Hello Maz, It's the wetted area of the donor electrode, the anode. Even if you're switching the polarity, at any moment only one is providing silver.
The suggested current density has always been phrased as 1 ma per 1 square inch. That means you need to estimate the surface area of your anode. A straight wire sticking down into the water would be estimated by... pi * diameter * length ... if you're willing to ignore the tiny bit of surface on the end. The problem is that the pointy end causes concentration of the electrical field and the current density there is much higher. One way people have gotten around that is to use "U" shaped electrodes, with both ends of the wire out of the water. Then it is pretty much the wetted length of the wire times the wire circumference, and no pointy bits to worry about. Keep asking. Let us know how it goes. Mike D. > One more clarification on current regulation, I believe, before I order > and hook em up. Dan mentioned using the 1ma current limiting diodes in > proportion to electrode surface area i.e.1ma/1sq in , whereas everyone > was more or less in agreement on the limit at or under 1ma. Is the > proportion the thing? And is it one or both electrodes? > > Maz > [Mike Devour, Citizen, Patriot, Libertarian] [mdev...@eskimo.com ] [Speaking only for myself... ] -- The Silver List is a moderated forum for discussing Colloidal Silver. Instructions for unsubscribing are posted at: http://silverlist.org To post, address your message to: silver-list@eskimo.com Address Off-Topic messages to: silver-off-topic-l...@eskimo.com The Silver List and Off Topic List archives are currently down... List maintainer: Mike Devour <mdev...@eskimo.com>
