Hello.
I haven't used distinct() yet, but if you modify your query:
query = dbSession.query( Candidate )\
.join( Vote )\
.filter(\
model.core.Candidate.id == model.core.Vote.candidate_id ,
model.core.Vote.yay == True ,
)\
.order_by(\
Thank you very much, Michael. It is exactly what I need.
On Tuesday, October 23, 2012 5:38:36 PM UTC-4, Michael Bayer wrote:
that might not be supported yet. it just emits AUTO_INCREMENT for now.
Looking at MySQL's docs it seems like you should just emit an ALTER for
that explicitly:
Hello.
Suppose I have the following query:
def people_older_than(age):
q = session.query(Person).order_by(Person.name)
q = q.filter(Person.age age)
return q
It returns a subset of Person instances. How can I augment the query so it
returns only their count? I.e.:
def
On Wed, Oct 24, 2012 at 3:59 PM, Ladislav Lenart lenart...@volny.cz wrote:
Hello.
Suppose I have the following query:
def people_older_than(age):
q = session.query(Person).order_by(Person.name)
q = q.filter(Person.age age)
return q
It returns a subset of Person instances.
Oh, you are right of course. This works, however I would still like to transform
the query programmatically (mainly out of curiosity) from
q = session.query(Person).order_by(Person.name)
q = q.filter(Person.age age)
return q
to
q = session.query(func.count(Person.id))
with_entities() will give you this:
http://docs.sqlalchemy.org/en/rel_0_7/orm/query.html#sqlalchemy.orm.query.Query.with_entities
On Oct 24, 2012, at 11:21 AM, Ladislav Lenart wrote:
Oh, you are right of course. This works, however I would still like to
transform
the query programmatically
I'm having a problem related to this as well. Is it possible for a join to
get tripped up in the de-dup process or is that guaranteed to only occur
for the mapper entity I query on? I am getting the de-duping if I query on
the mapped entity, but if I query on the id of the entity I get the full
