Perhaps so, But from what I have read of this thread, it seems that Frank is mistaken if he believes that current flows in an electrolyte by way of electrons, "Current consists of electrons flowing through the electrically conductive ionic solution." In fact current flows in an electrolyte by the mobility of ions which traverse the solvent to gain or loose electrons at the electrode-solvent boundary.
There is however, special cases (which usually involve extreme conditions), where free electrons do become solvated or hydrated. Hydrated electrons are most readily created by dissolving alkaline earth metals in liquid ammonia, and which are stable because they are caged or boxed by the solvent (the velocity of diffusion being the that of the cage). But in standard electrochemical cells this quote is sums current thought: " In particular, what is to be questioned is whether or not free electrons in solution are ever present at any stage of the reaction. In general, the answer is that they are not. That such an answer can be given is due to extensive studies of the so-called hydrated electron, e(aq), formed, for example, by bombardment of water with high energy b particles (electrons emitted during nuclear disintegrations). This extremely potent reducing agent is very short-lived in water and could not be involved as an intermediate in solution redox processes except perhaps those involving the alkali metals." http://www.chem.uwa.edu.au/enrolled_students/Chem100/Chem100_sect4/sec t4.3.html While free electrons are unlikely to be introduced by the electrodes, they may be introduced into a solution by photoionisation or injected by low energy electron beam, and given that Frank mentions nano or microsecond kilovolt pulses, with a peak power of tens of kilowatts... Regards Ivan. -----Original Message----- From: [email protected] [mailto:[email protected]] Sent: Saturday, 12 July 2003 5:34 p.m. To: [email protected] Subject: Re: CS> H2O2, ag(+), NaCl Aha! Now we know more about the mysterious "mesoprocess" then we did before. Soon the Japanese will be reverse engineering the process and selling it for pennies on the gallon. Either way, it's a free plug. http://www.colloidalsciencelab.com/ Andy (^_^) From: Frank Key No. We were not measuring Coulombs. We were measuring peak power in tens of kilowatts and average power in hundreds of watts along with pulse width in ns/us, pulse repetition rates, peak pulse voltage in kilovolts. From the raw data one could determine Coulombs, but we did not bother to do so. frank key -- The silver-list is a moderated forum for discussion of colloidal silver. Instructions for unsubscribing may be found at: http://silverlist.org To post, address your message to: [email protected] Silver-list archive: http://escribe.com/health/thesilverlist/index.html List maintainer: Mike Devour <[email protected]>
