Hi Ivan,
Excellent! You guys are awesome!
Regards
Rajeev J Sebastian
On Feb 12, 2008 12:21 AM, Ivan Mikhailov imikhai...@openlinksw.com wrote:
Rajeev,
BI extensions will be documented as soon as the syntax is stable. It can
be slightly changed because a) it's our work in progress and b
Hi Kunal,
Currently, only the rdf:type is inferenced, based on rdfs:subClassOf
... also, rdfs:subProperty is also used to infer arcs.
Regards
Rajeev J Sebastian
On Feb 6, 2008 2:56 AM, Kunal Patel kunaled...@yahoo.com wrote:
Hi,
I am trying to use Virtuoso as an RDFS/OWL storage, inference
this faster ?
Regards
Rajeev J Sebastian
-text expression, as described in the documentation:
Other than the suggestions not working for the error mentioned, I
should add that I am using the SPARQL endpoint for this, not the SQL
interface.
Regards
Rajeev J Sebastian
as the literal.
I get the following error:
37000 Error XM029: Free-text expression, line 0: Invalid character in
free-text search expression, it may not appear outside quoted string
at �
Both the above work for latin strings. I dont know about other scripts though.
Regards
Rajeev J Sebastian
... since that was
the value in my sample data.
Also, in Virtuoso, will there be equivalence between typed values ?
For e.g., in python, 1 == 1.0 works even thought first is integer and
second is a float
Regards
Rajeev J Sebastian
the describe and select works correctly.
(I wrote the above just for the mailing list archive.)
Thanks to all
Regards
Rajeev J Sebastian
On Jan 22, 2008 2:29 PM, Rajeev J Sebastian rajeev.sebast...@gmail.com wrote:
Hello Ivan,
Thanks for your response.
The reason I asked about it was that a particular
Hello all,
I had sent the below attached email to the list regarding an error I
had come across, but there was no response. Is the
virtuoso-users@lists.sourceforge.net the correct email address for
such questions ?
Regards
Rajeev J Sebastian
On Jan 19, 2008 5:51 AM, Rajeev J Sebastian
Hello all,
I am running Virtuoso Version 05.00.3023-pthreads.
When running a sparul something like:
insert {
foo:xyz foo:left 21.0396039604^^http://www.w3.org/2001/XMLSchema#float.
}
I get an error, 37000 Error SP031: SPARQL compiler: Current
implementation of SPARQL does not supports literals
... is this expected behaviour ?
Inference seems to work for instances of the classes c2, c3, c4 though
... (i.e., directly using your examples at
(http://docs.openlinksw.com/virtuoso/rdfsparqlrule.html)
Regards
Rajeev J Sebastian
the failure
reason we can see that in fact if it werent for the virtrdf context,
it will actually work.
Btw, thanks very much for your work on Virtuoso Triple Store! It is
really awesome and standards compliant.
Regards
Rajeev J Sebastian
Hi,
I'm unit testing a Virtuoso-over-SPARQL client, but the problem is
that the virtrdf context (i guess it refers to the rdf mapper) gets in
the way of the test.
Is there some way to get rid of it during testing ?
Regards
Rajeev J Sebastian
Hello Patrick van Kleef,
I see a problem in the Sparql endpoint ... if there is an error in the
query string, it doesnt return any HTTP 4xx error. Rather, it returns
a non Sparql Results XML response.
Do you have the same result there ?
Regards
Rajeev J Sebastian
On 9/25/07, Virtuoso
the developers give some suggestions on the best way to implement this ?
Regards
Rajeev J Sebastian
to console fine. The
problem is, ?o is of the any type as per your descriptions in
Virtuoso docs. But, I need to know whether in a given row of the
result set, whether ?o is bound to a blank node or an XML Schema
literal of some type, etc.
How can I determine that ?
Regards
Rajeev J Sebastian
:
LC_ALL=POSIX make
seems to work.
I'll give you the results when it is complete.
I have a question regarding VOS. What is the Inference capability of
VOS for RDF ? Is there any documentation regarding that ?
Regards
Rajeev J Sebastian
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