Hello, I would like to order a matrix by a specific column. For instance:
> test
[,1] [,2] [,3]
[1,]1 100 21
[2,]23 22
[3,]3 100 23
[4,]4 60 24
[5,]5 55 25
[6,]6 45 26
[7,]7 75 27
[8,]8 12 28
[9,]9 10 29
[10
Hello all,
I have a set of numbers that looks like this:
> id <- c(1, 1, 2, 2, 2, 3, 4, 4, 4, 4, 1, 2, 2, 2, 3, 3, 1, 1, 1, 2, 3, 4,
> 4, 4, 5, 5)
> id
[1] 1 1 2 2 2 3 4 4 4 4 1 2 2 2 3 3 1 1 1 2 3 4 4 4 5 5
Please ignore the bold numbers, I just want to make my problem clear.
I am going to or
structure of
your object.
HTH
Peter Alspach
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of aaron wells
> Sent: Wednesday, 11 March 2009 8:30 a.m.
> To: r-help@r-project.org
> Subject: [R] ordering
>
A) I predict that if you apply the str function to the second test
that you will find that "con" is not numeric but rather of class
character or factor. And the second test is probably not a matrix but
rather a dataframe. Matrices in R need to have all their elements of
the same class.
B)
Thanks Peter, that did the trick. I'll modify my function so that the numeric
conversion is done automatically thus saving me the extra step of converting
later on.
Aaron Wells
> Subject: RE: [R] ordering
> Date: Wed, 11 Mar 2009 08:41:50 +1300
&g
Hi there!
I need some assistance here with vector orderings. I have a set
of q vectors of length p, grouped by rows in a matrix A, q·p, that I
need to order lexicographically
(http://en.wikipedia.org/wiki/Lexicographical_order).
I also have another matrix B, p·r, and a vect
On Wed, Dec 2, 2009 at 3:30 PM, Lisa wrote:
>
> Hello all,
>
> I have a set of numbers that looks like this:
>
>> id <- c(1, 1, 2, 2, 2, 3, 4, 4, 4, 4, 1, 2, 2, 2, 3, 3, 1, 1, 1, 2, 3, 4,
>> 4, 4, 5, 5)
>> id
> [1] 1 1 2 2 2 3 4 4 4 4 1 2 2 2 3 3 1 1 1 2 3 4 4 4 5 5
>
> Please ignore the bold num
l Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Lisa
> Sent: Wednesday, December 02, 2009 1:30 PM
> To: r-help@r-project.org
> Subject: [R] Ordering numbers
>
>
> Hello all,
>
> I have a set of numbers that looks
ginal Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Senthil Kumar M
> Sent: Wednesday, December 02, 2009 1:36 PM
> To: Lisa
> Cc: r-help@r-project.org
> Subject: Re: [R] Ordering numbers
>
> On Wed, Dec 2, 2009 at 3:
Greg Snow wrote:
Here is one way:
id <- c(1, 1, 2, 2, 2, 3, 4, 4, 4, 4, 1, 2, 2, 2, 3, 3, 1, 1, 1, 2, 3, 4,
+ 4, 4, 5, 5)
id
[1] 1 1 2 2 2 3 4 4 4 4 1 2 2 2 3 3 1 1 1 2 3 4 4 4 5 5
tmp <- rle(id)
tmp
Run Length Encoding
lengths: int [1:12] 2 3 1 4 1 3 2 3 1 1 ...
values : num [1:12] 1
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Lisa
> Sent: Wednesday, December 02, 2009 12:30 PM
> To: r-help@r-project.org
> Subject: [R] Ordering numbers
>
>
> Hello all,
>
> I have a se
Hi all,
I have problem in ordering data frame. Could anyone help me?
> x
[,1] [,2] [,3]
[1,] "A" "1" "2"
[2,] "G" "3" "2"
[3,] "E" "2" "3"
> y
[,1] [,2] [,3]
[1,] "G" "3" "3"
[2,] "A" "3" "3"
[3,] "E" "3" "3"
I would like to order data frame x by the order of column 1 of d
Hi,
is there a R function that order a matrix according to some criteria
based on the rows(or cols) of that matrix?
For example, let's say that my matrix S is composed by n rows S_1,
S_2,.., S_n and that I compute some real value g_i=g(S_i) for each
row.
Then I want to order this set of g_i (from
Hello all, I want box plots by group to display in order of increasing
mean (or median) of each group but can't seem to figure it out and
couldn't find anything on R-seek, either.
My data looks like this:
meas unit sid gradersprti
1 2.24 1002 9902NA 0.860
2 3.04 1007 43
Hallo everyone,
I want to evaluate the change of the distribution for several size classes.
How can i order these separate histograms with the same y-axis along a
common x-axis according to their size classes. It would like it to look a
bit like this
(http://addictedtor.free.fr/graphiques/RGraphGa
Hello
I'm using a dataframe (mydata) where row names are sampling points and
column names are species in a multivariate analysis.
If I write boxplot(mydata) I'll have boxplots for each species abundance in
alphabetical order.
How to get the boxes orderer by the median?
Usually for this I write
Try
AA <- apply(A,1,function(x) paste(x,collapse=""))
and work with AA.
--- On Tue, 30/9/08, Jose Luis Aznarte M. <[EMAIL PROTECTED]> wrote:
> From: Jose Luis Aznarte M. <[EMAIL PROTECTED]>
> Subject: [R] ordering problem
> To: [EMAIL PROTECTED]
> Receiv
phoebe kong wrote:
Hi all,
I have problem in ordering data frame. Could anyone help me?
x
[,1] [,2] [,3]
[1,] "A" "1" "2"
[2,] "G" "3" "2"
[3,] "E" "2" "3"
y
[,1] [,2] [,3]
[1,] "G" "3" "3"
[2,] "A" "3" "3"
[3,] "E" "3" "3"
Are these really data.frames? They looks
Hi, I am generating multiple charts with facet_wrap() and what what I see,
R/ggplot sorts the panels by the facet variable. So adding an index to the
facet variable (1 - bucket, 2 - bucket, etc) does solve the sorting issue but
it's ugly.
I also read this post which, if I understand correctly,
Hi listers,
I could order a data that like this:
x<-c(2,6,8,8,1)
y<-c(1,6,3,5,4)
o<-order(x)
frame<-rbind(x,y)[,o]
But, I would like to know if there is a way to order my data without setting
up a data frame. I would like to keep independent vectors x and y.
Any suggestions?
Thanks in advance,
Mar
Hi all,
I've found a lot of helpful info regarding identifying and deleting duplicates
but I'd like to do something a little different - I'd like to identify the
duplicate values but instead of deletion, label them with a value.
I am working with historical data regarding school courses:
look at 'order'
yourMatrix[order(yourMatrix[, 'yourCol']), ]
On Fri, Jan 21, 2011 at 2:38 PM, Francesco Petrogalli
wrote:
> Hi,
> is there a R function that order a matrix according to some criteria
> based on the rows(or cols) of that matrix?
>
> For example, let's say that my matrix S is compo
I think you want the following, assuming you defined your function g():
gValues = apply(S, 1, g);
Sordered = S[order(gValues), ]
Peter
On Fri, Jan 21, 2011 at 11:38 AM, Francesco Petrogalli
wrote:
> Hi,
> is there a R function that order a matrix according to some criteria
> based on the rows(
Stuart Luppescu ccsr.uchicago.edu> writes:
>
> I want box plots by group to display in order of increasing
> mean (or median) of each group but can't seem to figure it out and
> couldn't find anything on R-seek, either.
>
?reorder ... ?
__
R-help
On Sun, 2011-01-23 at 17:37 -0600, Stuart Luppescu wrote:
[snip] Thanks to Ben and Dennis for their help, but right after I sent
the original message, I figured out how to solve my problem. I noticed
that boxplot() contains the at= argument. To get the box locations, I
used a line like this:
box.l
You could get close with the ggplot2 package using the function facet_grid or
facet_wrap, but each histogram would be on a separate x-axis
Scott
On Thursday, March 3, 2011 at 8:00 AM, djbirdnerd wrote:
> Hallo everyone,
>
> I want to evaluate the change of the distribution for several size clas
Em 3/3/2011 12:00, djbirdnerd escreveu:
Hallo everyone,
I want to evaluate the change of the distribution for several size classes.
How can i order these separate histograms with the same y-axis along a
common x-axis according to their size classes. It would like it to look a
bit like this
(http
not yet, but i have only just started programming in r...
I don't know if i will able to...
--
View this message in context:
http://r.789695.n4.nabble.com/Ordering-several-histograms-tp382p3336869.html
Sent from the R help mailing list archive at Nabble.com.
_
On 05.03.2011 18:40, djbirdnerd wrote:
not yet, but i have only just started programming in r...
I don't know if i will able to...
Without quoting the former thread and without replying to a particular
person (rather than the mailing list only): Do you expect anybody on the
mailing list kn
On Mar 20, 2015, at 2:20 PM, Antonio Silva wrote:
> Hello
>
> I'm using a dataframe (mydata) where row names are sampling points and
> column names are species in a multivariate analysis.
>
> If I write boxplot(mydata) I'll have boxplots for each species abundance in
> alphabetical order.
>
>
You can use the reorder() function to reorder the grouping vector's
factor levels according to a function of the data in each group. E.g.,
compare the following two plots:
d <- data.frame(Response=cos(1:15), Group=rep(c("A","B","C"),c(6,5,4)))
par(mfrow=c(1,2))
boxplot(Response ~ Group,
Thanks Bill and David
Here goes an example
SP1<-c(9,6,7,8,5,8,7,5,9,7)
SP2<-c(1,3,4,2,4,2,5,3,2,1)
SP3<-c(4,6,7,5,7,8,7,6,5,4)
SP4<-c(5,4,3,5,2,3,4,3,4,2)
mydata<-data.frame(SP1,SP2,SP3,SP4)
rownames(mydata)<-c("ST1","ST2","ST3","ST4","ST5","ST6","ST7","ST8","ST9","ST10")
mydata
boxplot(mydata)
There may be more concise ways to do this - but you are 99% there with your
approach:
try:
boxplot(mydata[,names(sort(apply(mydata,2,median)))])
B.
On Mar 21, 2015, at 6:49 PM, Antonio Silva wrote:
> Thanks Bill and David
>
> Here goes an example
>
> SP1<-c(9,6,7,8,5,8,7,5,9,7)
> SP2<-c(1,
... just for completeness - the more concise way: (no need to go through
names()).
boxplot(mydata[,order(apply(mydata,2,median))])
... or descending
boxplot(mydata[,order(-apply(mydata,2,median))])
B.
On Mar 21, 2015, at 7:04 PM, Boris Steipe wrote:
> There may be more concise ways to d
Dear Boris,
Thanks very much, have a great week.
Best regards
Antônio Olinto
Fisheries Institute
São Paulo, Brasil
2015-03-21 21:09 GMT-03:00 Boris Steipe :
> ... just for completeness - the more concise way: (no need to go through
> names()).
>
> boxplot(mydata[,order(apply(mydata,2,median)
cdouglass wrote
> Hello all,
>
> Totally new to this and I'm just doing a frequency distribution analysis
> on T-shirt sales by size. I have a .csv with 60 orders. I read in the
> data using read.csv. If I look at the summary() or table() of the data it
> looks fine, except that the shirt sizes
Dear colleagues,
Is there a way to order list items by date? I have a series of surveys in a
list where the name of each list item is the date the survey was taken but the
list items are out of order. Each data frame has a variable in it with the
survey date as well, if that helps.
Yours, Simon
Hi,
I am running the following -masked- code:
set.seed(23)
city <- sample(c("C1","C2"),size=100,replace=T)
reason <- sample(c("R1","R2","R3","R4"),size=100,replace=T)
df <- data.frame(city,reason)
library(gmodels)
CrossTable(df$reason,df$city,prop.r=F,prop.c=F,prop.t=F,prop.chisq=F)
And I get th
See ?factor.
You can either use ?ordered to create an ordered factor to sort the levels
as you desire or sort them with factor(). e.g.
> f <- factor(letters[3:1])
> f
[1] c b a
Levels: a b c ## default ordering
> f <- factor(f, levels = letters[3:1])
> f
[1] c b a
Levels: c b a ## explicit or
1. Unless there is good reason to keep a reply private, always cc the list.
This allows more brains, possible corrections, etc.
2. Have you read ?factor and ?unique ? Always study the docs carefully.
They are generally terse but complete, especially the base docs, and you
can often find your answe
On Wed, 15 Aug 2018 07:21:55 -0700
Stats Student wrote:
> Hi, I am generating multiple charts with facet_wrap() and what what I
> see, R/ggplot sorts the panels by the facet variable. So adding an
> index to the facet variable (1 - bucket, 2 - bucket, etc) does solve
> the sorting issue but it's
Understood. Will review the docs again.
My data is from an external source which, among other things, ensures that it's
sorted correctly. I was asking for a way to have ggplot use the ordering in
place, instead of re-ordering everything. Apologies if it wasn't clear from the
original post.
A
The result does NOT depend on whether or how the data itself are sorted, but
rather on how the levels of the factors in the data are sorted. Best results
will be obtained if you modify the data frame factors before giving the data
frame to ggplot. Doing so will allow all of the ggplot functions
Hi Marcio,
Is this what you want?
x <- c(2,6,8,8,1)
y <- c(1,6,3,5,4)
o <- order(x)
# If you want each vector order by x
x[o]
y[o]
You can also use sort(), but then each vector would be sorted by
itself, not both by x.
HTH,
Josh
On Thu, Sep 2, 2010 at 1:48 PM, Mestat wrote:
>
> Hi listers,
lp-boun...@r-
> project.org] On Behalf Of Mestat
> Sent: Thursday, September 02, 2010 2:49 PM
> To: r-help@r-project.org
> Subject: [R] Ordering data by variable
>
>
> Hi listers,
> I could order a data that like this:
> x<-c(2,6,8,8,1)
> y<-c(1,6,3,5,4)
> o<
On Thu, Sep 2, 2010 at 2:33 PM, Greg Snow wrote:
> Suggestion: use the power of R.
>
> If x and y are independent then sorting y based on x is meaningless.
>
> If sorting y based on x is meaningful, then they are not independent.
>
> Trying to force non-independent things to pretend that they are
Here is a way of putting "Order" on your data:
> x
V1 V2 V3 V4 V5
1 1 12345678 Soc101 34 02-04-2003
2 2 12345678 Soc101 62 31-11-2004
3 3 12345678 Psy104 63 03-05-2003
4 4 23456789 Soc101 73 02-04-2003
5 5 23456789 Psy104 76 25-02-2004
> x$order <- ave(x$V1, x$V2, x$V3, FU
Dear R helpers
Suppose I have a data.frame as given below -
my_dat = data.frame(class = c("XYZ", "XYZ", "XYZ", "XYZ", "XYZ","ABC", "ABC",
"ABC", "ABC", "ABC" ), var1 = c(20, 14, 89, 81, 17, 44, 36, 41, 11, 36), var2
= c(1001, 250, 456, 740, 380, 641, 111, 209, 830, 920))
> my_dat
class var
ovember 20, 2012 8:41 AM
> To: r-help@r-project.org
> Subject: [R] Ordering List Items Chronologically
>
> Dear colleagues,
> Is there a way to order list items by date? I have a series of surveys in a
> list where the
> name of each list item is the date the survey was ta
As long as all your names of list elements are in the same format,
this should do it:
mylist[order(names(mylist))]
Thanks for the reproducible example,
Sarah
On Tue, Nov 20, 2012 at 11:40 AM, Simon Kiss wrote:
> Dear colleagues,
> Is there a way to order list items by date? I have a series of
On Sep 10, 2011, at 4:03 PM, Luca Meyer wrote:
> Hi,
>
> I am running the following -masked- code:
>
> set.seed(23)
> city <- sample(c("C1","C2"),size=100,replace=T)
> reason <- sample(c("R1","R2","R3","R4"),size=100,replace=T)
> df <- data.frame(city,reason)
> library(gmodels)
> CrossTable(df$r
Hello everyone,
Say I have zoo object
x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1
x <- zoo(rnorm(5), x.Date)
y <- zoo(rt(5, df=2), x.Date)
z <- zoo(rt(5, df=5), x.Date)
Data <- merge(x,y,z)
What should I do to make the latest values appear at the top?
Thank you for your help!
Rega
Hi,
The lab in which I send my samples return the results in a format that
is difficult for me to run my analysis. The lab outputs the results
where each parameter is its own row and its not consistently in the
same order (and not each sample is tested for the same suite of
variables).
e.g.
>d
Dear R users,
I have the following data frame:
PROCHIdate_admission
2 CAO713 1999-12-11
4 CAO713 1999-10-25
21 CAO0001743 1989-05-04
25 CAO0001743 1996-09-12
26 CAO0001743 1989-05-17
27 CAO0001743 1987-09-17
28 CAO0001743 1987-09-19
2
Try this:
my_dat[order(my_dat$class, -my_dat$var1, decreasing = TRUE),]
On Mon, Mar 28, 2011 at 5:55 PM, Vincy Pyne wrote:
> Dear R helpers
>
> Suppose I have a data.frame as given below -
>
> my_dat = data.frame(class = c("XYZ", "XYZ", "XYZ", "XYZ", "XYZ","ABC", "ABC",
> "ABC", "ABC", "ABC" ),
Dear sir,
Thanks for the great solution.
Regards
Vincy
--- On Mon, 3/28/11, Henrique Dallazuanna wrote:
From: Henrique Dallazuanna
Subject: Re: [R] Ordering data.frame based on class
To: "Vincy Pyne"
Cc: r-help@r-project.org
Received: Monday, March 28, 2011, 9:02 PM
Try thi
Hi,
I have a vector in a data frame that looks
something like this:
day<-c('Day -1','Day 6','Day 10')
This vector specifies the order in which several
panel will appear in a lattice plots. But the order in
which such plots will appear will be the following:
Day -1, Day 10, Day 6. Which ma
I'm sure I'm missing something obvious in the documentation...
I'm generating a boxplot
boxplot(CleanValue~ApptCategory*ReportingCode,data=newfile)
where ApptCategory is a factor with possible values ("New","Established")
Problem is, the output orders those factors alphabetically, and I'd reall
To display that object in reverse time order try this:
as.data.frame(Data)[nrow(Data):1, ]
On Thu, Jul 9, 2009 at 5:21 AM, Sergey Goriatchev wrote:
> Hello everyone,
>
> Say I have zoo object
>
> x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1
> x <- zoo(rnorm(5), x.Date)
> y <- zoo(rt(5
Hi, Gabor
Thank you!
That is exactly what I did, even before your email. :-)
Regards,
Sergey
On Thu, Jul 9, 2009 at 12:52, Gabor Grothendieck wrote:
> To display that object in reverse time order try this:
>
> as.data.frame(Data)[nrow(Data):1, ]
>
>
> On Thu, Jul 9, 2009 at 5:21 AM, Sergey Goria
One additional thought. If the reason you want to do that is
just so that you can see the last few rows more easily then
tail(Data)
will display the last few rows or tail(Data, 10) will display
the last 10 rows.
On Thu, Jul 9, 2009 at 7:36 AM, Sergey Goriatchev wrote:
> Hi, Gabor
>
> Thank you!
Hi, Gabor
Yes, I am familiar with tail() function. I use it extensively on a day
to day basis.
In this particular case I needed to order a zoo object by date, after
I have created it with RBloomberg.
Thank you for your time!
Regards,
Sergey
On Thu, Jul 9, 2009 at 14:36, Gabor Grothendieck wrote
Try this also:
xtabs(value ~ site + parameter, data = DF)
On Tue, Sep 1, 2009 at 8:59 PM, Krista Chin <0574...@acadiau.ca> wrote:
> Hi,
>
> The lab in which I send my samples return the results in a format that
> is difficult for me to run my analysis. The lab outputs the results
> where each p
Try the reshape package:
> library(reshape)
> cast(DF, site ~ parameter)
site e1 e2 e3 e4 e5
1a 1 3 5 NA NA
2b 2 NA 1 NA NA
3c NA 2 NA 5 4
4d NA 4 NA 3 NA
5e 2 NA NA NA NA
(or the reshape command in R).
On Tue, Sep 1, 2009 at 7:59 PM, Krista Chin<0574...@acadiau.
I'm not sure what's incorrect about your result, but the following works:
d=data.frame(a=sample(letters[1:5],10,rep=T),b=rnorm(10),c=sample(1:10,10));
d
d[order(d$a,d$c),]
or, you can use orderBy:
lib(doBy)
orderBy(~a+b,data=d) #use a - sign to sort in descending sequence
Did you leave off the
Thanks David. Leaving off the tilde was the problem.
--
View this message in context:
http://n4.nabble.com/ordering-columns-in-a-data-frame-tp1587294p1587491.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org maili
Hello all,
I am searching for a way in R to re-order variables before presenting them
in a parallel coordinates plot.
So far I didn't find anything within a R related context on how to do this.
I did find some texts talking about how it should be done in general, here
is such example:
http://tiny
Hello everyone,
I am an R rookie and I'm learning as I program.
I am working on a script to process a large amount of data: I read a pattern of
filenames in the folder I want and import their data
filenames = list.files(path, pattern="*Q_Read_prist*")
myfiles = lapply(filenames, function(x) re
Hi All
I have a symmetric matrix of genes ( 100x100 matrix). I also have a matrix
(100x2) of two columns where column 1 has the gene names and column 2 has
the cluster it belongs to (they are sorted and grouped based on the cluster
no).
I would like to order the rows and columns of the 100x 100 m
Dear R users,
I have two files of seasonal rainfall data (more than 10,000 rows each); here
the first 8 rows of each file are reported.
Code_Raingouge,Y_init,M_init,D_init,h_init,m_init,Y_fin,M_fin,D_fin,h_fin,m_fin,Rainfall,N_Values,Quality_Level,Code_Station
2000,1952,12,1,0,0,1953,3,1,0,0,307
I'm trying to reproduce the 3rd graph on the page of this site:
http://learnr.wordpress.com/2009/03/17/ggplot2-barplots/ . However, the data
below produces a ggplot with the stacks sorted in alphabetical order from
the bottom up. I'd like the stacks to be in the order "Europe", "Asia",
"Americas, "
On 12/3/07, Judith Flores <[EMAIL PROTECTED]> wrote:
> Hi,
>
>I have a vector in a data frame that looks
> something like this:
>
> day<-c('Day -1','Day 6','Day 10')
>
>
>This vector specifies the order in which several
> panel will appear in a lattice plots. But the order in
> which such p
On Mon, 2007-12-03 at 13:21 -0800, Judith Flores wrote:
> Hi,
>
>I have a vector in a data frame that looks
> something like this:
>
> day<-c('Day -1','Day 6','Day 10')
>
>
>This vector specifies the order in which several
> panel will appear in a lattice plots. But the order in
> whic
Try mixedsort in the gtools package.
On Dec 3, 2007 4:21 PM, Judith Flores <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I have a vector in a data frame that looks
> something like this:
>
> day<-c('Day -1','Day 6','Day 10')
>
>
> This vector specifies the order in which several
> panel will appear in
...
Peter Alspach
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Tubin
> Sent: Thursday, 1 May 2008 6:40 a.m.
> To: r-help@r-project.org
> Subject: [R] ordering a factor in boxplot output
>
>
> I'm sure I'm missing som
The factor order defaults to alphabetical, and boxplot follows that.
Re-ordering the factor to the order of interest is probably the best way
of handling it.
However, if you don;t want to do that, you could perhaps also use the
at= parameter in boxplot. For example
x<-rnorm(50)
g<-factor(rep(c("
at is probably what you want.
HTH ...
Peter Alspach
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Tubin
> Sent: Thursday, 1 May 2008 6:40 a.m.
> To: r-help@r-project.org
> Subject: [R] ordering a factor in boxplot outp
Hello all,
I think I probably did something stupid, and R's part was to allow me to do it.
My goal was to control the order of factor levels appearing horizontally on a
boxplot. Enter search engines and perhaps some creative stupidity on my part,
and I came up with the following:
v=r
On Sat, 2 Jan 2010, Tal Galili wrote:
Hello all,
I am searching for a way in R to re-order variables before presenting them
in a parallel coordinates plot.
So far I didn't find anything within a R related context on how to do this.
I did find some texts talking about how it should be done in g
Hi Charles,
Thanks for answering - you are right about the posting guide (sorry).
In any case, my question wasn't on how to reorder the columns (that is
simple), but on how to choose what order to put them in.
Thanks,
Tal
Contact
Details:---
Hi Charles,
You're solution is great (and is actually what my professor suggested me to
do today).
In the meantime I searched even more and found this article:
http://davis.wpi.edu/~xmdv/docs/tr0313_osf.pdf
That gives a good description of the problem and of his attempts at solving
it.
I started
On Sun, 3 Jan 2010, Tal Galili wrote:
Hi Charles,
Thanks for answering - you are right about the posting guide (sorry).
In any case, my question wasn't on how to reorder the columns (that is
simple), but on how to choose what order to put them in.
OK, and I see you included a reference, so t
Hi, Tal,
Tal Galili wrote:
>
> In any case, my question wasn't on how to reorder the columns (that is
> simple), but on how to choose what order to put them in.
>
So is your question answered? Or what exactly is the problem using the
example below?
library(lattice)
parallel(~iris[1:4] | Spec
The thread below has a number of solutions. I personally like the one with
sprintf().
https://stat.ethz.ch/pipermail/r-help/2010-July/246059.html
B.
On Dec 4, 2015, at 5:51 AM, BARLAS Marios 247554 wrote:
> Hello everyone,
>
> I am an R rookie and I'm learning as I program.
>
> I am work
> filenames <- c("Q_Read_prist#1...@1.xls", "Q_Read_prist#1...@10.xls",
> "Q_Read_prist#1...@2.xls")
> filenames <- gtools::mixedsort(filenames, numeric.type="decimal")
> filenames
[1] "Q_Read_prist#1...@1.xls" "Q_Read_prist#1...@2.xls"
"Q_Read_prist#1...@10.xls"
/Henrik
On Fri, Dec 4, 2015 a
Mario,
I am certain there are more elegant solutions. This is an effort to make the
process clear by dividing out each transformation used into separate lines.
## Start of code
library(stringi) # This is written in C and C++ (ICU library), is fast, and is
well documented.
filenames <- c("Q_Read
tarting my PhD I feel
like I want something more "integrated"
Thanks,
Mario
From: Mark Sharp [msh...@txbiomed.org]
Sent: Friday, December 04, 2015 5:25 PM
To: BARLAS Marios 247554
Cc: r-help@r-project.org
Subject: Re: [R] Ordering Filenames stor
ot;,"c", "d", "e"),5))
df1 <- data.frame(smat, bmat)
orddata <- df1[order(df1[,2],decreasing=TRUE),]
I hope this helps.
--- On Sun, 6/26/11, Aparna Sampath wrote:
> From: Aparna Sampath
> Subject: [R] Ordering a matrix based on cluster no
> To: r
Thanks for the help! But when I tried it, it does not work the same way I
want. :(
after combining the two matrices, they look like this:
V1V2 X TEL.AML1.C41
Hyperdip.50.C23
1 TEL.AML1.C41 1TEL.AML1.C41 1.000 0.
r the gene name.
merge (smat, bmat, by= “gene”) # untested
Then apply the order command.
I hope I understood the problem this time
--- On Mon, 6/27/11, Aparna Sampath wrote:
> From: Aparna Sampath
> Subject: Re: [R] Ordering a matrix based on cluster no
> To: r-help@r-project.
Hello,
I am trying to figure out if there is a way to order the left side of a Sankey
diagram from most frequent to least frequent. I am using R version 3.2.1 and
using googleVis version 0.5.9 for the Sankey. I've tried sorting, but that does
not work. Is there anyway to force it to arrange the
On Fri, Jan 3, 2014 at 9:41 AM, Stefano Sofia
wrote:
>
> Dear R users,
> I have two files of seasonal rainfall data (more than 10,000 rows each); here
> the first 8 rows of each file are reported.
>
> Code_Raingouge,Y_init,M_init,D_init,h_init,m_init,Y_fin,M_fin,D_fin,h_fin,m_fin,Rainfall,N_Value
Hi Sofia!
You need to attach the data file before sorting:
attach(df_final)
or just use full qualified names (like df_final$Y_init)
Dmitry
On 03/01/2014 16:41, Stefano Sofia wrote:
> Dear R users,
> I have two files of seasonal rainfall data (more than 10,000 rows each); here
> the first 8 ro
Inline
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
H. Gilbert Welch
On Fri, Jan 3, 2014 at 7:08 AM, Dmitry Pavlyuk
wrote:
> Hi Sofia!
>
> You need to attach the data file before
Bert, why do you think that "attach" is not working in this case? Did
you check it before your advice? :)
I agree about "generally bad approach", but it is quite convenient for
work with one data set.
Dmitry
On 03/01/2014 18:28, Bert Gunter wrote:
Inline
Bert Gunter
Genentech Nonclinical Bio
You misunderstand = I was not sufficiently clear.
What is false is your statement that "you **need** to attach the data
file before sorting." You do not. with()/within() can be used to avoid
using the fully qualified names without attaching. I did not claim
that attaching first would not work, onl
Ah, ok, thank you for explanations!
Dmitry
On 03/01/2014 20:00, Bert Gunter wrote:
You misunderstand = I was not sufficiently clear.
What is false is your statement that "you **need** to attach the data
file before sorting." You do not. with()/within() can be used to avoid
using the fully qual
Hi:
levels(df.m2$Region)
[1] "Africa" "Americas" "Asia" "Europe" "Oceania"
Reorder your Region factor to the following:
df.m2$Region <- factor(df.m2$Region, levels = c('Europe', 'Asia',
'Americas', 'Africa', 'Oceania'))
Then recopy the code from the definitio
On Oct 18, 2011, at 7:59 PM, swonder03 wrote:
I'm trying to reproduce the 3rd graph on the page of this site:
http://learnr.wordpress.com/2009/03/17/ggplot2-barplots/ . However,
the data
below produces a ggplot with the stacks sorted in alphabetical order
from
the bottom up. I'd like the st
That worked great thank you.
--
View this message in context:
http://r.789695.n4.nabble.com/Ordering-of-stack-in-ggplot-package-ggplot2-tp3917159p3917520.html
Sent from the R help mailing list archive at Nabble.com.
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