Actually, what I have is probably not what you want, and I wrote
it as an example of what I was looking for, and what is probably possible.
My code is just a hack of the snow socket code.
To answer your questions:
1. The communication is done by serializing R objects. That is,
the process
Hi , i am using the R(1.8.1) tcl/tk library in order to build a graphical
user interface to mathematic function and i would like to know if it is
possible to retrieve the value of a tkentry to make a R vector
for exemple with an entry containing 1,2,3,4,5 i want to make a vector
which
Hello!
Please, somebody could explain me what exactly means that model names? For
example VVV: ellipsoidal, varying volume, shape, and orientation. Thanks.
Talita Perciano Costa Leite
Graduanda em Ciência da Computação
Universidade Federal de Alagoas - UFAL
Departamento de Tecnologia da
On Sun, 9 May 2004, Liaw, Andy wrote:
Dear R-help,
I've encounter what seems to me a strange problem with names-. Suppose I
define the function:
fun - function(x, f) {
m - tapply(x, f, mean)
ans - x - m[match(f, unique(f))]
names(ans) - names(x)
ans
}
which subtract
On Mon, 10 May 2004, Christophe Pallier wrote:
The use of tapply(x,f,mean)[match(f,unique(f))] assumes a particular
order in the result of tapply, no? It seems a bit dangerous to me.
My original code for the group means problem used rowsum(,reorder=FALSE)
rather than tapply(), and we do know
Julien Glenat [EMAIL PROTECTED] writes:
Hi , i am using the R(1.8.1) tcl/tk library in order to build a graphical
user interface to mathematic function and i would like to know if it is
possible to retrieve the value of a tkentry to make a R vector
for exemple with an entry containing
Dear R Help,
My apologies if this is widely known, but I didn't find this in the R
archives.
I am running WinXP pro and R 1.90. Rcmd build or check fails with the
error: Please set TMPDIR to a valid temporary directory
$TMPDIR is set to $TMPDIR or C:/TEMP in share\perl\R\Var.pm. TMPDIR or
aedin culhane wrote:
Dear R Help,
My apologies if this is widely known, but I didn't find this in the R
archives.
I am running WinXP pro and R 1.90. Rcmd build or check fails with the
error: Please set TMPDIR to a valid temporary directory
OK. So why do you not set an environment variable
Hi!
Talking about the function me. One of the result values of this funtion is
the loglik. I want to understand better what is this. Sombody could help me?
Talita Perciano Costa Leite
Graduanda em Ciência da Computação
Universidade Federal de Alagoas - UFAL
Departamento de Tecnologia da
Hi,
I'm have a list of integer vectors and I want to perform an outer()
like operation on the list. As an example, take the following list:
mylist - list(1:5,3:9,8:12)
A simple example of the kind of thing I want to do is to find the sum
of the shared numbers between each vector to give a
David Orme [EMAIL PROTECTED] writes:
Hi,
I'm have a list of integer vectors and I want to perform an outer()
like operation on the list. As an example, take the following list:
mylist - list(1:5,3:9,8:12)
A simple example of the kind of thing I want to do is to find the sum
of the
David Orme [EMAIL PROTECTED] wrote:
...
I'm have a list of integer vectors and I want to perform an outer()
like operation on the list. As an example, take the following list:
mylist - list(1:5,3:9,8:12)
A simple example of the kind of thing I want to do is to find the sum
of the shared
On 10 May 2004, at 15:45, Jason Turner wrote:
I'm having a hard time figuring out what you want. Who is this mystery
object test?
Ah - sorry all. That should be:
for(x in ind){
for(y in ind){
result[x,y] - sum(mylist[[x]][mylist[[x]] %in% mylist[[y]]])
}
}
As a style point, ind -
David Orme [EMAIL PROTECTED] writes:
Following up on Peter Dalgaard's suggestion, I've tried vectorizing
the function properly. Now I get the same answers from both the two
for() loops and the vectorized outer() call. What puzzles me slightly
is that using outer is about 13 times slower. I
outer() generally works by expanding out the lists like
Y - rep(y,length(x))
X - rep(x,each=length(y)) # or maybe it's vice versa, never mind...
FUN(X,Y,extras)
and then adds dims and dimnames. If FUN vectorizes, this is the
efficient way, but it does not in your case and the rep()s are
probably
Hi all,
Is there any documentation on running R like one would run a shell or
Perl script, with out/input directed appropriately, environment variable
access, and command switch processing?
I looked some, and even remembered to check the FAQ, but couldn't find
anything.
Thanks
W
On 10 May 2004, at 17:15, Heike Schmitt wrote:
I want to include a vector representing the sites - environmental data
correlation in a PCA.
I currently use prcomp (no scaling) to perform the PCA, and envfit to
retrieve the coordinates of the environmental data vector. However, the
vector length
Someone had modified the R source to handle this, but it has not been
incorporated into the official R source, if I'm not mistaken. Search the
R-devel archive.
HTH,
Andy
From: Webb Sprague
Hi all,
Is there any documentation on running R like one would run a shell or
Perl script, with
Dear list,
I am trying to prepare a handout showing how to use R for factor
analysis. As part of the exercise I want to save a correlation
matrix on a tutorial web page. I can save with no problem (saving
locally and then transferring to the web site). Although I can
load() the local file,
Liaw, Andy [EMAIL PROTECTED] writes:
Someone had modified the R source to handle this, but it has not been
incorporated into the official R source, if I'm not mistaken. Search the
R-devel archive.
You can do stuff like this though:
cat test.R
#!/bin/sh
tail +3 $0 | R --vanilla --args $@ ;
big5r.txt is delimited by CR not LF, and as R writes it as a binary file,
that's not the file that got saved.
Same problem with the header on big5r.
Try some octal dumps and find out which step is changing the file.
BTW, I would use load(url(someURL)) these days.
On Mon, 10 May 2004,
So --
I am getting the same thing - as far as the base-Ex.Rout.fail --
did undefining HAVE_WORKING STRPTIME fix the problem?
Despite using the suggestions on page 21 of the install guide,
I cannot seem to find the set of options necessary for dynamic linking.
I am loading with xlc, MAIN_LDFLAGS
Richard A. O'Keefe wrote:
I have a data set with 6 variables and 251 cases.
The people who supplied me with this data set believe that it falls
naturally into three groups, and have given me a rule for determining
group number from these 6 variables.
One possibility is to extract the coordinates
David Orme d.orme at imperial.ac.uk writes:
:
:
: outer() generally works by expanding out the lists like
:
: Y - rep(y,length(x))
: X - rep(x,each=length(y)) # or maybe it's vice versa, never mind...
: FUN(X,Y,extras)
:
: and then adds dims and dimnames. If FUN vectorizes, this is the
:
What do you actually know?
You don't have `known errors', as if you did you could correct the
values.
I doubt if you actually have a known range, more likely a standard error
or a confidence interval. (If you think you do have a known range, how
do
you know?)
Firstly, I must
I've been trying to get RODBC working in RAqua. For my database,
let's call it mydb, when I enter
odbcConnect(mydb)
or
odbcConnect(mydb, uid=postgres, pwd=secret),
RAqua thinks for about 10 seconds, then crashes.
mydb is a PostgreSQL 7.4.2 database running on my machine (Mac OS X
10.3.3). I am
Hi all!
I am trying to project coordinates collected by GPS collars. The data is in
decimal degrees and provides locations for two Sable antelope running
around in Kruger NP South Africa.
After a wide search it seems that proj4R provides most options for
projection of coordinates. However I
Does any other driver work? See the comments in the RODBC README.
In particular, does a 7.2.5 driver really work with 7.4.2, and do you have
a functioning driver -- the bundled one used to do exactly this.
On Mon, 10 May 2004, Anthony Darrouzet-Nardi wrote:
I've been trying to get RODBC
That someone might have been me; I did at one time figure out how to
execute scripts based on a first line like that of the subject line
of this thread.
As I recall, what I did was
1) before attempting to execute a script having such a first line,
define the env vars that R.bin needs
2)
This concerns a draft package not on CRAN, perhaps better discussed off
list for now. Could you please attach a few example points for me to look
at, and details of your R version and the proj4 library version you are
using? What happens when you run proj from the command line?
Roger Bivand
Hi
Associated with that attempt was a modification of the sources that I
made, commenting out two lines in system.c, specifically:
See file ./source/src/unix/system.c
line 239 in R-1.8.1 patched as of 12/3/03
snprintf(msg, 1024, ARGUMENT '%s' __ignored__\n, *av);
You may be interested in this thread from R-devel last October:
https://www.stat.math.ethz.ch/pipermail/r-devel/2003-October/027862.html
If I recall correctly, Duncan Temple Lang is working on different
ways to initialize R but I'm not sure what the status of that is.
-roger
Webb Sprague
Webb Sprague wwsprague at ucdavis.edu writes:
: Is there any documentation on running R like one would run a shell or
: Perl script, with out/input directed appropriately, environment variable
: access, and command switch processing?
:
: I looked some, and even remembered to check the FAQ, but
Dear Everybody:
I'm doing my usual how does that work in R thing with some Stata
projects. I find a gross gap between the Stata and R in Cox PH models,
and I hope you can give me some pointers about what goes wrong. I'm
getting signals from R/Survival that the model just can't be estimated,
Hello,
can someone give me an example of how to fit a linear model where the
response is a matrix, please? (other than a loop over lm calls)
The ?lm points me to model.matrix but it is not clear to me how to use a
model matrix in an lm call.
fit-lm(headmatrix ~ tailmatrix) causes
Try:
x = matrix(runif(30), 10, 3)
newx = matrix(runif(15), 5, 3)
y = rnorm(10)
fit = lm(y ~ x)
newyhat = predict(fit, newdata=data.frame(x=I(newx)))
HTH,
Andy
From: Claus Gwiggner
Hello,
can someone give me an example of how to fit a linear model
where the
response is a matrix,
Your problem might be that the names of 'newframe' don't match
the column names of 'tailmatrix'. It's hard to tell because you
don't provide an example.
Is 'newframe' a matrix or a dataframe?
If it is a dataframe, try:
names(newframe) - colnames(tailmatrix)
predict(fit, newframe)
-roger
Hi Murray:
Perhaps the errors are thrown by Mozilla because it encounters an
encrypted/secure page and does not know what to do (..:)..)? Would it help
if you went to Edit Preferences... Privacy and Security select SSL or
Certificates drop down list
and then once in SSL, or once in
I asked about putting some kind of coloured rug under a dendrogram.
Thomas Petzoldt [EMAIL PROTECTED] replied:
One possibility is to extract the coordinates used by the dendrogram
using par(usr) ...
Er, the documentation for par(usr) says
'usr' A vector of the form 'c(x1,
big5r.txt is delimited by CR not LF, and as R writes it as a binary file,
that's not the file that got saved.
Thanks. That was the problem. I was transferring the files from my
Mac to my web server (also a Mac) using Interarchy. It was putting
in CRs rather than LFs (the Interarchy options
It was a proxy settings problem. All fixed now. Sorry to disturb the list.
Murray Jorgensen
[EMAIL PROTECTED] wrote:
Hi Murray:
Perhaps the errors are thrown by Mozilla because it encounters an
encrypted/secure page and does not know what to do (..:)..)? Would it
help if you went to Edit
Hi.
(B
(B I've tried to create a polygon with one hole by gpclib using following
(Bexample script.
(B
(B holepoly - read.polyfile(system.file("poly-ex/hole-poly.txt", package
(B="gpclib"), nohole = FALSE)
(B area.poly(holepoly)
(B plot(holepoly,poly.args=list(col="red",border="blue"))
(B
Remember tapply with a single factor in R returns a 1D array. What you
are seeing are the dimnames, not the names: look at attributes() on your
return value (or even name() or str() on it).
I suspect you intended an as.vector() call in the formation of m.
Brian
On Sun, 9 May 2004, Liaw, Andy
Liaw, Andy [EMAIL PROTECTED] writes:
[BTW, this is using the tip that Thomas Lumley posted about forming the
group means. I've wanted to write a `tsweep' function that's sort of the
cross of tapply() and sweep().]
Also notice that this is
unsplit(lapply(split(x, g), scale, scale=FALSE), g)
Liaw, Andy wrote:
Suppose I
define the function:
fun - function(x, f) {
m - tapply(x, f, mean)
ans - x - m[match(f, unique(f))]
names(ans) - names(x)
ans
}
May I ask what is the purpose of match(f,unique(f)) ?
To remove the group means, I have be using:
x-tapply(x,f,mean)[f]
MailMarshal (an automated content monitoring gateway) has
not delivered the following message:
Message: Bfd6fc.0001.mml
From:[EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: Hello
This is due to automatic rules that have determined that the
intended recipient is
hello,
I am working with some data which i would like to find the best fit model for them.
First, this data are in a matrix. Each of the columns are treatments and the raws are
repetions for the each tratment.
So, i've already maden one chart with all the boxplot graphic, for each treatment.
Hi group,
I try to write a frame to a table (RODBC). I use
colnames(temp6) - c(ind_id,ser_id,period_id,year,calc,mean)
sqlSave(channel, temp6, tablename = series_indices_test,append= TRUE,
rownames=FALSE, verbose = FALSE, test = FALSE, nastring = -99, fast = FALSE)
This is
I tried following commands:
amp~time|subject/trial #this was the grouping structure of the data
plot(dip,inner=~condition,layout=c(2,2))
after the plot command I obtained this error message:
Error in if(!any(cond.max.level - cond.current.level 0)(row-1)* :
missing value where TRUE/FALSE
This was my point. Using RSPerl with ordinary CGI of course starts
a new process for each request.
But using fastcgi uses the same perl process for new requests. So, if
you can use fastcgi in conjunction with RSPerl (which i did not try),
there would be no startup overhead anymore.
Christian
Rodrigo [EMAIL PROTECTED] said:
I am working with some data which i would like to find the best fit model
for them.
First, this data are in a matrix. Each of the columns are treatments and
the raws are repetions for the each tratment.
Is the response in a separate vector, or is it one of the
Both of you might have missed my question from Friday: For very long `x'
(e.g., length=5), indexing by names can take a long time. See that
thread for detail. (For small data, you can hardly tell the difference.)
Also, I'm trying to write the function in a way that one can pass in more
On Mon, 10 May 2004, Liaw, Andy wrote:
Both of you might have missed my question from Friday: For very long `x'
(e.g., length=5), indexing by names can take a long time. See that
thread for detail. (For small data, you can hardly tell the difference.)
That's solved in R-devel as of
On Monday 10 May 2004 05:46, Stephan Moratti wrote:
I tried following commands:
amp~time|subject/trial #this was the grouping structure of the data
plot(dip,inner=~condition,layout=c(2,2))
after the plot command I obtained this error message:
Error in if(!any(cond.max.level -
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