On Wed, 28 May 2003, Paul Lemmens wrote:
Hi!
Apologies for sending the mail without any code. Apparently somewhere along
the way the .R attachments got filtered out. I have included the code below
as clean as possible. My original mail is below the code.
I still think you need not to be
Hoi Thomas,
--On woensdag 28 mei 2003 7:16 -0700 Thomas Lumley
[EMAIL PROTECTED] wrote:
On Wed, 28 May 2003, Paul Lemmens wrote:
Hi!
Apologies for sending the mail without any code. Apparently somewhere
along the way the .R attachments got filtered out. I have included the
code below as clean
Hello, There:
I read data from tab-delimted text file(1888.txt) in C:/temp, which has
thousands rows and 80 colulms, using read.delim(C:/temp/1888.txt). when I
retrieved the numeric coulum which has real zero values and applies R buid-in
function such as mean( ), sum() and got a result of NA.
On Wed, 28 May 2003, Paul Lemmens wrote:
Hoi Thomas,
--On woensdag 28 mei 2003 7:16 -0700 Thomas Lumley
[EMAIL PROTECTED] wrote:
On Wed, 28 May 2003, Paul Lemmens wrote:
Hi!
Apologies for sending the mail without any code. Apparently somewhere
along the way the .R attachments
Dear list members,
I'm relatively new to this list; can anyone tell me how to declare
missing values once a dataset has been attached?
For example here:
VAR1
1 1
2 2
3 1
4 3
5 2
6 1
7 3
8 3
9 1
102
11 98
122
13 97
14 99
On Wed, 2003-05-28 at 17:18, Roy, Supratik wrote:
I am having problems when calling supsmu in R 1.6.2 installed
on RedHat 8.0. I used the rpm provided on the R site. supsmu
seems to have not been installed by default - (i.e., as part of
the modreg package). It also does not occur as part of
Try the following function (the name is supposed to be a joke, by the
way),
which will also do the right thing with NAs and characters. Use it as
if(equal.enough(x,y)) rather than if(x==y), e.g.
equal.enough(0.1+0.2, 0.3)
[1] TRUE
My default of 15 significant figures may be overkill in many
Simon Fear wrote:
Try the following function (the name is supposed to be a joke, by the
way),
which will also do the right thing with NAs and characters. Use it as
if(equal.enough(x,y)) rather than if(x==y), e.g.
equal.enough(0.1+0.2, 0.3)
Oh, why not just go one step further, and redefine the
On Wed, 28 May 2003, Adrian Dusa wrote:
I would like values 97, 98 and 99 to be treated as missing values.
VAR1[VAR1 %in% c(97,98,99)]-NA
-thomas
__
[EMAIL PROTECTED] mailing list
https://www.stat.math.ethz.ch/mailman/listinfo/r-help
No problem, equal.enough(1+1,3,d.p.zero=10) !
But seriously, this is WHY NOT do that substitution: it helps me
remember
that I am not in fact truly testing for numeric identity.
S
-Original Message-
From: Barry Rowlingson [mailto:[EMAIL PROTECTED]
Sent: 28 May 2003 17:03
To: Simon
Dear all,
I am trying to minimize a function with 3 parameters using nlm. I have worked out the
2nd derivatives (incl the cross-product terms) and would like to supply them to nlm
for evaluation. What I am not sure about is how to set up the Hessian matrix for nlm.
That is,
attr(lhat,
Dear R help-list reader,
I would like to generate a plot which compares to states in a patient
treatment, before and after. for this reason I have generated a vector
before-c(1,30,23,40)
and
after-c(20,10,20,60)
the first element in before corresponds to the first element in after.
I would like
Many thanks to Spencer Graves, Simon Fear, Rolf Turner, Thomas Lumley,
Patrick Burns and Renaud Lancelot; you're quick and great.
Cheers,
Adrian
Adrian Dusa ([EMAIL PROTECTED])
Romanian Social Data Archive (www.roda.ro)
1, Schitu Magureanu Bd.
76625 Bucharest
On Wed, 2003-05-28 at 11:48, Frank Mattes wrote:
Dear R help-list reader,
I would like to generate a plot which compares to states in a patient
treatment, before and after. for this reason I have generated a vector
before-c(1,30,23,40)
and
after-c(20,10,20,60)
the first element in before
Frank -
Roughly speaking:
matplot(c(0,10), rbind(before, after), type=l, axes=F, xlab=time,
ylab=measurement)
axis(2)
axis(1, c(0,10), c(before,after))
Should do the job, if I interpret correctly the plot you have in mind.
See help(matplot) : Details, and many pages of help(par) for
On Wed, 28 May 2003 15:59:45 +0100 (BST), Prof Brian Ripley
[EMAIL PROTECTED] wrote:
print(c(0.1 + 0.2, 0.3), digits=20)
[1] 0.30004 0.2
yet
print(c(0.1, 0.2, 0.3), digits=20)
[1] 0.1 0.2 0.3
Is this the way things should work? Why isn't 0.3 printed as
On Wed, 28 May 2003 10:48:08 -0400, you wrote:
Hello, There:
I read data from tab-delimted text file(1888.txt) in C:/temp, which has
thousands rows and 80 colulms, using read.delim(C:/temp/1888.txt). when I
retrieved the numeric coulum which has real zero values and applies R buid-in
function
Dear R help reader,
I'm not an expert in R and are lerning a lot by reading the help
digest, which is sometimes difficult because the huge amount of data
posted. I have posted some questions before, and are impressed how
quick I got a solution for my problem. Sometimes with quite different
On 05/28/03 20:09, Frank Mattes wrote:
On the other site, it wasn't easy to search the help archive,
purely I didn't know how to formulate my problem.
I'm wondering if we could not collect all the answers / examples in a
database -
sorted in topics, like the help document Rtips.
I have no clue
I don't know if this will help you or not, but might worth a try. You can
replace the two inner for loops with nested calls to sapply(). For example:
sapply(1:5, function(x) sapply(6:10, function(y) x+y))
[,1] [,2] [,3] [,4] [,5]
[1,]789 10 11
[2,]89 10 11 12
Philippe Grosjean wrote:
I suspect that your problem comes from the rbind(). I have also noticed an
exponentially slower execution with the increase of the size of the data
frame that you rbind()s. It is much faster to rbind() several separated
temporary data frames (let's say, ten by ten loops),
I have a data set w/ an ordinal response taking on one of 10 categories.
I am considering using polr to fit a cumulative logits model. I
previously fit the model in SAS (using proc logistic) which provides a
test for the proportional odds assumption (p 0.001 for the test). Are
there simple
Dear rwatkins,
The car and lmtest packages both have functions for Durbin-Watson tests.
More generally, doing a search at http://www.r-project.org/ will get you
this kind of information.
I hope that this helps,
John
At 04:45 PM 5/28/2003 -0500, [EMAIL PROTECTED] wrote:
Is there a command to
Subject: [ANN] Quantian: A Knoppix remastering for Scientific Computing
X-Mailer: VM 7.03 under 21.4 (patch 6) Common Lisp XEmacs Lucid
FCC: /home/edd/mail/out/mail
From: Dirk Eddelbuettel [EMAIL PROTECTED]
--text follows this line--
[ Apologies for cross-postings; however, this message is being
On 28-May-03 Barry Rowlingson wrote:
Oh, why not just go one step further, and redefine the == operator!
== - function(x,y){equal.enough(x,y)}
before:
(.1+.2)==.3
[1] FALSE
after:
(.1+.2)==.3
[1] TRUE
This requires a slight modification to equal.enough, which I will not
From: John Fieberg [mailto:[EMAIL PROTECTED]
I have a data set w/ an ordinal response taking on one of 10
categories.
I am considering using polr to fit a cumulative logits model. I
previously fit the model in SAS (using proc logistic) which provides a
test for the proportional odds
Dear John:
I can make it on your suggestion in mean structural analysis.
I appreciate so much and love your package sem.
I hope your package sem will be extended in near future.
John Fox [EMAIL PROTECTED] wrote:
Dear Mitsuo,
My intention in writing the sem package was to provide a basic
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