Hi,
I'm puzzled on how to get this working:
class User(base):
Id = Column (Integer, primarykey=true)
Name= Column(Unicode(100))
Session.query(User).filter(User.Name.like(query+%)).all()
is all fine.
now I want to add an extension
On Dec 9, 2011, at 5:28 AM, Martijn Moeling wrote:
Hi,
I'm puzzled on how to get this working:
class User(base):
Id = Column (Integer, primarykey=true)
Name= Column(Unicode(100))
Hi ,
I'm using SA 0.5.
query1 = session.query(literal_column('Phrase').label('type')).filter(...)
query2 = session.query(literal_column('Exact').label('type')).filter(...)
and then :
query1.union(query2)
gives me :
SELECT* 'Phrase' as type*
FROM (SELECT 'Phrase' as type FROM table1 WHERE
Happy Friday all -
SQLAlchemy 0.7.4 is released. This is the latest and greatest, the version of
SQLAlchemy that I would choose above all others. Along with the recent
release of the new migrations tool, Alembic, you guys should be all humming
along very nicely with your databases at this
even simpler example:
session.query(literal_column('A').label('type')).union(session.query(literal_column('B').label('type'))).all()
returns:
[(u'A',), (u'A',)]
instead of
[(u'A',), (u'B',)]
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the UNION stuff in query() took awhile to get right and had a lot of bugs in
the 0.5 days. If you try 0.7, you'll get:
SELECT anon_1.type AS anon_1_type
FROM (SELECT 'Phrase' AS type UNION SELECT 'Exact' AS type) AS anon_1
so old bug, either work with SQL expressions (i.e. tables, select(),
Oh wow , thanks for the quick reply !
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