Ditto Boggle, the longer the word the more points you get.
--
Jacqueline Landman Gay | jac...@hyperactivesw.com
HyperActive Software | http://www.hyperactivesw.com
On March 11, 2022 8:03:20 AM Craig Newman via use-livecode
wrote:
I play Scrabble, not Boggle.
Regardless of which dictionary
I play Scrabble, not Boggle.
Regardless of which dictionary people use, there are many more words of 8 - 10
characters than of 4 - 6 characters.
Craig
> On Mar 10, 2022, at 5:25 PM, doc hawk via use-livecode
> wrote:
>
>
> jacqui jawed,
>
>
>> filter tHugeDict without regex pattern
jacqui jawed,
> filter tHugeDict without regex pattern "[qkxyz]”
I expect that would be faster.
But it will also bring words that are too long, although I have no idea whether
or not there would be enough to matter.
___
use-livecode mailing list
On 3/9/22 3:42 PM, doc hawk via use-livecode wrote:
Something like
^[manl]\{2,5\}$
which matches all strings of length 2 to 5 composed exclusively of the letters m,
a, n, & l ?
I want to eliminate all words contains any of the letters in the group. I didn't get
confirmation that my regex
jacqui juggled,
>
> Funny you should bring this up, as I was playing with it last night. Turns
> out that multiple filters do slow down on the Pixel so I was looking for the
> One True Regex.
Something like
^[manl]\{2,5\}$
which matches all strings of length 2 to 5 composed exclusively
Funny you should bring this up, as I was playing with it last night. Turns
out that multiple filters do slow down on the Pixel so I was looking for
the One True Regex.
I'm not great at this so would like verification from those who know if
this is what I need:
put "[" & tUnusedLetters & "]"
Hi Mark,
In regex the full stop stands for any single character whereby the * means
any other characters. If you want to only find things that begin with a
character put a ^ infront of the character you are searching for. So ^a.
should only return apple in your example.
Regards
Andy
On Mon, 7
So, playing around a bit more I discovered “a.*” does not return words that
“start with”, but rather words that “contain” the letter. So that explains
“apple, banana”. What isn’t clear to me is I get the exact same result using
“a.” with no asterisk, but if I search for “y.” it returns nothing
I am not an expert in regex or filtering by any means so Quentin’s message
prompted me to take a closer look. I started with the dictionary entry for
filter and I found this simple example:
filter items of "apple,banana,cherry" with regex pattern "b.*"
Since we are not specifying a destination,
sez j. landman gay:
> Interesting idea. There are 25 letters on each board, some are always
> repeats. I think I'd need
> a good regex so I wouldn't have to run the filter command multiple times.
> How's your regex?
I see you've already implemented something, but just for grins, here's my
10 matches
Mail list logo
