα, 25 Ιουνίου 2018, ο/η Ulrik Stervbo
έγραψε:
Hi Maria,
you are on the right way. The data.frame with the text must have the
same columns a
ASB, I got an errorann_text <-
data.frame(Q = 20, fit = 1.03, lab = "Text", asb = factor("ASB1",levels =
c("1","2","3")))
#Error in FUN(X[[i]], ...) : object 'ASB' not found
I would very much appreciate for your help.
Thank you very
Dear all,
I am writing as I would really need your help on the problem with gamm4. I have
tried to find a solution online but I wasn't very successful.
I am running a gamm4 model with an interaction between two variable using the
tensor term, t2. I have a group variable (super end group) with s
consdentcat2", "sexo", "estrato", "upa", "pesomorcc"), row.names = c(NA,
10L), class = "data.frame")##
bteste1 <-bteste[1:10, ]#bteste1 consdentcat2 sexo estrato upa
pesomorcc1
Dear Duncan
Many thanks for this; actually the vector solution works much better.
Best, Maria
Στις 12:27 μ.μ. Δευτέρα, 20 Νοεμβρίου 2017, ο/η Duncan Murdoch
έγραψε:
On 20/11/2017 7:09 AM, Maria Lathouri wrote:
> Dear all,
>
> I am really sorry for this. I have attached the s
Dear all,
I am really sorry for this. I have attached the script and a .csv file with an
example.
Hope this will help.
Many thanks,Maria
Στις 11:53 π.μ. Δευτέρα, 20 Νοεμβρίου 2017, ο/η Duncan Murdoch
έγραψε:
On 20/11/2017 6:38 AM, Maria Lathouri via R-help wrote:
> Dear all
colour changes in the legend but not the
actual bars in the plot. I don't know what I am doing wrong. I know that I am
missing something but I cannot figure it out.
I would very much appreciate for your help.
Many thanks,Maria
[[alternative HTML version deleted]]
__
doesn't go
through.
I will know for the next time.
Many thanks.
Regards,Maria
Στις 2:11 π.μ. Τρίτη, 12 Σεπτεμβρίου 2017, ο/η Duncan Mackay
έγραψε:
Hi Maria
Rule 1 make sure your data is in the right format
dat <- source("G:/1/savedat.txt")
> dat
$value
Locati
ed", "black", "red"), fill=c("red",
"black", "red"),
key=dat_key, scales = list(x = list(at = sdate, labels = format(sdate,
"%b-%y")), y=list(at=c(0, 20, 40, 60, 80))), xlab="Date",
panel = function(x, y, ...) {
Dear all
I am trying to make a plot in xyplot lattice by groups. I would like to show
"0" in y axis but I don't want to be aligned with the x axis. I want to be a
little bit above.
I have tried many options but I don't get what I want. I also tried ylim=c(0,
80) but both 0 and 80 are fully align
confidence intervals.
Kind regards,Maria
Στις 4:26 μ.μ. Δευτέρα, 12 Ιουνίου 2017, ο/η Duncan Mackay
έγραψε:
Hi Maria
If you have problems just start with a small model with predictions and then
plot with xyplot
the same applies to xyplot
Try
library(gamm4)
spring <- dget(file = &q
I am using a GAMM to model my data (this is as far as I know the only way I
can use the negative binomial distribution AND a correlation structure
within the model).
I measured animal detections (including zero detections) per hour at 3
different locations in an area. location is a factor in my mo
Hi Petr
I followed your suggestion and I have attached a saved txt file with the data
and the script using dput(). I hope this time will work.
But by the way your code worked as well.
Many thanks.
Kind regards,Maria
Στις 1:06 μ.μ. Τρίτη, 28 Φεβρουαρίου 2017, ο/η PIKAL Petr
έγραψε
if I can show every two years instead. I think it would be much
better.
Many thanks.
Kind regards,Maria
Στις 11:56 π.μ. Τρίτη, 28 Φεβρουαρίου 2017, ο/η Maria Lathouri via R-help
έγραψε:
Dear all,
Sorry about that. My mistake. Here is an example of my data
> head(aa) SDATE va
; 2012-12-10 0.484
I hope this helps.
Maria
Στις 10:00 μ.μ. Δευτέρα, 27 Φεβρουαρίου 2017, ο/η Jeff Newmiller
έγραψε:
While humorous, the term "Mexican Wall" is unlikely to be clear to the OP.
This is a reference to the mailing list anti-virus strategy of cutting out
attachments
Hi, I'm using the concurvity function to check for concurvity in my model.
The output I get when comparing to the rest of the model (ie full=TRUE)
many of the variables have concurvity values higher than 0.9. However when
comparing the terms pairwise most values are very small, less than 0.1
(with
ot(sdate, var1, type="l", xaxt="n")> axis(side=1, at=0:15,
> labels=strftime(d2, format="%m-%Y"), cex.axis=0.8,las=2)
But nothing happened. I cannot understand why it doesn't show anything.
I have attached the file as well in case you want to have a mo
Hi, I'm fitting a negative binomial GAM (using mgcv) to my data using
family=nb() so theta is estimated during the fitting process. When I then
extract this theta from the model and refit the same model with
family=negbin(theta) it gives a much lower AIC. I know using AIC to compare
negative binomi
ame thing.
I would very much appreciate if you could help me on that. Apparently, I am
missing something.
Thank you in advance.
Kind regards,Maria
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Dear all
I am stuck probably in a simple plotting question
My model is:model.1<-gamm4(y~s(x1, by=end.group)+Year+K1+k2+k3, data=..,
random=~(1|WB_ID/Site_ID))
where y is my dependent variable, x1 is the smooth covariate and I use the by
argument for the smooth term based on six different group
Good night,
How can I download and install R version 3.2.5 from cran mirror of
University of São Paulo, São Paulo?
Thanks for your support.
Maria Alice P. Jacques
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Hi,
I am Olga Viedma. I am running a Zero-inflated negative binomial (ZINB)
multi-level model using MCMCglmm package. I have a doubt. Can I use the "Liab"
outputs as fitted data, instead of the predicted values from "predict"? The
liab outputs fit very well with the observed data, whereas the
st; I was surprised by this result and not sure
if it's expected?
I am using R version 3.2.2 (2015-08-14) on Ubuntu 15.04
Thank you in advance,
Maria
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Dear all,
I would like to know if it is possible to estimate an integrated choice and
latent variable model with R. If it is so, please send me the name of the
respective package.
Best regards,
Maria Alice P. Jacques
Associated Researcher
University of Brasilia - Brazil
[[alternative
NA NA NA NA
hsa-let-7c -0.06436899 -0.03362183 -0.007440406 -0.2581606
-0.01517728> dim(fullcoefs)[1] 723 7
More speciffically, in this case I would expect some value for
"hsa-let-7a":"CYP1A2", as the penalty for it is 0.
Many thanks!
Maria
Dear all,
I am writing as I would like your help. I have a dataframe with two columns,
ASB and Flow, where the the first one has values 1, 2 or 3 and the second flow
data. Something like that:
ASBclass Flow1 11.51 9.2
2 10.5
3 6.7 ...
1, 1, 1, 1, 1, 1, 1)), .Names = c("regiao",
"estado", "cod_mun", "setor", "cap_int", "idade", "getario",
"sexo", "grp_etni", "quest_01", "quest_02", "density", "quest_03&
Hi,
I'm working with ordinal logistic regression and fitting the model with the
"clm" funtion of the ordinal package and would like to get the CI. According to
the Tutorial on fitting Cumulative Link Models with the ordinal Package, Rune
Haubo B Christensen (21 January 2015) you can run the OR,
somewhere and you can help :)
Best Livia
Fra: Livia Maria Vestergaard
Sendt: 19. maj 2015 10:16
Til: r-help@r-project.org
Emne: [R] Output interpretation: standard error of lm dummy variable
Hi guys
I have a statistical question to an analyse I ran in
Hi guys
I have a statistical question to an analyse I ran in R. It is a dummy variable
model with the 5 regions of Denmark as 4 independent dummy variables and price
as the dependent variable:
price = 10.325 - 0.176*Sjaeland - 0.368 * NJylland - 0.230*MJylland - 0.120*
Syddanmark
I understan
Hi Duncan
Thank you so much - it worked :)
Best
Livia
Fra: Duncan Mackay [dulca...@bigpond.com]
Sendt: 6. maj 2015 14:26
Til: R; Livia Maria Vestergaard
Emne: RE: [R] lm model exported from R to excel
Hi Livia
There are several html packages that
Hi all
I all. I am wondering whether anybody know how to export an output of an lm
model from R to excel in order to have excel recognize the table that comes and
divide the numbers in the table into columns and rows?
I really hope it is possible? :)
Best Livia
___
gt;
> load("id3.rda")
> >
> attach(id3)
> >
> >
> #transformando q13 em binária (o/1)
> >
>
q131<-ifelse(q13==1,0,ifelse(q13==2,1,ifelse(q13==3,1,
> > ifelse(q13==4,1,ifelse(q13==5,1,NA)
> > id3<-cbind(id3,q131)
> &
te...@utoronto.ca]
Sendt: 29. april 2015 20:25
Til: Livia Maria Vestergaard
Cc: r-help mailing list
Emne: Re: [R] LM() and time in R
Have a look at the help page for the function ts()
(type ?ts at the R prompt). Other than that, you haven't provided nearly
enough information for us to diagnos
inomial(link =
"logit"), data=id3)
tp1
library(ResourceSelection)
hoslem.test(tp1$q131, fitted(tp1), g=10)
dataframe: https://www.dropbox.com/s/9qrdf4mhd6tzypi/id3.rda?dl=0
______
Luciane Maria Pilotto
Mestre e Doutoranda em Saúde Bucal Cole
Hello,
I'm working with ordinal logistic regression model (polr) and would like to
test the proportional odds assumption. For this, I ran the binary logistic
regressions with varying cutpoints on the dependent variable, as described in
the following commands. When running the test of Hosmer and
Hello,
I need some help with a project that I’m working one.
Im trying to make a l regression model (lm) in r with time as independant
variable and gas prices as the depended.
But It seems like everything im trying to run it, R freeze, I think that I need
to tell R somehow that my time is time
Hi Peter,
Thank you so much for your tips. Have a nice Easter.
Gian
Il giovedì 2 aprile 2015, peter dalgaard ha scritto:
>
> > On 30 Mar 2015, at 17:11 , Gian Maria Niccolò Benucci <
> gian.benu...@gmail.com > wrote:
> >
> > Dear R-usrs,
> >
> > I am
Dear R-usrs,
I am trying to perform a MANOVA on a data frame with 31 columns about soil
parameters and 1 column containing the explanatory variable (Fraction) that
have three levels.
my code is the following:
datam <- read.table("data_manova2.csv", header=T, sep=",")
names(datam)
manova_fraction
Hi All,
First of all, I would like to wish you all a Happy New Year, full of
creativity, inspiration and prosperity.
Now, I have a data set with two uneven size parameters which is the following:
x1 x2
1 0.98 0.952 0.99 0.98
3 1.11 1.01
4
Dear all,
I'm using the package "survival" for adjusting the Cox model with multiple
events (Prentice, Williams and Peterson Model). I have several covariates,
some of them are time-dependent.
I'm using the function"cox.zph" to check the proportional hazards. Due to
the nature of the time-depende
Dear all,
I have a data frame (datos) of hourly wind speed and direction with 4columns
(1st date, 2nd hour, 3rd wind speed and 4rth wind direction). I have been able
to do the daily mean of the wind speed, but when I try to get the more frequent
wind direction of every day, it doesn't work. I ha
..@r-project.org]
> On Behalf Of Michael Friendly
> Sent: Thursday, July 10, 2014 3:22 AM
> To: Maria Judith Carmona H
> Cc: r-help@r-project.org; John Fox
> Subject: Re: [R] Cansisc: Error in eigen(eHe, symmetric = TRUE)
>
> Maria
>
> The variables
>
> Araceae
much more that I can say.
> Because I'm out of town and will be traveling tomorrow, I'm unlikely to be
> able to respond again for several days.
>
> Best,
> John
>
> On Wed, 9 Jul 2014 17:54:56 -0500
> Maria Judith Carmona H wrote:
> > Dear John,
> >
>
ning message:
In sqrt (wmd): NaNs produced
You see I get the same error.
Best regards,
Judith
On Wed, Jul 9, 2014 at 5:30 PM, John Fox wrote:
> Dear Maria Judith Carmona Higuita,
>
> Since you didn't include enough information (such as your access to your
> data) to reproduce the er
uot;std"), digits = 2)
The error is:
Error in eigen(eHe, symmetric = TRUE) : infinite or missing values in 'x'
In addition: Warning message:
In sqrt(wmd) : NaNs produced
Please help!
--
Maria Judith Carmona Higuita.
Estudiante de BiologÃa - Universidad de Antioquia
MedellÃn -
t;? I would like to build my model with these "sets"
only instead of listing every variable.
Also: is there a way of running all possible models with the different
combinations of these sets and/or variables, sort of like running ordistep for
ordinations?
Thanks a bunch i
ork with large
data sets.
Terry Therneau
____
De: Maria Helena Mourino Silva Nunes
Enviado: sexta-feira, 14 de Março de 2014 19:02
Para: r-help@r-project.org
Assunto: FrailtyHL package does not work
Dear all,
I want to describe the time interval between ma
Dear all,
I want to describe the time interval between mammography screenings as a
function of several clinical and demographic variables. For each woman (ID), I
have multiple events and each event corresponds to the time interval between
two consecutive mammography screenings. Also, women's da
Dear all,
I'm using the package "pscl" for adjusting a Zero-Inflated Negative Binomial
Regression to my data set. I would like to know if it is possible to compute
the standardised Pearson residuals from the output of this package.
Thanks in advanced.
Best regards,
Helena.
gnore that.
Do I need to join these parts into a single polygon? I tried this with
"unionSpatialPolygons" but another error appears: Error in unionSpatialPolygons
(sp1, IDS, threshold = NULL,: input lengths differ
Can anyone help me?
Att,
Maria Fernanda BonettiDoutoranda do Programa d
Hi there,
I just started using lme4 and I have a question about obtaining p-values. I'm
trying to get p-values for the output of a linear mixed-effects model. In my
experiment I have a 2 by 2 within subjects design, fully crossing two factors,
"Gram" and "Number". This is the command I used to
ce or earlier problems?
I have no idea if I am doing anything wrong or if there is a better
method for making the package, so any help will be really welcome.
Thank you,
Maria
--
The University of Edinburgh is a charitable body, registered in
Scotland, with registration number SC005336.
__
Thank you very much to you all, I'll play the codes and post my code once I
have tested it.
Cheers,
--
Gian
On 14 March 2013 16:27, John Kane wrote:
>
> The easiest way to supply data is to use the dput() function. Example
> with your file named "testfile":
> dput(testfile)
> Then copy
Hi again,
Thank you all for your support. I would love to have a graph in which two
variables are contemporary showed. For example a histogram and a curve
should be the perfect choice. I tried to use twoord.plot() but I am not
sure I understand how to manage the the arguments lx, ly, rx, ry... Any
Thank you all guys, for the useful information.
Gian
On 14 March 2013 14:14, Martin Morgan wrote:
> On 03/14/2013 02:19 AM, Gian Maria Niccolò Benucci wrote:
>
>> Dear all,
>>
>> I was wondering how to read DNA sequences in R, is there a specific
>> function and/
Hi all,
I would love to plot my data with R. I have abundance and frequency of fungal
taxonomic data that should be plotted in the same graph. In Microsoft Excel
is that possible but the graphic result is, as always, very poor. Is there
a function that may let me plot these data in R?
I have a mat
Dear all,
I was wondering how to read DNA sequences in R, is there a specific
function and/or a specific package for that?
Thank you very much in advance,
Gian
**
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https
Hi,
I am trying to install the rJava package in a Linux environment (Platform:
x86_64-suse-linux-gnu (64-bit)), where I am facing an issue which I cannot
solve so far and where I could require some help:
The installation seems to go fine, however in the last step of the installation
where load
Hi,
I have done a CCA with an environmental data matrix including both relative
abundance of plant species, soil properties (continuous, with different
units of concentrations), and factors that should explain my species
matrix.
Only after running the analysis have I realized that I should have d
Hi, I have a couple questions about fitting environmental (land use
factors, plant species presence-absence, and soil variables) constraints to
my CCA biplot. 1. After successfully plotting species and site scores in my
CCA, I have been trying to insert the biplot arrows of the environmental
constr
ress your
>> question to the author of that package (or use an appropriate title
>> line in your r-help posting).
>>
>> Best, John
>>
>> --**-- John Fox Sen.
>> William McMaster Prof. of Social Statistics Depa
I am currently working with R's polycor package and I have encountered a
problem. I tried to follow the steps as outlined in the sem.pdf file where
a CFA model is run using polychoric correlations. Every time I run the
command sem(model, data, N=.), I get the following warning message:
Warning mess
Thank you
On Mon, Oct 29, 2012 at 1:44 PM, R. Michael Weylandt <
michael.weyla...@gmail.com> wrote:
>
>
> On Oct 29, 2012, at 6:11 AM, sheenmaria wrote:
>
> > i need to find the best ticker from the group of some tickers.?
> > i also need to know on what basis we calculate the best ticker?
> >
Hello,
I'm using VAR models in R in order to obtain impulse responses of stock
market shock on US economy.
I have series of quarterly changes in real gdp, S&P 500 and quarterly level
of unemployment for 1985 - 2012 period.
My series are stationary. So I did all the steps below. However I don't
und
Hello,
I'm doing a research on the impulse responses in VAR models and I'm having
troubles in interpretation of R results.
My question is what is the shock of impulse variable that is produced to
obtain the response? Is it one-standard-deviation positive shock? If it is
so how can I obtain the re
Hi everyone,
Does anybody knows if there is an equivalent R function that gives the same
outcome as in "Explore" function in SPSS ?
(Analize->Descriptive Statistics->Explore)
It does a categorical vs quantitative variables analysis. ( But not linear
regression)
I need to compare intragroup (cat
n when 'replace = FALSE'
Why it does not work?
The whole dataset is composed of 536 rows and I just want to sample
randomly 200 of them...
Thank you in advance,
Gian
On 13 September 2012 14:01, Duncan Murdoch wrote:
> On 12-09-13 7:43 AM, Gian Maria Niccolò Benucci wrote:
>
>&g
8800 (ext. 5469)
Tel movil: 675 880 297
Fax: 925 268844
De: MARIA OLGA VIEDMA SILLERO
Enviado el: mié 26/09/2012 13:09
Para: ba...@stat.wisc.edu; bbol...@gmail.com; maech...@r-project.org
Asunto: problems making grids from lmer model
>
> Anna Freni Sterrantino
> Department of Statistics
> University of Bologna, Italy
> via Belle Arti 41, 40124 BO.
> --
> *Da:* Gian Maria Niccolò Benucci
> *A:* r-help@r-project.org
> *Inviato:* Giovedì 13 Settembre 2012 10:42
> *Oggetto:* [R] ran
Hi all,
I am wondering if do exist a function in R that allow me to sample or
choose randomly the rows (i.e., samples) inside a given matrix.
Thank you very much in advance.
Cheers,
--
Gian
[[alternative HTML version deleted]]
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R-help@r-pro
This is the named article:
http://ije.oxfordjournals.org/content/37/5/1161.long
maybe it can help you to help me... :-(
--
View this message in context:
http://r.789695.n4.nabble.com/INSTRUMENTAL-VARIABLES-WITH-BINARY-OUTCOMES-tp4642361p4642363.html
Sent from the R help mailing list archive
del1, model2) : The models are not nested
I wonder if anyone can help
Thanks in advance
Maria
----
Maria Manuel Angélico
IPMA, Portuguese Institute for Sea and Atmosphere
Lisboa , Portugal
tel: ++ 351 213027068
angel...@ipimar.pt
How can I perform cluster analysis using the mahalanobis distance instead of
the euclidean distance?
Thank you
Maria Froes
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Dear Mr/Mrs,
I have got the the data sets in the attachement (txt).
The fact is that on applying the easy method for JoSAE package on these
data sets I got the following error:
> result <- eblup.mse.f.wrap(domain.data = d.data, lme.obj = fit.lme1)
Error in solve.default(asympt.var.covar) :
Lapa
egards,
Ana Maria Dobre
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Hi Members,
Do exist the possibility to delete a command line into the history?
Fo example. If I' ve typed a line code that is wrong, Can I delete it from
the hostory in reason to do not save it in the .Rhistory file?
Thanks for helping,
Gian
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rrelation = corARMA(form =~
> Year|Tillage/Block, p = 1, q = 0))
>
> [I've assumed that the mapping between this message and the data you
> sent off list is DepVar=H, Treatment=Tillage]
>
> best,
> Simon
>
>
> On 17/02/12 09:35, HERNANDEZ PLAZA, MARIA EVA wrote
HELLO ALL,
I AM GETTING AN ERROR MESSAGE WHEN TRYING TO RUN A GAMM MODEL LIKE THE ONE
BELOW.
I AM USING R VERSION 2.14.1 (2011-12-22) AND MGCV 1.7-12.
M1 <-gamm(DepVar ~ Treatment + s(Year, by =Treatment), random=list(Block=~1),
na.action=na.omit, data = mydata, correlation = corARMA(f
Hi Petr,
You advice options(scipen=20) gave me the expected result and fix the
problem.
Thanks a lot!
Gian
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Dear List,
I will appreciate any advice regarding how to convert the following numbers
[I got in return by taxondive()] in numeric integers without the e.g.
6.4836e+01
abbreviations.
Thank you very much in advance,
Gian
> taxa_dive
Species Delta Delta* Lambda+ De
6.59, 6.77, 6.89, 7.35 but it don't show the ticks in each value. However I
would like to define the x values e.g. 5.0, 5.5, 6.0, 6.5, 7.0. I used the xlim
but it says error as well
>axis(1, at=c(5.0, 5.5, 6.0, 6.5, 7.0)) but still there is a problem.
Does anyone know how I can defi
Dear Sir,
Please help me to open my rda files. It's urgent to see the content and even
if I looked for solutions i didn't find one.
When I try to load my .rda file I receive this message:
"R> load(file = "SpecPhantomExp2WaterSupp Set2.rda")
Error: bad restore file magic number (file may be corrup
Dear list,
I have a seemingly simple problem with plotting predictions from nlme for
which I have not been able to find an answer in the archives nor do I see
any mention of this in Pinheiro & Bates 2000. I am using the following model
of chick growth for seven different species, with season, nest
Dear all,
I’m doing some simulation studies in order to compare the estimates (and
estimated standard deviations) from the ARMA(2,1) Model with an estimator that
I’ve constructed. For carrying out the simulations I created a VBA project
within Excel.
Now, I’m using the RExcel tool for running th
Hallo
yes I tried it as well and it works;
Thank you a lot
Maria
From: Dennis Murphy [djmu...@gmail.com]
Sent: 15 March 2011 21:36
To: Lathouri, Maria
Cc: r-help@r-project.org
Subject: Re: [R] fitting a distribution to a ecdf plot
Hi:
The fitdistrplus package
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