Hey,
I have a form and I want to submit it via Ajax:
wicket:panel
form wicket:id=form
div wicket:id=feedback/div
table width=100% cellpadding=2 cellspacing=2
tr
tdlabelwicket:message key=name/
/label/td
tdspan wicket:id=nameBorder
You should implement the onError method of the button and update
feedback panel to see possible validation errors.
**
Martin
2009/4/19 HHB hubaghd...@yahoo.ca:
Hey,
I have a form and I want to submit it via Ajax:
wicket:panel
form wicket:id=form
div wicket:id=feedback/div
All looks good to me, my guess is that you aren't entering in a name,
and so you're failing validation, but you haven't implemented onError
to add the feedback panel to the target in that case. Also, your
feedback panel probably needs setOutputMarkupId(true) to be of any
use, given that you're
Yes, you are right.
My isssue is solved now, thanks.
cpopetz wrote:
All looks good to me, my guess is that you aren't entering in a name,
and so you're failing validation, but you haven't implemented onError
to add the feedback panel to the target in that case. Also, your
feedback panel