Gabor Grothendieck wrote:
On 8/17/06, Martin Maechler [EMAIL PROTECTED] wrote:
Gregor == Gregor Gorjanc [EMAIL PROTECTED]
on Fri, 11 Aug 2006 00:27:27 + (UTC) writes:
[snip]
There are two problems:
1. as.POSIXlt is not generic. (This problem may not be too important
given
Le 17.08.2006 20:56, Adrian Dusa a écrit :
On Thursday 17 August 2006 21:41, Peter Dalgaard wrote:
[...]
Breaks the feature that you get to www.r-project.org just by typing
r, though...
It breaks also every usage of the google feeling lucky default behaviour
which is really useful
On Friday 18 August 2006 10:08, Romain Francois wrote:
Le 17.08.2006 20:56, Adrian Dusa a écrit :
[...]
It breaks also every usage of the google feeling lucky default behaviour
which is really useful I think.
There are R related firefox search plugins on mycroft. Find more info on
that on
Dear R-users
I need your help. I am agonised by the odd behaviour of R
described below
In the following program, data.frame work contains no rows,
when Pb set to 0.3 and 0.7
data-read.csv(output.csv,header=TRUE)
for(N in c(20,40,80,160,320,640,1280)){
for(Pb in seq(0.1,0.9,0.1)){
Hello,
I am hoping someone can advise me regarding an error message I received and
if needed, refine some syntax. I am wanting to calculate the word count for
each row of a dataframe. Below, I have 3 variables (V3.PD, V3.HD,
V3.LP) which I want to obtain a word count for, by each row which
Hello,
I'm using R 2.3.1 on Windows.
I'm generating some very long SQL statements. I do this by using paste() which
will contain many strings and variables. I'm getting an error when the the
total line length is longer than about 1013 characters. For example, it works
with the line
Thank you Sundar,
Yes, always integers. By demand data I meant the amount of ordered
products in a certain period. Therefore, x is a vector of periods (i.e.
Weeks in a year)
In my example we could see an article, that has only been ordered in two
weeks within one year.
All the zeros show, that
On Fri, 18 Aug 2006, Hiroto Miyoshi wrote:
Dear R-users
I need your help. I am agonised by the odd behaviour of R
described below
In the following program, data.frame work contains no rows,
when Pb set to 0.3 and 0.7
data-read.csv(output.csv,header=TRUE)
for(N in
You should put your SQL query in a variable, and use this variable in
your call. Something like:
MyQuery - bla bla bla
MyQuery - paste(MyQuery, more bla bla)
#
doMyRequest(MyQuery)
Best,
Philippe Grosjean
Eric Fegraus wrote:
Hello,
I'm using R 2.3.1 on Windows.
I'm generating
On Fri, 18 Aug 2006, Philippe Grosjean wrote:
You should put your SQL query in a variable, and use this variable in
your call. Something like:
MyQuery - bla bla bla
MyQuery - paste(MyQuery, more bla bla)
#
doMyRequest(MyQuery)
Indeed. For the record, R has an limit of 1024 chars
I have a plot like this, consisting of 18 different vioplots:
(monospaced font)
- - - - - -
lab |16 | |13 | |10 | | 7 | | 4 | | 1 |
- - - - - -
lab |17 | |14 | |11 | | 8 | | 5 | | 2 |
- - - - - -
lab |18 | |15 |
For normal panel data, the standard R tool is the nlme package,
documented in Pinheiro and Bates (2000) Mixed-Effects Models for S and
S-Plus (Springer). See the examples in ?corARMA.
I recommend you spend some quality time with Pinheiro and Bates
(2000). If you do that, I
RSiteSearch(grogger) produced nothing, which suggests that the
paper you cite is NOT cited in a help page in any package contributed to
CRAN. However, RSiteSearch(instrumental variables) just produced 31
hits for me, among which #11 was for systemfit{systemfit}, which
mentions
To whom it may concern:
I am trying a factorial design a system of mine that has two factors.
Each factor was set at four different levels, with one replication for
each of the combinations. My data is as follows:
A B Response
16002.5
'wc1' is a vector and not a matrix. The reference 'wc1[,1]' is not legal:
wc1 -c(V3.PD, V3.HD, V3.LP)
dim(wc1)
NULL
wc1[,1]
Error in wc1[, 1] : incorrect number of dimensions
What is it that you are trying to do?
On 8/18/06, Bob Green [EMAIL PROTECTED] wrote:
Hello,
I am hoping someone
On 8/18/06, Correia, L, Mr [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
To whom it may concern:
I am trying a factorial design a system of mine that has two factors.
Each factor was set at four different levels, with one replication for
each of the combinations. My data is as follows:
Hi, Markus,
One other suggestion is to add the lower argument to fitdistr:
fitdistr(x, dtnorm0, start = list(mean = 0, sd = 1), lower = 0)
where dtnorm0 is defined as before. This indicates to fitdistr that the
optimization should be constrained. See ?optim for details.
--sundar
Schweitzer,
Hi,
I have following dataframe. Column A indicates months.
DF - structure(list(A = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1,
2, 3, 4, 5, 7, 8, 11, 12, 1, 2, 3, 4, 5, 8), B = c(0, 0, 0, 8,
0, 19, 5, 19, 0, 0, 0, 11, 0, 8, 5, 11, 19, 8, 11, 10, 0, 8,
36, 10, 16, 10, 22)), .Names =
If you really want the quadratic terms, you need to keep those variables as
numeric, instead of factors. (You might also want to look into something
like the central composite designs.)
summary() and coef() on the resulting fitted object should give you want you
need. Things like these are
I am also trying to learn about lattice plots.
To get a succinct listing of the names of the lists of default parameter
settings, try:
names(trellis.par.get())
To get a succinct listing of all the default parameter settings, try:
str(trellis.par.get())
HTH,
Maurice Haynes
-Original
Harold,
I don't have a grouping variable. And yes, persons can be an important
source of variance, and they are the resp variable. rating is the
response.variable in the model you specified below. aov perhaps could give
me distorted results, because of unbalanced data (what estimation method it
Here are two solutions. In both we break up DF into rows
which start with 1.
In solution #1 we create a new data frame with the required sequence
for A and zeros for B and then we fill it in.
In solution #2 we convert each set of rows to a zoo object z
where column A is the times and B is the
Gabor,
Thanks a lot for the help. The 1st method works fine. In 2nd method I am
getting following error.
do.call(rbind, by(DF, cumsum(DF$A == 1), f))
Error in zoo(, time(as.ts(z)), z, fill = 0) :
unused argument(s) (fill ...)
Unable to figure out the cause.
Thanks,
I did run it so I am not sure how the error crept in. Anyways,
I have fixed it and a corrected version is below.
---
Here are two solutions. In both we break up DF into rows
which start with 1.
In #1 we create a new data frame with the required sequence
for A and zeros for B and then we fill
Dear all,
I have a question on handling of missing values in lmList. My data set
have continuous predictor and response, x and y, and a grouping variable
group.id. All these variables have NAs and the data set also has several
other variables that also contains NAs.
To create the
Dear List,
why does as.data.frame(cbind()) transform numeric variables to
factors, once one of the other variablesused is a character vector?
#
x.1 - rnorm(10)
x.2 - c(rep(Test,10))
Foo - as.data.frame(cbind(x.1))
is.factor(Foo$x.1)
Foo - as.data.frame(cbind(x.1,x.2))
is.factor(Foo$x.1)
#
I
I need to modify the graph of the autocorrelation. I tried to do it through
plot.acf but with no success.
1. I would like to get rid of the lag zero
2. I would like to have numbers on the x-axis only at lags 12, 24, 36, 48, 60,
...
Could anybody help me in this?
Any help will be appreciated
On 8/17/06, Debarchana Ghosh [EMAIL PROTECTED] wrote:
Hi All,
I'm trying to modify some of the default graphic parameters in a
conditional histogram. While I was able to change the default grey
background to white, I couldn't change the axis.font or the xlab font.
The default background is
Hi there,
it seems that if I update R, it doesn't find previously installed packages
anymore and is also not found by ESS.
Actually the update has been done by our system administrator who assumed
that there would be no problems with these things (I don't have root
access to this system) and
On 8/17/06, Anupam Tyagi [EMAIL PROTECTED] wrote:
Please read about lattice.par.settings, and not trellis.par.settings. Trellis
is
in S/S-plus.
As far as I know, there's no such thing as lattice.par.settings.
``Trellis''-compatible things in the lattice package have the same
names as the
On Fri, 2006-08-18 at 10:41 -0400, Tom Boonen wrote:
Dear List,
why does as.data.frame(cbind()) transform numeric variables to
factors, once one of the other variablesused is a character vector?
#
x.1 - rnorm(10)
x.2 - c(rep(Test,10))
Foo - as.data.frame(cbind(x.1))
is.factor(Foo$x.1)
On Fri, 18 Aug 2006, Tom Boonen wrote:
Dear List,
why does as.data.frame(cbind()) transform numeric variables to
factors, once one of the other variablesused is a character vector?
#
x.1 - rnorm(10)
x.2 - c(rep(Test,10))
Foo - as.data.frame(cbind(x.1))
is.factor(Foo$x.1)
Foo -
In R version 2.4.0 Under development (unstable) (2006-08-08 r38825)
one can do this:
as.data.frame(cbind(x.1,x.2),stringsAsFactors = FALSE)
On 8/18/06, Tom Boonen [EMAIL PROTECTED] wrote:
Dear List,
why does as.data.frame(cbind()) transform numeric variables to
factors, once one of the
Thanks everybody. I recognize my mistake now.
I think as.data.frame(cbind(x.1,x.2),stringsAsFactors = FALSE) would
be a good idea.
Tom
On 8/18/06, Prof Brian Ripley [EMAIL PROTECTED] wrote:
On Fri, 18 Aug 2006, Tom Boonen wrote:
Dear List,
why does as.data.frame(cbind()) transform
ESS finds R by one of two mechanisms.
If R is in your PATH, then ESS will find it.
Or, if you have explicitly set the emacs variable
inferior-R-program-name, in .emacs, site-start.el, or ess-site.el,
then ESS will find R.
My guess is that you have explicitly set inferior-R-program-name
to your
Hello list,
I've been searching around trying to find whether somebody has written such
a package of least angle regression on generalized linear models, like what
Lasso2 package does. The extension to generalized linear models is briefly
discussed in the comment by D. Madigan and G. Ridgeway. Is
Without knowing your OS this is hard to answer (and is the wrong list for
the ESS question).
For Windows users, the packages part is covered in the rw-FAQ.
For Unix-alikes, it all depends how the update was done, but normal
package update mechanisms (such as RPM) will not wipe out previously
Hello R-users and developers,
Once again, I'm asking for your help.
I can identify outliers in boxplot with this instruction
result - boxplot( Income ~ Sex, col = lightgray, data=dados)
if (length(result$out))
text(result$group, result$out, result$out, pos = 4, col = red)
But I
On Fri, 2006-08-18 at 11:17 -0400, Mike Wolfgang wrote:
Hello list,
I've been searching around trying to find whether somebody has written such
a package of least angle regression on generalized linear models, like what
Lasso2 package does. The extension to generalized linear models is
Thanks for the answers so far.
I have to go through this with my system administrator.
The system is slackware linux.
For Unix-alikes, it all depends how the update was done, but normal
package update mechanisms (such as RPM) will not wipe out previously
installed R packages: nor will 'make
Hi,
How can I read data of unequal number of observations (rows) as is (i.e.
without introducing NA for columns of less observations than the maximum.
Example:
AB C D
110 1 12
210 3 12
310 4 12
410
510
Thanks in advance.
I partly answered my question since independence_test() function in coin
package apparently do
Cochran-Armitage trend test just like Eric Lecoutre's function tabletrend() -
slightly modified here:
independence_test(pheno ~ geno, data = dat2, teststat = quad, scores =
list(geno = c(0, 1,
How do you indicate which fields are present in a record with less than the
full number? Via known delimiters for all fields? Via the order of values
(fields are filled in order and only the last fields in a record can
therefore be missing)?
If the former, see the sep parameter in read.table()
I believe `lars' does not currently fit glms. For that you'll probably need
to look at `glar', at:
http://www.insightful.com/Hesterberg/glars/default.asp
HTH,
Andy
From: Marc Schwartz
On Fri, 2006-08-18 at 11:17 -0400, Mike Wolfgang wrote:
Hello list,
I've been searching around
Andy,
Upon further review of the documentation for lars, you are correct.
Thanks for the pointer to the work by Tim et al.
Regards,
Marc
On Fri, 2006-08-18 at 12:48 -0400, Liaw, Andy wrote:
I believe `lars' does not currently fit glms. For that you'll probably need
to look at `glar', at:
Tom == Tom Boonen [EMAIL PROTECTED]
on Fri, 18 Aug 2006 11:16:45 -0400 writes:
Tom Thanks everybody. I recognize my mistake now.
Tom I thinkas.data.frame(cbind(x.1,x.2),stringsAsFactors = FALSE)
Tom would be a good idea.
I think
data.frame(x.1, x.2 = I(x.2))
would
Bert,
I tried readLines. It reads the data as is, but cant access individual
columns. Still cant figure out how to accomplish this. An example would be of
great help.
PS: How do you indicate which fields are present in a record with less than
the
full number? - Via known delimiters
test.txt:
V1V2V3V4
1 2 3 4
5 6 7
8 9
10 11
12 13 14 15
The fields are delimited by tab characters (\t)
In R:
read.table(choose.files(),sep='\t',head=TRUE)
V1 V2 V3 V4
1 1 2 3 4
Try this:
result - boxplot(Petal.Length ~ Species, iris)
if (length(result$out))
text(result$group, result$out, match(result$out, iris$Petal.Length),
pos = 4, col = red)
If the outliers can be non-unique then match is not enough.
In that case assume that the nth occurrence of
any value in
After upgrading to R-2.3.1 on Linux Redhat, I was suprised by this:
R x - c(721.077, 592.291, 372.208, 381.182)
R sum(x) - 2066.758
[1] 4.547474e-13
Now I understand that floating point arithmetic is not precise, but
1) the result is exactly 0 in R-2.2.1 (patched) on the same machine,
2)
Hi Stefano,
the manual tells us that we can access components of an acf object
directly by acf.obj[.], but assignment ]- does not work this way.
One way of doing what you want is to assign NA to x$acf[x$lag==0] like so:
x - acf(runif(100))
x$acf[1] - NA
plot(x)
But I suppose what you actually
I think you want to look at
sum(x)/2066.758 - 1
which on my Linux box is 2.2e-16.
-roger
Brahm, David wrote:
After upgrading to R-2.3.1 on Linux Redhat, I was suprised by this:
R x - c(721.077, 592.291, 372.208, 381.182)
R sum(x) - 2066.758
[1] 4.547474e-13
Now I understand that
Is there a simple function or process that will create permutations with
replacement?
I know that using the combinat package
## begin R code ##
library(combinat)
m - t(array(unlist(permn(3)), dim = c(3, 6)))
# we can get the permutations, for example 3!=6
# gives us
m
[,1]
I was concerned by this result (new in R-2.3.1):
R x - c(721.077, 592.291, 372.208, 381.182)
R sum(x) - 2066.758
[1] 4.547474e-13
But after Roger Peng's [EMAIL PROTECTED] insightful comment that the
relative difference (sum(x)/2066.758 - 1) is exactly what is expected,
I'm convinced that sum()
Is there a simple function or process that will create a matrix of
permutations with replacement?
I know that using the combinat package
## begin R code ##
library(combinat)
m - t(array(unlist(permn(3)), dim = c(3, 6)))
# we can get the permutations, for example 3!=6
# gives us
m
Dear R users,
I have a data structure as follows:
id two res1 res2 c1 c2 inter
1 -0.786093166 1 0 1 2 6
3 -0.308495749 1 0 0 1 2
5
If you also want 1,1,1 and so on, the number of these is n^n,
(n choices for each of n slots.)
In that case, you could use hcube from combinat.
David L. Reiner
Rho Trading Securities, LLC
Chicago IL 60605
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
At least for R 2.3.1, neweS requires that all of the variables have names
that correspond to the colnames of the matrix. That's fine, I know about
that, and I use a modified version of neweS that puts the names in there. It
works well with data from most sources.
However, we tried reading in the
Hi, I have a situation where I have a list of lists. Each list can
contain elements of different types (but each one will be a scalar) say
of double, integer or character.
However the elements of each list are always in the same order:
x - list('a', 1, 2)
y - list('b', 3, 4)
z - list('c', 5, 6)
But after Roger Peng's [EMAIL PROTECTED] **insightful** comment that the
... but as we are not in that other S language dialect, maybe it should
be his **peRceptive** comment. ;-)
(Sorry -- it's Friday)
-- Bert Gunter
__
R-help@stat.math.ethz.ch
On Fri, 2006-08-18 at 16:44 -0400, Rajarshi Guha wrote:
Hi, I have a situation where I have a list of lists. Each list can
contain elements of different types (but each one will be a scalar) say
of double, integer or character.
However the elements of each list are always in the same order:
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Jesse Albert Canchola
Sent: Friday, August 18, 2006 1:02 PM
To: r-help
Subject: [R] Permutations with replacement
Is there a simple function or process that will create permutations with
In reviewing this I found an error in the case that there is an
outlier in one group with an equal value in another group that
is not an outlier.Also the iris example does not have duplicate
outliers so its not a very good test. Here is a much shorter
version that does not have the cited
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