Anyone know of an R package that will allow me to do an inverse
Gaussian/Wald distribution transform of my data (reaction times)? Thanks!
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PLEASE do read the posting
Hi,
I have the following data about courses (504) in a university, two
attributes about the proportion of resources used (#resources_used /
#resources_available), namely the average and the standard deviation.
Thus I have:
[1] n=504 rows
[2] 1 id column and 2 attributes
Here's a sample of the
about R every day.
Regards
Gawesh
On Mon, Oct 17, 2011 at 2:11 AM, Sarah Goslee sarah.gos...@gmail.com wrote:
Hi,
On Sun, Oct 16, 2011 at 8:48 PM, gj gaw...@gmail.com wrote:
David is right. I am looking for the ecfd for fs$numstudents. The
other column is just an id.
I guess I don't know
Hi,
Newbie here. I read the R for Beginners but i still don't get this.
I have the following data (this is just an example) in a CSV file:
courseid numstudents
101 209
141 13
246 140
263 8
321 10
361
) ... pretty
clearly a numeric value for which an ECDF should make sense.
--
David.
--
Dennis
On Sun, Oct 16, 2011 at 8:31 AM, gj gaw...@gmail.com wrote:
Hi,
Newbie here. I read the R for Beginners but i still don't get this.
I have the following data (this is just an example) in a CSV file
Hi,
I want to do a visualisation of a matrix plot made up of several plots of
correlation matrices (using corrplot()). My data is in csv format. Here's an
example:
id,category,attribute1,attribute2,attribute3,attribute4
661,SCHS,43.2,0,56.5,1
12202,SCHS,161.7,5.7,155,16
1182,SCHS,21.4,0,29,0
Hi Petr,
It's not an equation. It's my mistake; the * are meant to be field
separators for the example data. I should have just use blank spaces as
follows:
users Group1 Group2 Group3
u110 5N/A
u2 6 N/A 4
u3 5 2
Thanks Petr. I will try it on the real data.
But that will only show that the groups are different or not.
Is there any way I can test if the users are different when they are in
different groups?
Regards
Gawesh
On Mon, Oct 10, 2011 at 11:17 AM, Petr PIKAL petr.pi...@precheza.cz wrote:
Hi
may be important in this
problem. I am only trying to help him frame the problem using an analogy.
** **
Anupam.
*From:* Bert Gunter [mailto:gunter.ber...@gene.com]
*Sent:* Monday, October 10, 2011 8:21 PM
*To:* Anupam
*Cc:* gj
*Subject:* Re: [R] help with statistics in R - how
Hi,
I'm a newbie to R. My knowledge of statistics is mostly self-taught. My
problem is how to measure the effect of users in groups. I can calculate a
particular attribute for a user in a group. But my hypothesis is that the
user's attribute is not independent of each other and that the user's
, if you see that I'm
going straight into the ditch with my solution please do let me know.
regards
gawesh
On Sun, May 15, 2011 at 12:28 AM, gj gaw...@gmail.com wrote:
Jim's suggestion did the trick:
tqm - do.call(rbind, tq) + 0.001
head(x.new) userid freq track rating
[1,] 11
[2,] 1 u2 15 1
[3,] 1 u3 126 4
[4,] 1 u4 117 3
[5,] 1 u5 76 2
[6,] 1 u6 103 3
On Sun, May 8, 2011 at 2:48 PM, gj gaw...@gmail.com wrote:
Hi,
I have a mysql table with fields userid,track,frequency e.g
u1,1,10
(0,1] (1,2] (2,4] (4,7] (7,16]
10 6 7 6 6
HTH,
Dennis
On Sat, May 14, 2011 at 9:42 AM, gj gaw...@gmail.com wrote:
Hi Jim,
Thanks very much for the code. I modified it a bit because I needed to
allocate the track ratings by userid (eg if user 1 plays track x once
wrote:
An easy way is to just offset the quantiles by a small increment so
that boundary condition is less likely. If you change the line
tqm - do.call(rbind, tq) + 0.001
in my example, that should do the trick.
On Sat, May 14, 2011 at 6:09 PM, gj gaw...@gmail.com wrote:
Hi,
I think I
Hi,
I have a mysql table with fields userid,track,frequency e.g
u1,1,10
u1,2,100
u1,3,110
u1,4,200
u1,5,120
u1,6,130
.
u2,1,23
.
.
where frequency is the number of times a music track is played by a
userid
I need to turn my 'frequency' table into a rating table (it's for a
recommender system).
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