(MASS)
as.fractions(c(0, 0.15, 0.827, .06, 0.266))
[1] 0 3/20 62/75 1/15 4/15
Regards, Muhammad Subianto
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Dear; Marc Schwartz and Deepayan Sarkar,
Thank you both very much for the suggestions! These are exactly what I
was looking for.
Best wishes, Muhammad Subianto
On this day 12/01/2006 09:09 PM, Deepayan Sarkar wrote:
On 12/1/06, Marc Schwartz [EMAIL PROTECTED] wrote:
On Fri, 2006-12-01 at 18
| ...
| | | | | | | | | | | | | |
-
satu dua tiga empatsatudua ...
black blond
I would be grateful if anybody could help me.
Thank you very much.
Muhammad
)
perfid.auc
Thank you very much for your help.
Best wishes, Muhammad Subianto
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and provide
to find AUC (with ROCR package, or other ROC
functions) from predict above.
Regards, Muhammad Subianto
for more information see The kernlab package here:
http://lib.stat.cmu.edu/R/CRAN/doc/packages/kernlab.pdf
cheers,
Amir
*/Muhammad Subianto [EMAIL PROTECTED]/* wrote:
Dear all,
I
Dear all,
Many thanks to Gabor Grothendieck and Jim Holtman, both of you always
reply (to answer) my problems.
Regards, Muhammad Subianto
##Gabor Grothendieck
If z is the result then z[[i]] is formed from x[[i]] and y[[i]] using
the previous solution, viz.
z - list()
z[[1]] - mapply(cbind, x
| | | |
| | | | | || | |
|pos|neg| |pos|neg||pos|neg|
| | | | | || | |
- --
v1v2v3 v7 v8
Thanks you for any helps.
Regards, Muhammad Subianto
Dear all,
Many Thanks to Jacques VESLOT and Jim Lemon for their helps.
Best, Muhammad Subianto
#Jacques VESLOT
barplot(t(sapply(split(z1[,1:8], z1$V9),colSums)), beside=T)
#Jim Lemon
barplot(sapply(z1[1:8],by,z1[9],sum),beside=TRUE)
On this day 30/08/2006 11:43, Muhammad Subianto wrote
Dear all,
To Gabor Grothendieck, (again) thanks you very much for your help.
Now, I can play around with lattice package.
Best, Muhammad Subianto
#Gabor
#reduce the data to a frequency matrix and
#then plot it using classic and then lattice graphics:
zm - as.matrix(rowsum(z1[-9], z1[,9
,]16 11 161
[2,]49 14 191
[3,]5 10 15 201
[[2]]
[,1] [,2] [,3] [,4] [,5]
[1]1611 161
[[3]]
[,1] [,2] [,3] [,4] [,5]
[1,]38 13 18 -1
[2,]5 10 15 20 -1
Best, Muhammad Subianto
points.neighb
Dear all,
Dimitris, thanks for your great help and quick response.
Best, Muhammad Subianto
dff[sapply(dff, is.matrix)]
[[1]]
[,1] [,2] [,3] [,4] [,5]
[1,]16 11 161
[2,]49 14 191
[3,]5 10 15 201
[[2]]
[,1] [,2] [,3] [,4] [,5]
[1
)))
lapply(a, function(x) matrix(unlist(x), nrow = length(x), byrow = TRUE))
but I don't know how to fix it.
Regards, Muhammad Subianto
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] [,4] [,5]
I want to remove these:
nc.test[[3]]
nc.test[[5]]
Because my list data have more 1000 lists are there any simple way to do this?
Best, Muhammad Subianto
points.neighb - function(p.class, list.nc, class.col) {
ntuples - nrow(p.class)
instvec - vector(list,length=ntuples)
for (i
On this day 28/08/2006 19:20, Muhammad Subianto wrote:
Dear all,
I am still working with list.
If I have an empty list how can I remove from list data.
Here is a toy example:
x - list(matrix(1:20, 5, 4),matrix(1:20, 5, 4),matrix(1:20, 5,
4),matrix(1:20, 5, 4),matrix(1:20, 5, 4))
y - list(c
Dear all,
I would like to thank everybody who replied for their useful
suggestions. Maybe, I am going through the book statistics to teach
(fresh) myself.
Wish you have a nice weekend.
Regards, Muhammad Subianto
On this day 24/08/2006 18:59, Muhammad Subianto wrote:
Dear all,
I apologize
(test, 1, paste, collapse=)
It doesn't work.
How can I do.
Thanks for any help.
Best, Muhammad Subianto
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Dear Stephen C. Upton Petr Pikal
Thank you both very much for the suggestions!
Best wishes, Muhammad Subianto
On this day 24/08/2006 12:03, Muhammad Subianto wrote:
Dear all,
I have a dataset
train - cbind(c(0,2,2,1,0), c(8,9,4,0,2), 6:10, c(-1, 1, 1, -1, 1))
test - cbind(1:5, c(0,1,5,1,3
46017 -1
[8,]11146018 -1
How can I do to check columns 2,3,4,6,7 and 9 have
the same value, and columns 1,5 and 8 have different values.
Best, Muhammad Subianto
__
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Dear all,
Andy, thanks you for your help and suggestions.
This is exactly what I was looking for.
Kindly regards, Muhammad Subianto
On 8/8/06, Liaw, Andy [EMAIL PROTECTED] wrote:
There may be better ways, but this should work:
R p.yes - 0.7
R n.yes - rbinom(1, nof.sample, p.yes)
R n.no
Dear all,
Suppose I have a dataset like below, then I take for example, 100
random sample class variable where contains yes and no
respectively, 70% and 30%.
I need a new 100 random sample from mydat dataset, but I can't get the result.
Thanks you very much for any helps.
Best, Muhammad Subianto
Dear JeeBee and all,
It is nice. Thanks you very much.
I must learn much more about ?as.fractions, ?as.numeric, ?as.character
and ?table functions.
Best wishes, Muhammad Subianto
On 7/28/06, JeeBee [EMAIL PROTECTED] wrote:
Ah I see, I did not read your story well enough.
You want to sort
need the result summary (order) like,
-1 1
0/42 0 4
2/42 1 1
4/42 0 3
5/42 0 1
9/42 1 2
13/42 1 1
16/42 0 1
17/42 0 2
21/42 1 0
22/42 0 1
Thanks very much for any suggestions.
Groeten Regards, Muhammad Subianto
On 7/26/06, JeeBee [EMAIL PROTECTED] wrote
How to make the result as sort (to increase) like this,
-1 1
0/42 0 4
2/42 1 1
4/42 0 3
5/42 0 1
9/42 1 2
13/42 1 1
16/42 0 1
17/42 0 2
21/42 1 0
22/42 0 1
Thank's for any help.
Best, Muhammad Subianto
__
R
Maybe like this:
mosaic(allmorph, direction = v, pop = FALSE,
gp=gpar(fill=c(grey(0.8),grey(0.4
Best, Muhammad Subianto
On 7/19/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
If you look at ?mosaic the ... argument says it gets passed to strucplot and
looking at ?strucplot we see
Maybe like this:
mosaic(allmorph, direction = v, pop = FALSE,
gp=gpar(fill=c(grey(0.8),grey(0.4
Best, Muhammad Subianto
On 7/19/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
If you look at ?mosaic the ... argument says it gets passed to strucplot and
looking at ?strucplot we see
)
and the package will be installed to /dir/of/R/libs
install.packages(NameOfPkgs,
lib=/dir/of/R/libs,
repos=NULL,
dependencies=TRUE,
contriburl=file:dir/of/pkgs)
Best, Muhammad Subianto
__
R
:
A - letters[1:8]
B - letters[1:8]
lp-list(A,B)
expand.grid(lp)
Best, Muhammad Subianto
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PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
. Thank you very much.
Best, Muhammad Subianto
version
_
platform i686-redhat-linux-gnu
arch i686
os linux-gnu
system i686, linux-gnu
status
major 2
minor 3.1
year 2006
month 06
day01
svn rev
On this day 12/07/2006 15:57, Peter Dalgaard wrote:
Muhammad Subianto [EMAIL PROTECTED] writes:
QuadSet.o RenderContext.o render.o rglview.o scene.o select.o Shape.o
SphereMesh.o SphereSet.o SpriteSet.o String.o Surface.o TextSet.o
Texture.o TriangleSet.o types.o Viewpoint.o win32gui.o
Dear all,
Per Jensen, thanks for your great help. All methods are very useful.
Best, Muhammad Subianto
On this day 20/06/2006 22:28, Per Jensen wrote:
A couple of suggestions:
#First solution
mydatexpanded-mydat[rep(1:5,mydat[,1]),]
sampledat-mydatexpanded[sample(1:85,7),-1]
#Second
So, the result random tuples (order from 6 random number):
0 1 0 1 1
0 1 0 1 1
1 1 0 1 1
1 1 0 1 1
1 1 1 1 1
0 0 0 0 1
I would be very happy if anyone could help me.
Thank you very much in advance.
Kindly regards, Muhammad Subianto
__
R-help
negative
I would be very happy if anyone could help me.
Thank you very much in advance.
Kindly regards, Muhammad Subianto
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, Muhammad Subianto
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PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Thank you very much for your useful suggestions.
These are exactly what I was looking for.
foo - list(foo1, foo2, foo3)
lapply(foo, function(x) matrix(unlist(x), nrow = length(x), byrow = TRUE))
or
lapply(foo, function(x) do.call('rbind', x))
Best, Muhammad Subianto
On 4/11/06, Muhammad
Thank you very much for your useful suggestions.
These are exactly what I was looking for.
foo - list(foo1, foo2, foo3)
lapply(foo, function(x) matrix(unlist(x), nrow = length(x), byrow = TRUE))
or
lapply(foo, function(x) do.call('rbind', x))
Best, Muhammad Subianto
On 4/11/06, Muhammad
. But I need to change a column name like [,1]
[,2] [,3]. I need the result like
[,1] [,2] [,3]
[1,] 1011
[2,] 2021
[3,] 1031
[4,] 2043
[5,] 1052
[6,] 2062
How can I do that?
Thanks in advance, Muhammad Subianto
Thank you very much for your help.
Best, Muhammad Subianto
On 4/6/06, Muhammad Subianto [EMAIL PROTECTED] wrote:
I have a question, which very easy to solve, but I can't find a solution.
I want to convert a data frame to matrix. Here my toy example:
L3 - c(1:3)
L10 - c(1:6)
d - data.frame
filename.zip? Is there any function to open R
workspace which it store in zip file? I hope some one can give me
advices.
Best, Muhammad Subianto
version
_
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major2
minor2.1
year 2005
month
' is shown in the browser
Regards, Muhammad Subianto
On 3/29/06, Philipp Pagel [EMAIL PROTECTED] wrote:
On Wed, Mar 29, 2006 at 11:44:03AM +0200, Muhammad Subianto wrote:
How can I open/load filename.zip? Is there any function to open R
workspace which it store in zip file?
I think you have
24/75 25/75 26/75
45 61117
28/75
62
Any suggestions would be appreciated. Thanks you.
Best, Muhammad Subianto
PS.
I found this website: http://www.mindspring.com/~alanh/fracs.html
On this day 27/01/2006 11:53, Prof Brian Ripley wrote:
library(MASS)
?fractions
help.search(fractions) gets you there.
Many Thanks to Berwin A Turlach and Prof Brian Ripley for your suggestions.
?fractions
Best regards, Muhammad Subianto
Thanks you for your help.
Best wishes, Muhammad Subianto
On this day 27/01/2006 12:08, Dimitris Rizopoulos wrote:
if it happens to know the denominator, then a simple approach could
be:
frac.fun - function(x, den){
dec - seq(0, den) / den
nams - paste(seq(0, den), den, sep
Thanks to Jim Holtman. This is very usefull to improve my script.
Best, Muhammad Subianto
On this day 20/12/2005 17:19, jim holtman wrote:
try this:
set.seed(1)
# generate some test data
x.1 - data.frame(seg=sample(1:6,20,T), class=sample(c('good',
'poor'),20,T))
x.1
(x.sp - split(x.1, x.1$seg
and poor class : 2,5
Thanks in advance.
Sincerely, Muhammad Subianto
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with
update.packages(ask=graphics,
repos=NULL,
contriburl=file:///h:/myFolder/myRepository)
Best, Muhammad Subianto
Cited:
- R News 5/1
- C:\Program Files\R\R-2.2.0\library\utils\html\update.packages.html
On this day 17/11/2005 08:27 AM, Prof Brian Ripley wrote
PACKAGES.gz
Could I make this folder (bin/windows/contrib/2.2/)? Why?
Regards, Muhammad Subianto
version
_
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major2
minor2.0
year 2005
month10
day 06
svn rev 35749
language R
the result like this,
$Hair
[1] Black Brown Red Blond
$Eye
[1] Brown Blue Hazel Green
$Sex
[1] Male Female
Best, Muhammad Subianto
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PLEASE do read the posting
Yes, thanks you very much.
Regards, Muhammad Subianto
HEC.list - list(Hair=Hair,Eye=Eye,Sex=Sex)
?list
On this day 15/11/2005 12:54 PM, Muhammad Subianto wrote:
Dear R-helpers,
How can I put the object name in list.
Hair - c(Black,Brown,Red,Blond)
Eye - c(Brown,Blue,Hazel,Green
).
The result I need like,
Var1 Var2 Var3
1 Black Brown Male
2 Black Blue Male
3 Black Hazel Male
4 Black Green Male
5 Black Brown Female
6 Black Blue Female
7 Black Hazel Female
8 Black Green Female
Thanks in advance.
Best, Muhammad Subianto
__
R
Thanks to everyone for your help.
Yuup, this is my stupid word secs which I put there.
Usually I get to run simulation on my machine only a few seconds.
Now, I recode my timestamp, but still I don't know how to make
x days, x hours, x minutes, x seconds.
Best wishes, Muhammad Subianto
: 1.960625 secs.
This is about two seconds or one day and nine hours?
Then, how could I convert to 1 day, 23 hours, ? minutes, ? seconds.
Thanks you very much for any suggestions.
Best wishes, Muhammad Subianto
# Begin
large dataset I can not make this manual.
Then I need the ID of row did not change, I mean like,
[3,]
[5,]
[29,]
In dataset this is about ID our customers.
I was wondering if anyone give me a trick to make simple.
Thanks you very much for any suggestions.
Best, Muhammad Subianto
Dear All,
Perfect. Thanks you very much for your help.
Best, Muhammad Subianto
my.reducedID-read.table(file.choose())
head(my.reducedID)
V1 V2 V3 V4 V5 V6 V7 V8 V9
[1,] 1 0 0 1 14 3 1 0 2
[2,] 2 0 0 1 14 3 1 0 2
[3,] 0 1 0 1 14 2 1 0 2
[4,] 0 0 1 1 14
?
Regards, Muhammad Subianto
R.version
_
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major2
minor2.0
year 2005
month10
day 06
svn rev 35749
language R
__
R-help
Your .Rdata file is probably corrupted.
I will investigate. Thanks for you info.
Because of my file .RData very large about 75MB.
Best wishes, Muhammad Subianto
On this day 19/10/2005 12:21 PM, Petr Pikal wrote:
Hi
Your .Rdata file is probably corrupted. Unless you have a working
copy
Dear R-list
I have a dataset like below (points), how can I produce a max value for
each column. I need a result like (I hope my eye correct):
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12]
[1,] 211 10 99 14 19695 8 5 7
This is a
Acchhh very easy, time to drink a cup of coffe, but
Thank you for your all.
apply(points, 2, max)
Best regards, Muhammad Subianto
On this day 17/10/2005 02:34 PM, Muhammad Subianto wrote:
Dear R-list
I have a dataset like below (points), how can I produce a max value for
each
,V17,V18,V19,V20)
Error: cannot allocate vector of size 36288 Kb
What is that? Is this about memory or I must run on machine 64bit?
Regards, Muhammad Subianto
P4 2.0GHz 512MB RAM
R.version$platform
[1] i686-redhat-linux-gnu
R.version$major
[1] 2
R.version$minor
[1] 1.1
R.version$year
[1
Dear all, Martyn Plummer and Jim Holtman (offlist) thanks you for quick
respons. Now I understand. I need more machine and memory.
Thanks a lot.
Muhammad Subianto
--- 20 columns and 54 billion rows? O:-)
On this day 13/10/2005 01:45 PM, Martyn Plummer wrote:
It's all about memory. In your
I fix this problem.
Thanks in advance for any help.
Best regards,
Muhammad Subianto
Here is a code:
neighb2 - function(point,domains) {
nn2 - sum(domains)*(sum(domains)-1)
nvar - length(point)
neighb - matrix(nrow=nn2,ncol=nvar)
k - 1
for (i in 1:nvar) {
restvars - 1:nvar
.
Best wishes, Muhammad Subianto
library(vcd)
oldpar - par(mfrow=c(1, 2))
## mosaic display for PreSex model
data(PreSex)
fm - loglm(~ PremaritalSex * ExtramaritalSex * (Gender + MaritalStatus),
data = aperm(PreSex, c(3, 2, 4, 1)))
## visualize Pearson statistic
plot(fm, split_vertical
On this day 16/09/2005 05:59 PM, Dieter Menne wrote:
Muhammad Subianto subianto at gmail.com writes:
I have a problem to make figures with two columns in package vcd.
Here an example code I take from \library\vcd\html\plot.loglm.html
What I need, I want to make two figures in one plot
Regards,
Muhammad Subianto
On this day 6/17/2005 8:14 AM, Omer Bakkalbasi wrote:
How do I convert the output of cor(x) to a columnar format?
Ex. from format below
XYZ
X 1.0 0.9 0.5
Y 0.9 1.0 0.1
Z 0.5 0.1 1.0
to format below
X X 1.0
X Y 0.9
X Z 0.5
Y X 0.9
Y
On this day 6/15/2005 12:03 AM, Gabor Grothendieck wrote:
Is the code in your post intended to show what worked so others
will know what to do
Yes, I succes to remove and install gregmisc again like I have posted
before.
Regards,
Muhammad Subianto
or is that code intended to show what you
can I change automatically 0=no and 1=yes.
Thank you very much in advance.
Kindly regards,
Muhammad Subianto
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Dear all,
Sean Davis, Dimitris Rizopoulos and Marc Schwartz, thanks for your great
help. It works perfectly. Thanks a lot.
All the best,
Muhammad Subianto
On this day 6/15/2005 4:06 PM, Sean Davis wrote:
x - data.frame(matrix(c(1,0,1,0,1,1),nrow=3))
x[x==0] - 'no'
x[x==1] - 'yes
' successfully unpacked and MD5 sums checked
...
then try to update again, still I must update package gregmisc, etc.
I have tried 3,4,5, times with the same result.
Best,
Muhammad Subianto
version
_
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major
(ask='graphics')
Regards,
Muhammad Subianto
R.2.1.0 on W2K
On this day 6/14/2005 1:51 PM, Gabor Grothendieck wrote:
On 6/14/05, Muhammad Subianto [EMAIL PROTECTED] wrote:
Dear all,
I have a problem to update package gregmisc.
After I update,
update.packages(ask='graphics')
trying URL
'http
Dear R-helpers,
On this day 6/12/2005 10:48 AM, Muhammad Subianto wrote:
Dear All,
Many thanks to Marc Schwartz and Gabor Grothendieck who have explained
me about using expand.grid function and clearly explain how to use
JGR.
dd - expand.grid(interface = interface, screen = screen
Dear all,
Again, I would like to thank Gabor Grothendieck for your help.
I can improve which you suggest with the others combination.
And thank you for your time.
Sincerely,
Muhammad Subianto
On this day 6/13/2005 2:38 PM, Gabor Grothendieck wrote:
The pattern seems to be that each row
no
Regards,
Muhammad Subianto
Notepad, Copy and Paste are my best friend to use R.2.1.0 on windows 2000
On 6/11/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 6/11/05, Marc Schwartz [EMAIL PROTECTED] wrote:
On Sat, 2005-06-11 at 20:44 +0200, Muhammad Subianto wrote:
Dear R-helpers,
I am
lcd laptop yes
usb lcd pc no
How can I do that?
I was wondering if someone can help me.
Thanks you for your time and best regards,
Muhammad Subianto
__
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,]
x y fac
3 XYZ C A
as.character(d[3,])
[1] 1 3 1
I think as.character the result something like
[3] XYZ C A
I don't know how to convert it.
Any help gratefully received.
Thank you very much in advance.
Kindly regards,
Muhammad Subianto
__
R
Dear all,
Thank you very much for your help.
I would like to thank Andy Liaw and Gabor Grothendieck for their fast help.
Regards,
Muhammad Subianto
On this day 6/10/2005 2:30 PM, Liaw, Andy wrote:
Is this what you want?
d[] - lapply(d, as.character)
str(d)
`data.frame': 10 obs
Dear R-Helper,
I want to know, is there any function/package can handle adaboost more
two classes?
I know packages gbm and boost, but there are only for 2 classes (correct
me if I mistake).
Regards, Muhammad Subianto
__
R-help@stat.math.ethz.ch
Dear all R-helpers,
Thanks you very much for your help. I would like to thanks Sean Davis
and Gabor Grothendieck for their help.
Best wishes, Muhammad Subianto
On this day 6/2/2005 3:21 PM, Gabor Grothendieck wrote:
Try this:
names(prima) - paste(xyz, names(prima), sep = .)
On this day
Dear all,
Many thanks for your help.
Regards,
Muhammad Subianto
On this day 5/18/2005 4:57 PM, Liaw, Andy wrote:
Is this what you want?
split(a, row(a))
$1
[1] 1 5 9
$2
[1] 2 6 10
$3
[1] 3 7 11
$4
[1] 4 8 12
Andy
On this day 5/18/2005 5:15 PM, [EMAIL PROTECTED] wrote:
Look
Dear Dr. Paul Murrel,
Yes, this is exactly what I need.
Thank's you very much.
Best wishes,
Muhammad Subianto
On this day 5/16/2005 5:36 AM, Paul Murrell wrote:
Hi
(cc'ed to Pierre Lapointe because this should answer the question
about [R] Centered overall title with layout() as well)
Muhammad
,
salmon.light = #dd9955,
yellowF = #00)
barplot(1:4,col = print.bw4)
Best,
Muhammad Subianto
On this day 5/16/2005 2:42 PM, Uwe Ligges wrote:
Muhammad Subianto wrote:
Thank's you very much.
But I need the plot with color not gray.
So you want a colorful rgb plot, OK, fine with your code
.
Thank you very much in advance.
Kindly regards,
Muhammad Subianto
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Group B | plot 4 |
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I would be very happy if anyone could help me.
Thank you very much in advance.
Sincerely,
Muhammad Subianto
it.
Thanks you for your help.
Best regards,
Muhammad Subianto
http://article.gmane.org/gmane.comp.lang.r.general/14604,14610
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,
Muhammad Subianto
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Excellent, this is exactly what I was looking for.
Many thanks and best regards,
Muhammad Subianto
On 4/29/05, Liaw, Andy [EMAIL PROTECTED] wrote:
Try:
a - data.frame(Sepal.Length=1:4, Sepal.Width=2:5,
Petal.Length=3:6, Petal.Width=4:7,
Species=rep(rosa,4
virginica virginica virginica virginica
[145] virginica virginica virginica virginica virginica virginica
Levels: setosa versicolor virginica
I want like,
y.iris level are,
[] setosa versicolor virginica
Best regards,
Muhammad Subianto
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Thanks you very much.
levels(y.iris)
Best regards,
Muhammad Subianto
[[alternative HTML version deleted]]
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0.2 setosa
4.9 3.1 1.5 0.1 setosa
Sincerely,
Muhammad Subianto
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Thanks all for your help.
Kind regards,
Muhammad Subianto
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to know which
variables showing in the plot. Are there any trick which variables are
showing in plot.
Thanks for your help.
Muhammad Subianto
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table() or ftable() functions because the 3rd column (Z) is
probability. Are there any function to make a table as I want?
Kind regards,
Muhammad Subianto
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PLEASE do read
Thanks to all of you.
That's what I want.
Best wishes,
Muhammad Subianto
Try
tapply(prevRND.dat$Z, list(X=prevRND.dat$X, Y=prevRND.dat$Y), mean)
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Andy Jaworskitry:
try:
tapply( Z, list( X, Y ), mean )
--
Bendix Carstensen
How about:
xtabs(Z
Maybe you can try with the other RHEL clone like CentOS-3:
http://install.linux.duke.edu/pub/linux/add-on/distrib/centos-3.1/i386/rpms/R-1.9.0-0.duke.1.el3.i386.rpm
http://install.linux.duke.edu/pub/linux/add-on/distrib/centos-3.1/i386/srpms/R-1.9.0-0.duke.1.el3.src.rpm
Best wishes,
Muhammad
Red Green 14
Red Hazel 14
Red Blue 17
Red Brown 26
Blond Green 16
Blond Hazel 10
Blond Blue 94
Blond Brown7
How can I do it. Thanks you for your help.
Best regards,
Muhammad Subianto
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https
Dear R-helper,
I use like this below (from Prof. Peter Dalgaard) and thanks to other
R-helper for your help.
Best regard,
Muhammad Subianto
as.data.frame(as.table(hec.data))
eye hair Freq
1 Green Black5
2 Hazel Black 15
3 Blue Black 20
it. Thanks you for your help.
Best regards,
Muhammad Subianto
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