thank you very much michael, this is some kind of mind spinning sqla
expression !!
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Hi Michael,
thank you very much for your prompt answer.
What I want to achieve is, counting the number of distinct items,
grouped by user_name
Given
Item1:
item_id = 1
service_id = 'test'
item_class = 'dummy'
Item2:
item_id = 2
service_id = 'other'
item_class = 'dummy'
from sqlalchemy import func, distinct
query(Invoice.user_name,
func.count(distinct(Item.id))).join(Invoice.items).group_by(Invoice.user_name)
On Jan 20, 2011, at 9:51 AM, NiL wrote:
Hi Michael,
thank you very much for your prompt answer.
What I want to achieve is, counting the number
thanks again
but the unicity of Item is guaranteed by the triplet of PK
I can't just discriminate the distinct() based on the item_id only (it
is not unique by itself in my set of data)
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session.query(Invoice.user_name,
Item).join(Invoice.item).distinct().from_self(Invoice.user_name,
func.count(1)).group_by(Invoice.user_name)
On Jan 20, 2011, at 11:45 AM, NiL wrote:
thanks again
but the unicity of Item is guaranteed by the triplet of PK
I can't just discriminate the
