I don't see the point at all in removing the ability to represent
expressions like *C1.x * C1.i + C2.y * C2.j *, it is perfectly desirable
and has a well-defined behavior under differential operators (since it's an
addition).
The point I brought up on github, is about the behavior of different
Thanks Aaron Meurer
I was not aware about that.
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Hey, all
Consider a pendulum of length OA = 2a, of mass m as a rigid body of center of
mass G (OG = a) which turn around (O,z). The angle between the reference frame
R and the rod is q.
The inertia of the body is I = (G,0,ma^2/3,ma^2/3)
When I ask Sympy for the angular momentum about point O, it
I propose an answer to my own question. Would there not an error in Sympy
? I can read here
http://docs.sympy.org/dev/modules/physics/mechanics/api/part_bod.html#sympy.physics.mechanics.rigidbody.RigidBody.angular_momentum
that:
*Angular momentum of the rigid body.*
The angular momentum H, abo
I have made a geodesic solver using sympy.diffgeom and scipy.integrate.
Currently I am having some issue with the solver. But the problem may be
related to Scipy. I have posted a thread here :
http://scicomp.stackexchange.com/questions/21103/numerical-solution-of-geodesic-differential-equations
I think you are correct. Here is the output if you change the angular
momentum function to use the velocity of the mass center:
In [1]: %paste
from sympy import symbols
from sympy.physics.mechanics import *
m,a = symbols('m a')
q = dynamicsymbols('q')
R = ReferenceFrame('R')
R1 = R.orientnew('R1
I just submitted this PR: https://github.com/sympy/sympy/pull/10037 with a
fix.
Jason
moorepants.info
+01 530-601-9791
On Sat, Oct 24, 2015 at 10:49 PM, Jason Moore wrote:
> I think you are correct. Here is the output if you change the angular
> momentum function to use the velocity of the mas
Thank you Jason for your reply and to fix proposal,
Philippe
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